Optimal. Leaf size=157 \[ -\frac {152 \cos (e+f x)}{1155 a^8 f (\sin (e+f x)+1)}+\frac {1003 \cos (e+f x)}{1155 a^8 f (\sin (e+f x)+1)^2}-\frac {846 \cos (e+f x)}{385 a^8 f (\sin (e+f x)+1)^3}+\frac {617 \cos (e+f x)}{231 a^8 f (\sin (e+f x)+1)^4}-\frac {52 \cos (e+f x)}{33 a^8 f (\sin (e+f x)+1)^5}+\frac {4 \cos (e+f x)}{11 a^8 f (\sin (e+f x)+1)^6} \]
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Rubi [A] time = 0.57, antiderivative size = 157, normalized size of antiderivative = 1.00, number of steps used = 24, number of rules used = 4, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.138, Rules used = {2875, 2872, 2650, 2648} \[ -\frac {152 \cos (e+f x)}{1155 a^8 f (\sin (e+f x)+1)}+\frac {1003 \cos (e+f x)}{1155 a^8 f (\sin (e+f x)+1)^2}-\frac {846 \cos (e+f x)}{385 a^8 f (\sin (e+f x)+1)^3}+\frac {617 \cos (e+f x)}{231 a^8 f (\sin (e+f x)+1)^4}-\frac {52 \cos (e+f x)}{33 a^8 f (\sin (e+f x)+1)^5}+\frac {4 \cos (e+f x)}{11 a^8 f (\sin (e+f x)+1)^6} \]
Antiderivative was successfully verified.
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Rule 2648
Rule 2650
Rule 2872
Rule 2875
Rubi steps
\begin {align*} \int \frac {\cos ^4(e+f x) \sin ^3(e+f x)}{(a+a \sin (e+f x))^8} \, dx &=\frac {\int \sec ^9(e+f x) (a-a \sin (e+f x))^8 \tan ^3(e+f x) \, dx}{a^{16}}\\ &=\frac {\int \left (-\frac {4}{a^4 (1+\sin (e+f x))^6}+\frac {16}{a^4 (1+\sin (e+f x))^5}-\frac {25}{a^4 (1+\sin (e+f x))^4}+\frac {19}{a^4 (1+\sin (e+f x))^3}-\frac {7}{a^4 (1+\sin (e+f x))^2}+\frac {1}{a^4 (1+\sin (e+f x))}\right ) \, dx}{a^4}\\ &=\frac {\int \frac {1}{1+\sin (e+f x)} \, dx}{a^8}-\frac {4 \int \frac {1}{(1+\sin (e+f x))^6} \, dx}{a^8}-\frac {7 \int \frac {1}{(1+\sin (e+f x))^2} \, dx}{a^8}+\frac {16 \int \frac {1}{(1+\sin (e+f x))^5} \, dx}{a^8}+\frac {19 \int \frac {1}{(1+\sin (e+f x))^3} \, dx}{a^8}-\frac {25 \int \frac {1}{(1+\sin (e+f x))^4} \, dx}{a^8}\\ &=\frac {4 \cos (e+f x)}{11 a^8 f (1+\sin (e+f x))^6}-\frac {16 \cos (e+f x)}{9 a^8 f (1+\sin (e+f x))^5}+\frac {25 \cos (e+f x)}{7 a^8 f (1+\sin (e+f x))^4}-\frac {19 \cos (e+f x)}{5 a^8 f (1+\sin (e+f x))^3}+\frac {7 \cos (e+f x)}{3 a^8 f (1+\sin (e+f x))^2}-\frac {\cos (e+f x)}{a^8 f (1+\sin (e+f x))}-\frac {20 \int \frac {1}{(1+\sin (e+f x))^5} \, dx}{11 a^8}-\frac {7 \int \frac {1}{1+\sin (e+f x)} \, dx}{3 a^8}+\frac {64 \int \frac {1}{(1+\sin (e+f x))^4} \, dx}{9 a^8}+\frac {38 \int \frac {1}{(1+\sin (e+f x))^2} \, dx}{5 a^8}-\frac {75 \int \frac {1}{(1+\sin (e+f x))^3} \, dx}{7 a^8}\\ &=\frac {4 \cos (e+f x)}{11 a^8 f (1+\sin (e+f x))^6}-\frac {52 \cos (e+f x)}{33 a^8 f (1+\sin (e+f x))^5}+\frac {23 \cos (e+f x)}{9 a^8 f (1+\sin (e+f x))^4}-\frac {58 \cos (e+f x)}{35 a^8 f (1+\sin (e+f x))^3}-\frac {\cos (e+f x)}{5 a^8 f (1+\sin (e+f x))^2}+\frac {4 \cos (e+f x)}{3 a^8 f (1+\sin (e+f x))}-\frac {80 \int \frac {1}{(1+\sin (e+f x))^4} \, dx}{99 a^8}+\frac {38 \int \frac {1}{1+\sin (e+f x)} \, dx}{15 a^8}+\frac {64 \int \frac {1}{(1+\sin (e+f x))^3} \, dx}{21 a^8}-\frac {30 \int \frac {1}{(1+\sin (e+f x))^2} \, dx}{7 a^8}\\ &=\frac {4 \cos (e+f x)}{11 a^8 f (1+\sin (e+f x))^6}-\frac {52 \cos (e+f x)}{33 a^8 f (1+\sin (e+f x))^5}+\frac {617 \cos (e+f x)}{231 a^8 f (1+\sin (e+f x))^4}-\frac {34 \cos (e+f x)}{15 a^8 f (1+\sin (e+f x))^3}+\frac {43 \cos (e+f x)}{35 a^8 f (1+\sin (e+f x))^2}-\frac {6 \cos (e+f x)}{5 a^8 f (1+\sin (e+f x))}-\frac {80 \int \frac {1}{(1+\sin (e+f x))^3} \, dx}{231 a^8}+\frac {128 \int \frac {1}{(1+\sin (e+f x))^2} \, dx}{105 a^8}-\frac {10 \int \frac {1}{1+\sin (e+f x)} \, dx}{7 a^8}\\ &=\frac {4 \cos (e+f x)}{11 a^8 f (1+\sin (e+f x))^6}-\frac {52 \cos (e+f x)}{33 a^8 f (1+\sin (e+f x))^5}+\frac {617 \cos (e+f x)}{231 a^8 f (1+\sin (e+f x))^4}-\frac {846 \cos (e+f x)}{385 a^8 f (1+\sin (e+f x))^3}+\frac {37 \cos (e+f x)}{45 a^8 f (1+\sin (e+f x))^2}+\frac {8 \cos (e+f x)}{35 a^8 f (1+\sin (e+f x))}-\frac {32 \int \frac {1}{(1+\sin (e+f x))^2} \, dx}{231 a^8}+\frac {128 \int \frac {1}{1+\sin (e+f x)} \, dx}{315 a^8}\\ &=\frac {4 \cos (e+f x)}{11 a^8 f (1+\sin (e+f x))^6}-\frac {52 \cos (e+f x)}{33 a^8 f (1+\sin (e+f x))^5}+\frac {617 \cos (e+f x)}{231 a^8 f (1+\sin (e+f x))^4}-\frac {846 \cos (e+f x)}{385 a^8 f (1+\sin (e+f x))^3}+\frac {1003 \cos (e+f x)}{1155 a^8 f (1+\sin (e+f x))^2}-\frac {8 \cos (e+f x)}{45 a^8 f (1+\sin (e+f x))}-\frac {32 \int \frac {1}{1+\sin (e+f x)} \, dx}{693 a^8}\\ &=\frac {4 \cos (e+f x)}{11 a^8 f (1+\sin (e+f x))^6}-\frac {52 \cos (e+f x)}{33 a^8 f (1+\sin (e+f x))^5}+\frac {617 \cos (e+f x)}{231 a^8 f (1+\sin (e+f x))^4}-\frac {846 \cos (e+f x)}{385 a^8 f (1+\sin (e+f x))^3}+\frac {1003 \cos (e+f x)}{1155 a^8 f (1+\sin (e+f x))^2}-\frac {152 \cos (e+f x)}{1155 a^8 f (1+\sin (e+f x))}\\ \end {align*}
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Mathematica [A] time = 3.18, size = 195, normalized size = 1.24 \[ -\frac {-299970 \sin \left (2 e+\frac {3 f x}{2}\right )+145695 \sin \left (2 e+\frac {5 f x}{2}\right )+44990 \sin \left (4 e+\frac {7 f x}{2}\right )-6710 \sin \left (4 e+\frac {9 f x}{2}\right )+\sin \left (6 e+\frac {11 f x}{2}\right )-486024 \cos \left (e+\frac {f x}{2}\right )+351450 \cos \left (e+\frac {3 f x}{2}\right )+180015 \cos \left (3 e+\frac {5 f x}{2}\right )-63580 \cos \left (3 e+\frac {7 f x}{2}\right )-15004 \cos \left (5 e+\frac {9 f x}{2}\right )+1975 \cos \left (5 e+\frac {11 f x}{2}\right )-425964 \sin \left (\frac {f x}{2}\right )}{240240 a^8 f \left (\sin \left (\frac {e}{2}\right )+\cos \left (\frac {e}{2}\right )\right ) \left (\sin \left (\frac {1}{2} (e+f x)\right )+\cos \left (\frac {1}{2} (e+f x)\right )\right )^{11}} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.46, size = 291, normalized size = 1.85 \[ \frac {152 \, \cos \left (f x + e\right )^{6} - 243 \, \cos \left (f x + e\right )^{5} - 745 \, \cos \left (f x + e\right )^{4} + 455 \, \cos \left (f x + e\right )^{3} + 1015 \, \cos \left (f x + e\right )^{2} + {\left (152 \, \cos \left (f x + e\right )^{5} + 395 \, \cos \left (f x + e\right )^{4} - 350 \, \cos \left (f x + e\right )^{3} - 805 \, \cos \left (f x + e\right )^{2} + 210 \, \cos \left (f x + e\right ) + 420\right )} \sin \left (f x + e\right ) - 210 \, \cos \left (f x + e\right ) - 420}{1155 \, {\left (a^{8} f \cos \left (f x + e\right )^{6} - 5 \, a^{8} f \cos \left (f x + e\right )^{5} - 18 \, a^{8} f \cos \left (f x + e\right )^{4} + 20 \, a^{8} f \cos \left (f x + e\right )^{3} + 48 \, a^{8} f \cos \left (f x + e\right )^{2} - 16 \, a^{8} f \cos \left (f x + e\right ) - 32 \, a^{8} f - {\left (a^{8} f \cos \left (f x + e\right )^{5} + 6 \, a^{8} f \cos \left (f x + e\right )^{4} - 12 \, a^{8} f \cos \left (f x + e\right )^{3} - 32 \, a^{8} f \cos \left (f x + e\right )^{2} + 16 \, a^{8} f \cos \left (f x + e\right ) + 32 \, a^{8} f\right )} \sin \left (f x + e\right )\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.48, size = 120, normalized size = 0.76 \[ -\frac {4 \, {\left (1155 \, \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{7} - 2079 \, \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{6} + 2541 \, \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{5} - 825 \, \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{4} + 165 \, \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{3} + 55 \, \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )^{2} + 11 \, \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 1\right )}}{1155 \, a^{8} f {\left (\tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 1\right )}^{11}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.53, size = 130, normalized size = 0.83 \[ \frac {\frac {256}{11 \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{11}}+\frac {2064}{7 \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{7}}-\frac {136}{\left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{6}}-\frac {384}{\left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{8}}-\frac {128}{\left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{10}}+\frac {176}{5 \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{5}}+\frac {896}{3 \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{9}}-\frac {4}{\left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )^{4}}}{f \,a^{8}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.35, size = 401, normalized size = 2.55 \[ -\frac {4 \, {\left (\frac {11 \, \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + \frac {55 \, \sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} + \frac {165 \, \sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}} - \frac {825 \, \sin \left (f x + e\right )^{4}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{4}} + \frac {2541 \, \sin \left (f x + e\right )^{5}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{5}} - \frac {2079 \, \sin \left (f x + e\right )^{6}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{6}} + \frac {1155 \, \sin \left (f x + e\right )^{7}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{7}} + 1\right )}}{1155 \, {\left (a^{8} + \frac {11 \, a^{8} \sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + \frac {55 \, a^{8} \sin \left (f x + e\right )^{2}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{2}} + \frac {165 \, a^{8} \sin \left (f x + e\right )^{3}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{3}} + \frac {330 \, a^{8} \sin \left (f x + e\right )^{4}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{4}} + \frac {462 \, a^{8} \sin \left (f x + e\right )^{5}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{5}} + \frac {462 \, a^{8} \sin \left (f x + e\right )^{6}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{6}} + \frac {330 \, a^{8} \sin \left (f x + e\right )^{7}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{7}} + \frac {165 \, a^{8} \sin \left (f x + e\right )^{8}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{8}} + \frac {55 \, a^{8} \sin \left (f x + e\right )^{9}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{9}} + \frac {11 \, a^{8} \sin \left (f x + e\right )^{10}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{10}} + \frac {a^{8} \sin \left (f x + e\right )^{11}}{{\left (\cos \left (f x + e\right ) + 1\right )}^{11}}\right )} f} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 9.41, size = 205, normalized size = 1.31 \[ -\frac {4\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4\,\left ({\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^7+11\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^6\,\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )+55\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^5\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2+165\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3-825\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^3\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^4+2541\,{\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^2\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^5-2079\,\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^6+1155\,{\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )}^7\right )}{1155\,a^8\,f\,{\left (\cos \left (\frac {e}{2}+\frac {f\,x}{2}\right )+\sin \left (\frac {e}{2}+\frac {f\,x}{2}\right )\right )}^{11}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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