Optimal. Leaf size=205 \[ -\frac {4 \cos (c+d x) (a \sin (c+d x)+a)^{3/2}}{385 a^3 d}-\frac {2 \sin ^4(c+d x) \cos (c+d x) \sqrt {a \sin (c+d x)+a}}{11 a^2 d}+\frac {8 \cos (c+d x) \sqrt {a \sin (c+d x)+a}}{1155 a^2 d}+\frac {14 \sin ^4(c+d x) \cos (c+d x)}{33 a d \sqrt {a \sin (c+d x)+a}}-\frac {2 \sin ^3(c+d x) \cos (c+d x)}{231 a d \sqrt {a \sin (c+d x)+a}}-\frac {4 \cos (c+d x)}{165 a d \sqrt {a \sin (c+d x)+a}} \]
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Rubi [A] time = 0.78, antiderivative size = 205, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 7, integrand size = 31, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.226, Rules used = {2880, 2770, 2759, 2751, 2646, 3046, 2981} \[ -\frac {2 \sin ^4(c+d x) \cos (c+d x) \sqrt {a \sin (c+d x)+a}}{11 a^2 d}-\frac {4 \cos (c+d x) (a \sin (c+d x)+a)^{3/2}}{385 a^3 d}+\frac {8 \cos (c+d x) \sqrt {a \sin (c+d x)+a}}{1155 a^2 d}+\frac {14 \sin ^4(c+d x) \cos (c+d x)}{33 a d \sqrt {a \sin (c+d x)+a}}-\frac {2 \sin ^3(c+d x) \cos (c+d x)}{231 a d \sqrt {a \sin (c+d x)+a}}-\frac {4 \cos (c+d x)}{165 a d \sqrt {a \sin (c+d x)+a}} \]
Antiderivative was successfully verified.
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Rule 2646
Rule 2751
Rule 2759
Rule 2770
Rule 2880
Rule 2981
Rule 3046
Rubi steps
\begin {align*} \int \frac {\cos ^4(c+d x) \sin ^3(c+d x)}{(a+a \sin (c+d x))^{3/2}} \, dx &=\frac {\int \sin ^3(c+d x) \sqrt {a+a \sin (c+d x)} \left (1+\sin ^2(c+d x)\right ) \, dx}{a^2}-\frac {2 \int \sin ^4(c+d x) \sqrt {a+a \sin (c+d x)} \, dx}{a^2}\\ &=\frac {4 \cos (c+d x) \sin ^4(c+d x)}{9 a d \sqrt {a+a \sin (c+d x)}}-\frac {2 \cos (c+d x) \sin ^4(c+d x) \sqrt {a+a \sin (c+d x)}}{11 a^2 d}+\frac {2 \int \sin ^3(c+d x) \left (\frac {19 a}{2}+\frac {1}{2} a \sin (c+d x)\right ) \sqrt {a+a \sin (c+d x)} \, dx}{11 a^3}-\frac {16 \int \sin ^3(c+d x) \sqrt {a+a \sin (c+d x)} \, dx}{9 a^2}\\ &=\frac {32 \cos (c+d x) \sin ^3(c+d x)}{63 a d \sqrt {a+a \sin (c+d x)}}+\frac {14 \cos (c+d x) \sin ^4(c+d x)}{33 a d \sqrt {a+a \sin (c+d x)}}-\frac {2 \cos (c+d x) \sin ^4(c+d x) \sqrt {a+a \sin (c+d x)}}{11 a^2 d}-\frac {32 \int \sin ^2(c+d x) \sqrt {a+a \sin (c+d x)} \, dx}{21 a^2}+\frac {179 \int \sin ^3(c+d x) \sqrt {a+a \sin (c+d x)} \, dx}{99 a^2}\\ &=-\frac {2 \cos (c+d x) \sin ^3(c+d x)}{231 a d \sqrt {a+a \sin (c+d x)}}+\frac {14 \cos (c+d x) \sin ^4(c+d x)}{33 a d \sqrt {a+a \sin (c+d x)}}-\frac {2 \cos (c+d x) \sin ^4(c+d x) \sqrt {a+a \sin (c+d x)}}{11 a^2 d}+\frac {64 \cos (c+d x) (a+a \sin (c+d x))^{3/2}}{105 a^3 d}-\frac {64 \int \left (\frac {3 a}{2}-a \sin (c+d x)\right ) \sqrt {a+a \sin (c+d x)} \, dx}{105 a^3}+\frac {358 \int \sin ^2(c+d x) \sqrt {a+a \sin (c+d x)} \, dx}{231 a^2}\\ &=-\frac {2 \cos (c+d x) \sin ^3(c+d x)}{231 a d \sqrt {a+a \sin (c+d x)}}+\frac {14 \cos (c+d x) \sin ^4(c+d x)}{33 a d \sqrt {a+a \sin (c+d x)}}-\frac {128 \cos (c+d x) \sqrt {a+a \sin (c+d x)}}{315 a^2 d}-\frac {2 \cos (c+d x) \sin ^4(c+d x) \sqrt {a+a \sin (c+d x)}}{11 a^2 d}-\frac {4 \cos (c+d x) (a+a \sin (c+d x))^{3/2}}{385 a^3 d}+\frac {716 \int \left (\frac {3 a}{2}-a \sin (c+d x)\right ) \sqrt {a+a \sin (c+d x)} \, dx}{1155 a^3}-\frac {32 \int \sqrt {a+a \sin (c+d x)} \, dx}{45 a^2}\\ &=\frac {64 \cos (c+d x)}{45 a d \sqrt {a+a \sin (c+d x)}}-\frac {2 \cos (c+d x) \sin ^3(c+d x)}{231 a d \sqrt {a+a \sin (c+d x)}}+\frac {14 \cos (c+d x) \sin ^4(c+d x)}{33 a d \sqrt {a+a \sin (c+d x)}}+\frac {8 \cos (c+d x) \sqrt {a+a \sin (c+d x)}}{1155 a^2 d}-\frac {2 \cos (c+d x) \sin ^4(c+d x) \sqrt {a+a \sin (c+d x)}}{11 a^2 d}-\frac {4 \cos (c+d x) (a+a \sin (c+d x))^{3/2}}{385 a^3 d}+\frac {358 \int \sqrt {a+a \sin (c+d x)} \, dx}{495 a^2}\\ &=-\frac {4 \cos (c+d x)}{165 a d \sqrt {a+a \sin (c+d x)}}-\frac {2 \cos (c+d x) \sin ^3(c+d x)}{231 a d \sqrt {a+a \sin (c+d x)}}+\frac {14 \cos (c+d x) \sin ^4(c+d x)}{33 a d \sqrt {a+a \sin (c+d x)}}+\frac {8 \cos (c+d x) \sqrt {a+a \sin (c+d x)}}{1155 a^2 d}-\frac {2 \cos (c+d x) \sin ^4(c+d x) \sqrt {a+a \sin (c+d x)}}{11 a^2 d}-\frac {4 \cos (c+d x) (a+a \sin (c+d x))^{3/2}}{385 a^3 d}\\ \end {align*}
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Mathematica [A] time = 5.59, size = 102, normalized size = 0.50 \[ \frac {\sqrt {a (\sin (c+d x)+1)} \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )^5 (-475 \sin (c+d x)+105 \sin (3 (c+d x))+140 \cos (2 (c+d x))-204)}{2310 a^2 d \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.47, size = 161, normalized size = 0.79 \[ -\frac {2 \, {\left (105 \, \cos \left (d x + c\right )^{6} - 140 \, \cos \left (d x + c\right )^{5} - 460 \, \cos \left (d x + c\right )^{4} + 274 \, \cos \left (d x + c\right )^{3} + 607 \, \cos \left (d x + c\right )^{2} + {\left (105 \, \cos \left (d x + c\right )^{5} + 245 \, \cos \left (d x + c\right )^{4} - 215 \, \cos \left (d x + c\right )^{3} - 489 \, \cos \left (d x + c\right )^{2} + 118 \, \cos \left (d x + c\right ) + 236\right )} \sin \left (d x + c\right ) - 118 \, \cos \left (d x + c\right ) - 236\right )} \sqrt {a \sin \left (d x + c\right ) + a}}{1155 \, {\left (a^{2} d \cos \left (d x + c\right ) + a^{2} d \sin \left (d x + c\right ) + a^{2} d\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.73, size = 286, normalized size = 1.40 \[ -\frac {8 \, {\left (\frac {59 \, \sqrt {2} \mathrm {sgn}\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )}{a^{\frac {3}{2}}} + \frac {2 \, {\left (\frac {2 \, a^{4}}{\mathrm {sgn}\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )} + {\left (\frac {11 \, a^{4}}{\mathrm {sgn}\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )} - {\left (\frac {264 \, a^{4}}{\mathrm {sgn}\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )} - {\left (\frac {693 \, a^{4}}{\mathrm {sgn}\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )} - {\left (\frac {693 \, a^{4}}{\mathrm {sgn}\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )} - {\left (\frac {264 \, a^{4}}{\mathrm {sgn}\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )} - {\left (\frac {2 \, a^{4} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2}}{\mathrm {sgn}\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )} + \frac {11 \, a^{4}}{\mathrm {sgn}\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )}\right )} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2}\right )} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2}\right )} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2}\right )}}{{\left (a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + a\right )}^{\frac {11}{2}}}\right )}}{1155 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 1.00, size = 77, normalized size = 0.38 \[ \frac {2 \left (1+\sin \left (d x +c \right )\right ) \left (\sin \left (d x +c \right )-1\right )^{3} \left (105 \left (\sin ^{3}\left (d x +c \right )\right )+70 \left (\sin ^{2}\left (d x +c \right )\right )+40 \sin \left (d x +c \right )+16\right )}{1155 a \cos \left (d x +c \right ) \sqrt {a +a \sin \left (d x +c \right )}\, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cos \left (d x + c\right )^{4} \sin \left (d x + c\right )^{3}}{{\left (a \sin \left (d x + c\right ) + a\right )}^{\frac {3}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\cos \left (c+d\,x\right )}^4\,{\sin \left (c+d\,x\right )}^3}{{\left (a+a\,\sin \left (c+d\,x\right )\right )}^{3/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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