3.673 \(\int \cot ^7(c+d x) \csc ^5(c+d x) (a+a \sin (c+d x)) \, dx\)

Optimal. Leaf size=97 \[ -\frac {a \cot ^{10}(c+d x)}{10 d}-\frac {a \cot ^8(c+d x)}{8 d}-\frac {a \csc ^{11}(c+d x)}{11 d}+\frac {a \csc ^9(c+d x)}{3 d}-\frac {3 a \csc ^7(c+d x)}{7 d}+\frac {a \csc ^5(c+d x)}{5 d} \]

[Out]

-1/8*a*cot(d*x+c)^8/d-1/10*a*cot(d*x+c)^10/d+1/5*a*csc(d*x+c)^5/d-3/7*a*csc(d*x+c)^7/d+1/3*a*csc(d*x+c)^9/d-1/
11*a*csc(d*x+c)^11/d

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Rubi [A]  time = 0.12, antiderivative size = 97, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, integrand size = 27, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.185, Rules used = {2834, 2606, 270, 2607, 14} \[ -\frac {a \cot ^{10}(c+d x)}{10 d}-\frac {a \cot ^8(c+d x)}{8 d}-\frac {a \csc ^{11}(c+d x)}{11 d}+\frac {a \csc ^9(c+d x)}{3 d}-\frac {3 a \csc ^7(c+d x)}{7 d}+\frac {a \csc ^5(c+d x)}{5 d} \]

Antiderivative was successfully verified.

[In]

Int[Cot[c + d*x]^7*Csc[c + d*x]^5*(a + a*Sin[c + d*x]),x]

[Out]

-(a*Cot[c + d*x]^8)/(8*d) - (a*Cot[c + d*x]^10)/(10*d) + (a*Csc[c + d*x]^5)/(5*d) - (3*a*Csc[c + d*x]^7)/(7*d)
+ (a*Csc[c + d*x]^9)/(3*d) - (a*Csc[c + d*x]^11)/(11*d)

Rule 14

Int[(u_)*((c_.)*(x_))^(m_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*u, x], x] /; FreeQ[{c, m}, x] && SumQ[u]
&&  !LinearQ[u, x] &&  !MatchQ[u, (a_) + (b_.)*(v_) /; FreeQ[{a, b}, x] && InverseFunctionQ[v]]

Rule 270

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*(a + b*x^n)^p,
x], x] /; FreeQ[{a, b, c, m, n}, x] && IGtQ[p, 0]

Rule 2606

Int[((a_.)*sec[(e_.) + (f_.)*(x_)])^(m_.)*((b_.)*tan[(e_.) + (f_.)*(x_)])^(n_.), x_Symbol] :> Dist[a/f, Subst[
Int[(a*x)^(m - 1)*(-1 + x^2)^((n - 1)/2), x], x, Sec[e + f*x]], x] /; FreeQ[{a, e, f, m}, x] && IntegerQ[(n -
1)/2] &&  !(IntegerQ[m/2] && LtQ[0, m, n + 1])

Rule 2607

Int[sec[(e_.) + (f_.)*(x_)]^(m_)*((b_.)*tan[(e_.) + (f_.)*(x_)])^(n_.), x_Symbol] :> Dist[1/f, Subst[Int[(b*x)
^n*(1 + x^2)^(m/2 - 1), x], x, Tan[e + f*x]], x] /; FreeQ[{b, e, f, n}, x] && IntegerQ[m/2] &&  !(IntegerQ[(n
- 1)/2] && LtQ[0, n, m - 1])

Rule 2834

Int[cos[(e_.) + (f_.)*(x_)]^(p_)*((d_.)*sin[(e_.) + (f_.)*(x_)])^(n_.)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]),
x_Symbol] :> Dist[a, Int[Cos[e + f*x]^p*(d*Sin[e + f*x])^n, x], x] + Dist[b/d, Int[Cos[e + f*x]^p*(d*Sin[e +
f*x])^(n + 1), x], x] /; FreeQ[{a, b, d, e, f, n, p}, x] && IntegerQ[(p - 1)/2] && IntegerQ[n] && ((LtQ[p, 0]
&& NeQ[a^2 - b^2, 0]) || LtQ[0, n, p - 1] || LtQ[p + 1, -n, 2*p + 1])

Rubi steps

\begin {align*} \int \cot ^7(c+d x) \csc ^5(c+d x) (a+a \sin (c+d x)) \, dx &=a \int \cot ^7(c+d x) \csc ^4(c+d x) \, dx+a \int \cot ^7(c+d x) \csc ^5(c+d x) \, dx\\ &=-\frac {a \operatorname {Subst}\left (\int x^4 \left (-1+x^2\right )^3 \, dx,x,\csc (c+d x)\right )}{d}-\frac {a \operatorname {Subst}\left (\int x^7 \left (1+x^2\right ) \, dx,x,-\cot (c+d x)\right )}{d}\\ &=-\frac {a \operatorname {Subst}\left (\int \left (x^7+x^9\right ) \, dx,x,-\cot (c+d x)\right )}{d}-\frac {a \operatorname {Subst}\left (\int \left (-x^4+3 x^6-3 x^8+x^{10}\right ) \, dx,x,\csc (c+d x)\right )}{d}\\ &=-\frac {a \cot ^8(c+d x)}{8 d}-\frac {a \cot ^{10}(c+d x)}{10 d}+\frac {a \csc ^5(c+d x)}{5 d}-\frac {3 a \csc ^7(c+d x)}{7 d}+\frac {a \csc ^9(c+d x)}{3 d}-\frac {a \csc ^{11}(c+d x)}{11 d}\\ \end {align*}

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Mathematica [A]  time = 0.14, size = 86, normalized size = 0.89 \[ -\frac {a \csc ^4(c+d x) \left (840 \csc ^7(c+d x)+924 \csc ^6(c+d x)-3080 \csc ^5(c+d x)-3465 \csc ^4(c+d x)+3960 \csc ^3(c+d x)+4620 \csc ^2(c+d x)-1848 \csc (c+d x)-2310\right )}{9240 d} \]

Antiderivative was successfully verified.

[In]

Integrate[Cot[c + d*x]^7*Csc[c + d*x]^5*(a + a*Sin[c + d*x]),x]

[Out]

-1/9240*(a*Csc[c + d*x]^4*(-2310 - 1848*Csc[c + d*x] + 4620*Csc[c + d*x]^2 + 3960*Csc[c + d*x]^3 - 3465*Csc[c
+ d*x]^4 - 3080*Csc[c + d*x]^5 + 924*Csc[c + d*x]^6 + 840*Csc[c + d*x]^7))/d

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fricas [A]  time = 0.93, size = 152, normalized size = 1.57 \[ \frac {1848 \, a \cos \left (d x + c\right )^{6} - 1584 \, a \cos \left (d x + c\right )^{4} + 704 \, a \cos \left (d x + c\right )^{2} + 231 \, {\left (10 \, a \cos \left (d x + c\right )^{6} - 10 \, a \cos \left (d x + c\right )^{4} + 5 \, a \cos \left (d x + c\right )^{2} - a\right )} \sin \left (d x + c\right ) - 128 \, a}{9240 \, {\left (d \cos \left (d x + c\right )^{10} - 5 \, d \cos \left (d x + c\right )^{8} + 10 \, d \cos \left (d x + c\right )^{6} - 10 \, d \cos \left (d x + c\right )^{4} + 5 \, d \cos \left (d x + c\right )^{2} - d\right )} \sin \left (d x + c\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^7*csc(d*x+c)^12*(a+a*sin(d*x+c)),x, algorithm="fricas")

[Out]

1/9240*(1848*a*cos(d*x + c)^6 - 1584*a*cos(d*x + c)^4 + 704*a*cos(d*x + c)^2 + 231*(10*a*cos(d*x + c)^6 - 10*a
*cos(d*x + c)^4 + 5*a*cos(d*x + c)^2 - a)*sin(d*x + c) - 128*a)/((d*cos(d*x + c)^10 - 5*d*cos(d*x + c)^8 + 10*
d*cos(d*x + c)^6 - 10*d*cos(d*x + c)^4 + 5*d*cos(d*x + c)^2 - d)*sin(d*x + c))

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giac [A]  time = 0.28, size = 92, normalized size = 0.95 \[ \frac {2310 \, a \sin \left (d x + c\right )^{7} + 1848 \, a \sin \left (d x + c\right )^{6} - 4620 \, a \sin \left (d x + c\right )^{5} - 3960 \, a \sin \left (d x + c\right )^{4} + 3465 \, a \sin \left (d x + c\right )^{3} + 3080 \, a \sin \left (d x + c\right )^{2} - 924 \, a \sin \left (d x + c\right ) - 840 \, a}{9240 \, d \sin \left (d x + c\right )^{11}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^7*csc(d*x+c)^12*(a+a*sin(d*x+c)),x, algorithm="giac")

[Out]

1/9240*(2310*a*sin(d*x + c)^7 + 1848*a*sin(d*x + c)^6 - 4620*a*sin(d*x + c)^5 - 3960*a*sin(d*x + c)^4 + 3465*a
*sin(d*x + c)^3 + 3080*a*sin(d*x + c)^2 - 924*a*sin(d*x + c) - 840*a)/(d*sin(d*x + c)^11)

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maple [B]  time = 0.39, size = 194, normalized size = 2.00 \[ \frac {a \left (-\frac {\cos ^{8}\left (d x +c \right )}{10 \sin \left (d x +c \right )^{10}}-\frac {\cos ^{8}\left (d x +c \right )}{40 \sin \left (d x +c \right )^{8}}\right )+a \left (-\frac {\cos ^{8}\left (d x +c \right )}{11 \sin \left (d x +c \right )^{11}}-\frac {\cos ^{8}\left (d x +c \right )}{33 \sin \left (d x +c \right )^{9}}-\frac {\cos ^{8}\left (d x +c \right )}{231 \sin \left (d x +c \right )^{7}}+\frac {\cos ^{8}\left (d x +c \right )}{1155 \sin \left (d x +c \right )^{5}}-\frac {\cos ^{8}\left (d x +c \right )}{1155 \sin \left (d x +c \right )^{3}}+\frac {\cos ^{8}\left (d x +c \right )}{231 \sin \left (d x +c \right )}+\frac {\left (\frac {16}{5}+\cos ^{6}\left (d x +c \right )+\frac {6 \left (\cos ^{4}\left (d x +c \right )\right )}{5}+\frac {8 \left (\cos ^{2}\left (d x +c \right )\right )}{5}\right ) \sin \left (d x +c \right )}{231}\right )}{d} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(d*x+c)^7*csc(d*x+c)^12*(a+a*sin(d*x+c)),x)

[Out]

1/d*(a*(-1/10/sin(d*x+c)^10*cos(d*x+c)^8-1/40/sin(d*x+c)^8*cos(d*x+c)^8)+a*(-1/11/sin(d*x+c)^11*cos(d*x+c)^8-1
/33/sin(d*x+c)^9*cos(d*x+c)^8-1/231/sin(d*x+c)^7*cos(d*x+c)^8+1/1155/sin(d*x+c)^5*cos(d*x+c)^8-1/1155/sin(d*x+
c)^3*cos(d*x+c)^8+1/231/sin(d*x+c)*cos(d*x+c)^8+1/231*(16/5+cos(d*x+c)^6+6/5*cos(d*x+c)^4+8/5*cos(d*x+c)^2)*si
n(d*x+c)))

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maxima [A]  time = 0.33, size = 92, normalized size = 0.95 \[ \frac {2310 \, a \sin \left (d x + c\right )^{7} + 1848 \, a \sin \left (d x + c\right )^{6} - 4620 \, a \sin \left (d x + c\right )^{5} - 3960 \, a \sin \left (d x + c\right )^{4} + 3465 \, a \sin \left (d x + c\right )^{3} + 3080 \, a \sin \left (d x + c\right )^{2} - 924 \, a \sin \left (d x + c\right ) - 840 \, a}{9240 \, d \sin \left (d x + c\right )^{11}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^7*csc(d*x+c)^12*(a+a*sin(d*x+c)),x, algorithm="maxima")

[Out]

1/9240*(2310*a*sin(d*x + c)^7 + 1848*a*sin(d*x + c)^6 - 4620*a*sin(d*x + c)^5 - 3960*a*sin(d*x + c)^4 + 3465*a
*sin(d*x + c)^3 + 3080*a*sin(d*x + c)^2 - 924*a*sin(d*x + c) - 840*a)/(d*sin(d*x + c)^11)

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mupad [B]  time = 9.28, size = 92, normalized size = 0.95 \[ -\frac {-\frac {a\,{\sin \left (c+d\,x\right )}^7}{4}-\frac {a\,{\sin \left (c+d\,x\right )}^6}{5}+\frac {a\,{\sin \left (c+d\,x\right )}^5}{2}+\frac {3\,a\,{\sin \left (c+d\,x\right )}^4}{7}-\frac {3\,a\,{\sin \left (c+d\,x\right )}^3}{8}-\frac {a\,{\sin \left (c+d\,x\right )}^2}{3}+\frac {a\,\sin \left (c+d\,x\right )}{10}+\frac {a}{11}}{d\,{\sin \left (c+d\,x\right )}^{11}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((cos(c + d*x)^7*(a + a*sin(c + d*x)))/sin(c + d*x)^12,x)

[Out]

-(a/11 + (a*sin(c + d*x))/10 - (a*sin(c + d*x)^2)/3 - (3*a*sin(c + d*x)^3)/8 + (3*a*sin(c + d*x)^4)/7 + (a*sin
(c + d*x)^5)/2 - (a*sin(c + d*x)^6)/5 - (a*sin(c + d*x)^7)/4)/(d*sin(c + d*x)^11)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)**7*csc(d*x+c)**12*(a+a*sin(d*x+c)),x)

[Out]

Timed out

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