Optimal. Leaf size=264 \[ -\frac {a^4}{160 d (a \sin (c+d x)+a)^5}+\frac {a^3}{256 d (a-a \sin (c+d x))^4}+\frac {19 a^3}{256 d (a \sin (c+d x)+a)^4}-\frac {3 a^2}{64 d (a-a \sin (c+d x))^3}-\frac {53 a^2}{128 d (a \sin (c+d x)+a)^3}-\frac {\sin ^2(c+d x)}{2 a d}+\frac {141 a}{512 d (a-a \sin (c+d x))^2}+\frac {765 a}{512 d (a \sin (c+d x)+a)^2}-\frac {39}{32 d (a-a \sin (c+d x))}-\frac {1155}{256 d (a \sin (c+d x)+a)}+\frac {\sin (c+d x)}{a d}-\frac {843 \log (1-\sin (c+d x))}{512 a d}-\frac {2229 \log (\sin (c+d x)+1)}{512 a d} \]
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Rubi [A] time = 0.28, antiderivative size = 264, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {2836, 12, 88} \[ -\frac {a^4}{160 d (a \sin (c+d x)+a)^5}+\frac {a^3}{256 d (a-a \sin (c+d x))^4}+\frac {19 a^3}{256 d (a \sin (c+d x)+a)^4}-\frac {3 a^2}{64 d (a-a \sin (c+d x))^3}-\frac {53 a^2}{128 d (a \sin (c+d x)+a)^3}-\frac {\sin ^2(c+d x)}{2 a d}+\frac {141 a}{512 d (a-a \sin (c+d x))^2}+\frac {765 a}{512 d (a \sin (c+d x)+a)^2}-\frac {39}{32 d (a-a \sin (c+d x))}-\frac {1155}{256 d (a \sin (c+d x)+a)}+\frac {\sin (c+d x)}{a d}-\frac {843 \log (1-\sin (c+d x))}{512 a d}-\frac {2229 \log (\sin (c+d x)+1)}{512 a d} \]
Antiderivative was successfully verified.
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Rule 12
Rule 88
Rule 2836
Rubi steps
\begin {align*} \int \frac {\sin ^3(c+d x) \tan ^9(c+d x)}{a+a \sin (c+d x)} \, dx &=\frac {a^9 \operatorname {Subst}\left (\int \frac {x^{12}}{a^{12} (a-x)^5 (a+x)^6} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac {\operatorname {Subst}\left (\int \frac {x^{12}}{(a-x)^5 (a+x)^6} \, dx,x,a \sin (c+d x)\right )}{a^3 d}\\ &=\frac {\operatorname {Subst}\left (\int \left (a+\frac {a^6}{64 (a-x)^5}-\frac {9 a^5}{64 (a-x)^4}+\frac {141 a^4}{256 (a-x)^3}-\frac {39 a^3}{32 (a-x)^2}+\frac {843 a^2}{512 (a-x)}-x+\frac {a^7}{32 (a+x)^6}-\frac {19 a^6}{64 (a+x)^5}+\frac {159 a^5}{128 (a+x)^4}-\frac {765 a^4}{256 (a+x)^3}+\frac {1155 a^3}{256 (a+x)^2}-\frac {2229 a^2}{512 (a+x)}\right ) \, dx,x,a \sin (c+d x)\right )}{a^3 d}\\ &=-\frac {843 \log (1-\sin (c+d x))}{512 a d}-\frac {2229 \log (1+\sin (c+d x))}{512 a d}+\frac {\sin (c+d x)}{a d}-\frac {\sin ^2(c+d x)}{2 a d}+\frac {a^3}{256 d (a-a \sin (c+d x))^4}-\frac {3 a^2}{64 d (a-a \sin (c+d x))^3}+\frac {141 a}{512 d (a-a \sin (c+d x))^2}-\frac {39}{32 d (a-a \sin (c+d x))}-\frac {a^4}{160 d (a+a \sin (c+d x))^5}+\frac {19 a^3}{256 d (a+a \sin (c+d x))^4}-\frac {53 a^2}{128 d (a+a \sin (c+d x))^3}+\frac {765 a}{512 d (a+a \sin (c+d x))^2}-\frac {1155}{256 d (a+a \sin (c+d x))}\\ \end {align*}
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Mathematica [A] time = 6.17, size = 169, normalized size = 0.64 \[ -\frac {1280 \sin ^2(c+d x)-2560 \sin (c+d x)+\frac {3120}{1-\sin (c+d x)}+\frac {11550}{\sin (c+d x)+1}-\frac {705}{(1-\sin (c+d x))^2}-\frac {3825}{(\sin (c+d x)+1)^2}+\frac {120}{(1-\sin (c+d x))^3}+\frac {1060}{(\sin (c+d x)+1)^3}-\frac {10}{(1-\sin (c+d x))^4}-\frac {190}{(\sin (c+d x)+1)^4}+\frac {16}{(\sin (c+d x)+1)^5}+4215 \log (1-\sin (c+d x))+11145 \log (\sin (c+d x)+1)}{2560 a d} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.56, size = 217, normalized size = 0.82 \[ -\frac {1280 \, \cos \left (d x + c\right )^{10} + 6510 \, \cos \left (d x + c\right )^{8} + 3590 \, \cos \left (d x + c\right )^{6} - 1124 \, \cos \left (d x + c\right )^{4} + 272 \, \cos \left (d x + c\right )^{2} + 11145 \, {\left (\cos \left (d x + c\right )^{8} \sin \left (d x + c\right ) + \cos \left (d x + c\right )^{8}\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) + 4215 \, {\left (\cos \left (d x + c\right )^{8} \sin \left (d x + c\right ) + \cos \left (d x + c\right )^{8}\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) - 2 \, {\left (640 \, \cos \left (d x + c\right )^{10} + 960 \, \cos \left (d x + c\right )^{8} - 5385 \, \cos \left (d x + c\right )^{6} + 2810 \, \cos \left (d x + c\right )^{4} - 952 \, \cos \left (d x + c\right )^{2} + 144\right )} \sin \left (d x + c\right ) - 32}{2560 \, {\left (a d \cos \left (d x + c\right )^{8} \sin \left (d x + c\right ) + a d \cos \left (d x + c\right )^{8}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.41, size = 181, normalized size = 0.69 \[ -\frac {\frac {44580 \, \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right )}{a} + \frac {16860 \, \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right )}{a} + \frac {5120 \, {\left (a \sin \left (d x + c\right )^{2} - 2 \, a \sin \left (d x + c\right )\right )}}{a^{2}} - \frac {5 \, {\left (7025 \, \sin \left (d x + c\right )^{4} - 25604 \, \sin \left (d x + c\right )^{3} + 35226 \, \sin \left (d x + c\right )^{2} - 21644 \, \sin \left (d x + c\right ) + 5005\right )}}{a {\left (\sin \left (d x + c\right ) - 1\right )}^{4}} - \frac {101791 \, \sin \left (d x + c\right )^{5} + 462755 \, \sin \left (d x + c\right )^{4} + 848410 \, \sin \left (d x + c\right )^{3} + 782370 \, \sin \left (d x + c\right )^{2} + 362335 \, \sin \left (d x + c\right ) + 67347}{a {\left (\sin \left (d x + c\right ) + 1\right )}^{5}}}{10240 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.50, size = 227, normalized size = 0.86 \[ \frac {1}{256 a d \left (\sin \left (d x +c \right )-1\right )^{4}}+\frac {3}{64 a d \left (\sin \left (d x +c \right )-1\right )^{3}}+\frac {141}{512 a d \left (\sin \left (d x +c \right )-1\right )^{2}}+\frac {39}{32 a d \left (\sin \left (d x +c \right )-1\right )}-\frac {843 \ln \left (\sin \left (d x +c \right )-1\right )}{512 a d}-\frac {\sin ^{2}\left (d x +c \right )}{2 a d}+\frac {\sin \left (d x +c \right )}{a d}-\frac {1}{160 a d \left (1+\sin \left (d x +c \right )\right )^{5}}+\frac {19}{256 a d \left (1+\sin \left (d x +c \right )\right )^{4}}-\frac {53}{128 a d \left (1+\sin \left (d x +c \right )\right )^{3}}+\frac {765}{512 a d \left (1+\sin \left (d x +c \right )\right )^{2}}-\frac {1155}{256 a d \left (1+\sin \left (d x +c \right )\right )}-\frac {2229 \ln \left (1+\sin \left (d x +c \right )\right )}{512 a d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.34, size = 236, normalized size = 0.89 \[ -\frac {\frac {2 \, {\left (4215 \, \sin \left (d x + c\right )^{8} - 5385 \, \sin \left (d x + c\right )^{7} - 18655 \, \sin \left (d x + c\right )^{6} + 13345 \, \sin \left (d x + c\right )^{5} + 30113 \, \sin \left (d x + c\right )^{4} - 11487 \, \sin \left (d x + c\right )^{3} - 21257 \, \sin \left (d x + c\right )^{2} + 3383 \, \sin \left (d x + c\right ) + 5568\right )}}{a \sin \left (d x + c\right )^{9} + a \sin \left (d x + c\right )^{8} - 4 \, a \sin \left (d x + c\right )^{7} - 4 \, a \sin \left (d x + c\right )^{6} + 6 \, a \sin \left (d x + c\right )^{5} + 6 \, a \sin \left (d x + c\right )^{4} - 4 \, a \sin \left (d x + c\right )^{3} - 4 \, a \sin \left (d x + c\right )^{2} + a \sin \left (d x + c\right ) + a} + \frac {1280 \, {\left (\sin \left (d x + c\right )^{2} - 2 \, \sin \left (d x + c\right )\right )}}{a} + \frac {11145 \, \log \left (\sin \left (d x + c\right ) + 1\right )}{a} + \frac {4215 \, \log \left (\sin \left (d x + c\right ) - 1\right )}{a}}{2560 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 11.20, size = 648, normalized size = 2.45 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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