Optimal. Leaf size=78 \[ -\frac {B (a \sin (c+d x)+a)^6}{6 a^4 d}-\frac {(A-3 B) (a \sin (c+d x)+a)^5}{5 a^3 d}+\frac {(A-B) (a \sin (c+d x)+a)^4}{2 a^2 d} \]
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Rubi [A] time = 0.11, antiderivative size = 78, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 31, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.065, Rules used = {2836, 77} \[ -\frac {(A-3 B) (a \sin (c+d x)+a)^5}{5 a^3 d}+\frac {(A-B) (a \sin (c+d x)+a)^4}{2 a^2 d}-\frac {B (a \sin (c+d x)+a)^6}{6 a^4 d} \]
Antiderivative was successfully verified.
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Rule 77
Rule 2836
Rubi steps
\begin {align*} \int \cos ^3(c+d x) (a+a \sin (c+d x))^2 (A+B \sin (c+d x)) \, dx &=\frac {\operatorname {Subst}\left (\int (a-x) (a+x)^3 \left (A+\frac {B x}{a}\right ) \, dx,x,a \sin (c+d x)\right )}{a^3 d}\\ &=\frac {\operatorname {Subst}\left (\int \left (2 a (A-B) (a+x)^3+(-A+3 B) (a+x)^4-\frac {B (a+x)^5}{a}\right ) \, dx,x,a \sin (c+d x)\right )}{a^3 d}\\ &=\frac {(A-B) (a+a \sin (c+d x))^4}{2 a^2 d}-\frac {(A-3 B) (a+a \sin (c+d x))^5}{5 a^3 d}-\frac {B (a+a \sin (c+d x))^6}{6 a^4 d}\\ \end {align*}
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Mathematica [A] time = 0.43, size = 66, normalized size = 0.85 \[ \frac {a^2 \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )^8 (-4 (3 A-4 B) \sin (c+d x)+18 A+5 B \cos (2 (c+d x))-9 B)}{60 d} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.76, size = 91, normalized size = 1.17 \[ \frac {5 \, B a^{2} \cos \left (d x + c\right )^{6} - 15 \, {\left (A + B\right )} a^{2} \cos \left (d x + c\right )^{4} - 2 \, {\left (3 \, {\left (A + 2 \, B\right )} a^{2} \cos \left (d x + c\right )^{4} - 2 \, {\left (3 \, A + B\right )} a^{2} \cos \left (d x + c\right )^{2} - 4 \, {\left (3 \, A + B\right )} a^{2}\right )} \sin \left (d x + c\right )}{30 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.25, size = 116, normalized size = 1.49 \[ -\frac {5 \, B a^{2} \sin \left (d x + c\right )^{6} + 6 \, A a^{2} \sin \left (d x + c\right )^{5} + 12 \, B a^{2} \sin \left (d x + c\right )^{5} + 15 \, A a^{2} \sin \left (d x + c\right )^{4} - 20 \, B a^{2} \sin \left (d x + c\right )^{3} - 30 \, A a^{2} \sin \left (d x + c\right )^{2} - 15 \, B a^{2} \sin \left (d x + c\right )^{2} - 30 \, A a^{2} \sin \left (d x + c\right )}{30 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.48, size = 171, normalized size = 2.19 \[ \frac {a^{2} A \left (-\frac {\sin \left (d x +c \right ) \left (\cos ^{4}\left (d x +c \right )\right )}{5}+\frac {\left (2+\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right )}{15}\right )+B \,a^{2} \left (-\frac {\left (\sin ^{2}\left (d x +c \right )\right ) \left (\cos ^{4}\left (d x +c \right )\right )}{6}-\frac {\left (\cos ^{4}\left (d x +c \right )\right )}{12}\right )-\frac {a^{2} A \left (\cos ^{4}\left (d x +c \right )\right )}{2}+2 B \,a^{2} \left (-\frac {\sin \left (d x +c \right ) \left (\cos ^{4}\left (d x +c \right )\right )}{5}+\frac {\left (2+\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right )}{15}\right )+\frac {a^{2} A \left (2+\cos ^{2}\left (d x +c \right )\right ) \sin \left (d x +c \right )}{3}-\frac {B \,a^{2} \left (\cos ^{4}\left (d x +c \right )\right )}{4}}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.31, size = 96, normalized size = 1.23 \[ -\frac {5 \, B a^{2} \sin \left (d x + c\right )^{6} + 6 \, {\left (A + 2 \, B\right )} a^{2} \sin \left (d x + c\right )^{5} + 15 \, A a^{2} \sin \left (d x + c\right )^{4} - 20 \, B a^{2} \sin \left (d x + c\right )^{3} - 15 \, {\left (2 \, A + B\right )} a^{2} \sin \left (d x + c\right )^{2} - 30 \, A a^{2} \sin \left (d x + c\right )}{30 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 9.08, size = 96, normalized size = 1.23 \[ -\frac {\frac {A\,a^2\,{\sin \left (c+d\,x\right )}^4}{2}-\frac {a^2\,{\sin \left (c+d\,x\right )}^2\,\left (2\,A+B\right )}{2}+\frac {a^2\,{\sin \left (c+d\,x\right )}^5\,\left (A+2\,B\right )}{5}-\frac {2\,B\,a^2\,{\sin \left (c+d\,x\right )}^3}{3}+\frac {B\,a^2\,{\sin \left (c+d\,x\right )}^6}{6}-A\,a^2\,\sin \left (c+d\,x\right )}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 3.51, size = 228, normalized size = 2.92 \[ \begin {cases} \frac {2 A a^{2} \sin ^{5}{\left (c + d x \right )}}{15 d} + \frac {A a^{2} \sin ^{3}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{3 d} + \frac {2 A a^{2} \sin ^{3}{\left (c + d x \right )}}{3 d} + \frac {A a^{2} \sin {\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{d} - \frac {A a^{2} \cos ^{4}{\left (c + d x \right )}}{2 d} + \frac {B a^{2} \sin ^{6}{\left (c + d x \right )}}{12 d} + \frac {4 B a^{2} \sin ^{5}{\left (c + d x \right )}}{15 d} + \frac {B a^{2} \sin ^{4}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{4 d} + \frac {2 B a^{2} \sin ^{3}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{3 d} - \frac {B a^{2} \cos ^{4}{\left (c + d x \right )}}{4 d} & \text {for}\: d \neq 0 \\x \left (A + B \sin {\relax (c )}\right ) \left (a \sin {\relax (c )} + a\right )^{2} \cos ^{3}{\relax (c )} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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