Optimal. Leaf size=863 \[ \frac {2 \sqrt {2} \sqrt {\cos (c+d x)} \Pi \left (-\frac {\sqrt {a-b}}{\sqrt {a+b}};\left .\sin ^{-1}\left (\frac {\sqrt {\sin (c+d x)}}{\sqrt {\cos (c+d x)+1}}\right )\right |-1\right ) \sqrt {e \tan (c+d x)} b^3}{a (a-b)^{3/2} (a+b)^{3/2} d e^2 \sqrt {\sin (c+d x)}}-\frac {2 \sqrt {2} \sqrt {\cos (c+d x)} \Pi \left (\frac {\sqrt {a-b}}{\sqrt {a+b}};\left .\sin ^{-1}\left (\frac {\sqrt {\sin (c+d x)}}{\sqrt {\cos (c+d x)+1}}\right )\right |-1\right ) \sqrt {e \tan (c+d x)} b^3}{a (a-b)^{3/2} (a+b)^{3/2} d e^2 \sqrt {\sin (c+d x)}}-\frac {\tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right ) b^2}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {\tan ^{-1}\left (\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}+1\right ) b^2}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {\log \left (\sqrt {e} \tan (c+d x)+\sqrt {e}-\sqrt {2} \sqrt {e \tan (c+d x)}\right ) b^2}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {\log \left (\sqrt {e} \tan (c+d x)+\sqrt {e}+\sqrt {2} \sqrt {e \tan (c+d x)}\right ) b^2}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {2 \cos (c+d x) (e \tan (c+d x))^{3/2} b}{\left (a^2-b^2\right ) d e^3}+\frac {2 \cos (c+d x) E\left (\left .c+d x-\frac {\pi }{4}\right |2\right ) \sqrt {e \tan (c+d x)} b}{\left (a^2-b^2\right ) d e^2 \sqrt {\sin (2 c+2 d x)}}+\frac {a \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \tan ^{-1}\left (\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}+1\right )}{\sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \log \left (\sqrt {e} \tan (c+d x)+\sqrt {e}-\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}+\frac {a \log \left (\sqrt {e} \tan (c+d x)+\sqrt {e}+\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}} \]
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Rubi [A] time = 1.25, antiderivative size = 863, normalized size of antiderivative = 1.00, number of steps used = 39, number of rules used = 23, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.920, Rules used = {3893, 3882, 3884, 3476, 329, 297, 1162, 617, 204, 1165, 628, 2613, 2615, 2572, 2639, 3890, 2733, 2730, 2906, 2905, 490, 1213, 537} \[ \frac {2 \sqrt {2} \sqrt {\cos (c+d x)} \Pi \left (-\frac {\sqrt {a-b}}{\sqrt {a+b}};\left .\sin ^{-1}\left (\frac {\sqrt {\sin (c+d x)}}{\sqrt {\cos (c+d x)+1}}\right )\right |-1\right ) \sqrt {e \tan (c+d x)} b^3}{a (a-b)^{3/2} (a+b)^{3/2} d e^2 \sqrt {\sin (c+d x)}}-\frac {2 \sqrt {2} \sqrt {\cos (c+d x)} \Pi \left (\frac {\sqrt {a-b}}{\sqrt {a+b}};\left .\sin ^{-1}\left (\frac {\sqrt {\sin (c+d x)}}{\sqrt {\cos (c+d x)+1}}\right )\right |-1\right ) \sqrt {e \tan (c+d x)} b^3}{a (a-b)^{3/2} (a+b)^{3/2} d e^2 \sqrt {\sin (c+d x)}}-\frac {\tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right ) b^2}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {\tan ^{-1}\left (\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}+1\right ) b^2}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {\log \left (\sqrt {e} \tan (c+d x)+\sqrt {e}-\sqrt {2} \sqrt {e \tan (c+d x)}\right ) b^2}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {\log \left (\sqrt {e} \tan (c+d x)+\sqrt {e}+\sqrt {2} \sqrt {e \tan (c+d x)}\right ) b^2}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {2 \cos (c+d x) (e \tan (c+d x))^{3/2} b}{\left (a^2-b^2\right ) d e^3}+\frac {2 \cos (c+d x) E\left (\left .c+d x-\frac {\pi }{4}\right |2\right ) \sqrt {e \tan (c+d x)} b}{\left (a^2-b^2\right ) d e^2 \sqrt {\sin (2 c+2 d x)}}+\frac {a \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \tan ^{-1}\left (\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}+1\right )}{\sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \log \left (\sqrt {e} \tan (c+d x)+\sqrt {e}-\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}+\frac {a \log \left (\sqrt {e} \tan (c+d x)+\sqrt {e}+\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}} \]
Antiderivative was successfully verified.
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Rule 204
Rule 297
Rule 329
Rule 490
Rule 537
Rule 617
Rule 628
Rule 1162
Rule 1165
Rule 1213
Rule 2572
Rule 2613
Rule 2615
Rule 2639
Rule 2730
Rule 2733
Rule 2905
Rule 2906
Rule 3476
Rule 3882
Rule 3884
Rule 3890
Rule 3893
Rubi steps
\begin {align*} \int \frac {1}{(a+b \sec (c+d x)) (e \tan (c+d x))^{3/2}} \, dx &=\frac {\int \frac {a-b \sec (c+d x)}{(e \tan (c+d x))^{3/2}} \, dx}{a^2-b^2}+\frac {b^2 \int \frac {\sqrt {e \tan (c+d x)}}{a+b \sec (c+d x)} \, dx}{\left (a^2-b^2\right ) e^2}\\ &=-\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}+\frac {2 \int \left (-\frac {a}{2}-\frac {1}{2} b \sec (c+d x)\right ) \sqrt {e \tan (c+d x)} \, dx}{\left (a^2-b^2\right ) e^2}+\frac {b^2 \int \sqrt {e \tan (c+d x)} \, dx}{a \left (a^2-b^2\right ) e^2}-\frac {b^3 \int \frac {\sqrt {e \tan (c+d x)}}{b+a \cos (c+d x)} \, dx}{a \left (a^2-b^2\right ) e^2}\\ &=-\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}-\frac {a \int \sqrt {e \tan (c+d x)} \, dx}{\left (a^2-b^2\right ) e^2}-\frac {b \int \sec (c+d x) \sqrt {e \tan (c+d x)} \, dx}{\left (a^2-b^2\right ) e^2}+\frac {b^2 \operatorname {Subst}\left (\int \frac {\sqrt {x}}{e^2+x^2} \, dx,x,e \tan (c+d x)\right )}{a \left (a^2-b^2\right ) d e}-\frac {\left (b^3 \sqrt {e \cot (c+d x)} \sqrt {e \tan (c+d x)}\right ) \int \frac {1}{(b+a \cos (c+d x)) \sqrt {e \cot (c+d x)}} \, dx}{a \left (a^2-b^2\right ) e^2}\\ &=-\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}-\frac {2 b \cos (c+d x) (e \tan (c+d x))^{3/2}}{\left (a^2-b^2\right ) d e^3}+\frac {(2 b) \int \cos (c+d x) \sqrt {e \tan (c+d x)} \, dx}{\left (a^2-b^2\right ) e^2}-\frac {a \operatorname {Subst}\left (\int \frac {\sqrt {x}}{e^2+x^2} \, dx,x,e \tan (c+d x)\right )}{\left (a^2-b^2\right ) d e}+\frac {\left (2 b^2\right ) \operatorname {Subst}\left (\int \frac {x^2}{e^2+x^4} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{a \left (a^2-b^2\right ) d e}-\frac {\left (b^3 \sqrt {-\cos (c+d x)} \sqrt {e \tan (c+d x)}\right ) \int \frac {\sqrt {\sin (c+d x)}}{\sqrt {-\cos (c+d x)} (b+a \cos (c+d x))} \, dx}{a \left (a^2-b^2\right ) e^2 \sqrt {\sin (c+d x)}}\\ &=-\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}-\frac {2 b \cos (c+d x) (e \tan (c+d x))^{3/2}}{\left (a^2-b^2\right ) d e^3}-\frac {(2 a) \operatorname {Subst}\left (\int \frac {x^2}{e^2+x^4} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{\left (a^2-b^2\right ) d e}-\frac {b^2 \operatorname {Subst}\left (\int \frac {e-x^2}{e^2+x^4} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{a \left (a^2-b^2\right ) d e}+\frac {b^2 \operatorname {Subst}\left (\int \frac {e+x^2}{e^2+x^4} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{a \left (a^2-b^2\right ) d e}+\frac {\left (2 b \sqrt {\cos (c+d x)} \sqrt {e \tan (c+d x)}\right ) \int \sqrt {\cos (c+d x)} \sqrt {\sin (c+d x)} \, dx}{\left (a^2-b^2\right ) e^2 \sqrt {\sin (c+d x)}}-\frac {\left (b^3 \sqrt {\cos (c+d x)} \sqrt {e \tan (c+d x)}\right ) \int \frac {\sqrt {\sin (c+d x)}}{\sqrt {\cos (c+d x)} (b+a \cos (c+d x))} \, dx}{a \left (a^2-b^2\right ) e^2 \sqrt {\sin (c+d x)}}\\ &=-\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}-\frac {2 b \cos (c+d x) (e \tan (c+d x))^{3/2}}{\left (a^2-b^2\right ) d e^3}+\frac {b^2 \operatorname {Subst}\left (\int \frac {\sqrt {2} \sqrt {e}+2 x}{-e-\sqrt {2} \sqrt {e} x-x^2} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {b^2 \operatorname {Subst}\left (\int \frac {\sqrt {2} \sqrt {e}-2 x}{-e+\sqrt {2} \sqrt {e} x-x^2} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {a \operatorname {Subst}\left (\int \frac {e-x^2}{e^2+x^4} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{\left (a^2-b^2\right ) d e}-\frac {a \operatorname {Subst}\left (\int \frac {e+x^2}{e^2+x^4} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{\left (a^2-b^2\right ) d e}+\frac {b^2 \operatorname {Subst}\left (\int \frac {1}{e-\sqrt {2} \sqrt {e} x+x^2} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{2 a \left (a^2-b^2\right ) d e}+\frac {b^2 \operatorname {Subst}\left (\int \frac {1}{e+\sqrt {2} \sqrt {e} x+x^2} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{2 a \left (a^2-b^2\right ) d e}-\frac {\left (4 \sqrt {2} b^3 \sqrt {\cos (c+d x)} \sqrt {e \tan (c+d x)}\right ) \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {1-x^4} \left (a+b+(-a+b) x^4\right )} \, dx,x,\frac {\sqrt {\sin (c+d x)}}{\sqrt {1+\cos (c+d x)}}\right )}{a \left (a^2-b^2\right ) d e^2 \sqrt {\sin (c+d x)}}+\frac {\left (2 b \cos (c+d x) \sqrt {e \tan (c+d x)}\right ) \int \sqrt {\sin (2 c+2 d x)} \, dx}{\left (a^2-b^2\right ) e^2 \sqrt {\sin (2 c+2 d x)}}\\ &=\frac {b^2 \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)-\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {b^2 \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)+\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}+\frac {2 b \cos (c+d x) E\left (\left .c-\frac {\pi }{4}+d x\right |2\right ) \sqrt {e \tan (c+d x)}}{\left (a^2-b^2\right ) d e^2 \sqrt {\sin (2 c+2 d x)}}-\frac {2 b \cos (c+d x) (e \tan (c+d x))^{3/2}}{\left (a^2-b^2\right ) d e^3}-\frac {a \operatorname {Subst}\left (\int \frac {\sqrt {2} \sqrt {e}+2 x}{-e-\sqrt {2} \sqrt {e} x-x^2} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \operatorname {Subst}\left (\int \frac {\sqrt {2} \sqrt {e}-2 x}{-e+\sqrt {2} \sqrt {e} x-x^2} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}+\frac {b^2 \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {b^2 \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \operatorname {Subst}\left (\int \frac {1}{e-\sqrt {2} \sqrt {e} x+x^2} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{2 \left (a^2-b^2\right ) d e}-\frac {a \operatorname {Subst}\left (\int \frac {1}{e+\sqrt {2} \sqrt {e} x+x^2} \, dx,x,\sqrt {e \tan (c+d x)}\right )}{2 \left (a^2-b^2\right ) d e}-\frac {\left (2 \sqrt {2} b^3 \sqrt {\cos (c+d x)} \sqrt {e \tan (c+d x)}\right ) \operatorname {Subst}\left (\int \frac {1}{\left (\sqrt {a+b}-\sqrt {a-b} x^2\right ) \sqrt {1-x^4}} \, dx,x,\frac {\sqrt {\sin (c+d x)}}{\sqrt {1+\cos (c+d x)}}\right )}{a \sqrt {a-b} \left (a^2-b^2\right ) d e^2 \sqrt {\sin (c+d x)}}+\frac {\left (2 \sqrt {2} b^3 \sqrt {\cos (c+d x)} \sqrt {e \tan (c+d x)}\right ) \operatorname {Subst}\left (\int \frac {1}{\left (\sqrt {a+b}+\sqrt {a-b} x^2\right ) \sqrt {1-x^4}} \, dx,x,\frac {\sqrt {\sin (c+d x)}}{\sqrt {1+\cos (c+d x)}}\right )}{a \sqrt {a-b} \left (a^2-b^2\right ) d e^2 \sqrt {\sin (c+d x)}}\\ &=-\frac {b^2 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {b^2 \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)-\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}+\frac {b^2 \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)-\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {a \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)+\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {b^2 \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)+\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}+\frac {2 b \cos (c+d x) E\left (\left .c-\frac {\pi }{4}+d x\right |2\right ) \sqrt {e \tan (c+d x)}}{\left (a^2-b^2\right ) d e^2 \sqrt {\sin (2 c+2 d x)}}-\frac {2 b \cos (c+d x) (e \tan (c+d x))^{3/2}}{\left (a^2-b^2\right ) d e^3}-\frac {a \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}+\frac {a \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {\left (2 \sqrt {2} b^3 \sqrt {\cos (c+d x)} \sqrt {e \tan (c+d x)}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-x^2} \sqrt {1+x^2} \left (\sqrt {a+b}-\sqrt {a-b} x^2\right )} \, dx,x,\frac {\sqrt {\sin (c+d x)}}{\sqrt {1+\cos (c+d x)}}\right )}{a \sqrt {a-b} \left (a^2-b^2\right ) d e^2 \sqrt {\sin (c+d x)}}+\frac {\left (2 \sqrt {2} b^3 \sqrt {\cos (c+d x)} \sqrt {e \tan (c+d x)}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-x^2} \sqrt {1+x^2} \left (\sqrt {a+b}+\sqrt {a-b} x^2\right )} \, dx,x,\frac {\sqrt {\sin (c+d x)}}{\sqrt {1+\cos (c+d x)}}\right )}{a \sqrt {a-b} \left (a^2-b^2\right ) d e^2 \sqrt {\sin (c+d x)}}\\ &=\frac {a \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {b^2 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}+\frac {b^2 \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt {e \tan (c+d x)}}{\sqrt {e}}\right )}{\sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {a \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)-\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}+\frac {b^2 \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)-\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}+\frac {a \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)+\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} \left (a^2-b^2\right ) d e^{3/2}}-\frac {b^2 \log \left (\sqrt {e}+\sqrt {e} \tan (c+d x)+\sqrt {2} \sqrt {e \tan (c+d x)}\right )}{2 \sqrt {2} a \left (a^2-b^2\right ) d e^{3/2}}-\frac {2 (a-b \sec (c+d x))}{\left (a^2-b^2\right ) d e \sqrt {e \tan (c+d x)}}+\frac {2 \sqrt {2} b^3 \sqrt {\cos (c+d x)} \Pi \left (-\frac {\sqrt {a-b}}{\sqrt {a+b}};\left .\sin ^{-1}\left (\frac {\sqrt {\sin (c+d x)}}{\sqrt {1+\cos (c+d x)}}\right )\right |-1\right ) \sqrt {e \tan (c+d x)}}{a (a-b)^{3/2} (a+b)^{3/2} d e^2 \sqrt {\sin (c+d x)}}-\frac {2 \sqrt {2} b^3 \sqrt {\cos (c+d x)} \Pi \left (\frac {\sqrt {a-b}}{\sqrt {a+b}};\left .\sin ^{-1}\left (\frac {\sqrt {\sin (c+d x)}}{\sqrt {1+\cos (c+d x)}}\right )\right |-1\right ) \sqrt {e \tan (c+d x)}}{a (a-b)^{3/2} (a+b)^{3/2} d e^2 \sqrt {\sin (c+d x)}}+\frac {2 b \cos (c+d x) E\left (\left .c-\frac {\pi }{4}+d x\right |2\right ) \sqrt {e \tan (c+d x)}}{\left (a^2-b^2\right ) d e^2 \sqrt {\sin (2 c+2 d x)}}-\frac {2 b \cos (c+d x) (e \tan (c+d x))^{3/2}}{\left (a^2-b^2\right ) d e^3}\\ \end {align*}
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Mathematica [C] time = 27.53, size = 1571, normalized size = 1.82 \[ \text {result too large to display} \]
Warning: Unable to verify antiderivative.
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fricas [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (b \sec \left (d x + c\right ) + a\right )} \left (e \tan \left (d x + c\right )\right )^{\frac {3}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 1.71, size = 6426, normalized size = 7.45 \[ \text {output too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (b \sec \left (d x + c\right ) + a\right )} \left (e \tan \left (d x + c\right )\right )^{\frac {3}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {\cos \left (c+d\,x\right )}{{\left (e\,\mathrm {tan}\left (c+d\,x\right )\right )}^{3/2}\,\left (b+a\,\cos \left (c+d\,x\right )\right )} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{\left (e \tan {\left (c + d x \right )}\right )^{\frac {3}{2}} \left (a + b \sec {\left (c + d x \right )}\right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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