Optimal. Leaf size=99 \[ -\frac {\tan ^3(c+d x)}{a^3 d}-\frac {\tan (c+d x)}{a^3 d}-\frac {13 \tanh ^{-1}(\sin (c+d x))}{8 a^3 d}+\frac {\tan (c+d x) \sec ^3(c+d x)}{4 a^3 d}+\frac {11 \tan (c+d x) \sec (c+d x)}{8 a^3 d}+\frac {x}{a^3} \]
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Rubi [A] time = 0.20, antiderivative size = 99, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 9, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.429, Rules used = {3888, 3886, 3473, 8, 2611, 3770, 2607, 30, 3768} \[ -\frac {\tan ^3(c+d x)}{a^3 d}-\frac {\tan (c+d x)}{a^3 d}-\frac {13 \tanh ^{-1}(\sin (c+d x))}{8 a^3 d}+\frac {\tan (c+d x) \sec ^3(c+d x)}{4 a^3 d}+\frac {11 \tan (c+d x) \sec (c+d x)}{8 a^3 d}+\frac {x}{a^3} \]
Antiderivative was successfully verified.
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Rule 8
Rule 30
Rule 2607
Rule 2611
Rule 3473
Rule 3768
Rule 3770
Rule 3886
Rule 3888
Rubi steps
\begin {align*} \int \frac {\tan ^8(c+d x)}{(a+a \sec (c+d x))^3} \, dx &=\frac {\int (-a+a \sec (c+d x))^3 \tan ^2(c+d x) \, dx}{a^6}\\ &=\frac {\int \left (-a^3 \tan ^2(c+d x)+3 a^3 \sec (c+d x) \tan ^2(c+d x)-3 a^3 \sec ^2(c+d x) \tan ^2(c+d x)+a^3 \sec ^3(c+d x) \tan ^2(c+d x)\right ) \, dx}{a^6}\\ &=-\frac {\int \tan ^2(c+d x) \, dx}{a^3}+\frac {\int \sec ^3(c+d x) \tan ^2(c+d x) \, dx}{a^3}+\frac {3 \int \sec (c+d x) \tan ^2(c+d x) \, dx}{a^3}-\frac {3 \int \sec ^2(c+d x) \tan ^2(c+d x) \, dx}{a^3}\\ &=-\frac {\tan (c+d x)}{a^3 d}+\frac {3 \sec (c+d x) \tan (c+d x)}{2 a^3 d}+\frac {\sec ^3(c+d x) \tan (c+d x)}{4 a^3 d}-\frac {\int \sec ^3(c+d x) \, dx}{4 a^3}+\frac {\int 1 \, dx}{a^3}-\frac {3 \int \sec (c+d x) \, dx}{2 a^3}-\frac {3 \operatorname {Subst}\left (\int x^2 \, dx,x,\tan (c+d x)\right )}{a^3 d}\\ &=\frac {x}{a^3}-\frac {3 \tanh ^{-1}(\sin (c+d x))}{2 a^3 d}-\frac {\tan (c+d x)}{a^3 d}+\frac {11 \sec (c+d x) \tan (c+d x)}{8 a^3 d}+\frac {\sec ^3(c+d x) \tan (c+d x)}{4 a^3 d}-\frac {\tan ^3(c+d x)}{a^3 d}-\frac {\int \sec (c+d x) \, dx}{8 a^3}\\ &=\frac {x}{a^3}-\frac {13 \tanh ^{-1}(\sin (c+d x))}{8 a^3 d}-\frac {\tan (c+d x)}{a^3 d}+\frac {11 \sec (c+d x) \tan (c+d x)}{8 a^3 d}+\frac {\sec ^3(c+d x) \tan (c+d x)}{4 a^3 d}-\frac {\tan ^3(c+d x)}{a^3 d}\\ \end {align*}
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Mathematica [B] time = 0.76, size = 230, normalized size = 2.32 \[ \frac {\sec ^4(c+d x) \left (38 \sin (c+d x)-32 \sin (2 (c+d x))+22 \sin (3 (c+d x))+39 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )+4 \cos (2 (c+d x)) \left (13 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )-13 \log \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )+8 d x\right )+\cos (4 (c+d x)) \left (13 \log \left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )-13 \log \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )+8 d x\right )-39 \log \left (\sin \left (\frac {1}{2} (c+d x)\right )+\cos \left (\frac {1}{2} (c+d x)\right )\right )+24 d x\right )}{64 a^3 d} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.78, size = 97, normalized size = 0.98 \[ \frac {16 \, d x \cos \left (d x + c\right )^{4} - 13 \, \cos \left (d x + c\right )^{4} \log \left (\sin \left (d x + c\right ) + 1\right ) + 13 \, \cos \left (d x + c\right )^{4} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, {\left (11 \, \cos \left (d x + c\right )^{2} - 8 \, \cos \left (d x + c\right ) + 2\right )} \sin \left (d x + c\right )}{16 \, a^{3} d \cos \left (d x + c\right )^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 11.18, size = 123, normalized size = 1.24 \[ \frac {\frac {8 \, {\left (d x + c\right )}}{a^{3}} - \frac {13 \, \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right )}{a^{3}} + \frac {13 \, \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right )}{a^{3}} + \frac {2 \, {\left (21 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} + 3 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 13 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 5 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{4} a^{3}}}{8 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.62, size = 228, normalized size = 2.30 \[ \frac {1}{4 a^{3} d \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{4}}+\frac {3}{2 a^{3} d \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{3}}+\frac {27}{8 a^{3} d \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )^{2}}+\frac {21}{8 a^{3} d \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}+\frac {13 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{8 a^{3} d}-\frac {1}{4 a^{3} d \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{4}}+\frac {3}{2 a^{3} d \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{3}}-\frac {27}{8 a^{3} d \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )^{2}}+\frac {21}{8 a^{3} d \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}-\frac {13 \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{8 a^{3} d}+\frac {2 \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d \,a^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.52, size = 257, normalized size = 2.60 \[ \frac {\frac {2 \, {\left (\frac {5 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac {13 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {3 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} + \frac {21 \, \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}}\right )}}{a^{3} - \frac {4 \, a^{3} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {6 \, a^{3} \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}} - \frac {4 \, a^{3} \sin \left (d x + c\right )^{6}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{6}} + \frac {a^{3} \sin \left (d x + c\right )^{8}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{8}}} + \frac {16 \, \arctan \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a^{3}} - \frac {13 \, \log \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + 1\right )}{a^{3}} + \frac {13 \, \log \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - 1\right )}{a^{3}}}{8 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.93, size = 148, normalized size = 1.49 \[ \frac {x}{a^3}-\frac {13\,\mathrm {atanh}\left (\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\right )}{4\,a^3\,d}+\frac {\frac {21\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7}{4}+\frac {3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^5}{4}-\frac {13\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3}{4}+\frac {5\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{4}}{d\,\left (a^3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8-4\,a^3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6+6\,a^3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4-4\,a^3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+a^3\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {\int \frac {\tan ^{8}{\left (c + d x \right )}}{\sec ^{3}{\left (c + d x \right )} + 3 \sec ^{2}{\left (c + d x \right )} + 3 \sec {\left (c + d x \right )} + 1}\, dx}{a^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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