3.197 \(\int \frac {\cos (x)}{\sec (x)-\tan (x)} \, dx\)

Optimal. Leaf size=6 \[ x-\cos (x) \]

[Out]

x-cos(x)

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Rubi [A]  time = 0.06, antiderivative size = 6, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {4391, 2682, 8} \[ x-\cos (x) \]

Antiderivative was successfully verified.

[In]

Int[Cos[x]/(Sec[x] - Tan[x]),x]

[Out]

x - Cos[x]

Rule 8

Int[a_, x_Symbol] :> Simp[a*x, x] /; FreeQ[a, x]

Rule 2682

Int[(cos[(e_.) + (f_.)*(x_)]*(g_.))^(p_)/((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(g*(g*Cos[e
+ f*x])^(p - 1))/(b*f*(p - 1)), x] + Dist[g^2/a, Int[(g*Cos[e + f*x])^(p - 2), x], x] /; FreeQ[{a, b, e, f, g
}, x] && EqQ[a^2 - b^2, 0] && GtQ[p, 1] && IntegerQ[2*p]

Rule 4391

Int[(u_.)*((b_.)*sec[(c_.) + (d_.)*(x_)]^(n_.) + (a_.)*tan[(c_.) + (d_.)*(x_)]^(n_.))^(p_), x_Symbol] :> Int[A
ctivateTrig[u]*Sec[c + d*x]^(n*p)*(b + a*Sin[c + d*x]^n)^p, x] /; FreeQ[{a, b, c, d}, x] && IntegersQ[n, p]

Rubi steps

\begin {align*} \int \frac {\cos (x)}{\sec (x)-\tan (x)} \, dx &=\int \frac {\cos ^2(x)}{1-\sin (x)} \, dx\\ &=-\cos (x)+\int 1 \, dx\\ &=x-\cos (x)\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 6, normalized size = 1.00 \[ x-\cos (x) \]

Antiderivative was successfully verified.

[In]

Integrate[Cos[x]/(Sec[x] - Tan[x]),x]

[Out]

x - Cos[x]

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fricas [A]  time = 0.58, size = 6, normalized size = 1.00 \[ x - \cos \relax (x) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(x)/(sec(x)-tan(x)),x, algorithm="fricas")

[Out]

x - cos(x)

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giac [B]  time = 1.03, size = 14, normalized size = 2.33 \[ x - \frac {2}{\tan \left (\frac {1}{2} \, x\right )^{2} + 1} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(x)/(sec(x)-tan(x)),x, algorithm="giac")

[Out]

x - 2/(tan(1/2*x)^2 + 1)

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maple [B]  time = 0.11, size = 15, normalized size = 2.50 \[ -\frac {2}{\tan ^{2}\left (\frac {x}{2}\right )+1}+x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(x)/(sec(x)-tan(x)),x)

[Out]

-2/(tan(1/2*x)^2+1)+x

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maxima [B]  time = 0.49, size = 30, normalized size = 5.00 \[ -\frac {2}{\frac {\sin \relax (x)^{2}}{{\left (\cos \relax (x) + 1\right )}^{2}} + 1} + 2 \, \arctan \left (\frac {\sin \relax (x)}{\cos \relax (x) + 1}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(x)/(sec(x)-tan(x)),x, algorithm="maxima")

[Out]

-2/(sin(x)^2/(cos(x) + 1)^2 + 1) + 2*arctan(sin(x)/(cos(x) + 1))

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mupad [B]  time = 0.58, size = 6, normalized size = 1.00 \[ x-\cos \relax (x) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-cos(x)/(tan(x) - 1/cos(x)),x)

[Out]

x - cos(x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cos {\relax (x )}}{- \tan {\relax (x )} + \sec {\relax (x )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(x)/(sec(x)-tan(x)),x)

[Out]

Integral(cos(x)/(-tan(x) + sec(x)), x)

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