3.328 \(\int \frac {1}{(-\cos (x)+\sec (x))^3} \, dx\)

Optimal. Leaf size=17 \[ \frac {\csc ^3(x)}{3}-\frac {\csc ^5(x)}{5} \]

[Out]

1/3*csc(x)^3-1/5*csc(x)^5

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Rubi [A]  time = 0.04, antiderivative size = 17, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {4397, 2606, 14} \[ \frac {\csc ^3(x)}{3}-\frac {\csc ^5(x)}{5} \]

Antiderivative was successfully verified.

[In]

Int[(-Cos[x] + Sec[x])^(-3),x]

[Out]

Csc[x]^3/3 - Csc[x]^5/5

Rule 14

Int[(u_)*((c_.)*(x_))^(m_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*u, x], x] /; FreeQ[{c, m}, x] && SumQ[u]
&&  !LinearQ[u, x] &&  !MatchQ[u, (a_) + (b_.)*(v_) /; FreeQ[{a, b}, x] && InverseFunctionQ[v]]

Rule 2606

Int[((a_.)*sec[(e_.) + (f_.)*(x_)])^(m_.)*((b_.)*tan[(e_.) + (f_.)*(x_)])^(n_.), x_Symbol] :> Dist[a/f, Subst[
Int[(a*x)^(m - 1)*(-1 + x^2)^((n - 1)/2), x], x, Sec[e + f*x]], x] /; FreeQ[{a, e, f, m}, x] && IntegerQ[(n -
1)/2] &&  !(IntegerQ[m/2] && LtQ[0, m, n + 1])

Rule 4397

Int[u_, x_Symbol] :> Int[TrigSimplify[u], x] /; TrigSimplifyQ[u]

Rubi steps

\begin {align*} \int \frac {1}{(-\cos (x)+\sec (x))^3} \, dx &=\int \cot ^3(x) \csc ^3(x) \, dx\\ &=-\operatorname {Subst}\left (\int x^2 \left (-1+x^2\right ) \, dx,x,\csc (x)\right )\\ &=-\operatorname {Subst}\left (\int \left (-x^2+x^4\right ) \, dx,x,\csc (x)\right )\\ &=\frac {\csc ^3(x)}{3}-\frac {\csc ^5(x)}{5}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 17, normalized size = 1.00 \[ \frac {\csc ^3(x)}{3}-\frac {\csc ^5(x)}{5} \]

Antiderivative was successfully verified.

[In]

Integrate[(-Cos[x] + Sec[x])^(-3),x]

[Out]

Csc[x]^3/3 - Csc[x]^5/5

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fricas [B]  time = 1.02, size = 28, normalized size = 1.65 \[ -\frac {5 \, \cos \relax (x)^{2} - 2}{15 \, {\left (\cos \relax (x)^{4} - 2 \, \cos \relax (x)^{2} + 1\right )} \sin \relax (x)} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-cos(x)+sec(x))^3,x, algorithm="fricas")

[Out]

-1/15*(5*cos(x)^2 - 2)/((cos(x)^4 - 2*cos(x)^2 + 1)*sin(x))

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giac [A]  time = 0.13, size = 14, normalized size = 0.82 \[ \frac {5 \, \sin \relax (x)^{2} - 3}{15 \, \sin \relax (x)^{5}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-cos(x)+sec(x))^3,x, algorithm="giac")

[Out]

1/15*(5*sin(x)^2 - 3)/sin(x)^5

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maple [A]  time = 0.10, size = 14, normalized size = 0.82 \[ \frac {1}{3 \sin \relax (x )^{3}}-\frac {1}{5 \sin \relax (x )^{5}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(-cos(x)+sec(x))^3,x)

[Out]

1/3/sin(x)^3-1/5/sin(x)^5

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maxima [B]  time = 0.32, size = 73, normalized size = 4.29 \[ \frac {{\left (\frac {5 \, \sin \relax (x)^{2}}{{\left (\cos \relax (x) + 1\right )}^{2}} + \frac {30 \, \sin \relax (x)^{4}}{{\left (\cos \relax (x) + 1\right )}^{4}} - 3\right )} {\left (\cos \relax (x) + 1\right )}^{5}}{480 \, \sin \relax (x)^{5}} + \frac {\sin \relax (x)}{16 \, {\left (\cos \relax (x) + 1\right )}} + \frac {\sin \relax (x)^{3}}{96 \, {\left (\cos \relax (x) + 1\right )}^{3}} - \frac {\sin \relax (x)^{5}}{160 \, {\left (\cos \relax (x) + 1\right )}^{5}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-cos(x)+sec(x))^3,x, algorithm="maxima")

[Out]

1/480*(5*sin(x)^2/(cos(x) + 1)^2 + 30*sin(x)^4/(cos(x) + 1)^4 - 3)*(cos(x) + 1)^5/sin(x)^5 + 1/16*sin(x)/(cos(
x) + 1) + 1/96*sin(x)^3/(cos(x) + 1)^3 - 1/160*sin(x)^5/(cos(x) + 1)^5

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mupad [B]  time = 2.38, size = 14, normalized size = 0.82 \[ \frac {5\,{\sin \relax (x)}^2-3}{15\,{\sin \relax (x)}^5} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-1/(cos(x) - 1/cos(x))^3,x)

[Out]

(5*sin(x)^2 - 3)/(15*sin(x)^5)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ - \int \frac {1}{\cos ^{3}{\relax (x )} - 3 \cos ^{2}{\relax (x )} \sec {\relax (x )} + 3 \cos {\relax (x )} \sec ^{2}{\relax (x )} - \sec ^{3}{\relax (x )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(-cos(x)+sec(x))**3,x)

[Out]

-Integral(1/(cos(x)**3 - 3*cos(x)**2*sec(x) + 3*cos(x)*sec(x)**2 - sec(x)**3), x)

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