Optimal. Leaf size=157 \[ -\frac {4 a \left (15 a^2+4 c^2\right ) \sin (d+e x)}{3 e}-\frac {4 c \left (15 a^2+4 c^2\right ) \cos (d+e x)}{3 e}+4 a x \left (5 a^2+3 c^2\right )-\frac {20 \left (a^2 \sin (d+e x)+a c \cos (d+e x)\right ) (a (-\cos (d+e x))+a+c \sin (d+e x))}{3 e}-\frac {8 (a \sin (d+e x)+c \cos (d+e x)) (a (-\cos (d+e x))+a+c \sin (d+e x))^2}{3 e} \]
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Rubi [A] time = 0.13, antiderivative size = 157, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {3120, 3146, 2637, 2638} \[ -\frac {4 a \left (15 a^2+4 c^2\right ) \sin (d+e x)}{3 e}-\frac {4 c \left (15 a^2+4 c^2\right ) \cos (d+e x)}{3 e}+4 a x \left (5 a^2+3 c^2\right )-\frac {20 \left (a^2 \sin (d+e x)+a c \cos (d+e x)\right ) (a (-\cos (d+e x))+a+c \sin (d+e x))}{3 e}-\frac {8 (a \sin (d+e x)+c \cos (d+e x)) (a (-\cos (d+e x))+a+c \sin (d+e x))^2}{3 e} \]
Antiderivative was successfully verified.
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Rule 2637
Rule 2638
Rule 3120
Rule 3146
Rubi steps
\begin {align*} \int (2 a-2 a \cos (d+e x)+2 c \sin (d+e x))^3 \, dx &=-\frac {8 (c \cos (d+e x)+a \sin (d+e x)) (a-a \cos (d+e x)+c \sin (d+e x))^2}{3 e}+\frac {1}{3} \int (2 a-2 a \cos (d+e x)+2 c \sin (d+e x)) \left (4 \left (5 a^2+2 c^2\right )-20 a^2 \cos (d+e x)+20 a c \sin (d+e x)\right ) \, dx\\ &=-\frac {20 \left (a c \cos (d+e x)+a^2 \sin (d+e x)\right ) (a-a \cos (d+e x)+c \sin (d+e x))}{3 e}-\frac {8 (c \cos (d+e x)+a \sin (d+e x)) (a-a \cos (d+e x)+c \sin (d+e x))^2}{3 e}+\frac {\int \left (48 a^2 \left (5 a^2+3 c^2\right )-16 a^2 \left (15 a^2+4 c^2\right ) \cos (d+e x)+16 a c \left (15 a^2+4 c^2\right ) \sin (d+e x)\right ) \, dx}{12 a}\\ &=4 a \left (5 a^2+3 c^2\right ) x-\frac {20 \left (a c \cos (d+e x)+a^2 \sin (d+e x)\right ) (a-a \cos (d+e x)+c \sin (d+e x))}{3 e}-\frac {8 (c \cos (d+e x)+a \sin (d+e x)) (a-a \cos (d+e x)+c \sin (d+e x))^2}{3 e}-\frac {1}{3} \left (4 a \left (15 a^2+4 c^2\right )\right ) \int \cos (d+e x) \, dx+\frac {1}{3} \left (4 c \left (15 a^2+4 c^2\right )\right ) \int \sin (d+e x) \, dx\\ &=4 a \left (5 a^2+3 c^2\right ) x-\frac {4 c \left (15 a^2+4 c^2\right ) \cos (d+e x)}{3 e}-\frac {4 a \left (15 a^2+4 c^2\right ) \sin (d+e x)}{3 e}-\frac {20 \left (a c \cos (d+e x)+a^2 \sin (d+e x)\right ) (a-a \cos (d+e x)+c \sin (d+e x))}{3 e}-\frac {8 (c \cos (d+e x)+a \sin (d+e x)) (a-a \cos (d+e x)+c \sin (d+e x))^2}{3 e}\\ \end {align*}
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Mathematica [A] time = 0.43, size = 136, normalized size = 0.87 \[ \frac {2 \left (6 a \left (5 a^2+3 c^2\right ) (d+e x)-9 a \left (5 a^2+c^2\right ) \sin (d+e x)+9 a \left (a^2-c^2\right ) \sin (2 (d+e x))-a \left (a^2-3 c^2\right ) \sin (3 (d+e x))-9 c \left (5 a^2+c^2\right ) \cos (d+e x)+c \left (c^2-3 a^2\right ) \cos (3 (d+e x))+18 a^2 c \cos (2 (d+e x))\right )}{3 e} \]
Antiderivative was successfully verified.
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fricas [A] time = 1.95, size = 134, normalized size = 0.85 \[ \frac {4 \, {\left (18 \, a^{2} c \cos \left (e x + d\right )^{2} - 2 \, {\left (3 \, a^{2} c - c^{3}\right )} \cos \left (e x + d\right )^{3} + 3 \, {\left (5 \, a^{3} + 3 \, a c^{2}\right )} e x - 6 \, {\left (3 \, a^{2} c + c^{3}\right )} \cos \left (e x + d\right ) - {\left (22 \, a^{3} + 6 \, a c^{2} + 2 \, {\left (a^{3} - 3 \, a c^{2}\right )} \cos \left (e x + d\right )^{2} - 9 \, {\left (a^{3} - a c^{2}\right )} \cos \left (e x + d\right )\right )} \sin \left (e x + d\right )\right )}}{3 \, e} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.19, size = 151, normalized size = 0.96 \[ 12 \, a^{2} c \cos \left (2 \, x e + 2 \, d\right ) e^{\left (-1\right )} - \frac {2}{3} \, {\left (3 \, a^{2} c - c^{3}\right )} \cos \left (3 \, x e + 3 \, d\right ) e^{\left (-1\right )} - 6 \, {\left (5 \, a^{2} c + c^{3}\right )} \cos \left (x e + d\right ) e^{\left (-1\right )} - \frac {2}{3} \, {\left (a^{3} - 3 \, a c^{2}\right )} e^{\left (-1\right )} \sin \left (3 \, x e + 3 \, d\right ) + 6 \, {\left (a^{3} - a c^{2}\right )} e^{\left (-1\right )} \sin \left (2 \, x e + 2 \, d\right ) - 6 \, {\left (5 \, a^{3} + a c^{2}\right )} e^{\left (-1\right )} \sin \left (x e + d\right ) + 4 \, {\left (5 \, a^{3} + 3 \, a c^{2}\right )} x \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.25, size = 178, normalized size = 1.13 \[ \frac {-\frac {8 a^{3} \left (2+\cos ^{2}\left (e x +d \right )\right ) \sin \left (e x +d \right )}{3}-8 a^{2} c \left (\cos ^{3}\left (e x +d \right )\right )+24 a^{3} \left (\frac {\sin \left (e x +d \right ) \cos \left (e x +d \right )}{2}+\frac {e x}{2}+\frac {d}{2}\right )-8 a \,c^{2} \left (\sin ^{3}\left (e x +d \right )\right )+24 a^{2} c \left (\cos ^{2}\left (e x +d \right )\right )-24 a^{3} \sin \left (e x +d \right )-\frac {8 c^{3} \left (2+\sin ^{2}\left (e x +d \right )\right ) \cos \left (e x +d \right )}{3}+24 a \,c^{2} \left (-\frac {\sin \left (e x +d \right ) \cos \left (e x +d \right )}{2}+\frac {e x}{2}+\frac {d}{2}\right )-24 a^{2} c \cos \left (e x +d \right )+8 a^{3} \left (e x +d \right )}{e} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.33, size = 188, normalized size = 1.20 \[ -\frac {8 \, a^{2} c \cos \left (e x + d\right )^{3}}{e} - \frac {8 \, a c^{2} \sin \left (e x + d\right )^{3}}{e} + 8 \, a^{3} x + \frac {8 \, {\left (\sin \left (e x + d\right )^{3} - 3 \, \sin \left (e x + d\right )\right )} a^{3}}{3 \, e} + \frac {8 \, {\left (\cos \left (e x + d\right )^{3} - 3 \, \cos \left (e x + d\right )\right )} c^{3}}{3 \, e} - 24 \, a^{2} {\left (\frac {c \cos \left (e x + d\right )}{e} + \frac {a \sin \left (e x + d\right )}{e}\right )} + 6 \, {\left (\frac {4 \, a c \cos \left (e x + d\right )^{2}}{e} + \frac {{\left (2 \, e x + 2 \, d + \sin \left (2 \, e x + 2 \, d\right )\right )} a^{2}}{e} + \frac {{\left (2 \, e x + 2 \, d - \sin \left (2 \, e x + 2 \, d\right )\right )} c^{2}}{e}\right )} a \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 3.21, size = 258, normalized size = 1.64 \[ \frac {8\,a\,\mathrm {atan}\left (\frac {8\,a\,\mathrm {tan}\left (\frac {d}{2}+\frac {e\,x}{2}\right )\,\left (5\,a^2+3\,c^2\right )}{40\,a^3+24\,a\,c^2}\right )\,\left (5\,a^2+3\,c^2\right )}{e}-\frac {\mathrm {tan}\left (\frac {d}{2}+\frac {e\,x}{2}\right )\,\left (40\,a^3+24\,a\,c^2\right )+64\,a^2\,c-{\mathrm {tan}\left (\frac {d}{2}+\frac {e\,x}{2}\right )}^5\,\left (24\,a\,c^2-88\,a^3\right )+{\mathrm {tan}\left (\frac {d}{2}+\frac {e\,x}{2}\right )}^3\,\left (\frac {320\,a^3}{3}+64\,a\,c^2\right )+{\mathrm {tan}\left (\frac {d}{2}+\frac {e\,x}{2}\right )}^2\,\left (192\,a^2\,c+32\,c^3\right )+\frac {32\,c^3}{3}+192\,a^2\,c\,{\mathrm {tan}\left (\frac {d}{2}+\frac {e\,x}{2}\right )}^4}{e\,\left ({\mathrm {tan}\left (\frac {d}{2}+\frac {e\,x}{2}\right )}^6+3\,{\mathrm {tan}\left (\frac {d}{2}+\frac {e\,x}{2}\right )}^4+3\,{\mathrm {tan}\left (\frac {d}{2}+\frac {e\,x}{2}\right )}^2+1\right )}-\frac {8\,a\,\left (5\,a^2+3\,c^2\right )\,\left (\mathrm {atan}\left (\mathrm {tan}\left (\frac {d}{2}+\frac {e\,x}{2}\right )\right )-\frac {e\,x}{2}\right )}{e} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.76, size = 291, normalized size = 1.85 \[ \begin {cases} 12 a^{3} x \sin ^{2}{\left (d + e x \right )} + 12 a^{3} x \cos ^{2}{\left (d + e x \right )} + 8 a^{3} x - \frac {16 a^{3} \sin ^{3}{\left (d + e x \right )}}{3 e} - \frac {8 a^{3} \sin {\left (d + e x \right )} \cos ^{2}{\left (d + e x \right )}}{e} + \frac {12 a^{3} \sin {\left (d + e x \right )} \cos {\left (d + e x \right )}}{e} - \frac {24 a^{3} \sin {\left (d + e x \right )}}{e} - \frac {8 a^{2} c \cos ^{3}{\left (d + e x \right )}}{e} + \frac {24 a^{2} c \cos ^{2}{\left (d + e x \right )}}{e} - \frac {24 a^{2} c \cos {\left (d + e x \right )}}{e} + 12 a c^{2} x \sin ^{2}{\left (d + e x \right )} + 12 a c^{2} x \cos ^{2}{\left (d + e x \right )} - \frac {8 a c^{2} \sin ^{3}{\left (d + e x \right )}}{e} - \frac {12 a c^{2} \sin {\left (d + e x \right )} \cos {\left (d + e x \right )}}{e} - \frac {8 c^{3} \sin ^{2}{\left (d + e x \right )} \cos {\left (d + e x \right )}}{e} - \frac {16 c^{3} \cos ^{3}{\left (d + e x \right )}}{3 e} & \text {for}\: e \neq 0 \\x \left (- 2 a \cos {\relax (d )} + 2 a + 2 c \sin {\relax (d )}\right )^{3} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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