Optimal. Leaf size=107 \[ -\frac {\sin \left (\frac {2 b}{d}\right ) (b c-a d) \text {Ci}\left (\frac {2 (b c-a d)}{d (c+d x)}\right )}{d^2}+\frac {\cos \left (\frac {2 b}{d}\right ) (b c-a d) \text {Si}\left (\frac {2 (b c-a d)}{d (c+d x)}\right )}{d^2}+\frac {(c+d x) \cos ^2\left (\frac {a+b x}{c+d x}\right )}{d} \]
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Rubi [A] time = 0.16, antiderivative size = 107, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {4564, 3313, 12, 3303, 3299, 3302} \[ -\frac {\sin \left (\frac {2 b}{d}\right ) (b c-a d) \text {CosIntegral}\left (\frac {2 (b c-a d)}{d (c+d x)}\right )}{d^2}+\frac {\cos \left (\frac {2 b}{d}\right ) (b c-a d) \text {Si}\left (\frac {2 (b c-a d)}{d (c+d x)}\right )}{d^2}+\frac {(c+d x) \cos ^2\left (\frac {a+b x}{c+d x}\right )}{d} \]
Antiderivative was successfully verified.
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Rule 12
Rule 3299
Rule 3302
Rule 3303
Rule 3313
Rule 4564
Rubi steps
\begin {align*} \int \cos ^2\left (\frac {a+b x}{c+d x}\right ) \, dx &=-\frac {\operatorname {Subst}\left (\int \frac {\cos ^2\left (\frac {b}{d}-\frac {(b c-a d) x}{d}\right )}{x^2} \, dx,x,\frac {1}{c+d x}\right )}{d}\\ &=\frac {(c+d x) \cos ^2\left (\frac {a+b x}{c+d x}\right )}{d}+\frac {(2 (b c-a d)) \operatorname {Subst}\left (\int -\frac {\sin \left (\frac {2 b}{d}-\frac {2 (b c-a d) x}{d}\right )}{2 x} \, dx,x,\frac {1}{c+d x}\right )}{d^2}\\ &=\frac {(c+d x) \cos ^2\left (\frac {a+b x}{c+d x}\right )}{d}-\frac {(b c-a d) \operatorname {Subst}\left (\int \frac {\sin \left (\frac {2 b}{d}-\frac {2 (b c-a d) x}{d}\right )}{x} \, dx,x,\frac {1}{c+d x}\right )}{d^2}\\ &=\frac {(c+d x) \cos ^2\left (\frac {a+b x}{c+d x}\right )}{d}+\frac {\left ((b c-a d) \cos \left (\frac {2 b}{d}\right )\right ) \operatorname {Subst}\left (\int \frac {\sin \left (\frac {2 (b c-a d) x}{d}\right )}{x} \, dx,x,\frac {1}{c+d x}\right )}{d^2}-\frac {\left ((b c-a d) \sin \left (\frac {2 b}{d}\right )\right ) \operatorname {Subst}\left (\int \frac {\cos \left (\frac {2 (b c-a d) x}{d}\right )}{x} \, dx,x,\frac {1}{c+d x}\right )}{d^2}\\ &=\frac {(c+d x) \cos ^2\left (\frac {a+b x}{c+d x}\right )}{d}-\frac {(b c-a d) \text {Ci}\left (\frac {2 (b c-a d)}{d (c+d x)}\right ) \sin \left (\frac {2 b}{d}\right )}{d^2}+\frac {(b c-a d) \cos \left (\frac {2 b}{d}\right ) \text {Si}\left (\frac {2 (b c-a d)}{d (c+d x)}\right )}{d^2}\\ \end {align*}
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Mathematica [C] time = 6.14, size = 400, normalized size = 3.74 \[ \frac {\left (a c d-b c^2\right ) \left (\frac {\left (-1+e^{\frac {4 i b}{d}}\right ) \left (e^{\frac {4 i b c}{d (c+d x)}}-e^{\frac {4 i a}{c+d x}}\right ) \exp \left (-\frac {2 i (a d+2 b c+b d x)}{d (c+d x)}\right )}{8 (b c-a d)}-\frac {\left (1+e^{\frac {4 i b}{d}}\right ) \left (e^{\frac {4 i a}{c+d x}}+e^{\frac {4 i b c}{d (c+d x)}}\right ) \exp \left (-\frac {2 i (a d+2 b c+b d x)}{d (c+d x)}\right )}{8 (b c-a d)}\right )}{d}+\frac {2 a d \sin \left (\frac {2 b}{d}\right ) \text {Ci}\left (\frac {2 (a d-b c)}{d (c+d x)}\right )-2 b c \sin \left (\frac {2 b}{d}\right ) \text {Ci}\left (\frac {2 (a d-b c)}{d (c+d x)}\right )+2 a d \cos \left (\frac {2 b}{d}\right ) \text {Si}\left (\frac {2 (a d-b c)}{d (c+d x)}\right )-2 b c \cos \left (\frac {2 b}{d}\right ) \text {Si}\left (\frac {2 (a d-b c)}{d (c+d x)}\right )+d^2 x}{2 d^2}-\frac {1}{2} x \sin \left (\frac {2 b}{d}\right ) \sin \left (\frac {2 (a d-b c)}{d (c+d x)}\right )+\frac {1}{2} x \cos \left (\frac {2 b}{d}\right ) \cos \left (\frac {2 (a d-b c)}{d (c+d x)}\right ) \]
Warning: Unable to verify antiderivative.
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fricas [A] time = 2.20, size = 144, normalized size = 1.35 \[ \frac {2 \, {\left (d^{2} x + c d\right )} \cos \left (\frac {b x + a}{d x + c}\right )^{2} - 2 \, {\left (b c - a d\right )} \cos \left (\frac {2 \, b}{d}\right ) \operatorname {Si}\left (-\frac {2 \, {\left (b c - a d\right )}}{d^{2} x + c d}\right ) - {\left ({\left (b c - a d\right )} \operatorname {Ci}\left (\frac {2 \, {\left (b c - a d\right )}}{d^{2} x + c d}\right ) + {\left (b c - a d\right )} \operatorname {Ci}\left (-\frac {2 \, {\left (b c - a d\right )}}{d^{2} x + c d}\right )\right )} \sin \left (\frac {2 \, b}{d}\right )}{2 \, d^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 68.63, size = 683, normalized size = 6.38 \[ -\frac {{\left (2 \, b^{3} c^{2} \operatorname {Ci}\left (-\frac {2 \, {\left (b - \frac {{\left (b x + a\right )} d}{d x + c}\right )}}{d}\right ) \sin \left (\frac {2 \, b}{d}\right ) - 4 \, a b^{2} c d \operatorname {Ci}\left (-\frac {2 \, {\left (b - \frac {{\left (b x + a\right )} d}{d x + c}\right )}}{d}\right ) \sin \left (\frac {2 \, b}{d}\right ) - \frac {2 \, {\left (b x + a\right )} b^{2} c^{2} d \operatorname {Ci}\left (-\frac {2 \, {\left (b - \frac {{\left (b x + a\right )} d}{d x + c}\right )}}{d}\right ) \sin \left (\frac {2 \, b}{d}\right )}{d x + c} + 2 \, a^{2} b d^{2} \operatorname {Ci}\left (-\frac {2 \, {\left (b - \frac {{\left (b x + a\right )} d}{d x + c}\right )}}{d}\right ) \sin \left (\frac {2 \, b}{d}\right ) + \frac {4 \, {\left (b x + a\right )} a b c d^{2} \operatorname {Ci}\left (-\frac {2 \, {\left (b - \frac {{\left (b x + a\right )} d}{d x + c}\right )}}{d}\right ) \sin \left (\frac {2 \, b}{d}\right )}{d x + c} - \frac {2 \, {\left (b x + a\right )} a^{2} d^{3} \operatorname {Ci}\left (-\frac {2 \, {\left (b - \frac {{\left (b x + a\right )} d}{d x + c}\right )}}{d}\right ) \sin \left (\frac {2 \, b}{d}\right )}{d x + c} - 2 \, b^{3} c^{2} \cos \left (\frac {2 \, b}{d}\right ) \operatorname {Si}\left (\frac {2 \, {\left (b - \frac {{\left (b x + a\right )} d}{d x + c}\right )}}{d}\right ) + 4 \, a b^{2} c d \cos \left (\frac {2 \, b}{d}\right ) \operatorname {Si}\left (\frac {2 \, {\left (b - \frac {{\left (b x + a\right )} d}{d x + c}\right )}}{d}\right ) + \frac {2 \, {\left (b x + a\right )} b^{2} c^{2} d \cos \left (\frac {2 \, b}{d}\right ) \operatorname {Si}\left (\frac {2 \, {\left (b - \frac {{\left (b x + a\right )} d}{d x + c}\right )}}{d}\right )}{d x + c} - 2 \, a^{2} b d^{2} \cos \left (\frac {2 \, b}{d}\right ) \operatorname {Si}\left (\frac {2 \, {\left (b - \frac {{\left (b x + a\right )} d}{d x + c}\right )}}{d}\right ) - \frac {4 \, {\left (b x + a\right )} a b c d^{2} \cos \left (\frac {2 \, b}{d}\right ) \operatorname {Si}\left (\frac {2 \, {\left (b - \frac {{\left (b x + a\right )} d}{d x + c}\right )}}{d}\right )}{d x + c} + \frac {2 \, {\left (b x + a\right )} a^{2} d^{3} \cos \left (\frac {2 \, b}{d}\right ) \operatorname {Si}\left (\frac {2 \, {\left (b - \frac {{\left (b x + a\right )} d}{d x + c}\right )}}{d}\right )}{d x + c} - b^{2} c^{2} d \cos \left (\frac {2 \, {\left (b x + a\right )}}{d x + c}\right ) + 2 \, a b c d^{2} \cos \left (\frac {2 \, {\left (b x + a\right )}}{d x + c}\right ) - a^{2} d^{3} \cos \left (\frac {2 \, {\left (b x + a\right )}}{d x + c}\right ) - b^{2} c^{2} d + 2 \, a b c d^{2} - a^{2} d^{3}\right )} {\left (\frac {b c}{{\left (b c - a d\right )}^{2}} - \frac {a d}{{\left (b c - a d\right )}^{2}}\right )}}{2 \, {\left (b d^{2} - \frac {{\left (b x + a\right )} d^{3}}{d x + c}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.14, size = 195, normalized size = 1.82 \[ -\frac {\left (d a -c b \right ) \left (\frac {d^{2} \left (-\frac {2 \cos \left (\frac {2 d a -2 c b}{d \left (d x +c \right )}+\frac {2 b}{d}\right )}{\left (\left (\frac {b}{d}+\frac {d a -c b}{d \left (d x +c \right )}\right ) d -b \right ) d}-\frac {2 \left (\frac {2 \Si \left (\frac {2 d a -2 c b}{d \left (d x +c \right )}\right ) \cos \left (\frac {2 b}{d}\right )}{d}+\frac {2 \Ci \left (\frac {2 d a -2 c b}{d \left (d x +c \right )}\right ) \sin \left (\frac {2 b}{d}\right )}{d}\right )}{d}\right )}{4}-\frac {d}{2 \left (\left (\frac {b}{d}+\frac {d a -c b}{d \left (d x +c \right )}\right ) d -b \right )}\right )}{d^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {1}{2} \, x + \frac {1}{2} \, \int \cos \left (\frac {2 \, {\left (b x + a\right )}}{d x + c}\right )\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int {\cos \left (\frac {a+b\,x}{c+d\,x}\right )}^2 \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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