Optimal. Leaf size=359 \[ \frac {a^5 \left (3 a^2+5 b^2\right ) \tan (d+e x) \sec (d+e x) \left (a^2 \sec ^2(d+e x)+2 a b \sec (d+e x)+b^2\right )^{3/2}}{6 e \left (a^2 \sec (d+e x)+a b\right )^3}+\frac {a^4 b \left (11 a^2+8 b^2\right ) \tan (d+e x) \left (a^2 \sec ^2(d+e x)+2 a b \sec (d+e x)+b^2\right )^{3/2}}{3 e \left (a^2 \sec (d+e x)+a b\right )^3}+\frac {\left (a^4+9 a^2 b^2+2 b^4\right ) \tanh ^{-1}(\sin (d+e x)) \left (a^2 \sec ^2(d+e x)+2 a b \sec (d+e x)+b^2\right )^{3/2}}{2 e (a \sec (d+e x)+b)^3}+\frac {a^4 b^3 x \left (a^2 \sec ^2(d+e x)+2 a b \sec (d+e x)+b^2\right )^{3/2}}{\left (a^2 \sec (d+e x)+a b\right )^3}+\frac {b \tan (d+e x) \left (a^3 \sec (d+e x)+a^2 b\right )^2 \left (a^2 \sec ^2(d+e x)+2 a b \sec (d+e x)+b^2\right )^{3/2}}{3 e \left (a^2 \sec (d+e x)+a b\right )^3} \]
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Rubi [A] time = 0.29, antiderivative size = 359, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, integrand size = 41, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.146, Rules used = {4174, 3918, 4048, 3770, 3767, 8} \[ \frac {a^4 b^3 x \left (a^2 \sec ^2(d+e x)+2 a b \sec (d+e x)+b^2\right )^{3/2}}{\left (a^2 \sec (d+e x)+a b\right )^3}+\frac {a^5 \left (3 a^2+5 b^2\right ) \tan (d+e x) \sec (d+e x) \left (a^2 \sec ^2(d+e x)+2 a b \sec (d+e x)+b^2\right )^{3/2}}{6 e \left (a^2 \sec (d+e x)+a b\right )^3}+\frac {a^4 b \left (11 a^2+8 b^2\right ) \tan (d+e x) \left (a^2 \sec ^2(d+e x)+2 a b \sec (d+e x)+b^2\right )^{3/2}}{3 e \left (a^2 \sec (d+e x)+a b\right )^3}+\frac {b \tan (d+e x) \left (a^2 b+a^3 \sec (d+e x)\right )^2 \left (a^2 \sec ^2(d+e x)+2 a b \sec (d+e x)+b^2\right )^{3/2}}{3 e \left (a^2 \sec (d+e x)+a b\right )^3}+\frac {\left (9 a^2 b^2+a^4+2 b^4\right ) \tanh ^{-1}(\sin (d+e x)) \left (a^2 \sec ^2(d+e x)+2 a b \sec (d+e x)+b^2\right )^{3/2}}{2 e (a \sec (d+e x)+b)^3} \]
Antiderivative was successfully verified.
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Rule 8
Rule 3767
Rule 3770
Rule 3918
Rule 4048
Rule 4174
Rubi steps
\begin {align*} \int (a+b \sec (d+e x)) \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2} \, dx &=\frac {\left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2} \int \left (2 a b+2 a^2 \sec (d+e x)\right )^3 (a+b \sec (d+e x)) \, dx}{\left (2 a b+2 a^2 \sec (d+e x)\right )^3}\\ &=\frac {b \left (a^2 b+a^3 \sec (d+e x)\right )^2 \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2} \tan (d+e x)}{3 e \left (a b+a^2 \sec (d+e x)\right )^3}+\frac {\left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2} \int \left (2 a b+2 a^2 \sec (d+e x)\right ) \left (12 a^3 b^2+4 a^2 b \left (8 a^2+3 b^2\right ) \sec (d+e x)+4 a^3 \left (3 a^2+5 b^2\right ) \sec ^2(d+e x)\right ) \, dx}{3 \left (2 a b+2 a^2 \sec (d+e x)\right )^3}\\ &=\frac {a^5 \left (3 a^2+5 b^2\right ) \sec (d+e x) \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2} \tan (d+e x)}{6 e \left (a b+a^2 \sec (d+e x)\right )^3}+\frac {b \left (a^2 b+a^3 \sec (d+e x)\right )^2 \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2} \tan (d+e x)}{3 e \left (a b+a^2 \sec (d+e x)\right )^3}+\frac {\left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2} \int \left (48 a^4 b^3+24 a^3 \left (a^4+9 a^2 b^2+2 b^4\right ) \sec (d+e x)+16 a^4 b \left (11 a^2+8 b^2\right ) \sec ^2(d+e x)\right ) \, dx}{6 \left (2 a b+2 a^2 \sec (d+e x)\right )^3}\\ &=\frac {a^4 b^3 x \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2}}{\left (a b+a^2 \sec (d+e x)\right )^3}+\frac {a^5 \left (3 a^2+5 b^2\right ) \sec (d+e x) \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2} \tan (d+e x)}{6 e \left (a b+a^2 \sec (d+e x)\right )^3}+\frac {b \left (a^2 b+a^3 \sec (d+e x)\right )^2 \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2} \tan (d+e x)}{3 e \left (a b+a^2 \sec (d+e x)\right )^3}+\frac {\left (8 a^4 b \left (11 a^2+8 b^2\right ) \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2}\right ) \int \sec ^2(d+e x) \, dx}{3 \left (2 a b+2 a^2 \sec (d+e x)\right )^3}+\frac {\left (4 a^3 \left (a^4+9 a^2 b^2+2 b^4\right ) \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2}\right ) \int \sec (d+e x) \, dx}{\left (2 a b+2 a^2 \sec (d+e x)\right )^3}\\ &=\frac {\left (a^4+9 a^2 b^2+2 b^4\right ) \tanh ^{-1}(\sin (d+e x)) \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2}}{2 e (b+a \sec (d+e x))^3}+\frac {a^4 b^3 x \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2}}{\left (a b+a^2 \sec (d+e x)\right )^3}+\frac {a^5 \left (3 a^2+5 b^2\right ) \sec (d+e x) \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2} \tan (d+e x)}{6 e \left (a b+a^2 \sec (d+e x)\right )^3}+\frac {b \left (a^2 b+a^3 \sec (d+e x)\right )^2 \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2} \tan (d+e x)}{3 e \left (a b+a^2 \sec (d+e x)\right )^3}-\frac {\left (8 a^4 b \left (11 a^2+8 b^2\right ) \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2}\right ) \operatorname {Subst}(\int 1 \, dx,x,-\tan (d+e x))}{3 e \left (2 a b+2 a^2 \sec (d+e x)\right )^3}\\ &=\frac {\left (a^4+9 a^2 b^2+2 b^4\right ) \tanh ^{-1}(\sin (d+e x)) \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2}}{2 e (b+a \sec (d+e x))^3}+\frac {a^4 b^3 x \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2}}{\left (a b+a^2 \sec (d+e x)\right )^3}+\frac {a^4 b \left (11 a^2+8 b^2\right ) \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2} \tan (d+e x)}{3 e \left (a b+a^2 \sec (d+e x)\right )^3}+\frac {a^5 \left (3 a^2+5 b^2\right ) \sec (d+e x) \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2} \tan (d+e x)}{6 e \left (a b+a^2 \sec (d+e x)\right )^3}+\frac {b \left (a^2 b+a^3 \sec (d+e x)\right )^2 \left (b^2+2 a b \sec (d+e x)+a^2 \sec ^2(d+e x)\right )^{3/2} \tan (d+e x)}{3 e \left (a b+a^2 \sec (d+e x)\right )^3}\\ \end {align*}
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Mathematica [A] time = 0.82, size = 128, normalized size = 0.36 \[ \frac {\cos (d+e x) \sqrt {(a \sec (d+e x)+b)^2} \left (2 a^3 b \tan ^3(d+e x)+3 a \tan (d+e x) \left (a \left (a^2+3 b^2\right ) \sec (d+e x)+8 a^2 b+6 b^3\right )+3 \left (a^4+9 a^2 b^2+2 b^4\right ) \tanh ^{-1}(\sin (d+e x))+6 a b^3 e x\right )}{6 e (a+b \cos (d+e x))} \]
Antiderivative was successfully verified.
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fricas [A] time = 1.58, size = 162, normalized size = 0.45 \[ \frac {12 \, a b^{3} e x \cos \left (e x + d\right )^{3} + 3 \, {\left (a^{4} + 9 \, a^{2} b^{2} + 2 \, b^{4}\right )} \cos \left (e x + d\right )^{3} \log \left (\sin \left (e x + d\right ) + 1\right ) - 3 \, {\left (a^{4} + 9 \, a^{2} b^{2} + 2 \, b^{4}\right )} \cos \left (e x + d\right )^{3} \log \left (-\sin \left (e x + d\right ) + 1\right ) + 2 \, {\left (2 \, a^{3} b + 2 \, {\left (11 \, a^{3} b + 9 \, a b^{3}\right )} \cos \left (e x + d\right )^{2} + 3 \, {\left (a^{4} + 3 \, a^{2} b^{2}\right )} \cos \left (e x + d\right )\right )} \sin \left (e x + d\right )}{12 \, e \cos \left (e x + d\right )^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.51, size = 652, normalized size = 1.82 \[ \frac {1}{6} \, {\left (6 \, {\left (x e + d\right )} a b^{3} \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right ) + 3 \, {\left (a^{4} \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right ) + 9 \, a^{2} b^{2} \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right ) + 2 \, b^{4} \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right )\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, x e + \frac {1}{2} \, d\right ) + 1 \right |}\right ) - 3 \, {\left (a^{4} \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right ) + 9 \, a^{2} b^{2} \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right ) + 2 \, b^{4} \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right )\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, x e + \frac {1}{2} \, d\right ) - 1 \right |}\right ) + \frac {2 \, {\left (3 \, a^{4} \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right ) \tan \left (\frac {1}{2} \, x e + \frac {1}{2} \, d\right )^{5} - 24 \, a^{3} b \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right ) \tan \left (\frac {1}{2} \, x e + \frac {1}{2} \, d\right )^{5} + 9 \, a^{2} b^{2} \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right ) \tan \left (\frac {1}{2} \, x e + \frac {1}{2} \, d\right )^{5} - 18 \, a b^{3} \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right ) \tan \left (\frac {1}{2} \, x e + \frac {1}{2} \, d\right )^{5} + 40 \, a^{3} b \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right ) \tan \left (\frac {1}{2} \, x e + \frac {1}{2} \, d\right )^{3} + 36 \, a b^{3} \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right ) \tan \left (\frac {1}{2} \, x e + \frac {1}{2} \, d\right )^{3} - 3 \, a^{4} \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right ) \tan \left (\frac {1}{2} \, x e + \frac {1}{2} \, d\right ) - 24 \, a^{3} b \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right ) \tan \left (\frac {1}{2} \, x e + \frac {1}{2} \, d\right ) - 9 \, a^{2} b^{2} \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right ) \tan \left (\frac {1}{2} \, x e + \frac {1}{2} \, d\right ) - 18 \, a b^{3} \mathrm {sgn}\left (b \cos \left (x e + d\right )^{2} + a \cos \left (x e + d\right )\right ) \tan \left (\frac {1}{2} \, x e + \frac {1}{2} \, d\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, x e + \frac {1}{2} \, d\right )^{2} - 1\right )}^{3}}\right )} e^{\left (-1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.61, size = 387, normalized size = 1.08 \[ \frac {\left (3 \ln \left (\frac {1-\cos \left (e x +d \right )+\sin \left (e x +d \right )}{\sin \left (e x +d \right )}\right ) \left (\cos ^{3}\left (e x +d \right )\right ) a^{4}+27 \ln \left (\frac {1-\cos \left (e x +d \right )+\sin \left (e x +d \right )}{\sin \left (e x +d \right )}\right ) \left (\cos ^{3}\left (e x +d \right )\right ) a^{2} b^{2}+6 \ln \left (\frac {1-\cos \left (e x +d \right )+\sin \left (e x +d \right )}{\sin \left (e x +d \right )}\right ) \left (\cos ^{3}\left (e x +d \right )\right ) b^{4}-3 \ln \left (-\frac {\cos \left (e x +d \right )-1+\sin \left (e x +d \right )}{\sin \left (e x +d \right )}\right ) \left (\cos ^{3}\left (e x +d \right )\right ) a^{4}-27 \ln \left (-\frac {\cos \left (e x +d \right )-1+\sin \left (e x +d \right )}{\sin \left (e x +d \right )}\right ) \left (\cos ^{3}\left (e x +d \right )\right ) a^{2} b^{2}-6 \ln \left (-\frac {\cos \left (e x +d \right )-1+\sin \left (e x +d \right )}{\sin \left (e x +d \right )}\right ) \left (\cos ^{3}\left (e x +d \right )\right ) b^{4}+6 \left (\cos ^{3}\left (e x +d \right )\right ) \left (e x +d \right ) a \,b^{3}+22 \sin \left (e x +d \right ) \left (\cos ^{2}\left (e x +d \right )\right ) a^{3} b +18 \sin \left (e x +d \right ) \left (\cos ^{2}\left (e x +d \right )\right ) a \,b^{3}+3 \sin \left (e x +d \right ) \cos \left (e x +d \right ) a^{4}+9 \sin \left (e x +d \right ) \cos \left (e x +d \right ) a^{2} b^{2}+2 a^{3} b \sin \left (e x +d \right )\right ) \left (\frac {\left (b \cos \left (e x +d \right )+a \right )^{2}}{\cos \left (e x +d \right )^{2}}\right )^{\frac {3}{2}}}{6 e \left (b \cos \left (e x +d \right )+a \right )^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.45, size = 440, normalized size = 1.23 \[ \frac {3 \, {\left (4 \, b^{3} \arctan \left (\frac {\sin \left (e x + d\right )}{\cos \left (e x + d\right ) + 1}\right ) + {\left (a^{3} + 6 \, a b^{2}\right )} \log \left (\frac {\sin \left (e x + d\right )}{\cos \left (e x + d\right ) + 1} + 1\right ) - {\left (a^{3} + 6 \, a b^{2}\right )} \log \left (\frac {\sin \left (e x + d\right )}{\cos \left (e x + d\right ) + 1} - 1\right ) - \frac {2 \, {\left (\frac {{\left (a^{3} + 6 \, a^{2} b\right )} \sin \left (e x + d\right )}{\cos \left (e x + d\right ) + 1} + \frac {{\left (a^{3} - 6 \, a^{2} b\right )} \sin \left (e x + d\right )^{3}}{{\left (\cos \left (e x + d\right ) + 1\right )}^{3}}\right )}}{\frac {2 \, \sin \left (e x + d\right )^{2}}{{\left (\cos \left (e x + d\right ) + 1\right )}^{2}} - \frac {\sin \left (e x + d\right )^{4}}{{\left (\cos \left (e x + d\right ) + 1\right )}^{4}} - 1}\right )} a + {\left (3 \, {\left (3 \, a^{2} b + 2 \, b^{3}\right )} \log \left (\frac {\sin \left (e x + d\right )}{\cos \left (e x + d\right ) + 1} + 1\right ) - 3 \, {\left (3 \, a^{2} b + 2 \, b^{3}\right )} \log \left (\frac {\sin \left (e x + d\right )}{\cos \left (e x + d\right ) + 1} - 1\right ) - \frac {2 \, {\left (\frac {3 \, {\left (2 \, a^{3} + 3 \, a^{2} b + 6 \, a b^{2}\right )} \sin \left (e x + d\right )}{\cos \left (e x + d\right ) + 1} - \frac {4 \, {\left (a^{3} + 9 \, a b^{2}\right )} \sin \left (e x + d\right )^{3}}{{\left (\cos \left (e x + d\right ) + 1\right )}^{3}} + \frac {3 \, {\left (2 \, a^{3} - 3 \, a^{2} b + 6 \, a b^{2}\right )} \sin \left (e x + d\right )^{5}}{{\left (\cos \left (e x + d\right ) + 1\right )}^{5}}\right )}}{\frac {3 \, \sin \left (e x + d\right )^{2}}{{\left (\cos \left (e x + d\right ) + 1\right )}^{2}} - \frac {3 \, \sin \left (e x + d\right )^{4}}{{\left (\cos \left (e x + d\right ) + 1\right )}^{4}} + \frac {\sin \left (e x + d\right )^{6}}{{\left (\cos \left (e x + d\right ) + 1\right )}^{6}} - 1}\right )} b}{6 \, e} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \left (a+\frac {b}{\cos \left (d+e\,x\right )}\right )\,{\left (b^2+\frac {a^2}{{\cos \left (d+e\,x\right )}^2}+\frac {2\,a\,b}{\cos \left (d+e\,x\right )}\right )}^{3/2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (a + b \sec {\left (d + e x \right )}\right ) \left (\left (a \sec {\left (d + e x \right )} + b\right )^{2}\right )^{\frac {3}{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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