3.912 \(\int \frac {\cos (x)+\sin (x)}{\sqrt {\cos (x)} \sqrt {\sin (x)}} \, dx\)

Optimal. Leaf size=57 \[ \sqrt {2} \tan ^{-1}\left (\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1\right )-\sqrt {2} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right ) \]

[Out]

-arctan(1-2^(1/2)*sin(x)^(1/2)/cos(x)^(1/2))*2^(1/2)+arctan(1+2^(1/2)*sin(x)^(1/2)/cos(x)^(1/2))*2^(1/2)

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Rubi [B]  time = 0.21, antiderivative size = 243, normalized size of antiderivative = 4.26, number of steps used = 22, number of rules used = 9, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {3107, 2575, 297, 1162, 617, 204, 1165, 628, 2574} \[ \frac {\tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {\cos (x)}}{\sqrt {\sin (x)}}\right )}{\sqrt {2}}-\frac {\tan ^{-1}\left (\frac {\sqrt {2} \sqrt {\cos (x)}}{\sqrt {\sin (x)}}+1\right )}{\sqrt {2}}-\frac {\tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )}{\sqrt {2}}+\frac {\tan ^{-1}\left (\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1\right )}{\sqrt {2}}+\frac {\log \left (\tan (x)-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\tan (x)+\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\cot (x)-\frac {\sqrt {2} \sqrt {\cos (x)}}{\sqrt {\sin (x)}}+1\right )}{2 \sqrt {2}}+\frac {\log \left (\cot (x)+\frac {\sqrt {2} \sqrt {\cos (x)}}{\sqrt {\sin (x)}}+1\right )}{2 \sqrt {2}} \]

Antiderivative was successfully verified.

[In]

Int[(Cos[x] + Sin[x])/(Sqrt[Cos[x]]*Sqrt[Sin[x]]),x]

[Out]

ArcTan[1 - (Sqrt[2]*Sqrt[Cos[x]])/Sqrt[Sin[x]]]/Sqrt[2] - ArcTan[1 + (Sqrt[2]*Sqrt[Cos[x]])/Sqrt[Sin[x]]]/Sqrt
[2] - ArcTan[1 - (Sqrt[2]*Sqrt[Sin[x]])/Sqrt[Cos[x]]]/Sqrt[2] + ArcTan[1 + (Sqrt[2]*Sqrt[Sin[x]])/Sqrt[Cos[x]]
]/Sqrt[2] - Log[1 + Cot[x] - (Sqrt[2]*Sqrt[Cos[x]])/Sqrt[Sin[x]]]/(2*Sqrt[2]) + Log[1 + Cot[x] + (Sqrt[2]*Sqrt
[Cos[x]])/Sqrt[Sin[x]]]/(2*Sqrt[2]) + Log[1 - (Sqrt[2]*Sqrt[Sin[x]])/Sqrt[Cos[x]] + Tan[x]]/(2*Sqrt[2]) - Log[
1 + (Sqrt[2]*Sqrt[Sin[x]])/Sqrt[Cos[x]] + Tan[x]]/(2*Sqrt[2])

Rule 204

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTan[(Rt[-b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[-b, 2]), x] /
; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 297

Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]},
Dist[1/(2*s), Int[(r + s*x^2)/(a + b*x^4), x], x] - Dist[1/(2*s), Int[(r - s*x^2)/(a + b*x^4), x], x]] /; Free
Q[{a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ,
b]]))

Rule 617

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*Simplify[(a*c)/b^2]}, Dist[-2/b, Sub
st[Int[1/(q - x^2), x], x, 1 + (2*c*x)/b], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /;
FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 628

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[(d*Log[RemoveContent[a + b*x +
c*x^2, x]])/b, x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 1162

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[(2*d)/e, 2]}, Dist[e/(2*c), Int[1/S
imp[d/e + q*x + x^2, x], x], x] + Dist[e/(2*c), Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e},
x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]

Rule 1165

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[(-2*d)/e, 2]}, Dist[e/(2*c*q), Int[
(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Dist[e/(2*c*q), Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /
; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]

Rule 2574

Int[(cos[(e_.) + (f_.)*(x_)]*(b_.))^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m_), x_Symbol] :> With[{k = Denomina
tor[m]}, Dist[(k*a*b)/f, Subst[Int[x^(k*(m + 1) - 1)/(a^2 + b^2*x^(2*k)), x], x, (a*Sin[e + f*x])^(1/k)/(b*Cos
[e + f*x])^(1/k)], x]] /; FreeQ[{a, b, e, f}, x] && EqQ[m + n, 0] && GtQ[m, 0] && LtQ[m, 1]

Rule 2575

Int[(cos[(e_.) + (f_.)*(x_)]*(a_.))^(m_)*((b_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> With[{k = Denomina
tor[m]}, -Dist[(k*a*b)/f, Subst[Int[x^(k*(m + 1) - 1)/(a^2 + b^2*x^(2*k)), x], x, (a*Cos[e + f*x])^(1/k)/(b*Si
n[e + f*x])^(1/k)], x]] /; FreeQ[{a, b, e, f}, x] && EqQ[m + n, 0] && GtQ[m, 0] && LtQ[m, 1]

Rule 3107

Int[cos[(c_.) + (d_.)*(x_)]^(m_.)*sin[(c_.) + (d_.)*(x_)]^(n_.)*(cos[(c_.) + (d_.)*(x_)]*(a_.) + (b_.)*sin[(c_
.) + (d_.)*(x_)])^(p_.), x_Symbol] :> Int[ExpandTrig[cos[c + d*x]^m*sin[c + d*x]^n*(a*cos[c + d*x] + b*sin[c +
d*x])^p, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && IGtQ[p, 0]

Rubi steps

\begin {align*} \int \frac {\cos (x)+\sin (x)}{\sqrt {\cos (x)} \sqrt {\sin (x)}} \, dx &=\int \left (\frac {\sqrt {\cos (x)}}{\sqrt {\sin (x)}}+\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right ) \, dx\\ &=\int \frac {\sqrt {\cos (x)}}{\sqrt {\sin (x)}} \, dx+\int \frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}} \, dx\\ &=-\left (2 \operatorname {Subst}\left (\int \frac {x^2}{1+x^4} \, dx,x,\frac {\sqrt {\cos (x)}}{\sqrt {\sin (x)}}\right )\right )+2 \operatorname {Subst}\left (\int \frac {x^2}{1+x^4} \, dx,x,\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )\\ &=\operatorname {Subst}\left (\int \frac {1-x^2}{1+x^4} \, dx,x,\frac {\sqrt {\cos (x)}}{\sqrt {\sin (x)}}\right )-\operatorname {Subst}\left (\int \frac {1-x^2}{1+x^4} \, dx,x,\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )-\operatorname {Subst}\left (\int \frac {1+x^2}{1+x^4} \, dx,x,\frac {\sqrt {\cos (x)}}{\sqrt {\sin (x)}}\right )+\operatorname {Subst}\left (\int \frac {1+x^2}{1+x^4} \, dx,x,\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )\\ &=-\left (\frac {1}{2} \operatorname {Subst}\left (\int \frac {1}{1-\sqrt {2} x+x^2} \, dx,x,\frac {\sqrt {\cos (x)}}{\sqrt {\sin (x)}}\right )\right )+\frac {1}{2} \operatorname {Subst}\left (\int \frac {1}{1-\sqrt {2} x+x^2} \, dx,x,\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )-\frac {1}{2} \operatorname {Subst}\left (\int \frac {1}{1+\sqrt {2} x+x^2} \, dx,x,\frac {\sqrt {\cos (x)}}{\sqrt {\sin (x)}}\right )+\frac {1}{2} \operatorname {Subst}\left (\int \frac {1}{1+\sqrt {2} x+x^2} \, dx,x,\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )-\frac {\operatorname {Subst}\left (\int \frac {\sqrt {2}+2 x}{-1-\sqrt {2} x-x^2} \, dx,x,\frac {\sqrt {\cos (x)}}{\sqrt {\sin (x)}}\right )}{2 \sqrt {2}}+\frac {\operatorname {Subst}\left (\int \frac {\sqrt {2}+2 x}{-1-\sqrt {2} x-x^2} \, dx,x,\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )}{2 \sqrt {2}}-\frac {\operatorname {Subst}\left (\int \frac {\sqrt {2}-2 x}{-1+\sqrt {2} x-x^2} \, dx,x,\frac {\sqrt {\cos (x)}}{\sqrt {\sin (x)}}\right )}{2 \sqrt {2}}+\frac {\operatorname {Subst}\left (\int \frac {\sqrt {2}-2 x}{-1+\sqrt {2} x-x^2} \, dx,x,\frac {\sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )}{2 \sqrt {2}}\\ &=-\frac {\log \left (1+\cot (x)-\frac {\sqrt {2} \sqrt {\cos (x)}}{\sqrt {\sin (x)}}\right )}{2 \sqrt {2}}+\frac {\log \left (1+\cot (x)+\frac {\sqrt {2} \sqrt {\cos (x)}}{\sqrt {\sin (x)}}\right )}{2 \sqrt {2}}+\frac {\log \left (1-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+\tan (x)\right )}{2 \sqrt {2}}-\frac {\log \left (1+\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+\tan (x)\right )}{2 \sqrt {2}}-\frac {\operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt {\cos (x)}}{\sqrt {\sin (x)}}\right )}{\sqrt {2}}+\frac {\operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt {\cos (x)}}{\sqrt {\sin (x)}}\right )}{\sqrt {2}}+\frac {\operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )}{\sqrt {2}}-\frac {\operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )}{\sqrt {2}}\\ &=\frac {\tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {\cos (x)}}{\sqrt {\sin (x)}}\right )}{\sqrt {2}}-\frac {\tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt {\cos (x)}}{\sqrt {\sin (x)}}\right )}{\sqrt {2}}-\frac {\tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )}{\sqrt {2}}+\frac {\tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}\right )}{\sqrt {2}}-\frac {\log \left (1+\cot (x)-\frac {\sqrt {2} \sqrt {\cos (x)}}{\sqrt {\sin (x)}}\right )}{2 \sqrt {2}}+\frac {\log \left (1+\cot (x)+\frac {\sqrt {2} \sqrt {\cos (x)}}{\sqrt {\sin (x)}}\right )}{2 \sqrt {2}}+\frac {\log \left (1-\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+\tan (x)\right )}{2 \sqrt {2}}-\frac {\log \left (1+\frac {\sqrt {2} \sqrt {\sin (x)}}{\sqrt {\cos (x)}}+\tan (x)\right )}{2 \sqrt {2}}\\ \end {align*}

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Mathematica [C]  time = 0.06, size = 68, normalized size = 1.19 \[ \frac {2 \sqrt {\sin (x)} \sqrt [4]{\cos ^2(x)} \left (\sin (x) \sqrt {\cos ^2(x)} \, _2F_1\left (\frac {3}{4},\frac {3}{4};\frac {7}{4};\sin ^2(x)\right )+3 \cos (x) \, _2F_1\left (\frac {1}{4},\frac {1}{4};\frac {5}{4};\sin ^2(x)\right )\right )}{3 \cos ^{\frac {3}{2}}(x)} \]

Antiderivative was successfully verified.

[In]

Integrate[(Cos[x] + Sin[x])/(Sqrt[Cos[x]]*Sqrt[Sin[x]]),x]

[Out]

(2*(Cos[x]^2)^(1/4)*Sqrt[Sin[x]]*(3*Cos[x]*Hypergeometric2F1[1/4, 1/4, 5/4, Sin[x]^2] + Sqrt[Cos[x]^2]*Hyperge
ometric2F1[3/4, 3/4, 7/4, Sin[x]^2]*Sin[x]))/(3*Cos[x]^(3/2))

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fricas [B]  time = 0.98, size = 85, normalized size = 1.49 \[ -\frac {1}{4} \, \sqrt {2} \arctan \left (-\frac {{\left (32 \, \sqrt {2} \cos \relax (x)^{4} - 32 \, \sqrt {2} \cos \relax (x)^{2} + 16 \, \sqrt {2} \cos \relax (x) \sin \relax (x) - \sqrt {2}\right )} \sqrt {\cos \relax (x)} \sqrt {\sin \relax (x)}}{8 \, {\left (4 \, \cos \relax (x)^{5} - 3 \, \cos \relax (x)^{3} - {\left (4 \, \cos \relax (x)^{4} - 5 \, \cos \relax (x)^{2}\right )} \sin \relax (x) - \cos \relax (x)\right )}}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((cos(x)+sin(x))/cos(x)^(1/2)/sin(x)^(1/2),x, algorithm="fricas")

[Out]

-1/4*sqrt(2)*arctan(-1/8*(32*sqrt(2)*cos(x)^4 - 32*sqrt(2)*cos(x)^2 + 16*sqrt(2)*cos(x)*sin(x) - sqrt(2))*sqrt
(cos(x))*sqrt(sin(x))/(4*cos(x)^5 - 3*cos(x)^3 - (4*cos(x)^4 - 5*cos(x)^2)*sin(x) - cos(x)))

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cos \relax (x) + \sin \relax (x)}{\sqrt {\cos \relax (x)} \sqrt {\sin \relax (x)}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((cos(x)+sin(x))/cos(x)^(1/2)/sin(x)^(1/2),x, algorithm="giac")

[Out]

integrate((cos(x) + sin(x))/(sqrt(cos(x))*sqrt(sin(x))), x)

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maple [C]  time = 0.26, size = 134, normalized size = 2.35 \[ \frac {\sqrt {\frac {1-\cos \relax (x )+\sin \relax (x )}{\sin \relax (x )}}\, \sqrt {2}\, \sqrt {\frac {\cos \relax (x )-1+\sin \relax (x )}{\sin \relax (x )}}\, \sqrt {\frac {-1+\cos \relax (x )}{\sin \relax (x )}}\, \left (\sin ^{\frac {3}{2}}\relax (x )\right ) \left (i \EllipticPi \left (\sqrt {\frac {1-\cos \relax (x )+\sin \relax (x )}{\sin \relax (x )}}, \frac {1}{2}+\frac {i}{2}, \frac {\sqrt {2}}{2}\right )-i \EllipticPi \left (\sqrt {\frac {1-\cos \relax (x )+\sin \relax (x )}{\sin \relax (x )}}, \frac {1}{2}-\frac {i}{2}, \frac {\sqrt {2}}{2}\right )+\EllipticF \left (\sqrt {\frac {1-\cos \relax (x )+\sin \relax (x )}{\sin \relax (x )}}, \frac {\sqrt {2}}{2}\right )\right )}{\sqrt {\cos \relax (x )}\, \left (-1+\cos \relax (x )\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((cos(x)+sin(x))/cos(x)^(1/2)/sin(x)^(1/2),x)

[Out]

((1-cos(x)+sin(x))/sin(x))^(1/2)*2^(1/2)*((cos(x)-1+sin(x))/sin(x))^(1/2)*((-1+cos(x))/sin(x))^(1/2)*sin(x)^(3
/2)*(I*EllipticPi(((1-cos(x)+sin(x))/sin(x))^(1/2),1/2+1/2*I,1/2*2^(1/2))-I*EllipticPi(((1-cos(x)+sin(x))/sin(
x))^(1/2),1/2-1/2*I,1/2*2^(1/2))+EllipticF(((1-cos(x)+sin(x))/sin(x))^(1/2),1/2*2^(1/2)))/cos(x)^(1/2)/(-1+cos
(x))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cos \relax (x) + \sin \relax (x)}{\sqrt {\cos \relax (x)} \sqrt {\sin \relax (x)}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((cos(x)+sin(x))/cos(x)^(1/2)/sin(x)^(1/2),x, algorithm="maxima")

[Out]

integrate((cos(x) + sin(x))/(sqrt(cos(x))*sqrt(sin(x))), x)

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mupad [B]  time = 4.62, size = 51, normalized size = 0.89 \[ -\frac {2\,\sqrt {\cos \relax (x)}\,{\sin \relax (x)}^{3/2}\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{4},\frac {1}{4};\ \frac {5}{4};\ {\cos \relax (x)}^2\right )}{{\left ({\sin \relax (x)}^2\right )}^{3/4}}-\frac {2\,{\cos \relax (x)}^{3/2}\,\sqrt {\sin \relax (x)}\,{{}}_2{\mathrm {F}}_1\left (\frac {3}{4},\frac {3}{4};\ \frac {7}{4};\ {\cos \relax (x)}^2\right )}{3\,{\left ({\sin \relax (x)}^2\right )}^{1/4}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((cos(x) + sin(x))/(cos(x)^(1/2)*sin(x)^(1/2)),x)

[Out]

- (2*cos(x)^(1/2)*sin(x)^(3/2)*hypergeom([1/4, 1/4], 5/4, cos(x)^2))/(sin(x)^2)^(3/4) - (2*cos(x)^(3/2)*sin(x)
^(1/2)*hypergeom([3/4, 3/4], 7/4, cos(x)^2))/(3*(sin(x)^2)^(1/4))

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sin {\relax (x )} + \cos {\relax (x )}}{\sqrt {\sin {\relax (x )}} \sqrt {\cos {\relax (x )}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((cos(x)+sin(x))/cos(x)**(1/2)/sin(x)**(1/2),x)

[Out]

Integral((sin(x) + cos(x))/(sqrt(sin(x))*sqrt(cos(x))), x)

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