Optimal. Leaf size=60 \[ \frac {1}{8} \sqrt {1-x} x^{3/2}+\frac {1}{2} x^2 \sin ^{-1}\left (\sqrt {x}\right )+\frac {3}{16} \sqrt {1-x} \sqrt {x}+\frac {3}{32} \sin ^{-1}(1-2 x) \]
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Rubi [A] time = 0.02, antiderivative size = 60, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.750, Rules used = {4842, 12, 50, 53, 619, 216} \[ \frac {1}{8} \sqrt {1-x} x^{3/2}+\frac {1}{2} x^2 \sin ^{-1}\left (\sqrt {x}\right )+\frac {3}{16} \sqrt {1-x} \sqrt {x}+\frac {3}{32} \sin ^{-1}(1-2 x) \]
Antiderivative was successfully verified.
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Rule 12
Rule 50
Rule 53
Rule 216
Rule 619
Rule 4842
Rubi steps
\begin {align*} \int x \sin ^{-1}\left (\sqrt {x}\right ) \, dx &=\frac {1}{2} x^2 \sin ^{-1}\left (\sqrt {x}\right )-\frac {1}{2} \int \frac {x^{3/2}}{2 \sqrt {1-x}} \, dx\\ &=\frac {1}{2} x^2 \sin ^{-1}\left (\sqrt {x}\right )-\frac {1}{4} \int \frac {x^{3/2}}{\sqrt {1-x}} \, dx\\ &=\frac {1}{8} \sqrt {1-x} x^{3/2}+\frac {1}{2} x^2 \sin ^{-1}\left (\sqrt {x}\right )-\frac {3}{16} \int \frac {\sqrt {x}}{\sqrt {1-x}} \, dx\\ &=\frac {3}{16} \sqrt {1-x} \sqrt {x}+\frac {1}{8} \sqrt {1-x} x^{3/2}+\frac {1}{2} x^2 \sin ^{-1}\left (\sqrt {x}\right )-\frac {3}{32} \int \frac {1}{\sqrt {1-x} \sqrt {x}} \, dx\\ &=\frac {3}{16} \sqrt {1-x} \sqrt {x}+\frac {1}{8} \sqrt {1-x} x^{3/2}+\frac {1}{2} x^2 \sin ^{-1}\left (\sqrt {x}\right )-\frac {3}{32} \int \frac {1}{\sqrt {x-x^2}} \, dx\\ &=\frac {3}{16} \sqrt {1-x} \sqrt {x}+\frac {1}{8} \sqrt {1-x} x^{3/2}+\frac {1}{2} x^2 \sin ^{-1}\left (\sqrt {x}\right )+\frac {3}{32} \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-x^2}} \, dx,x,1-2 x\right )\\ &=\frac {3}{16} \sqrt {1-x} \sqrt {x}+\frac {1}{8} \sqrt {1-x} x^{3/2}+\frac {3}{32} \sin ^{-1}(1-2 x)+\frac {1}{2} x^2 \sin ^{-1}\left (\sqrt {x}\right )\\ \end {align*}
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Mathematica [A] time = 0.03, size = 47, normalized size = 0.78 \[ \frac {1}{16} \left (2 \sqrt {1-x} x^{3/2}+\left (8 x^2-3\right ) \sin ^{-1}\left (\sqrt {x}\right )+3 \sqrt {-((x-1) x)}\right ) \]
Antiderivative was successfully verified.
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fricas [A] time = 0.43, size = 31, normalized size = 0.52 \[ \frac {1}{16} \, {\left (2 \, x + 3\right )} \sqrt {x} \sqrt {-x + 1} + \frac {1}{16} \, {\left (8 \, x^{2} - 3\right )} \arcsin \left (\sqrt {x}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.17, size = 50, normalized size = 0.83 \[ \frac {1}{2} \, {\left (x - 1\right )}^{2} \arcsin \left (\sqrt {x}\right ) - \frac {1}{8} \, \sqrt {x} {\left (-x + 1\right )}^{\frac {3}{2}} + {\left (x - 1\right )} \arcsin \left (\sqrt {x}\right ) + \frac {5}{16} \, \sqrt {x} \sqrt {-x + 1} + \frac {5}{16} \, \arcsin \left (\sqrt {x}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.00, size = 41, normalized size = 0.68 \[ \frac {x^{2} \arcsin \left (\sqrt {x}\right )}{2}+\frac {x^{\frac {3}{2}} \sqrt {1-x}}{8}+\frac {3 \sqrt {1-x}\, \sqrt {x}}{16}-\frac {3 \arcsin \left (\sqrt {x}\right )}{16} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.40, size = 40, normalized size = 0.67 \[ \frac {1}{2} \, x^{2} \arcsin \left (\sqrt {x}\right ) + \frac {1}{8} \, x^{\frac {3}{2}} \sqrt {-x + 1} + \frac {3}{16} \, \sqrt {x} \sqrt {-x + 1} - \frac {3}{16} \, \arcsin \left (\sqrt {x}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.02 \[ \int x\,\mathrm {asin}\left (\sqrt {x}\right ) \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 3.83, size = 58, normalized size = 0.97 \[ \frac {x^{2} \operatorname {asin}{\left (\sqrt {x} \right )}}{2} - \frac {\begin {cases} \frac {\sqrt {x} \left (1 - 2 x\right ) \sqrt {1 - x}}{8} - \frac {\sqrt {x} \sqrt {1 - x}}{2} + \frac {3 \operatorname {asin}{\left (\sqrt {x} \right )}}{8} & \text {for}\: x \geq 0 \wedge x < 1 \end {cases}}{2} \]
Verification of antiderivative is not currently implemented for this CAS.
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