3.105 \(\int \frac {\tan ^{-1}(c+(i+c) \coth (a+b x))}{x} \, dx\)

Optimal. Leaf size=22 \[ \text {Int}\left (\frac {\tan ^{-1}(c+(c+i) \coth (a+b x))}{x},x\right ) \]

[Out]

CannotIntegrate(arctan(c+(I+c)*coth(b*x+a))/x,x)

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Rubi [A]  time = 0.11, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\tan ^{-1}(c+(i+c) \coth (a+b x))}{x} \, dx \]

Verification is Not applicable to the result.

[In]

Int[ArcTan[c + (I + c)*Coth[a + b*x]]/x,x]

[Out]

Defer[Int][ArcTan[c + (I + c)*Coth[a + b*x]]/x, x]

Rubi steps

\begin {align*} \int \frac {\tan ^{-1}(c+(i+c) \coth (a+b x))}{x} \, dx &=\int \frac {\tan ^{-1}(c+(i+c) \coth (a+b x))}{x} \, dx\\ \end {align*}

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Mathematica [A]  time = 4.13, size = 0, normalized size = 0.00 \[ \int \frac {\tan ^{-1}(c+(i+c) \coth (a+b x))}{x} \, dx \]

Verification is Not applicable to the result.

[In]

Integrate[ArcTan[c + (I + c)*Coth[a + b*x]]/x,x]

[Out]

Integrate[ArcTan[c + (I + c)*Coth[a + b*x]]/x, x]

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fricas [A]  time = 0.46, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {i \, \log \left (-\frac {{\left (c + i\right )} e^{\left (2 \, b x + 2 \, a\right )}}{c e^{\left (2 \, b x + 2 \, a\right )} + i}\right )}{2 \, x}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arctan(c+(I+c)*coth(b*x+a))/x,x, algorithm="fricas")

[Out]

integral(1/2*I*log(-(c + I)*e^(2*b*x + 2*a)/(c*e^(2*b*x + 2*a) + I))/x, x)

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giac [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\arctan \left ({\left (c + i\right )} \coth \left (b x + a\right ) + c\right )}{x}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arctan(c+(I+c)*coth(b*x+a))/x,x, algorithm="giac")

[Out]

integrate(arctan((c + I)*coth(b*x + a) + c)/x, x)

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maple [A]  time = 2.01, size = 0, normalized size = 0.00 \[ \int \frac {\arctan \left (c +\left (i+c \right ) \coth \left (b x +a \right )\right )}{x}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(arctan(c+(I+c)*coth(b*x+a))/x,x)

[Out]

int(arctan(c+(I+c)*coth(b*x+a))/x,x)

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maxima [A]  time = 0.00, size = 0, normalized size = 0.00 \[ i \, b x + \frac {1}{2} \, \pi \log \relax (x) - \frac {1}{4} \, {\left (4 \, \pi - 4 i \, a - 2 \, \arctan \relax (c) - i \, \log \left (c^{2} + 1\right )\right )} \log \relax (x) - \frac {1}{2} \, \int \frac {\arctan \left (c e^{\left (2 \, b x + 2 \, a\right )}\right )}{x}\,{d x} - \frac {1}{4} i \, \int \frac {\log \left (c^{2} e^{\left (4 \, b x + 4 \, a\right )} + 1\right )}{x}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(arctan(c+(I+c)*coth(b*x+a))/x,x, algorithm="maxima")

[Out]

I*b*x + 1/2*pi*log(x) - 1/4*(4*pi - 4*I*a - 2*arctan(c) - I*log(c^2 + 1))*log(x) - 1/2*integrate(arctan(c*e^(2
*b*x + 2*a))/x, x) - 1/4*I*integrate(log(c^2*e^(4*b*x + 4*a) + 1)/x, x)

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mupad [A]  time = 0.00, size = -1, normalized size = -0.05 \[ \int \frac {\mathrm {atan}\left (c+\mathrm {coth}\left (a+b\,x\right )\,\left (c+1{}\mathrm {i}\right )\right )}{x} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(atan(c + coth(a + b*x)*(c + 1i))/x,x)

[Out]

int(atan(c + coth(a + b*x)*(c + 1i))/x, x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(atan(c+(I+c)*coth(b*x+a))/x,x)

[Out]

Timed out

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