Optimal. Leaf size=74 \[ -\frac {2 (a A+b B) \tanh ^{-1}\left (\frac {b-a \tanh \left (\frac {x}{2}\right )}{\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2}}-\frac {\cosh (x) (A b-a B)}{\left (a^2+b^2\right ) (a+b \sinh (x))} \]
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Rubi [A] time = 0.08, antiderivative size = 74, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {2754, 12, 2660, 618, 206} \[ -\frac {2 (a A+b B) \tanh ^{-1}\left (\frac {b-a \tanh \left (\frac {x}{2}\right )}{\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2}}-\frac {\cosh (x) (A b-a B)}{\left (a^2+b^2\right ) (a+b \sinh (x))} \]
Antiderivative was successfully verified.
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Rule 12
Rule 206
Rule 618
Rule 2660
Rule 2754
Rubi steps
\begin {align*} \int \frac {A+B \sinh (x)}{(a+b \sinh (x))^2} \, dx &=-\frac {(A b-a B) \cosh (x)}{\left (a^2+b^2\right ) (a+b \sinh (x))}-\frac {\int \frac {-a A-b B}{a+b \sinh (x)} \, dx}{a^2+b^2}\\ &=-\frac {(A b-a B) \cosh (x)}{\left (a^2+b^2\right ) (a+b \sinh (x))}+\frac {(a A+b B) \int \frac {1}{a+b \sinh (x)} \, dx}{a^2+b^2}\\ &=-\frac {(A b-a B) \cosh (x)}{\left (a^2+b^2\right ) (a+b \sinh (x))}+\frac {(2 (a A+b B)) \operatorname {Subst}\left (\int \frac {1}{a+2 b x-a x^2} \, dx,x,\tanh \left (\frac {x}{2}\right )\right )}{a^2+b^2}\\ &=-\frac {(A b-a B) \cosh (x)}{\left (a^2+b^2\right ) (a+b \sinh (x))}-\frac {(4 (a A+b B)) \operatorname {Subst}\left (\int \frac {1}{4 \left (a^2+b^2\right )-x^2} \, dx,x,2 b-2 a \tanh \left (\frac {x}{2}\right )\right )}{a^2+b^2}\\ &=-\frac {2 (a A+b B) \tanh ^{-1}\left (\frac {b-a \tanh \left (\frac {x}{2}\right )}{\sqrt {a^2+b^2}}\right )}{\left (a^2+b^2\right )^{3/2}}-\frac {(A b-a B) \cosh (x)}{\left (a^2+b^2\right ) (a+b \sinh (x))}\\ \end {align*}
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Mathematica [A] time = 0.15, size = 82, normalized size = 1.11 \[ \frac {\frac {2 (a A+b B) \tan ^{-1}\left (\frac {b-a \tanh \left (\frac {x}{2}\right )}{\sqrt {-a^2-b^2}}\right )}{\sqrt {-a^2-b^2}}+\frac {\cosh (x) (a B-A b)}{a+b \sinh (x)}}{a^2+b^2} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.60, size = 444, normalized size = 6.00 \[ -\frac {2 \, B a^{3} b - 2 \, A a^{2} b^{2} + 2 \, B a b^{3} - 2 \, A b^{4} - {\left (A a b^{2} + B b^{3} - {\left (A a b^{2} + B b^{3}\right )} \cosh \relax (x)^{2} - {\left (A a b^{2} + B b^{3}\right )} \sinh \relax (x)^{2} - 2 \, {\left (A a^{2} b + B a b^{2}\right )} \cosh \relax (x) - 2 \, {\left (A a^{2} b + B a b^{2} + {\left (A a b^{2} + B b^{3}\right )} \cosh \relax (x)\right )} \sinh \relax (x)\right )} \sqrt {a^{2} + b^{2}} \log \left (\frac {b^{2} \cosh \relax (x)^{2} + b^{2} \sinh \relax (x)^{2} + 2 \, a b \cosh \relax (x) + 2 \, a^{2} + b^{2} + 2 \, {\left (b^{2} \cosh \relax (x) + a b\right )} \sinh \relax (x) - 2 \, \sqrt {a^{2} + b^{2}} {\left (b \cosh \relax (x) + b \sinh \relax (x) + a\right )}}{b \cosh \relax (x)^{2} + b \sinh \relax (x)^{2} + 2 \, a \cosh \relax (x) + 2 \, {\left (b \cosh \relax (x) + a\right )} \sinh \relax (x) - b}\right ) - 2 \, {\left (B a^{4} - A a^{3} b + B a^{2} b^{2} - A a b^{3}\right )} \cosh \relax (x) - 2 \, {\left (B a^{4} - A a^{3} b + B a^{2} b^{2} - A a b^{3}\right )} \sinh \relax (x)}{a^{4} b^{2} + 2 \, a^{2} b^{4} + b^{6} - {\left (a^{4} b^{2} + 2 \, a^{2} b^{4} + b^{6}\right )} \cosh \relax (x)^{2} - {\left (a^{4} b^{2} + 2 \, a^{2} b^{4} + b^{6}\right )} \sinh \relax (x)^{2} - 2 \, {\left (a^{5} b + 2 \, a^{3} b^{3} + a b^{5}\right )} \cosh \relax (x) - 2 \, {\left (a^{5} b + 2 \, a^{3} b^{3} + a b^{5} + {\left (a^{4} b^{2} + 2 \, a^{2} b^{4} + b^{6}\right )} \cosh \relax (x)\right )} \sinh \relax (x)} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.17, size = 119, normalized size = 1.61 \[ \frac {{\left (A a + B b\right )} \log \left (\frac {{\left | 2 \, b e^{x} + 2 \, a - 2 \, \sqrt {a^{2} + b^{2}} \right |}}{{\left | 2 \, b e^{x} + 2 \, a + 2 \, \sqrt {a^{2} + b^{2}} \right |}}\right )}{{\left (a^{2} + b^{2}\right )}^{\frac {3}{2}}} - \frac {2 \, {\left (B a^{2} e^{x} - A a b e^{x} - B a b + A b^{2}\right )}}{{\left (a^{2} b + b^{3}\right )} {\left (b e^{\left (2 \, x\right )} + 2 \, a e^{x} - b\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.04, size = 113, normalized size = 1.53 \[ -\frac {2 \left (-\frac {b \left (A b -a B \right ) \tanh \left (\frac {x}{2}\right )}{a \left (a^{2}+b^{2}\right )}-\frac {A b -a B}{a^{2}+b^{2}}\right )}{a \left (\tanh ^{2}\left (\frac {x}{2}\right )\right )-2 \tanh \left (\frac {x}{2}\right ) b -a}+\frac {2 \left (A a +b B \right ) \arctanh \left (\frac {2 a \tanh \left (\frac {x}{2}\right )-2 b}{2 \sqrt {a^{2}+b^{2}}}\right )}{\left (a^{2}+b^{2}\right )^{\frac {3}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.42, size = 229, normalized size = 3.09 \[ A {\left (\frac {a \log \left (\frac {b e^{\left (-x\right )} - a - \sqrt {a^{2} + b^{2}}}{b e^{\left (-x\right )} - a + \sqrt {a^{2} + b^{2}}}\right )}{{\left (a^{2} + b^{2}\right )}^{\frac {3}{2}}} - \frac {2 \, {\left (a e^{\left (-x\right )} + b\right )}}{a^{2} b + b^{3} + 2 \, {\left (a^{3} + a b^{2}\right )} e^{\left (-x\right )} - {\left (a^{2} b + b^{3}\right )} e^{\left (-2 \, x\right )}}\right )} + B {\left (\frac {b \log \left (\frac {b e^{\left (-x\right )} - a - \sqrt {a^{2} + b^{2}}}{b e^{\left (-x\right )} - a + \sqrt {a^{2} + b^{2}}}\right )}{{\left (a^{2} + b^{2}\right )}^{\frac {3}{2}}} + \frac {2 \, {\left (a^{2} e^{\left (-x\right )} + a b\right )}}{a^{2} b^{2} + b^{4} + 2 \, {\left (a^{3} b + a b^{3}\right )} e^{\left (-x\right )} - {\left (a^{2} b^{2} + b^{4}\right )} e^{\left (-2 \, x\right )}}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.88, size = 223, normalized size = 3.01 \[ \frac {\ln \left (\frac {2\,\left (b-a\,{\mathrm {e}}^x\right )\,\left (A\,a+B\,b\right )}{b\,{\left (a^2+b^2\right )}^{3/2}}-\frac {2\,{\mathrm {e}}^x\,\left (A\,a+B\,b\right )}{a^2\,b+b^3}\right )\,\left (A\,a+B\,b\right )}{{\left (a^2+b^2\right )}^{3/2}}-\frac {\ln \left (-\frac {2\,{\mathrm {e}}^x\,\left (A\,a+B\,b\right )}{a^2\,b+b^3}-\frac {2\,\left (b-a\,{\mathrm {e}}^x\right )\,\left (A\,a+B\,b\right )}{b\,{\left (a^2+b^2\right )}^{3/2}}\right )\,\left (A\,a+B\,b\right )}{{\left (a^2+b^2\right )}^{3/2}}-\frac {\frac {2\,\left (A\,b^3-B\,a\,b^2\right )}{b\,\left (a^2\,b+b^3\right )}+\frac {2\,{\mathrm {e}}^x\,\left (B\,a^2\,b^2-A\,a\,b^3\right )}{b^2\,\left (a^2\,b+b^3\right )}}{2\,a\,{\mathrm {e}}^x-b+b\,{\mathrm {e}}^{2\,x}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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