Optimal. Leaf size=136 \[ \frac {b \left (a^2-3 b^2\right )}{2 \left (a^2+b^2\right )^2 (a+b \sinh (x))}+\frac {\text {sech}^2(x) (a \sinh (x)+b)}{2 \left (a^2+b^2\right ) (a+b \sinh (x))}+\frac {4 a b^3 \log (a+b \sinh (x))}{\left (a^2+b^2\right )^3}-\frac {4 a b^3 \log (\cosh (x))}{\left (a^2+b^2\right )^3}+\frac {\left (a^4+6 a^2 b^2-3 b^4\right ) \tan ^{-1}(\sinh (x))}{2 \left (a^2+b^2\right )^3} \]
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Rubi [A] time = 0.16, antiderivative size = 136, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.462, Rules used = {2668, 741, 801, 635, 203, 260} \[ \frac {b \left (a^2-3 b^2\right )}{2 \left (a^2+b^2\right )^2 (a+b \sinh (x))}+\frac {4 a b^3 \log (a+b \sinh (x))}{\left (a^2+b^2\right )^3}+\frac {\left (6 a^2 b^2+a^4-3 b^4\right ) \tan ^{-1}(\sinh (x))}{2 \left (a^2+b^2\right )^3}-\frac {4 a b^3 \log (\cosh (x))}{\left (a^2+b^2\right )^3}+\frac {\text {sech}^2(x) (a \sinh (x)+b)}{2 \left (a^2+b^2\right ) (a+b \sinh (x))} \]
Antiderivative was successfully verified.
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Rule 203
Rule 260
Rule 635
Rule 741
Rule 801
Rule 2668
Rubi steps
\begin {align*} \int \frac {\text {sech}^3(x)}{(a+b \sinh (x))^2} \, dx &=b^3 \operatorname {Subst}\left (\int \frac {1}{(a+x)^2 \left (-b^2-x^2\right )^2} \, dx,x,b \sinh (x)\right )\\ &=\frac {\text {sech}^2(x) (b+a \sinh (x))}{2 \left (a^2+b^2\right ) (a+b \sinh (x))}-\frac {b \operatorname {Subst}\left (\int \frac {a^2+3 b^2+2 a x}{(a+x)^2 \left (-b^2-x^2\right )} \, dx,x,b \sinh (x)\right )}{2 \left (a^2+b^2\right )}\\ &=\frac {\text {sech}^2(x) (b+a \sinh (x))}{2 \left (a^2+b^2\right ) (a+b \sinh (x))}-\frac {b \operatorname {Subst}\left (\int \left (\frac {a^2-3 b^2}{\left (a^2+b^2\right ) (a+x)^2}-\frac {8 a b^2}{\left (a^2+b^2\right )^2 (a+x)}+\frac {-a^4-6 a^2 b^2+3 b^4+8 a b^2 x}{\left (a^2+b^2\right )^2 \left (b^2+x^2\right )}\right ) \, dx,x,b \sinh (x)\right )}{2 \left (a^2+b^2\right )}\\ &=\frac {4 a b^3 \log (a+b \sinh (x))}{\left (a^2+b^2\right )^3}+\frac {b \left (a^2-3 b^2\right )}{2 \left (a^2+b^2\right )^2 (a+b \sinh (x))}+\frac {\text {sech}^2(x) (b+a \sinh (x))}{2 \left (a^2+b^2\right ) (a+b \sinh (x))}-\frac {b \operatorname {Subst}\left (\int \frac {-a^4-6 a^2 b^2+3 b^4+8 a b^2 x}{b^2+x^2} \, dx,x,b \sinh (x)\right )}{2 \left (a^2+b^2\right )^3}\\ &=\frac {4 a b^3 \log (a+b \sinh (x))}{\left (a^2+b^2\right )^3}+\frac {b \left (a^2-3 b^2\right )}{2 \left (a^2+b^2\right )^2 (a+b \sinh (x))}+\frac {\text {sech}^2(x) (b+a \sinh (x))}{2 \left (a^2+b^2\right ) (a+b \sinh (x))}-\frac {\left (4 a b^3\right ) \operatorname {Subst}\left (\int \frac {x}{b^2+x^2} \, dx,x,b \sinh (x)\right )}{\left (a^2+b^2\right )^3}+\frac {\left (b \left (a^4+6 a^2 b^2-3 b^4\right )\right ) \operatorname {Subst}\left (\int \frac {1}{b^2+x^2} \, dx,x,b \sinh (x)\right )}{2 \left (a^2+b^2\right )^3}\\ &=\frac {\left (a^4+6 a^2 b^2-3 b^4\right ) \tan ^{-1}(\sinh (x))}{2 \left (a^2+b^2\right )^3}-\frac {4 a b^3 \log (\cosh (x))}{\left (a^2+b^2\right )^3}+\frac {4 a b^3 \log (a+b \sinh (x))}{\left (a^2+b^2\right )^3}+\frac {b \left (a^2-3 b^2\right )}{2 \left (a^2+b^2\right )^2 (a+b \sinh (x))}+\frac {\text {sech}^2(x) (b+a \sinh (x))}{2 \left (a^2+b^2\right ) (a+b \sinh (x))}\\ \end {align*}
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Mathematica [A] time = 2.44, size = 260, normalized size = 1.91 \[ -\frac {\frac {b \left (\frac {2 a \left (a^2+b^2\right ) \left (\left (\sqrt {-b^2}-a\right ) \log \left (\sqrt {-b^2}-b \sinh (x)\right )-2 \sqrt {-b^2} \log (a+b \sinh (x))+\left (a+\sqrt {-b^2}\right ) \log \left (\sqrt {-b^2}+b \sinh (x)\right )\right )}{\sqrt {-b^2}}+\left (3 b^2-a^2\right ) \left (\frac {2 \left (a^2+b^2\right )}{a+b \sinh (x)}+\left (\frac {b^2-a^2}{\sqrt {-b^2}}+2 a\right ) \log \left (\sqrt {-b^2}-b \sinh (x)\right )+\left (\frac {a^2-b^2}{\sqrt {-b^2}}+2 a\right ) \log \left (\sqrt {-b^2}+b \sinh (x)\right )-4 a \log (a+b \sinh (x))\right )\right )}{\left (a^2+b^2\right )^2}-\frac {2 \text {sech}^2(x) (a \sinh (x)+b)}{a+b \sinh (x)}}{4 \left (a^2+b^2\right )} \]
Antiderivative was successfully verified.
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fricas [B] time = 1.71, size = 2615, normalized size = 19.23 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.18, size = 295, normalized size = 2.17 \[ \frac {4 \, a b^{4} \log \left ({\left | -b {\left (e^{\left (-x\right )} - e^{x}\right )} + 2 \, a \right |}\right )}{a^{6} b + 3 \, a^{4} b^{3} + 3 \, a^{2} b^{5} + b^{7}} - \frac {2 \, a b^{3} \log \left ({\left (e^{\left (-x\right )} - e^{x}\right )}^{2} + 4\right )}{a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}} + \frac {{\left (\pi + 2 \, \arctan \left (\frac {1}{2} \, {\left (e^{\left (2 \, x\right )} - 1\right )} e^{\left (-x\right )}\right )\right )} {\left (a^{4} + 6 \, a^{2} b^{2} - 3 \, b^{4}\right )}}{4 \, {\left (a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}\right )}} - \frac {a^{2} b {\left (e^{\left (-x\right )} - e^{x}\right )}^{2} - 3 \, b^{3} {\left (e^{\left (-x\right )} - e^{x}\right )}^{2} - 2 \, a^{3} {\left (e^{\left (-x\right )} - e^{x}\right )} - 2 \, a b^{2} {\left (e^{\left (-x\right )} - e^{x}\right )} + 8 \, a^{2} b - 8 \, b^{3}}{{\left (a^{4} + 2 \, a^{2} b^{2} + b^{4}\right )} {\left (b {\left (e^{\left (-x\right )} - e^{x}\right )}^{3} - 2 \, a {\left (e^{\left (-x\right )} - e^{x}\right )}^{2} + 4 \, b {\left (e^{\left (-x\right )} - e^{x}\right )} - 8 \, a\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.10, size = 548, normalized size = 4.03 \[ -\frac {2 b^{4} a \tanh \left (\frac {x}{2}\right )}{\left (a^{2}+b^{2}\right )^{3} \left (a \left (\tanh ^{2}\left (\frac {x}{2}\right )\right )-2 \tanh \left (\frac {x}{2}\right ) b -a \right )}-\frac {2 b^{6} \tanh \left (\frac {x}{2}\right )}{\left (a^{2}+b^{2}\right )^{3} a \left (a \left (\tanh ^{2}\left (\frac {x}{2}\right )\right )-2 \tanh \left (\frac {x}{2}\right ) b -a \right )}+\frac {4 b^{3} a \ln \left (a \left (\tanh ^{2}\left (\frac {x}{2}\right )\right )-2 \tanh \left (\frac {x}{2}\right ) b -a \right )}{\left (a^{2}+b^{2}\right )^{3}}-\frac {\left (\tanh ^{3}\left (\frac {x}{2}\right )\right ) a^{4}}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) \left (a^{2}+b^{2}\right ) \left (\tanh ^{2}\left (\frac {x}{2}\right )+1\right )^{2}}+\frac {\left (\tanh ^{3}\left (\frac {x}{2}\right )\right ) b^{4}}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) \left (a^{2}+b^{2}\right ) \left (\tanh ^{2}\left (\frac {x}{2}\right )+1\right )^{2}}-\frac {4 \left (\tanh ^{2}\left (\frac {x}{2}\right )\right ) a^{3} b}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) \left (a^{2}+b^{2}\right ) \left (\tanh ^{2}\left (\frac {x}{2}\right )+1\right )^{2}}-\frac {4 \left (\tanh ^{2}\left (\frac {x}{2}\right )\right ) a \,b^{3}}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) \left (a^{2}+b^{2}\right ) \left (\tanh ^{2}\left (\frac {x}{2}\right )+1\right )^{2}}+\frac {\tanh \left (\frac {x}{2}\right ) a^{4}}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) \left (a^{2}+b^{2}\right ) \left (\tanh ^{2}\left (\frac {x}{2}\right )+1\right )^{2}}-\frac {\tanh \left (\frac {x}{2}\right ) b^{4}}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) \left (a^{2}+b^{2}\right ) \left (\tanh ^{2}\left (\frac {x}{2}\right )+1\right )^{2}}-\frac {4 a \,b^{3} \ln \left (\tanh ^{2}\left (\frac {x}{2}\right )+1\right )}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) \left (a^{2}+b^{2}\right )}+\frac {\arctan \left (\tanh \left (\frac {x}{2}\right )\right ) a^{4}}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) \left (a^{2}+b^{2}\right )}+\frac {6 \arctan \left (\tanh \left (\frac {x}{2}\right )\right ) a^{2} b^{2}}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) \left (a^{2}+b^{2}\right )}-\frac {3 \arctan \left (\tanh \left (\frac {x}{2}\right )\right ) b^{4}}{\left (a^{4}+2 a^{2} b^{2}+b^{4}\right ) \left (a^{2}+b^{2}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.42, size = 375, normalized size = 2.76 \[ \frac {4 \, a b^{3} \log \left (-2 \, a e^{\left (-x\right )} + b e^{\left (-2 \, x\right )} - b\right )}{a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}} - \frac {4 \, a b^{3} \log \left (e^{\left (-2 \, x\right )} + 1\right )}{a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}} - \frac {{\left (a^{4} + 6 \, a^{2} b^{2} - 3 \, b^{4}\right )} \arctan \left (e^{\left (-x\right )}\right )}{a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}} + \frac {{\left (a^{2} b - 3 \, b^{3}\right )} e^{\left (-x\right )} + 2 \, {\left (a^{3} + a b^{2}\right )} e^{\left (-2 \, x\right )} + 2 \, {\left (3 \, a^{2} b - b^{3}\right )} e^{\left (-3 \, x\right )} - 2 \, {\left (a^{3} + a b^{2}\right )} e^{\left (-4 \, x\right )} + {\left (a^{2} b - 3 \, b^{3}\right )} e^{\left (-5 \, x\right )}}{a^{4} b + 2 \, a^{2} b^{3} + b^{5} + 2 \, {\left (a^{5} + 2 \, a^{3} b^{2} + a b^{4}\right )} e^{\left (-x\right )} + {\left (a^{4} b + 2 \, a^{2} b^{3} + b^{5}\right )} e^{\left (-2 \, x\right )} + 4 \, {\left (a^{5} + 2 \, a^{3} b^{2} + a b^{4}\right )} e^{\left (-3 \, x\right )} - {\left (a^{4} b + 2 \, a^{2} b^{3} + b^{5}\right )} e^{\left (-4 \, x\right )} + 2 \, {\left (a^{5} + 2 \, a^{3} b^{2} + a b^{4}\right )} e^{\left (-5 \, x\right )} - {\left (a^{4} b + 2 \, a^{2} b^{3} + b^{5}\right )} e^{\left (-6 \, x\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 5.07, size = 519, normalized size = 3.82 \[ \frac {\frac {4\,\left (a^7\,b+3\,a^5\,b^3+3\,a^3\,b^5+a\,b^7\right )}{\left (a^2+b^2\right )\,{\left (a^4+2\,a^2\,b^2+b^4\right )}^2}+\frac {{\mathrm {e}}^x\,\left (a^8+2\,a^6\,b^2-2\,a^2\,b^6-b^8\right )}{\left (a^2+b^2\right )\,{\left (a^4+2\,a^2\,b^2+b^4\right )}^2}}{{\mathrm {e}}^{2\,x}+1}-\frac {\frac {4\,a\,b}{a^4+2\,a^2\,b^2+b^4}+\frac {2\,{\mathrm {e}}^x\,\left (a^2-b^2\right )}{a^4+2\,a^2\,b^2+b^4}}{2\,{\mathrm {e}}^{2\,x}+{\mathrm {e}}^{4\,x}+1}+\frac {\ln \left ({\mathrm {e}}^x+1{}\mathrm {i}\right )\,\left (a-b\,3{}\mathrm {i}\right )}{2\,\left (-a^3\,1{}\mathrm {i}-3\,a^2\,b+a\,b^2\,3{}\mathrm {i}+b^3\right )}+\frac {\ln \left (1+{\mathrm {e}}^x\,1{}\mathrm {i}\right )\,\left (-3\,b+a\,1{}\mathrm {i}\right )}{2\,\left (-a^3-a^2\,b\,3{}\mathrm {i}+3\,a\,b^2+b^3\,1{}\mathrm {i}\right )}+\frac {4\,a\,b^3\,\ln \left (9\,b^9\,{\mathrm {e}}^{2\,x}-a^8\,b-9\,b^9-220\,a^2\,b^7-30\,a^4\,b^5-12\,a^6\,b^3+2\,a^9\,{\mathrm {e}}^x+220\,a^2\,b^7\,{\mathrm {e}}^{2\,x}+30\,a^4\,b^5\,{\mathrm {e}}^{2\,x}+12\,a^6\,b^3\,{\mathrm {e}}^{2\,x}+18\,a\,b^8\,{\mathrm {e}}^x+a^8\,b\,{\mathrm {e}}^{2\,x}+440\,a^3\,b^6\,{\mathrm {e}}^x+60\,a^5\,b^4\,{\mathrm {e}}^x+24\,a^7\,b^2\,{\mathrm {e}}^x\right )}{a^6+3\,a^4\,b^2+3\,a^2\,b^4+b^6}-\frac {2\,{\mathrm {e}}^x\,\left (a^4\,b^6+2\,a^2\,b^8+b^{10}\right )}{b^2\,\left (a^2\,b+b^3\right )\,\left (a^2+b^2\right )\,\left (2\,a\,{\mathrm {e}}^x-b+b\,{\mathrm {e}}^{2\,x}\right )\,\left (a^4+2\,a^2\,b^2+b^4\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {sech}^{3}{\relax (x )}}{\left (a + b \sinh {\relax (x )}\right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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