3.50 \(\int x^{-1-n} \cosh (a+b x^n) \, dx\)

Optimal. Leaf size=45 \[ \frac {b \sinh (a) \text {Chi}\left (b x^n\right )}{n}+\frac {b \cosh (a) \text {Shi}\left (b x^n\right )}{n}-\frac {x^{-n} \cosh \left (a+b x^n\right )}{n} \]

[Out]

-cosh(a+b*x^n)/n/(x^n)+b*cosh(a)*Shi(b*x^n)/n+b*Chi(b*x^n)*sinh(a)/n

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Rubi [A]  time = 0.09, antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.312, Rules used = {5321, 3297, 3303, 3298, 3301} \[ \frac {b \sinh (a) \text {Chi}\left (b x^n\right )}{n}+\frac {b \cosh (a) \text {Shi}\left (b x^n\right )}{n}-\frac {x^{-n} \cosh \left (a+b x^n\right )}{n} \]

Antiderivative was successfully verified.

[In]

Int[x^(-1 - n)*Cosh[a + b*x^n],x]

[Out]

-(Cosh[a + b*x^n]/(n*x^n)) + (b*CoshIntegral[b*x^n]*Sinh[a])/n + (b*Cosh[a]*SinhIntegral[b*x^n])/n

Rule 3297

Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)], x_Symbol] :> Simp[((c + d*x)^(m + 1)*Sin[e + f*x])/(d*(
m + 1)), x] - Dist[f/(d*(m + 1)), Int[(c + d*x)^(m + 1)*Cos[e + f*x], x], x] /; FreeQ[{c, d, e, f}, x] && LtQ[
m, -1]

Rule 3298

Int[sin[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[(I*SinhIntegral[(c*f*fz)
/d + f*fz*x])/d, x] /; FreeQ[{c, d, e, f, fz}, x] && EqQ[d*e - c*f*fz*I, 0]

Rule 3301

Int[sin[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[CoshIntegral[(c*f*fz)/d
+ f*fz*x]/d, x] /; FreeQ[{c, d, e, f, fz}, x] && EqQ[d*(e - Pi/2) - c*f*fz*I, 0]

Rule 3303

Int[sin[(e_.) + (f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Dist[Cos[(d*e - c*f)/d], Int[Sin[(c*f)/d + f*x]
/(c + d*x), x], x] + Dist[Sin[(d*e - c*f)/d], Int[Cos[(c*f)/d + f*x]/(c + d*x), x], x] /; FreeQ[{c, d, e, f},
x] && NeQ[d*e - c*f, 0]

Rule 5321

Int[((a_.) + Cosh[(c_.) + (d_.)*(x_)^(n_)]*(b_.))^(p_.)*(x_)^(m_.), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simpli
fy[(m + 1)/n] - 1)*(a + b*Cosh[c + d*x])^p, x], x, x^n], x] /; FreeQ[{a, b, c, d, m, n, p}, x] && IntegerQ[Sim
plify[(m + 1)/n]] && (EqQ[p, 1] || EqQ[m, n - 1] || (IntegerQ[p] && GtQ[Simplify[(m + 1)/n], 0]))

Rubi steps

\begin {align*} \int x^{-1-n} \cosh \left (a+b x^n\right ) \, dx &=\frac {\operatorname {Subst}\left (\int \frac {\cosh (a+b x)}{x^2} \, dx,x,x^n\right )}{n}\\ &=-\frac {x^{-n} \cosh \left (a+b x^n\right )}{n}+\frac {b \operatorname {Subst}\left (\int \frac {\sinh (a+b x)}{x} \, dx,x,x^n\right )}{n}\\ &=-\frac {x^{-n} \cosh \left (a+b x^n\right )}{n}+\frac {(b \cosh (a)) \operatorname {Subst}\left (\int \frac {\sinh (b x)}{x} \, dx,x,x^n\right )}{n}+\frac {(b \sinh (a)) \operatorname {Subst}\left (\int \frac {\cosh (b x)}{x} \, dx,x,x^n\right )}{n}\\ &=-\frac {x^{-n} \cosh \left (a+b x^n\right )}{n}+\frac {b \text {Chi}\left (b x^n\right ) \sinh (a)}{n}+\frac {b \cosh (a) \text {Shi}\left (b x^n\right )}{n}\\ \end {align*}

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Mathematica [A]  time = 0.07, size = 46, normalized size = 1.02 \[ \frac {x^{-n} \left (b \sinh (a) x^n \text {Chi}\left (b x^n\right )+b \cosh (a) x^n \text {Shi}\left (b x^n\right )-\cosh \left (a+b x^n\right )\right )}{n} \]

Antiderivative was successfully verified.

[In]

Integrate[x^(-1 - n)*Cosh[a + b*x^n],x]

[Out]

(-Cosh[a + b*x^n] + b*x^n*CoshIntegral[b*x^n]*Sinh[a] + b*x^n*Cosh[a]*SinhIntegral[b*x^n])/(n*x^n)

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fricas [B]  time = 0.60, size = 140, normalized size = 3.11 \[ \frac {{\left ({\left (b \cosh \relax (a) + b \sinh \relax (a)\right )} \cosh \left (n \log \relax (x)\right ) + {\left (b \cosh \relax (a) + b \sinh \relax (a)\right )} \sinh \left (n \log \relax (x)\right )\right )} {\rm Ei}\left (b \cosh \left (n \log \relax (x)\right ) + b \sinh \left (n \log \relax (x)\right )\right ) - {\left ({\left (b \cosh \relax (a) - b \sinh \relax (a)\right )} \cosh \left (n \log \relax (x)\right ) + {\left (b \cosh \relax (a) - b \sinh \relax (a)\right )} \sinh \left (n \log \relax (x)\right )\right )} {\rm Ei}\left (-b \cosh \left (n \log \relax (x)\right ) - b \sinh \left (n \log \relax (x)\right )\right ) - 2 \, \cosh \left (b \cosh \left (n \log \relax (x)\right ) + b \sinh \left (n \log \relax (x)\right ) + a\right )}{2 \, {\left (n \cosh \left (n \log \relax (x)\right ) + n \sinh \left (n \log \relax (x)\right )\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(-1-n)*cosh(a+b*x^n),x, algorithm="fricas")

[Out]

1/2*(((b*cosh(a) + b*sinh(a))*cosh(n*log(x)) + (b*cosh(a) + b*sinh(a))*sinh(n*log(x)))*Ei(b*cosh(n*log(x)) + b
*sinh(n*log(x))) - ((b*cosh(a) - b*sinh(a))*cosh(n*log(x)) + (b*cosh(a) - b*sinh(a))*sinh(n*log(x)))*Ei(-b*cos
h(n*log(x)) - b*sinh(n*log(x))) - 2*cosh(b*cosh(n*log(x)) + b*sinh(n*log(x)) + a))/(n*cosh(n*log(x)) + n*sinh(
n*log(x)))

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{-n - 1} \cosh \left (b x^{n} + a\right )\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(-1-n)*cosh(a+b*x^n),x, algorithm="giac")

[Out]

integrate(x^(-n - 1)*cosh(b*x^n + a), x)

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maple [A]  time = 0.14, size = 74, normalized size = 1.64 \[ -\frac {{\mathrm e}^{-a -b \,x^{n}} x^{-n}}{2 n}+\frac {b \,{\mathrm e}^{-a} \Ei \left (1, b \,x^{n}\right )}{2 n}-\frac {{\mathrm e}^{a +b \,x^{n}} x^{-n}}{2 n}-\frac {b \,{\mathrm e}^{a} \Ei \left (1, -b \,x^{n}\right )}{2 n} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(-1-n)*cosh(a+b*x^n),x)

[Out]

-1/2/n*exp(-a-b*x^n)/(x^n)+1/2/n*b*exp(-a)*Ei(1,b*x^n)-1/2*exp(a+b*x^n)/(x^n)/n-1/2/n*b*exp(a)*Ei(1,-b*x^n)

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maxima [A]  time = 0.40, size = 34, normalized size = 0.76 \[ -\frac {b e^{\left (-a\right )} \Gamma \left (-1, b x^{n}\right )}{2 \, n} + \frac {b e^{a} \Gamma \left (-1, -b x^{n}\right )}{2 \, n} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(-1-n)*cosh(a+b*x^n),x, algorithm="maxima")

[Out]

-1/2*b*e^(-a)*gamma(-1, b*x^n)/n + 1/2*b*e^a*gamma(-1, -b*x^n)/n

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {\mathrm {cosh}\left (a+b\,x^n\right )}{x^{n+1}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cosh(a + b*x^n)/x^(n + 1),x)

[Out]

int(cosh(a + b*x^n)/x^(n + 1), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{- n - 1} \cosh {\left (a + b x^{n} \right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**(-1-n)*cosh(a+b*x**n),x)

[Out]

Integral(x**(-n - 1)*cosh(a + b*x**n), x)

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