Optimal. Leaf size=54 \[ \frac {\tan ^{-1}(\sinh (x))}{b}-\frac {2 a \tan ^{-1}\left (\frac {\sqrt {a-b} \tanh \left (\frac {x}{2}\right )}{\sqrt {a+b}}\right )}{b \sqrt {a-b} \sqrt {a+b}} \]
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Rubi [A] time = 0.10, antiderivative size = 54, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.385, Rules used = {3789, 3770, 3831, 2659, 205} \[ \frac {\tan ^{-1}(\sinh (x))}{b}-\frac {2 a \tan ^{-1}\left (\frac {\sqrt {a-b} \tanh \left (\frac {x}{2}\right )}{\sqrt {a+b}}\right )}{b \sqrt {a-b} \sqrt {a+b}} \]
Antiderivative was successfully verified.
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Rule 205
Rule 2659
Rule 3770
Rule 3789
Rule 3831
Rubi steps
\begin {align*} \int \frac {\text {sech}^2(x)}{a+b \text {sech}(x)} \, dx &=\frac {\int \text {sech}(x) \, dx}{b}-\frac {a \int \frac {\text {sech}(x)}{a+b \text {sech}(x)} \, dx}{b}\\ &=\frac {\tan ^{-1}(\sinh (x))}{b}-\frac {a \int \frac {1}{1+\frac {a \cosh (x)}{b}} \, dx}{b^2}\\ &=\frac {\tan ^{-1}(\sinh (x))}{b}-\frac {(2 a) \operatorname {Subst}\left (\int \frac {1}{1+\frac {a}{b}-\left (1-\frac {a}{b}\right ) x^2} \, dx,x,\tanh \left (\frac {x}{2}\right )\right )}{b^2}\\ &=\frac {\tan ^{-1}(\sinh (x))}{b}-\frac {2 a \tan ^{-1}\left (\frac {\sqrt {a-b} \tanh \left (\frac {x}{2}\right )}{\sqrt {a+b}}\right )}{\sqrt {a-b} b \sqrt {a+b}}\\ \end {align*}
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Mathematica [A] time = 0.05, size = 54, normalized size = 1.00 \[ \frac {2 \left (\frac {a \tan ^{-1}\left (\frac {(b-a) \tanh \left (\frac {x}{2}\right )}{\sqrt {a^2-b^2}}\right )}{\sqrt {a^2-b^2}}+\tan ^{-1}\left (\tanh \left (\frac {x}{2}\right )\right )\right )}{b} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.44, size = 219, normalized size = 4.06 \[ \left [-\frac {\sqrt {-a^{2} + b^{2}} a \log \left (\frac {a^{2} \cosh \relax (x)^{2} + a^{2} \sinh \relax (x)^{2} + 2 \, a b \cosh \relax (x) - a^{2} + 2 \, b^{2} + 2 \, {\left (a^{2} \cosh \relax (x) + a b\right )} \sinh \relax (x) + 2 \, \sqrt {-a^{2} + b^{2}} {\left (a \cosh \relax (x) + a \sinh \relax (x) + b\right )}}{a \cosh \relax (x)^{2} + a \sinh \relax (x)^{2} + 2 \, b \cosh \relax (x) + 2 \, {\left (a \cosh \relax (x) + b\right )} \sinh \relax (x) + a}\right ) - 2 \, {\left (a^{2} - b^{2}\right )} \arctan \left (\cosh \relax (x) + \sinh \relax (x)\right )}{a^{2} b - b^{3}}, \frac {2 \, {\left (\sqrt {a^{2} - b^{2}} a \arctan \left (-\frac {a \cosh \relax (x) + a \sinh \relax (x) + b}{\sqrt {a^{2} - b^{2}}}\right ) + {\left (a^{2} - b^{2}\right )} \arctan \left (\cosh \relax (x) + \sinh \relax (x)\right )\right )}}{a^{2} b - b^{3}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.12, size = 45, normalized size = 0.83 \[ -\frac {2 \, a \arctan \left (\frac {a e^{x} + b}{\sqrt {a^{2} - b^{2}}}\right )}{\sqrt {a^{2} - b^{2}} b} + \frac {2 \, \arctan \left (e^{x}\right )}{b} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.09, size = 51, normalized size = 0.94 \[ -\frac {2 a \arctan \left (\frac {\left (a -b \right ) \tanh \left (\frac {x}{2}\right )}{\sqrt {\left (a +b \right ) \left (a -b \right )}}\right )}{b \sqrt {\left (a +b \right ) \left (a -b \right )}}+\frac {2 \arctan \left (\tanh \left (\frac {x}{2}\right )\right )}{b} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 4.01, size = 286, normalized size = 5.30 \[ \frac {a\,\ln \left (64\,a\,b^4-64\,a^3\,b^2+128\,b^5\,{\mathrm {e}}^x-64\,a\,b^3\,\sqrt {b^2-a^2}+32\,a^3\,b\,\sqrt {b^2-a^2}+32\,a^4\,b\,{\mathrm {e}}^x-128\,b^4\,{\mathrm {e}}^x\,\sqrt {b^2-a^2}-160\,a^2\,b^3\,{\mathrm {e}}^x+96\,a^2\,b^2\,{\mathrm {e}}^x\,\sqrt {b^2-a^2}\right )}{b\,\sqrt {b^2-a^2}}-\frac {\ln \left ({\mathrm {e}}^x-\mathrm {i}\right )\,1{}\mathrm {i}-\ln \left ({\mathrm {e}}^x+1{}\mathrm {i}\right )\,1{}\mathrm {i}}{b}-\frac {a\,\ln \left (64\,a\,b^4-64\,a^3\,b^2+128\,b^5\,{\mathrm {e}}^x+64\,a\,b^3\,\sqrt {b^2-a^2}-32\,a^3\,b\,\sqrt {b^2-a^2}+32\,a^4\,b\,{\mathrm {e}}^x+128\,b^4\,{\mathrm {e}}^x\,\sqrt {b^2-a^2}-160\,a^2\,b^3\,{\mathrm {e}}^x-96\,a^2\,b^2\,{\mathrm {e}}^x\,\sqrt {b^2-a^2}\right )}{b\,\sqrt {b^2-a^2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {sech}^{2}{\relax (x )}}{a + b \operatorname {sech}{\relax (x )}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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