Optimal. Leaf size=51 \[ \frac {2 \tanh (a+b x)}{3 b \sqrt {\text {sech}^2(a+b x)}}+\frac {\tanh (a+b x)}{3 b \text {sech}^2(a+b x)^{3/2}} \]
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Rubi [A] time = 0.02, antiderivative size = 51, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {4122, 192, 191} \[ \frac {2 \tanh (a+b x)}{3 b \sqrt {\text {sech}^2(a+b x)}}+\frac {\tanh (a+b x)}{3 b \text {sech}^2(a+b x)^{3/2}} \]
Antiderivative was successfully verified.
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Rule 191
Rule 192
Rule 4122
Rubi steps
\begin {align*} \int \frac {1}{\text {sech}^2(a+b x)^{3/2}} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {1}{\left (1-x^2\right )^{5/2}} \, dx,x,\tanh (a+b x)\right )}{b}\\ &=\frac {\tanh (a+b x)}{3 b \text {sech}^2(a+b x)^{3/2}}+\frac {2 \operatorname {Subst}\left (\int \frac {1}{\left (1-x^2\right )^{3/2}} \, dx,x,\tanh (a+b x)\right )}{3 b}\\ &=\frac {\tanh (a+b x)}{3 b \text {sech}^2(a+b x)^{3/2}}+\frac {2 \tanh (a+b x)}{3 b \sqrt {\text {sech}^2(a+b x)}}\\ \end {align*}
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Mathematica [A] time = 0.07, size = 44, normalized size = 0.86 \[ \frac {\tanh ^3(a+b x)+3 \tanh (a+b x) \text {sech}^2(a+b x)}{3 b \text {sech}^2(a+b x)^{3/2}} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.39, size = 32, normalized size = 0.63 \[ \frac {\sinh \left (b x + a\right )^{3} + 3 \, {\left (\cosh \left (b x + a\right )^{2} + 3\right )} \sinh \left (b x + a\right )}{12 \, b} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.11, size = 48, normalized size = 0.94 \[ -\frac {{\left (9 \, e^{\left (2 \, b x + 2 \, a\right )} + 1\right )} e^{\left (-3 \, b x - 3 \, a\right )} - e^{\left (3 \, b x + 3 \, a\right )} - 9 \, e^{\left (b x + a\right )}}{24 \, b} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.44, size = 201, normalized size = 3.94 \[ \frac {{\mathrm e}^{4 b x +4 a}}{24 b \left (1+{\mathrm e}^{2 b x +2 a}\right ) \sqrt {\frac {{\mathrm e}^{2 b x +2 a}}{\left (1+{\mathrm e}^{2 b x +2 a}\right )^{2}}}}+\frac {3 \,{\mathrm e}^{2 b x +2 a}}{8 b \left (1+{\mathrm e}^{2 b x +2 a}\right ) \sqrt {\frac {{\mathrm e}^{2 b x +2 a}}{\left (1+{\mathrm e}^{2 b x +2 a}\right )^{2}}}}-\frac {3}{8 b \left (1+{\mathrm e}^{2 b x +2 a}\right ) \sqrt {\frac {{\mathrm e}^{2 b x +2 a}}{\left (1+{\mathrm e}^{2 b x +2 a}\right )^{2}}}}-\frac {{\mathrm e}^{-2 b x -2 a}}{24 b \left (1+{\mathrm e}^{2 b x +2 a}\right ) \sqrt {\frac {{\mathrm e}^{2 b x +2 a}}{\left (1+{\mathrm e}^{2 b x +2 a}\right )^{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.33, size = 54, normalized size = 1.06 \[ \frac {e^{\left (3 \, b x + 3 \, a\right )}}{24 \, b} + \frac {3 \, e^{\left (b x + a\right )}}{8 \, b} - \frac {3 \, e^{\left (-b x - a\right )}}{8 \, b} - \frac {e^{\left (-3 \, b x - 3 \, a\right )}}{24 \, b} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {1}{{\left (\frac {1}{{\mathrm {cosh}\left (a+b\,x\right )}^2}\right )}^{3/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 18.85, size = 54, normalized size = 1.06 \[ \begin {cases} - \frac {2 \tanh ^{3}{\left (a + b x \right )}}{3 b \left (\operatorname {sech}^{2}{\left (a + b x \right )}\right )^{\frac {3}{2}}} + \frac {\tanh {\left (a + b x \right )}}{b \left (\operatorname {sech}^{2}{\left (a + b x \right )}\right )^{\frac {3}{2}}} & \text {for}\: b \neq 0 \\\frac {x}{\left (\operatorname {sech}^{2}{\relax (a )}\right )^{\frac {3}{2}}} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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