Optimal. Leaf size=124 \[ -\frac {1}{8} b \cosh (a) \text {Chi}(b x)-\frac {3}{16} b \cosh (3 a) \text {Chi}(3 b x)+\frac {5}{16} b \cosh (5 a) \text {Chi}(5 b x)-\frac {1}{8} b \sinh (a) \text {Shi}(b x)-\frac {3}{16} b \sinh (3 a) \text {Shi}(3 b x)+\frac {5}{16} b \sinh (5 a) \text {Shi}(5 b x)+\frac {\sinh (a+b x)}{8 x}+\frac {\sinh (3 a+3 b x)}{16 x}-\frac {\sinh (5 a+5 b x)}{16 x} \]
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Rubi [A] time = 0.25, antiderivative size = 124, normalized size of antiderivative = 1.00, number of steps used = 14, number of rules used = 5, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {5448, 3297, 3303, 3298, 3301} \[ -\frac {1}{8} b \cosh (a) \text {Chi}(b x)-\frac {3}{16} b \cosh (3 a) \text {Chi}(3 b x)+\frac {5}{16} b \cosh (5 a) \text {Chi}(5 b x)-\frac {1}{8} b \sinh (a) \text {Shi}(b x)-\frac {3}{16} b \sinh (3 a) \text {Shi}(3 b x)+\frac {5}{16} b \sinh (5 a) \text {Shi}(5 b x)+\frac {\sinh (a+b x)}{8 x}+\frac {\sinh (3 a+3 b x)}{16 x}-\frac {\sinh (5 a+5 b x)}{16 x} \]
Antiderivative was successfully verified.
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Rule 3297
Rule 3298
Rule 3301
Rule 3303
Rule 5448
Rubi steps
\begin {align*} \int \frac {\cosh ^2(a+b x) \sinh ^3(a+b x)}{x^2} \, dx &=\int \left (-\frac {\sinh (a+b x)}{8 x^2}-\frac {\sinh (3 a+3 b x)}{16 x^2}+\frac {\sinh (5 a+5 b x)}{16 x^2}\right ) \, dx\\ &=-\left (\frac {1}{16} \int \frac {\sinh (3 a+3 b x)}{x^2} \, dx\right )+\frac {1}{16} \int \frac {\sinh (5 a+5 b x)}{x^2} \, dx-\frac {1}{8} \int \frac {\sinh (a+b x)}{x^2} \, dx\\ &=\frac {\sinh (a+b x)}{8 x}+\frac {\sinh (3 a+3 b x)}{16 x}-\frac {\sinh (5 a+5 b x)}{16 x}-\frac {1}{8} b \int \frac {\cosh (a+b x)}{x} \, dx-\frac {1}{16} (3 b) \int \frac {\cosh (3 a+3 b x)}{x} \, dx+\frac {1}{16} (5 b) \int \frac {\cosh (5 a+5 b x)}{x} \, dx\\ &=\frac {\sinh (a+b x)}{8 x}+\frac {\sinh (3 a+3 b x)}{16 x}-\frac {\sinh (5 a+5 b x)}{16 x}-\frac {1}{8} (b \cosh (a)) \int \frac {\cosh (b x)}{x} \, dx-\frac {1}{16} (3 b \cosh (3 a)) \int \frac {\cosh (3 b x)}{x} \, dx+\frac {1}{16} (5 b \cosh (5 a)) \int \frac {\cosh (5 b x)}{x} \, dx-\frac {1}{8} (b \sinh (a)) \int \frac {\sinh (b x)}{x} \, dx-\frac {1}{16} (3 b \sinh (3 a)) \int \frac {\sinh (3 b x)}{x} \, dx+\frac {1}{16} (5 b \sinh (5 a)) \int \frac {\sinh (5 b x)}{x} \, dx\\ &=-\frac {1}{8} b \cosh (a) \text {Chi}(b x)-\frac {3}{16} b \cosh (3 a) \text {Chi}(3 b x)+\frac {5}{16} b \cosh (5 a) \text {Chi}(5 b x)+\frac {\sinh (a+b x)}{8 x}+\frac {\sinh (3 a+3 b x)}{16 x}-\frac {\sinh (5 a+5 b x)}{16 x}-\frac {1}{8} b \sinh (a) \text {Shi}(b x)-\frac {3}{16} b \sinh (3 a) \text {Shi}(3 b x)+\frac {5}{16} b \sinh (5 a) \text {Shi}(5 b x)\\ \end {align*}
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Mathematica [A] time = 0.27, size = 106, normalized size = 0.85 \[ \frac {-2 b x \cosh (a) \text {Chi}(b x)-3 b x \cosh (3 a) \text {Chi}(3 b x)+5 b x \cosh (5 a) \text {Chi}(5 b x)-2 b x \sinh (a) \text {Shi}(b x)-3 b x \sinh (3 a) \text {Shi}(3 b x)+5 b x \sinh (5 a) \text {Shi}(5 b x)+2 \sinh (a+b x)+\sinh (3 (a+b x))-\sinh (5 (a+b x))}{16 x} \]
Antiderivative was successfully verified.
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fricas [A] time = 1.01, size = 203, normalized size = 1.64 \[ -\frac {2 \, \sinh \left (b x + a\right )^{5} + 2 \, {\left (10 \, \cosh \left (b x + a\right )^{2} - 1\right )} \sinh \left (b x + a\right )^{3} - 5 \, {\left (b x {\rm Ei}\left (5 \, b x\right ) + b x {\rm Ei}\left (-5 \, b x\right )\right )} \cosh \left (5 \, a\right ) + 3 \, {\left (b x {\rm Ei}\left (3 \, b x\right ) + b x {\rm Ei}\left (-3 \, b x\right )\right )} \cosh \left (3 \, a\right ) + 2 \, {\left (b x {\rm Ei}\left (b x\right ) + b x {\rm Ei}\left (-b x\right )\right )} \cosh \relax (a) + 2 \, {\left (5 \, \cosh \left (b x + a\right )^{4} - 3 \, \cosh \left (b x + a\right )^{2} - 2\right )} \sinh \left (b x + a\right ) - 5 \, {\left (b x {\rm Ei}\left (5 \, b x\right ) - b x {\rm Ei}\left (-5 \, b x\right )\right )} \sinh \left (5 \, a\right ) + 3 \, {\left (b x {\rm Ei}\left (3 \, b x\right ) - b x {\rm Ei}\left (-3 \, b x\right )\right )} \sinh \left (3 \, a\right ) + 2 \, {\left (b x {\rm Ei}\left (b x\right ) - b x {\rm Ei}\left (-b x\right )\right )} \sinh \relax (a)}{32 \, x} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.15, size = 140, normalized size = 1.13 \[ \frac {5 \, b x {\rm Ei}\left (5 \, b x\right ) e^{\left (5 \, a\right )} - 3 \, b x {\rm Ei}\left (3 \, b x\right ) e^{\left (3 \, a\right )} - 2 \, b x {\rm Ei}\left (-b x\right ) e^{\left (-a\right )} - 3 \, b x {\rm Ei}\left (-3 \, b x\right ) e^{\left (-3 \, a\right )} + 5 \, b x {\rm Ei}\left (-5 \, b x\right ) e^{\left (-5 \, a\right )} - 2 \, b x {\rm Ei}\left (b x\right ) e^{a} - e^{\left (5 \, b x + 5 \, a\right )} + e^{\left (3 \, b x + 3 \, a\right )} + 2 \, e^{\left (b x + a\right )} - 2 \, e^{\left (-b x - a\right )} - e^{\left (-3 \, b x - 3 \, a\right )} + e^{\left (-5 \, b x - 5 \, a\right )}}{32 \, x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.41, size = 158, normalized size = 1.27 \[ \frac {{\mathrm e}^{-5 b x -5 a}}{32 x}-\frac {5 b \,{\mathrm e}^{-5 a} \Ei \left (1, 5 b x \right )}{32}-\frac {{\mathrm e}^{-3 b x -3 a}}{32 x}+\frac {3 b \,{\mathrm e}^{-3 a} \Ei \left (1, 3 b x \right )}{32}-\frac {{\mathrm e}^{-b x -a}}{16 x}+\frac {b \,{\mathrm e}^{-a} \Ei \left (1, b x \right )}{16}+\frac {{\mathrm e}^{b x +a}}{16 x}+\frac {b \,{\mathrm e}^{a} \Ei \left (1, -b x \right )}{16}+\frac {{\mathrm e}^{3 b x +3 a}}{32 x}+\frac {3 b \,{\mathrm e}^{3 a} \Ei \left (1, -3 b x \right )}{32}-\frac {{\mathrm e}^{5 b x +5 a}}{32 x}-\frac {5 b \,{\mathrm e}^{5 a} \Ei \left (1, -5 b x \right )}{32} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.47, size = 76, normalized size = 0.61 \[ \frac {5}{32} \, b e^{\left (-5 \, a\right )} \Gamma \left (-1, 5 \, b x\right ) - \frac {3}{32} \, b e^{\left (-3 \, a\right )} \Gamma \left (-1, 3 \, b x\right ) - \frac {1}{16} \, b e^{\left (-a\right )} \Gamma \left (-1, b x\right ) - \frac {1}{16} \, b e^{a} \Gamma \left (-1, -b x\right ) - \frac {3}{32} \, b e^{\left (3 \, a\right )} \Gamma \left (-1, -3 \, b x\right ) + \frac {5}{32} \, b e^{\left (5 \, a\right )} \Gamma \left (-1, -5 \, b x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\mathrm {cosh}\left (a+b\,x\right )}^2\,{\mathrm {sinh}\left (a+b\,x\right )}^3}{x^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sinh ^{3}{\left (a + b x \right )} \cosh ^{2}{\left (a + b x \right )}}{x^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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