Optimal. Leaf size=227 \[ \frac {2 b^2 e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )}{9 d}-\frac {4}{3} a b^2 e^2 x+\frac {2 b e^2 \sqrt {(c+d x)^2+1} \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}-\frac {b e^2 (c+d x)^2 \sqrt {(c+d x)^2+1} \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}+\frac {e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^3}{3 d}-\frac {2 b^3 e^2 \left ((c+d x)^2+1\right )^{3/2}}{27 d}+\frac {14 b^3 e^2 \sqrt {(c+d x)^2+1}}{9 d}-\frac {4 b^3 e^2 (c+d x) \sinh ^{-1}(c+d x)}{3 d} \]
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Rubi [A] time = 0.30, antiderivative size = 227, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 9, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.391, Rules used = {5865, 12, 5661, 5758, 5717, 5653, 261, 266, 43} \[ \frac {2 b^2 e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )}{9 d}-\frac {4}{3} a b^2 e^2 x+\frac {2 b e^2 \sqrt {(c+d x)^2+1} \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}-\frac {b e^2 (c+d x)^2 \sqrt {(c+d x)^2+1} \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}+\frac {e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^3}{3 d}-\frac {2 b^3 e^2 \left ((c+d x)^2+1\right )^{3/2}}{27 d}+\frac {14 b^3 e^2 \sqrt {(c+d x)^2+1}}{9 d}-\frac {4 b^3 e^2 (c+d x) \sinh ^{-1}(c+d x)}{3 d} \]
Antiderivative was successfully verified.
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Rule 12
Rule 43
Rule 261
Rule 266
Rule 5653
Rule 5661
Rule 5717
Rule 5758
Rule 5865
Rubi steps
\begin {align*} \int (c e+d e x)^2 \left (a+b \sinh ^{-1}(c+d x)\right )^3 \, dx &=\frac {\operatorname {Subst}\left (\int e^2 x^2 \left (a+b \sinh ^{-1}(x)\right )^3 \, dx,x,c+d x\right )}{d}\\ &=\frac {e^2 \operatorname {Subst}\left (\int x^2 \left (a+b \sinh ^{-1}(x)\right )^3 \, dx,x,c+d x\right )}{d}\\ &=\frac {e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^3}{3 d}-\frac {\left (b e^2\right ) \operatorname {Subst}\left (\int \frac {x^3 \left (a+b \sinh ^{-1}(x)\right )^2}{\sqrt {1+x^2}} \, dx,x,c+d x\right )}{d}\\ &=-\frac {b e^2 (c+d x)^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}+\frac {e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^3}{3 d}+\frac {\left (2 b e^2\right ) \operatorname {Subst}\left (\int \frac {x \left (a+b \sinh ^{-1}(x)\right )^2}{\sqrt {1+x^2}} \, dx,x,c+d x\right )}{3 d}+\frac {\left (2 b^2 e^2\right ) \operatorname {Subst}\left (\int x^2 \left (a+b \sinh ^{-1}(x)\right ) \, dx,x,c+d x\right )}{3 d}\\ &=\frac {2 b^2 e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )}{9 d}+\frac {2 b e^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}-\frac {b e^2 (c+d x)^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}+\frac {e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^3}{3 d}-\frac {\left (4 b^2 e^2\right ) \operatorname {Subst}\left (\int \left (a+b \sinh ^{-1}(x)\right ) \, dx,x,c+d x\right )}{3 d}-\frac {\left (2 b^3 e^2\right ) \operatorname {Subst}\left (\int \frac {x^3}{\sqrt {1+x^2}} \, dx,x,c+d x\right )}{9 d}\\ &=-\frac {4}{3} a b^2 e^2 x+\frac {2 b^2 e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )}{9 d}+\frac {2 b e^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}-\frac {b e^2 (c+d x)^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}+\frac {e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^3}{3 d}-\frac {\left (b^3 e^2\right ) \operatorname {Subst}\left (\int \frac {x}{\sqrt {1+x}} \, dx,x,(c+d x)^2\right )}{9 d}-\frac {\left (4 b^3 e^2\right ) \operatorname {Subst}\left (\int \sinh ^{-1}(x) \, dx,x,c+d x\right )}{3 d}\\ &=-\frac {4}{3} a b^2 e^2 x-\frac {4 b^3 e^2 (c+d x) \sinh ^{-1}(c+d x)}{3 d}+\frac {2 b^2 e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )}{9 d}+\frac {2 b e^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}-\frac {b e^2 (c+d x)^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}+\frac {e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^3}{3 d}-\frac {\left (b^3 e^2\right ) \operatorname {Subst}\left (\int \left (-\frac {1}{\sqrt {1+x}}+\sqrt {1+x}\right ) \, dx,x,(c+d x)^2\right )}{9 d}+\frac {\left (4 b^3 e^2\right ) \operatorname {Subst}\left (\int \frac {x}{\sqrt {1+x^2}} \, dx,x,c+d x\right )}{3 d}\\ &=-\frac {4}{3} a b^2 e^2 x+\frac {14 b^3 e^2 \sqrt {1+(c+d x)^2}}{9 d}-\frac {2 b^3 e^2 \left (1+(c+d x)^2\right )^{3/2}}{27 d}-\frac {4 b^3 e^2 (c+d x) \sinh ^{-1}(c+d x)}{3 d}+\frac {2 b^2 e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )}{9 d}+\frac {2 b e^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}-\frac {b e^2 (c+d x)^2 \sqrt {1+(c+d x)^2} \left (a+b \sinh ^{-1}(c+d x)\right )^2}{3 d}+\frac {e^2 (c+d x)^3 \left (a+b \sinh ^{-1}(c+d x)\right )^3}{3 d}\\ \end {align*}
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Mathematica [A] time = 0.33, size = 258, normalized size = 1.14 \[ \frac {e^2 \left (a \left (3 a^2+2 b^2\right ) (c+d x)^3+\frac {1}{3} b \sqrt {(c+d x)^2+1} \left (-\left (9 a^2+2 b^2\right ) (c+d x)^2+18 a^2+40 b^2\right )-b \sinh ^{-1}(c+d x) \left (-9 a^2 (c+d x)^3+6 a b \sqrt {(c+d x)^2+1} (c+d x)^2-12 a b \sqrt {(c+d x)^2+1}-2 b^2 (c+d x)^3+12 b^2 (c+d x)\right )-12 a b^2 (c+d x)-3 b^2 \sinh ^{-1}(c+d x)^2 \left (-3 a (c+d x)^3+b \sqrt {(c+d x)^2+1} (c+d x)^2-2 b \sqrt {(c+d x)^2+1}\right )+3 b^3 (c+d x)^3 \sinh ^{-1}(c+d x)^3\right )}{9 d} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.63, size = 613, normalized size = 2.70 \[ \frac {3 \, {\left (3 \, a^{3} + 2 \, a b^{2}\right )} d^{3} e^{2} x^{3} + 9 \, {\left (3 \, a^{3} + 2 \, a b^{2}\right )} c d^{2} e^{2} x^{2} - 9 \, {\left (4 \, a b^{2} - {\left (3 \, a^{3} + 2 \, a b^{2}\right )} c^{2}\right )} d e^{2} x + 9 \, {\left (b^{3} d^{3} e^{2} x^{3} + 3 \, b^{3} c d^{2} e^{2} x^{2} + 3 \, b^{3} c^{2} d e^{2} x + b^{3} c^{3} e^{2}\right )} \log \left (d x + c + \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1}\right )^{3} + 9 \, {\left (3 \, a b^{2} d^{3} e^{2} x^{3} + 9 \, a b^{2} c d^{2} e^{2} x^{2} + 9 \, a b^{2} c^{2} d e^{2} x + 3 \, a b^{2} c^{3} e^{2} - {\left (b^{3} d^{2} e^{2} x^{2} + 2 \, b^{3} c d e^{2} x + {\left (b^{3} c^{2} - 2 \, b^{3}\right )} e^{2}\right )} \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1}\right )} \log \left (d x + c + \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1}\right )^{2} + 3 \, {\left ({\left (9 \, a^{2} b + 2 \, b^{3}\right )} d^{3} e^{2} x^{3} + 3 \, {\left (9 \, a^{2} b + 2 \, b^{3}\right )} c d^{2} e^{2} x^{2} - 3 \, {\left (4 \, b^{3} - {\left (9 \, a^{2} b + 2 \, b^{3}\right )} c^{2}\right )} d e^{2} x - {\left (12 \, b^{3} c - {\left (9 \, a^{2} b + 2 \, b^{3}\right )} c^{3}\right )} e^{2} - 6 \, {\left (a b^{2} d^{2} e^{2} x^{2} + 2 \, a b^{2} c d e^{2} x + {\left (a b^{2} c^{2} - 2 \, a b^{2}\right )} e^{2}\right )} \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1}\right )} \log \left (d x + c + \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1}\right ) - {\left ({\left (9 \, a^{2} b + 2 \, b^{3}\right )} d^{2} e^{2} x^{2} + 2 \, {\left (9 \, a^{2} b + 2 \, b^{3}\right )} c d e^{2} x - {\left (18 \, a^{2} b + 40 \, b^{3} - {\left (9 \, a^{2} b + 2 \, b^{3}\right )} c^{2}\right )} e^{2}\right )} \sqrt {d^{2} x^{2} + 2 \, c d x + c^{2} + 1}}{27 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (d e x + c e\right )}^{2} {\left (b \operatorname {arsinh}\left (d x + c\right ) + a\right )}^{3}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.04, size = 302, normalized size = 1.33 \[ \frac {\frac {\left (d x +c \right )^{3} e^{2} a^{3}}{3}+e^{2} b^{3} \left (\frac {\left (d x +c \right )^{3} \arcsinh \left (d x +c \right )^{3}}{3}+\frac {2 \arcsinh \left (d x +c \right )^{2} \sqrt {1+\left (d x +c \right )^{2}}}{3}-\frac {\left (d x +c \right )^{2} \arcsinh \left (d x +c \right )^{2} \sqrt {1+\left (d x +c \right )^{2}}}{3}-\frac {4 \left (d x +c \right ) \arcsinh \left (d x +c \right )}{3}+\frac {40 \sqrt {1+\left (d x +c \right )^{2}}}{27}+\frac {2 \left (d x +c \right )^{3} \arcsinh \left (d x +c \right )}{9}-\frac {2 \left (d x +c \right )^{2} \sqrt {1+\left (d x +c \right )^{2}}}{27}\right )+3 e^{2} a \,b^{2} \left (\frac {\left (d x +c \right )^{3} \arcsinh \left (d x +c \right )^{2}}{3}+\frac {4 \arcsinh \left (d x +c \right ) \sqrt {1+\left (d x +c \right )^{2}}}{9}-\frac {2 \arcsinh \left (d x +c \right ) \sqrt {1+\left (d x +c \right )^{2}}\, \left (d x +c \right )^{2}}{9}-\frac {4 d x}{9}-\frac {4 c}{9}+\frac {2 \left (d x +c \right )^{3}}{27}\right )+3 e^{2} a^{2} b \left (\frac {\left (d x +c \right )^{3} \arcsinh \left (d x +c \right )}{3}-\frac {\left (d x +c \right )^{2} \sqrt {1+\left (d x +c \right )^{2}}}{9}+\frac {2 \sqrt {1+\left (d x +c \right )^{2}}}{9}\right )}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int {\left (c\,e+d\,e\,x\right )}^2\,{\left (a+b\,\mathrm {asinh}\left (c+d\,x\right )\right )}^3 \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 4.99, size = 1173, normalized size = 5.17 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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