Optimal. Leaf size=248 \[ -\frac {1-a^2 x^2}{20 a}-\frac {\log \left (1-a^2 x^2\right )}{2 a}+\frac {1}{5} x \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^3+\frac {4}{15} x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^3+\frac {3 \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^2}{20 a}+\frac {2 \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^2}{5 a}-\frac {1}{10} x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)+\frac {4 \text {Li}_3\left (1-\frac {2}{1-a x}\right )}{5 a}-\frac {8 \text {Li}_2\left (1-\frac {2}{1-a x}\right ) \tanh ^{-1}(a x)}{5 a}+\frac {8}{15} x \tanh ^{-1}(a x)^3+\frac {8 \tanh ^{-1}(a x)^3}{15 a}-x \tanh ^{-1}(a x)-\frac {8 \log \left (\frac {2}{1-a x}\right ) \tanh ^{-1}(a x)^2}{5 a} \]
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Rubi [A] time = 0.25, antiderivative size = 248, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 9, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.474, Rules used = {5944, 5910, 5984, 5918, 5948, 6058, 6610, 260, 5942} \[ \frac {4 \text {PolyLog}\left (3,1-\frac {2}{1-a x}\right )}{5 a}-\frac {8 \tanh ^{-1}(a x) \text {PolyLog}\left (2,1-\frac {2}{1-a x}\right )}{5 a}-\frac {1-a^2 x^2}{20 a}-\frac {\log \left (1-a^2 x^2\right )}{2 a}+\frac {1}{5} x \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^3+\frac {4}{15} x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^3+\frac {3 \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^2}{20 a}+\frac {2 \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^2}{5 a}-\frac {1}{10} x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)+\frac {8}{15} x \tanh ^{-1}(a x)^3+\frac {8 \tanh ^{-1}(a x)^3}{15 a}-x \tanh ^{-1}(a x)-\frac {8 \log \left (\frac {2}{1-a x}\right ) \tanh ^{-1}(a x)^2}{5 a} \]
Antiderivative was successfully verified.
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Rule 260
Rule 5910
Rule 5918
Rule 5942
Rule 5944
Rule 5948
Rule 5984
Rule 6058
Rule 6610
Rubi steps
\begin {align*} \int \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^3 \, dx &=\frac {3 \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^2}{20 a}+\frac {1}{5} x \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^3-\frac {3}{10} \int \left (1-a^2 x^2\right ) \tanh ^{-1}(a x) \, dx+\frac {4}{5} \int \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^3 \, dx\\ &=-\frac {1-a^2 x^2}{20 a}-\frac {1}{10} x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)+\frac {2 \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^2}{5 a}+\frac {3 \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^2}{20 a}+\frac {4}{15} x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^3+\frac {1}{5} x \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^3-\frac {1}{5} \int \tanh ^{-1}(a x) \, dx+\frac {8}{15} \int \tanh ^{-1}(a x)^3 \, dx-\frac {4}{5} \int \tanh ^{-1}(a x) \, dx\\ &=-\frac {1-a^2 x^2}{20 a}-x \tanh ^{-1}(a x)-\frac {1}{10} x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)+\frac {2 \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^2}{5 a}+\frac {3 \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^2}{20 a}+\frac {8}{15} x \tanh ^{-1}(a x)^3+\frac {4}{15} x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^3+\frac {1}{5} x \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^3+\frac {1}{5} a \int \frac {x}{1-a^2 x^2} \, dx+\frac {1}{5} (4 a) \int \frac {x}{1-a^2 x^2} \, dx-\frac {1}{5} (8 a) \int \frac {x \tanh ^{-1}(a x)^2}{1-a^2 x^2} \, dx\\ &=-\frac {1-a^2 x^2}{20 a}-x \tanh ^{-1}(a x)-\frac {1}{10} x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)+\frac {2 \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^2}{5 a}+\frac {3 \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^2}{20 a}+\frac {8 \tanh ^{-1}(a x)^3}{15 a}+\frac {8}{15} x \tanh ^{-1}(a x)^3+\frac {4}{15} x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^3+\frac {1}{5} x \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^3-\frac {\log \left (1-a^2 x^2\right )}{2 a}-\frac {8}{5} \int \frac {\tanh ^{-1}(a x)^2}{1-a x} \, dx\\ &=-\frac {1-a^2 x^2}{20 a}-x \tanh ^{-1}(a x)-\frac {1}{10} x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)+\frac {2 \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^2}{5 a}+\frac {3 \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^2}{20 a}+\frac {8 \tanh ^{-1}(a x)^3}{15 a}+\frac {8}{15} x \tanh ^{-1}(a x)^3+\frac {4}{15} x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^3+\frac {1}{5} x \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^3-\frac {8 \tanh ^{-1}(a x)^2 \log \left (\frac {2}{1-a x}\right )}{5 a}-\frac {\log \left (1-a^2 x^2\right )}{2 a}+\frac {16}{5} \int \frac {\tanh ^{-1}(a x) \log \left (\frac {2}{1-a x}\right )}{1-a^2 x^2} \, dx\\ &=-\frac {1-a^2 x^2}{20 a}-x \tanh ^{-1}(a x)-\frac {1}{10} x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)+\frac {2 \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^2}{5 a}+\frac {3 \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^2}{20 a}+\frac {8 \tanh ^{-1}(a x)^3}{15 a}+\frac {8}{15} x \tanh ^{-1}(a x)^3+\frac {4}{15} x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^3+\frac {1}{5} x \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^3-\frac {8 \tanh ^{-1}(a x)^2 \log \left (\frac {2}{1-a x}\right )}{5 a}-\frac {\log \left (1-a^2 x^2\right )}{2 a}-\frac {8 \tanh ^{-1}(a x) \text {Li}_2\left (1-\frac {2}{1-a x}\right )}{5 a}+\frac {8}{5} \int \frac {\text {Li}_2\left (1-\frac {2}{1-a x}\right )}{1-a^2 x^2} \, dx\\ &=-\frac {1-a^2 x^2}{20 a}-x \tanh ^{-1}(a x)-\frac {1}{10} x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)+\frac {2 \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^2}{5 a}+\frac {3 \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^2}{20 a}+\frac {8 \tanh ^{-1}(a x)^3}{15 a}+\frac {8}{15} x \tanh ^{-1}(a x)^3+\frac {4}{15} x \left (1-a^2 x^2\right ) \tanh ^{-1}(a x)^3+\frac {1}{5} x \left (1-a^2 x^2\right )^2 \tanh ^{-1}(a x)^3-\frac {8 \tanh ^{-1}(a x)^2 \log \left (\frac {2}{1-a x}\right )}{5 a}-\frac {\log \left (1-a^2 x^2\right )}{2 a}-\frac {8 \tanh ^{-1}(a x) \text {Li}_2\left (1-\frac {2}{1-a x}\right )}{5 a}+\frac {4 \text {Li}_3\left (1-\frac {2}{1-a x}\right )}{5 a}\\ \end {align*}
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Mathematica [A] time = 0.60, size = 183, normalized size = 0.74 \[ \frac {12 a^5 x^5 \tanh ^{-1}(a x)^3+9 a^4 x^4 \tanh ^{-1}(a x)^2-40 a^3 x^3 \tanh ^{-1}(a x)^3+6 a^3 x^3 \tanh ^{-1}(a x)+3 a^2 x^2-30 \log \left (1-a^2 x^2\right )-42 a^2 x^2 \tanh ^{-1}(a x)^2+96 \tanh ^{-1}(a x) \text {Li}_2\left (-e^{-2 \tanh ^{-1}(a x)}\right )+48 \text {Li}_3\left (-e^{-2 \tanh ^{-1}(a x)}\right )+60 a x \tanh ^{-1}(a x)^3-66 a x \tanh ^{-1}(a x)-32 \tanh ^{-1}(a x)^3+33 \tanh ^{-1}(a x)^2-96 \tanh ^{-1}(a x)^2 \log \left (e^{-2 \tanh ^{-1}(a x)}+1\right )-3}{60 a} \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.55, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (a^{4} x^{4} - 2 \, a^{2} x^{2} + 1\right )} \operatorname {artanh}\left (a x\right )^{3}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (a^{2} x^{2} - 1\right )}^{2} \operatorname {artanh}\left (a x\right )^{3}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 2.46, size = 883, normalized size = 3.56 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {{\left (36 \, a^{5} x^{5} - 45 \, a^{4} x^{4} - 140 \, a^{3} x^{3} + 210 \, a^{2} x^{2} + 480 \, a x - 60 \, {\left (3 \, a^{5} x^{5} - 10 \, a^{3} x^{3} + 15 \, a x + 8\right )} \log \left (a x + 1\right )\right )} \log \left (-a x + 1\right )^{2}}{2400 \, a} - \frac {{\left (\log \left (-a x + 1\right )^{3} - 3 \, \log \left (-a x + 1\right )^{2} + 6 \, \log \left (-a x + 1\right ) - 6\right )} {\left (a x - 1\right )}}{8 \, a} - \frac {288 \, {\left (125 \, \log \left (-a x + 1\right )^{3} - 75 \, \log \left (-a x + 1\right )^{2} + 30 \, \log \left (-a x + 1\right ) - 6\right )} {\left (a x - 1\right )}^{5} + 5625 \, {\left (32 \, \log \left (-a x + 1\right )^{3} - 24 \, \log \left (-a x + 1\right )^{2} + 12 \, \log \left (-a x + 1\right ) - 3\right )} {\left (a x - 1\right )}^{4} + 40000 \, {\left (9 \, \log \left (-a x + 1\right )^{3} - 9 \, \log \left (-a x + 1\right )^{2} + 6 \, \log \left (-a x + 1\right ) - 2\right )} {\left (a x - 1\right )}^{3} + 90000 \, {\left (4 \, \log \left (-a x + 1\right )^{3} - 6 \, \log \left (-a x + 1\right )^{2} + 6 \, \log \left (-a x + 1\right ) - 3\right )} {\left (a x - 1\right )}^{2} + 180000 \, {\left (\log \left (-a x + 1\right )^{3} - 3 \, \log \left (-a x + 1\right )^{2} + 6 \, \log \left (-a x + 1\right ) - 6\right )} {\left (a x - 1\right )}}{1440000 \, a} + \frac {4 \, {\left (9 \, \log \left (-a x + 1\right )^{3} - 9 \, \log \left (-a x + 1\right )^{2} + 6 \, \log \left (-a x + 1\right ) - 2\right )} {\left (a x - 1\right )}^{3} + 27 \, {\left (4 \, \log \left (-a x + 1\right )^{3} - 6 \, \log \left (-a x + 1\right )^{2} + 6 \, \log \left (-a x + 1\right ) - 3\right )} {\left (a x - 1\right )}^{2} + 108 \, {\left (\log \left (-a x + 1\right )^{3} - 3 \, \log \left (-a x + 1\right )^{2} + 6 \, \log \left (-a x + 1\right ) - 6\right )} {\left (a x - 1\right )}}{432 \, a} - \frac {1}{8} \, \int -\frac {150 \, {\left (a^{5} x^{5} - a^{4} x^{4} - 2 \, a^{3} x^{3} + 2 \, a^{2} x^{2} + a x - 1\right )} \log \left (a x + 1\right )^{3} + {\left (36 \, a^{5} x^{5} - 45 \, a^{4} x^{4} - 140 \, a^{3} x^{3} + 210 \, a^{2} x^{2} - 450 \, {\left (a^{5} x^{5} - a^{4} x^{4} - 2 \, a^{3} x^{3} + 2 \, a^{2} x^{2} + a x - 1\right )} \log \left (a x + 1\right )^{2} + 480 \, a x - 60 \, {\left (3 \, a^{5} x^{5} - 10 \, a^{3} x^{3} + 15 \, a x + 8\right )} \log \left (a x + 1\right )\right )} \log \left (-a x + 1\right )}{150 \, {\left (a x - 1\right )}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int {\mathrm {atanh}\left (a\,x\right )}^3\,{\left (a^2\,x^2-1\right )}^2 \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (a x - 1\right )^{2} \left (a x + 1\right )^{2} \operatorname {atanh}^{3}{\left (a x \right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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