Optimal. Leaf size=171 \[ \frac {2 i \tanh ^{-1}(a x) \text {Li}_2\left (-i e^{\tanh ^{-1}(a x)}\right )}{a^3}-\frac {2 i \tanh ^{-1}(a x) \text {Li}_2\left (i e^{\tanh ^{-1}(a x)}\right )}{a^3}-\frac {2 i \text {Li}_3\left (-i e^{\tanh ^{-1}(a x)}\right )}{a^3}+\frac {2 i \text {Li}_3\left (i e^{\tanh ^{-1}(a x)}\right )}{a^3}-\frac {2 \tanh ^{-1}(a x)^2 \tan ^{-1}\left (e^{\tanh ^{-1}(a x)}\right )}{a^3}+\frac {2 x}{a^2 \sqrt {1-a^2 x^2}}+\frac {x \tanh ^{-1}(a x)^2}{a^2 \sqrt {1-a^2 x^2}}-\frac {2 \tanh ^{-1}(a x)}{a^3 \sqrt {1-a^2 x^2}} \]
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Rubi [A] time = 0.25, antiderivative size = 171, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 8, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {6028, 5952, 4180, 2531, 2282, 6589, 5962, 191} \[ \frac {2 i \tanh ^{-1}(a x) \text {PolyLog}\left (2,-i e^{\tanh ^{-1}(a x)}\right )}{a^3}-\frac {2 i \tanh ^{-1}(a x) \text {PolyLog}\left (2,i e^{\tanh ^{-1}(a x)}\right )}{a^3}-\frac {2 i \text {PolyLog}\left (3,-i e^{\tanh ^{-1}(a x)}\right )}{a^3}+\frac {2 i \text {PolyLog}\left (3,i e^{\tanh ^{-1}(a x)}\right )}{a^3}+\frac {2 x}{a^2 \sqrt {1-a^2 x^2}}+\frac {x \tanh ^{-1}(a x)^2}{a^2 \sqrt {1-a^2 x^2}}-\frac {2 \tanh ^{-1}(a x)}{a^3 \sqrt {1-a^2 x^2}}-\frac {2 \tanh ^{-1}(a x)^2 \tan ^{-1}\left (e^{\tanh ^{-1}(a x)}\right )}{a^3} \]
Antiderivative was successfully verified.
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Rule 191
Rule 2282
Rule 2531
Rule 4180
Rule 5952
Rule 5962
Rule 6028
Rule 6589
Rubi steps
\begin {align*} \int \frac {x^2 \tanh ^{-1}(a x)^2}{\left (1-a^2 x^2\right )^{3/2}} \, dx &=\frac {\int \frac {\tanh ^{-1}(a x)^2}{\left (1-a^2 x^2\right )^{3/2}} \, dx}{a^2}-\frac {\int \frac {\tanh ^{-1}(a x)^2}{\sqrt {1-a^2 x^2}} \, dx}{a^2}\\ &=-\frac {2 \tanh ^{-1}(a x)}{a^3 \sqrt {1-a^2 x^2}}+\frac {x \tanh ^{-1}(a x)^2}{a^2 \sqrt {1-a^2 x^2}}-\frac {\operatorname {Subst}\left (\int x^2 \text {sech}(x) \, dx,x,\tanh ^{-1}(a x)\right )}{a^3}+\frac {2 \int \frac {1}{\left (1-a^2 x^2\right )^{3/2}} \, dx}{a^2}\\ &=\frac {2 x}{a^2 \sqrt {1-a^2 x^2}}-\frac {2 \tanh ^{-1}(a x)}{a^3 \sqrt {1-a^2 x^2}}+\frac {x \tanh ^{-1}(a x)^2}{a^2 \sqrt {1-a^2 x^2}}-\frac {2 \tan ^{-1}\left (e^{\tanh ^{-1}(a x)}\right ) \tanh ^{-1}(a x)^2}{a^3}+\frac {(2 i) \operatorname {Subst}\left (\int x \log \left (1-i e^x\right ) \, dx,x,\tanh ^{-1}(a x)\right )}{a^3}-\frac {(2 i) \operatorname {Subst}\left (\int x \log \left (1+i e^x\right ) \, dx,x,\tanh ^{-1}(a x)\right )}{a^3}\\ &=\frac {2 x}{a^2 \sqrt {1-a^2 x^2}}-\frac {2 \tanh ^{-1}(a x)}{a^3 \sqrt {1-a^2 x^2}}+\frac {x \tanh ^{-1}(a x)^2}{a^2 \sqrt {1-a^2 x^2}}-\frac {2 \tan ^{-1}\left (e^{\tanh ^{-1}(a x)}\right ) \tanh ^{-1}(a x)^2}{a^3}+\frac {2 i \tanh ^{-1}(a x) \text {Li}_2\left (-i e^{\tanh ^{-1}(a x)}\right )}{a^3}-\frac {2 i \tanh ^{-1}(a x) \text {Li}_2\left (i e^{\tanh ^{-1}(a x)}\right )}{a^3}-\frac {(2 i) \operatorname {Subst}\left (\int \text {Li}_2\left (-i e^x\right ) \, dx,x,\tanh ^{-1}(a x)\right )}{a^3}+\frac {(2 i) \operatorname {Subst}\left (\int \text {Li}_2\left (i e^x\right ) \, dx,x,\tanh ^{-1}(a x)\right )}{a^3}\\ &=\frac {2 x}{a^2 \sqrt {1-a^2 x^2}}-\frac {2 \tanh ^{-1}(a x)}{a^3 \sqrt {1-a^2 x^2}}+\frac {x \tanh ^{-1}(a x)^2}{a^2 \sqrt {1-a^2 x^2}}-\frac {2 \tan ^{-1}\left (e^{\tanh ^{-1}(a x)}\right ) \tanh ^{-1}(a x)^2}{a^3}+\frac {2 i \tanh ^{-1}(a x) \text {Li}_2\left (-i e^{\tanh ^{-1}(a x)}\right )}{a^3}-\frac {2 i \tanh ^{-1}(a x) \text {Li}_2\left (i e^{\tanh ^{-1}(a x)}\right )}{a^3}-\frac {(2 i) \operatorname {Subst}\left (\int \frac {\text {Li}_2(-i x)}{x} \, dx,x,e^{\tanh ^{-1}(a x)}\right )}{a^3}+\frac {(2 i) \operatorname {Subst}\left (\int \frac {\text {Li}_2(i x)}{x} \, dx,x,e^{\tanh ^{-1}(a x)}\right )}{a^3}\\ &=\frac {2 x}{a^2 \sqrt {1-a^2 x^2}}-\frac {2 \tanh ^{-1}(a x)}{a^3 \sqrt {1-a^2 x^2}}+\frac {x \tanh ^{-1}(a x)^2}{a^2 \sqrt {1-a^2 x^2}}-\frac {2 \tan ^{-1}\left (e^{\tanh ^{-1}(a x)}\right ) \tanh ^{-1}(a x)^2}{a^3}+\frac {2 i \tanh ^{-1}(a x) \text {Li}_2\left (-i e^{\tanh ^{-1}(a x)}\right )}{a^3}-\frac {2 i \tanh ^{-1}(a x) \text {Li}_2\left (i e^{\tanh ^{-1}(a x)}\right )}{a^3}-\frac {2 i \text {Li}_3\left (-i e^{\tanh ^{-1}(a x)}\right )}{a^3}+\frac {2 i \text {Li}_3\left (i e^{\tanh ^{-1}(a x)}\right )}{a^3}\\ \end {align*}
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Mathematica [A] time = 0.35, size = 193, normalized size = 1.13 \[ \frac {i \left (-\frac {2 i a x}{\sqrt {1-a^2 x^2}}-\frac {i a x \tanh ^{-1}(a x)^2}{\sqrt {1-a^2 x^2}}+\frac {2 i \tanh ^{-1}(a x)}{\sqrt {1-a^2 x^2}}+2 \tanh ^{-1}(a x) \text {Li}_2\left (-i e^{-\tanh ^{-1}(a x)}\right )-2 \tanh ^{-1}(a x) \text {Li}_2\left (i e^{-\tanh ^{-1}(a x)}\right )+2 \text {Li}_3\left (-i e^{-\tanh ^{-1}(a x)}\right )-2 \text {Li}_3\left (i e^{-\tanh ^{-1}(a x)}\right )+\tanh ^{-1}(a x)^2 \log \left (1-i e^{-\tanh ^{-1}(a x)}\right )-\tanh ^{-1}(a x)^2 \log \left (1+i e^{-\tanh ^{-1}(a x)}\right )\right )}{a^3} \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.40, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\sqrt {-a^{2} x^{2} + 1} x^{2} \operatorname {artanh}\left (a x\right )^{2}}{a^{4} x^{4} - 2 \, a^{2} x^{2} + 1}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{2} \operatorname {artanh}\left (a x\right )^{2}}{{\left (-a^{2} x^{2} + 1\right )}^{\frac {3}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.40, size = 0, normalized size = 0.00 \[ \int \frac {x^{2} \arctanh \left (a x \right )^{2}}{\left (-a^{2} x^{2}+1\right )^{\frac {3}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{2} \operatorname {artanh}\left (a x\right )^{2}}{{\left (-a^{2} x^{2} + 1\right )}^{\frac {3}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {x^2\,{\mathrm {atanh}\left (a\,x\right )}^2}{{\left (1-a^2\,x^2\right )}^{3/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{2} \operatorname {atanh}^{2}{\left (a x \right )}}{\left (- \left (a x - 1\right ) \left (a x + 1\right )\right )^{\frac {3}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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