Optimal. Leaf size=187 \[ -\frac {6 a}{\sqrt {1-a^2 x^2}}-\frac {\sqrt {1-a^2 x^2} \tanh ^{-1}(a x)^3}{x}+\frac {a^2 x \tanh ^{-1}(a x)^3}{\sqrt {1-a^2 x^2}}-\frac {3 a \tanh ^{-1}(a x)^2}{\sqrt {1-a^2 x^2}}+\frac {6 a^2 x \tanh ^{-1}(a x)}{\sqrt {1-a^2 x^2}}-6 a \tanh ^{-1}(a x) \text {Li}_2\left (-e^{\tanh ^{-1}(a x)}\right )+6 a \tanh ^{-1}(a x) \text {Li}_2\left (e^{\tanh ^{-1}(a x)}\right )+6 a \text {Li}_3\left (-e^{\tanh ^{-1}(a x)}\right )-6 a \text {Li}_3\left (e^{\tanh ^{-1}(a x)}\right )-6 a \tanh ^{-1}\left (e^{\tanh ^{-1}(a x)}\right ) \tanh ^{-1}(a x)^2 \]
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Rubi [A] time = 0.42, antiderivative size = 187, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 9, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {6030, 6008, 6020, 4182, 2531, 2282, 6589, 5962, 5958} \[ -6 a \tanh ^{-1}(a x) \text {PolyLog}\left (2,-e^{\tanh ^{-1}(a x)}\right )+6 a \tanh ^{-1}(a x) \text {PolyLog}\left (2,e^{\tanh ^{-1}(a x)}\right )+6 a \text {PolyLog}\left (3,-e^{\tanh ^{-1}(a x)}\right )-6 a \text {PolyLog}\left (3,e^{\tanh ^{-1}(a x)}\right )-\frac {6 a}{\sqrt {1-a^2 x^2}}-\frac {\sqrt {1-a^2 x^2} \tanh ^{-1}(a x)^3}{x}+\frac {a^2 x \tanh ^{-1}(a x)^3}{\sqrt {1-a^2 x^2}}-\frac {3 a \tanh ^{-1}(a x)^2}{\sqrt {1-a^2 x^2}}+\frac {6 a^2 x \tanh ^{-1}(a x)}{\sqrt {1-a^2 x^2}}-6 a \tanh ^{-1}\left (e^{\tanh ^{-1}(a x)}\right ) \tanh ^{-1}(a x)^2 \]
Antiderivative was successfully verified.
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Rule 2282
Rule 2531
Rule 4182
Rule 5958
Rule 5962
Rule 6008
Rule 6020
Rule 6030
Rule 6589
Rubi steps
\begin {align*} \int \frac {\tanh ^{-1}(a x)^3}{x^2 \left (1-a^2 x^2\right )^{3/2}} \, dx &=a^2 \int \frac {\tanh ^{-1}(a x)^3}{\left (1-a^2 x^2\right )^{3/2}} \, dx+\int \frac {\tanh ^{-1}(a x)^3}{x^2 \sqrt {1-a^2 x^2}} \, dx\\ &=-\frac {3 a \tanh ^{-1}(a x)^2}{\sqrt {1-a^2 x^2}}+\frac {a^2 x \tanh ^{-1}(a x)^3}{\sqrt {1-a^2 x^2}}-\frac {\sqrt {1-a^2 x^2} \tanh ^{-1}(a x)^3}{x}+(3 a) \int \frac {\tanh ^{-1}(a x)^2}{x \sqrt {1-a^2 x^2}} \, dx+\left (6 a^2\right ) \int \frac {\tanh ^{-1}(a x)}{\left (1-a^2 x^2\right )^{3/2}} \, dx\\ &=-\frac {6 a}{\sqrt {1-a^2 x^2}}+\frac {6 a^2 x \tanh ^{-1}(a x)}{\sqrt {1-a^2 x^2}}-\frac {3 a \tanh ^{-1}(a x)^2}{\sqrt {1-a^2 x^2}}+\frac {a^2 x \tanh ^{-1}(a x)^3}{\sqrt {1-a^2 x^2}}-\frac {\sqrt {1-a^2 x^2} \tanh ^{-1}(a x)^3}{x}+(3 a) \operatorname {Subst}\left (\int x^2 \text {csch}(x) \, dx,x,\tanh ^{-1}(a x)\right )\\ &=-\frac {6 a}{\sqrt {1-a^2 x^2}}+\frac {6 a^2 x \tanh ^{-1}(a x)}{\sqrt {1-a^2 x^2}}-\frac {3 a \tanh ^{-1}(a x)^2}{\sqrt {1-a^2 x^2}}-6 a \tanh ^{-1}\left (e^{\tanh ^{-1}(a x)}\right ) \tanh ^{-1}(a x)^2+\frac {a^2 x \tanh ^{-1}(a x)^3}{\sqrt {1-a^2 x^2}}-\frac {\sqrt {1-a^2 x^2} \tanh ^{-1}(a x)^3}{x}-(6 a) \operatorname {Subst}\left (\int x \log \left (1-e^x\right ) \, dx,x,\tanh ^{-1}(a x)\right )+(6 a) \operatorname {Subst}\left (\int x \log \left (1+e^x\right ) \, dx,x,\tanh ^{-1}(a x)\right )\\ &=-\frac {6 a}{\sqrt {1-a^2 x^2}}+\frac {6 a^2 x \tanh ^{-1}(a x)}{\sqrt {1-a^2 x^2}}-\frac {3 a \tanh ^{-1}(a x)^2}{\sqrt {1-a^2 x^2}}-6 a \tanh ^{-1}\left (e^{\tanh ^{-1}(a x)}\right ) \tanh ^{-1}(a x)^2+\frac {a^2 x \tanh ^{-1}(a x)^3}{\sqrt {1-a^2 x^2}}-\frac {\sqrt {1-a^2 x^2} \tanh ^{-1}(a x)^3}{x}-6 a \tanh ^{-1}(a x) \text {Li}_2\left (-e^{\tanh ^{-1}(a x)}\right )+6 a \tanh ^{-1}(a x) \text {Li}_2\left (e^{\tanh ^{-1}(a x)}\right )+(6 a) \operatorname {Subst}\left (\int \text {Li}_2\left (-e^x\right ) \, dx,x,\tanh ^{-1}(a x)\right )-(6 a) \operatorname {Subst}\left (\int \text {Li}_2\left (e^x\right ) \, dx,x,\tanh ^{-1}(a x)\right )\\ &=-\frac {6 a}{\sqrt {1-a^2 x^2}}+\frac {6 a^2 x \tanh ^{-1}(a x)}{\sqrt {1-a^2 x^2}}-\frac {3 a \tanh ^{-1}(a x)^2}{\sqrt {1-a^2 x^2}}-6 a \tanh ^{-1}\left (e^{\tanh ^{-1}(a x)}\right ) \tanh ^{-1}(a x)^2+\frac {a^2 x \tanh ^{-1}(a x)^3}{\sqrt {1-a^2 x^2}}-\frac {\sqrt {1-a^2 x^2} \tanh ^{-1}(a x)^3}{x}-6 a \tanh ^{-1}(a x) \text {Li}_2\left (-e^{\tanh ^{-1}(a x)}\right )+6 a \tanh ^{-1}(a x) \text {Li}_2\left (e^{\tanh ^{-1}(a x)}\right )+(6 a) \operatorname {Subst}\left (\int \frac {\text {Li}_2(-x)}{x} \, dx,x,e^{\tanh ^{-1}(a x)}\right )-(6 a) \operatorname {Subst}\left (\int \frac {\text {Li}_2(x)}{x} \, dx,x,e^{\tanh ^{-1}(a x)}\right )\\ &=-\frac {6 a}{\sqrt {1-a^2 x^2}}+\frac {6 a^2 x \tanh ^{-1}(a x)}{\sqrt {1-a^2 x^2}}-\frac {3 a \tanh ^{-1}(a x)^2}{\sqrt {1-a^2 x^2}}-6 a \tanh ^{-1}\left (e^{\tanh ^{-1}(a x)}\right ) \tanh ^{-1}(a x)^2+\frac {a^2 x \tanh ^{-1}(a x)^3}{\sqrt {1-a^2 x^2}}-\frac {\sqrt {1-a^2 x^2} \tanh ^{-1}(a x)^3}{x}-6 a \tanh ^{-1}(a x) \text {Li}_2\left (-e^{\tanh ^{-1}(a x)}\right )+6 a \tanh ^{-1}(a x) \text {Li}_2\left (e^{\tanh ^{-1}(a x)}\right )+6 a \text {Li}_3\left (-e^{\tanh ^{-1}(a x)}\right )-6 a \text {Li}_3\left (e^{\tanh ^{-1}(a x)}\right )\\ \end {align*}
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Mathematica [A] time = 2.00, size = 270, normalized size = 1.44 \[ -\frac {6 a}{\sqrt {1-a^2 x^2}}+\frac {a^2 x \tanh ^{-1}(a x)^3}{\sqrt {1-a^2 x^2}}-\frac {3 a \tanh ^{-1}(a x)^2}{\sqrt {1-a^2 x^2}}+\frac {6 a^2 x \tanh ^{-1}(a x)}{\sqrt {1-a^2 x^2}}+\frac {\sqrt {1-a^2 x^2} \tanh ^{-1}(a x)^3 \sinh ^2\left (\frac {1}{2} \tanh ^{-1}(a x)\right )}{x}-\frac {a^2 x \tanh ^{-1}(a x)^3 \text {csch}^2\left (\frac {1}{2} \tanh ^{-1}(a x)\right )}{4 \sqrt {1-a^2 x^2}}+6 a \tanh ^{-1}(a x) \text {Li}_2\left (-e^{-\tanh ^{-1}(a x)}\right )-6 a \tanh ^{-1}(a x) \text {Li}_2\left (e^{-\tanh ^{-1}(a x)}\right )+6 a \text {Li}_3\left (-e^{-\tanh ^{-1}(a x)}\right )-6 a \text {Li}_3\left (e^{-\tanh ^{-1}(a x)}\right )+3 a \tanh ^{-1}(a x)^2 \log \left (1-e^{-\tanh ^{-1}(a x)}\right )-3 a \tanh ^{-1}(a x)^2 \log \left (e^{-\tanh ^{-1}(a x)}+1\right ) \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.50, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\sqrt {-a^{2} x^{2} + 1} \operatorname {artanh}\left (a x\right )^{3}}{a^{4} x^{6} - 2 \, a^{2} x^{4} + x^{2}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {artanh}\left (a x\right )^{3}}{{\left (-a^{2} x^{2} + 1\right )}^{\frac {3}{2}} x^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.48, size = 282, normalized size = 1.51 \[ -\frac {a \left (\arctanh \left (a x \right )^{3}-3 \arctanh \left (a x \right )^{2}+6 \arctanh \left (a x \right )-6\right ) \sqrt {-\left (a x -1\right ) \left (a x +1\right )}}{2 \left (a x -1\right )}-\frac {\left (\arctanh \left (a x \right )^{3}+3 \arctanh \left (a x \right )^{2}+6 \arctanh \left (a x \right )+6\right ) a \sqrt {-\left (a x -1\right ) \left (a x +1\right )}}{2 \left (a x +1\right )}-\frac {\sqrt {-\left (a x -1\right ) \left (a x +1\right )}\, \arctanh \left (a x \right )^{3}}{x}-3 a \arctanh \left (a x \right )^{2} \ln \left (1+\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )-6 a \arctanh \left (a x \right ) \polylog \left (2, -\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )+6 a \polylog \left (3, -\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )+3 a \arctanh \left (a x \right )^{2} \ln \left (1-\frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )+6 a \arctanh \left (a x \right ) \polylog \left (2, \frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right )-6 a \polylog \left (3, \frac {a x +1}{\sqrt {-a^{2} x^{2}+1}}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {artanh}\left (a x\right )^{3}}{{\left (-a^{2} x^{2} + 1\right )}^{\frac {3}{2}} x^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\mathrm {atanh}\left (a\,x\right )}^3}{x^2\,{\left (1-a^2\,x^2\right )}^{3/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {atanh}^{3}{\left (a x \right )}}{x^{2} \left (- \left (a x - 1\right ) \left (a x + 1\right )\right )^{\frac {3}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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