Optimal. Leaf size=156 \[ -\frac {7 a^2 \sqrt {c-\frac {c}{a^2 x^2}}}{8 x}+\frac {2 a \sqrt {c-\frac {c}{a^2 x^2}}}{3 x^2}-\frac {\sqrt {c-\frac {c}{a^2 x^2}}}{4 x^3}-\frac {7 a^4 x \sqrt {c-\frac {c}{a^2 x^2}} \tanh ^{-1}\left (\sqrt {1-a x} \sqrt {a x+1}\right )}{8 \sqrt {1-a x} \sqrt {a x+1}}+\frac {4}{3} a^3 \sqrt {c-\frac {c}{a^2 x^2}} \]
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Rubi [A] time = 0.42, antiderivative size = 156, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 7, integrand size = 27, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.259, Rules used = {6159, 6129, 98, 151, 12, 92, 208} \[ \frac {4}{3} a^3 \sqrt {c-\frac {c}{a^2 x^2}}-\frac {7 a^2 \sqrt {c-\frac {c}{a^2 x^2}}}{8 x}+\frac {2 a \sqrt {c-\frac {c}{a^2 x^2}}}{3 x^2}-\frac {\sqrt {c-\frac {c}{a^2 x^2}}}{4 x^3}-\frac {7 a^4 x \sqrt {c-\frac {c}{a^2 x^2}} \tanh ^{-1}\left (\sqrt {1-a x} \sqrt {a x+1}\right )}{8 \sqrt {1-a x} \sqrt {a x+1}} \]
Antiderivative was successfully verified.
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Rule 12
Rule 92
Rule 98
Rule 151
Rule 208
Rule 6129
Rule 6159
Rubi steps
\begin {align*} \int \frac {e^{-2 \tanh ^{-1}(a x)} \sqrt {c-\frac {c}{a^2 x^2}}}{x^4} \, dx &=\frac {\left (\sqrt {c-\frac {c}{a^2 x^2}} x\right ) \int \frac {e^{-2 \tanh ^{-1}(a x)} \sqrt {1-a x} \sqrt {1+a x}}{x^5} \, dx}{\sqrt {1-a x} \sqrt {1+a x}}\\ &=\frac {\left (\sqrt {c-\frac {c}{a^2 x^2}} x\right ) \int \frac {(1-a x)^{3/2}}{x^5 \sqrt {1+a x}} \, dx}{\sqrt {1-a x} \sqrt {1+a x}}\\ &=-\frac {\sqrt {c-\frac {c}{a^2 x^2}}}{4 x^3}-\frac {\left (\sqrt {c-\frac {c}{a^2 x^2}} x\right ) \int \frac {8 a-7 a^2 x}{x^4 \sqrt {1-a x} \sqrt {1+a x}} \, dx}{4 \sqrt {1-a x} \sqrt {1+a x}}\\ &=-\frac {\sqrt {c-\frac {c}{a^2 x^2}}}{4 x^3}+\frac {2 a \sqrt {c-\frac {c}{a^2 x^2}}}{3 x^2}+\frac {\left (\sqrt {c-\frac {c}{a^2 x^2}} x\right ) \int \frac {21 a^2-16 a^3 x}{x^3 \sqrt {1-a x} \sqrt {1+a x}} \, dx}{12 \sqrt {1-a x} \sqrt {1+a x}}\\ &=-\frac {\sqrt {c-\frac {c}{a^2 x^2}}}{4 x^3}+\frac {2 a \sqrt {c-\frac {c}{a^2 x^2}}}{3 x^2}-\frac {7 a^2 \sqrt {c-\frac {c}{a^2 x^2}}}{8 x}-\frac {\left (\sqrt {c-\frac {c}{a^2 x^2}} x\right ) \int \frac {32 a^3-21 a^4 x}{x^2 \sqrt {1-a x} \sqrt {1+a x}} \, dx}{24 \sqrt {1-a x} \sqrt {1+a x}}\\ &=\frac {4}{3} a^3 \sqrt {c-\frac {c}{a^2 x^2}}-\frac {\sqrt {c-\frac {c}{a^2 x^2}}}{4 x^3}+\frac {2 a \sqrt {c-\frac {c}{a^2 x^2}}}{3 x^2}-\frac {7 a^2 \sqrt {c-\frac {c}{a^2 x^2}}}{8 x}+\frac {\left (\sqrt {c-\frac {c}{a^2 x^2}} x\right ) \int \frac {21 a^4}{x \sqrt {1-a x} \sqrt {1+a x}} \, dx}{24 \sqrt {1-a x} \sqrt {1+a x}}\\ &=\frac {4}{3} a^3 \sqrt {c-\frac {c}{a^2 x^2}}-\frac {\sqrt {c-\frac {c}{a^2 x^2}}}{4 x^3}+\frac {2 a \sqrt {c-\frac {c}{a^2 x^2}}}{3 x^2}-\frac {7 a^2 \sqrt {c-\frac {c}{a^2 x^2}}}{8 x}+\frac {\left (7 a^4 \sqrt {c-\frac {c}{a^2 x^2}} x\right ) \int \frac {1}{x \sqrt {1-a x} \sqrt {1+a x}} \, dx}{8 \sqrt {1-a x} \sqrt {1+a x}}\\ &=\frac {4}{3} a^3 \sqrt {c-\frac {c}{a^2 x^2}}-\frac {\sqrt {c-\frac {c}{a^2 x^2}}}{4 x^3}+\frac {2 a \sqrt {c-\frac {c}{a^2 x^2}}}{3 x^2}-\frac {7 a^2 \sqrt {c-\frac {c}{a^2 x^2}}}{8 x}-\frac {\left (7 a^5 \sqrt {c-\frac {c}{a^2 x^2}} x\right ) \operatorname {Subst}\left (\int \frac {1}{a-a x^2} \, dx,x,\sqrt {1-a x} \sqrt {1+a x}\right )}{8 \sqrt {1-a x} \sqrt {1+a x}}\\ &=\frac {4}{3} a^3 \sqrt {c-\frac {c}{a^2 x^2}}-\frac {\sqrt {c-\frac {c}{a^2 x^2}}}{4 x^3}+\frac {2 a \sqrt {c-\frac {c}{a^2 x^2}}}{3 x^2}-\frac {7 a^2 \sqrt {c-\frac {c}{a^2 x^2}}}{8 x}-\frac {7 a^4 \sqrt {c-\frac {c}{a^2 x^2}} x \tanh ^{-1}\left (\sqrt {1-a x} \sqrt {1+a x}\right )}{8 \sqrt {1-a x} \sqrt {1+a x}}\\ \end {align*}
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Mathematica [A] time = 0.08, size = 94, normalized size = 0.60 \[ \frac {\sqrt {c-\frac {c}{a^2 x^2}} \left (21 a^4 x^4 \tan ^{-1}\left (\frac {1}{\sqrt {a^2 x^2-1}}\right )+\sqrt {a^2 x^2-1} \left (32 a^3 x^3-21 a^2 x^2+16 a x-6\right )\right )}{24 x^3 \sqrt {a^2 x^2-1}} \]
Warning: Unable to verify antiderivative.
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fricas [A] time = 1.58, size = 216, normalized size = 1.38 \[ \left [\frac {21 \, a^{3} \sqrt {-c} x^{3} \log \left (-\frac {a^{2} c x^{2} - 2 \, a \sqrt {-c} x \sqrt {\frac {a^{2} c x^{2} - c}{a^{2} x^{2}}} - 2 \, c}{x^{2}}\right ) + 2 \, {\left (32 \, a^{3} x^{3} - 21 \, a^{2} x^{2} + 16 \, a x - 6\right )} \sqrt {\frac {a^{2} c x^{2} - c}{a^{2} x^{2}}}}{48 \, x^{3}}, \frac {21 \, a^{3} \sqrt {c} x^{3} \arctan \left (\frac {a \sqrt {c} x \sqrt {\frac {a^{2} c x^{2} - c}{a^{2} x^{2}}}}{a^{2} c x^{2} - c}\right ) + {\left (32 \, a^{3} x^{3} - 21 \, a^{2} x^{2} + 16 \, a x - 6\right )} \sqrt {\frac {a^{2} c x^{2} - c}{a^{2} x^{2}}}}{24 \, x^{3}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 6.17, size = 316, normalized size = 2.03 \[ -\frac {1}{12} \, {\left (21 \, a^{2} \sqrt {c} \arctan \left (-\frac {\sqrt {a^{2} c} x - \sqrt {a^{2} c x^{2} - c}}{\sqrt {c}}\right ) \mathrm {sgn}\relax (x) - \frac {21 \, {\left (\sqrt {a^{2} c} x - \sqrt {a^{2} c x^{2} - c}\right )}^{7} a^{2} c \mathrm {sgn}\relax (x) + 45 \, {\left (\sqrt {a^{2} c} x - \sqrt {a^{2} c x^{2} - c}\right )}^{5} a^{2} c^{2} \mathrm {sgn}\relax (x) + 96 \, {\left (\sqrt {a^{2} c} x - \sqrt {a^{2} c x^{2} - c}\right )}^{4} a c^{\frac {5}{2}} {\left | a \right |} \mathrm {sgn}\relax (x) - 45 \, {\left (\sqrt {a^{2} c} x - \sqrt {a^{2} c x^{2} - c}\right )}^{3} a^{2} c^{3} \mathrm {sgn}\relax (x) + 128 \, {\left (\sqrt {a^{2} c} x - \sqrt {a^{2} c x^{2} - c}\right )}^{2} a c^{\frac {7}{2}} {\left | a \right |} \mathrm {sgn}\relax (x) - 21 \, {\left (\sqrt {a^{2} c} x - \sqrt {a^{2} c x^{2} - c}\right )} a^{2} c^{4} \mathrm {sgn}\relax (x) + 32 \, a c^{\frac {9}{2}} {\left | a \right |} \mathrm {sgn}\relax (x)}{{\left ({\left (\sqrt {a^{2} c} x - \sqrt {a^{2} c x^{2} - c}\right )}^{2} + c\right )}^{4}}\right )} {\left | a \right |} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.05, size = 410, normalized size = 2.63 \[ -\frac {\sqrt {\frac {c \left (a^{2} x^{2}-1\right )}{a^{2} x^{2}}}\, a^{2} \left (-48 \sqrt {-\frac {c}{a^{2}}}\, \sqrt {\frac {c \left (a^{2} x^{2}-1\right )}{a^{2}}}\, x^{5} a^{3} c +48 \sqrt {-\frac {c}{a^{2}}}\, \left (\frac {c \left (a^{2} x^{2}-1\right )}{a^{2}}\right )^{\frac {3}{2}} x^{3} a^{3}+48 \sqrt {-\frac {c}{a^{2}}}\, c^{\frac {3}{2}} \ln \left (x \sqrt {c}+\sqrt {\frac {c \left (a^{2} x^{2}-1\right )}{a^{2}}}\right ) x^{4} a -48 \sqrt {-\frac {c}{a^{2}}}\, c^{\frac {3}{2}} \ln \left (\frac {\sqrt {c}\, \sqrt {\frac {\left (a x -1\right ) \left (a x +1\right ) c}{a^{2}}}+c x}{\sqrt {c}}\right ) x^{4} a +48 \sqrt {-\frac {c}{a^{2}}}\, \sqrt {\frac {\left (a x -1\right ) \left (a x +1\right ) c}{a^{2}}}\, x^{4} a^{2} c -21 \sqrt {-\frac {c}{a^{2}}}\, \sqrt {\frac {c \left (a^{2} x^{2}-1\right )}{a^{2}}}\, x^{4} a^{2} c -27 \sqrt {-\frac {c}{a^{2}}}\, \left (\frac {c \left (a^{2} x^{2}-1\right )}{a^{2}}\right )^{\frac {3}{2}} x^{2} a^{2}-21 \ln \left (\frac {2 \sqrt {-\frac {c}{a^{2}}}\, \sqrt {\frac {c \left (a^{2} x^{2}-1\right )}{a^{2}}}\, a^{2}-2 c}{a^{2} x}\right ) x^{4} c^{2}+16 a \left (\frac {c \left (a^{2} x^{2}-1\right )}{a^{2}}\right )^{\frac {3}{2}} \sqrt {-\frac {c}{a^{2}}}\, x -6 \left (\frac {c \left (a^{2} x^{2}-1\right )}{a^{2}}\right )^{\frac {3}{2}} \sqrt {-\frac {c}{a^{2}}}\right )}{24 x^{3} \sqrt {-\frac {c}{a^{2}}}\, \sqrt {\frac {c \left (a^{2} x^{2}-1\right )}{a^{2}}}\, c} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -\int \frac {{\left (a^{2} x^{2} - 1\right )} \sqrt {c - \frac {c}{a^{2} x^{2}}}}{{\left (a x + 1\right )}^{2} x^{4}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ -\int \frac {\sqrt {c-\frac {c}{a^2\,x^2}}\,\left (a^2\,x^2-1\right )}{x^4\,{\left (a\,x+1\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ - \int \left (- \frac {\sqrt {c - \frac {c}{a^{2} x^{2}}}}{a x^{5} + x^{4}}\right )\, dx - \int \frac {a x \sqrt {c - \frac {c}{a^{2} x^{2}}}}{a x^{5} + x^{4}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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