3.125 \(\int \text {Chi}(a+b x) \sinh (a+b x) \, dx\)

Optimal. Leaf size=46 \[ -\frac {\text {Chi}(2 a+2 b x)}{2 b}+\frac {\text {Chi}(a+b x) \cosh (a+b x)}{b}-\frac {\log (a+b x)}{2 b} \]

[Out]

-1/2*Chi(2*b*x+2*a)/b+Chi(b*x+a)*cosh(b*x+a)/b-1/2*ln(b*x+a)/b

________________________________________________________________________________________

Rubi [A]  time = 0.08, antiderivative size = 46, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {6547, 3312, 3301} \[ -\frac {\text {Chi}(2 a+2 b x)}{2 b}+\frac {\text {Chi}(a+b x) \cosh (a+b x)}{b}-\frac {\log (a+b x)}{2 b} \]

Antiderivative was successfully verified.

[In]

Int[CoshIntegral[a + b*x]*Sinh[a + b*x],x]

[Out]

(Cosh[a + b*x]*CoshIntegral[a + b*x])/b - CoshIntegral[2*a + 2*b*x]/(2*b) - Log[a + b*x]/(2*b)

Rule 3301

Int[sin[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbol] :> Simp[CoshIntegral[(c*f*fz)/d
+ f*fz*x]/d, x] /; FreeQ[{c, d, e, f, fz}, x] && EqQ[d*(e - Pi/2) - c*f*fz*I, 0]

Rule 3312

Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sin
[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1])
)

Rule 6547

Int[CoshIntegral[(c_.) + (d_.)*(x_)]*Sinh[(a_.) + (b_.)*(x_)], x_Symbol] :> Simp[(Cosh[a + b*x]*CoshIntegral[c
+ d*x])/b, x] - Dist[d/b, Int[(Cosh[a + b*x]*Cosh[c + d*x])/(c + d*x), x], x] /; FreeQ[{a, b, c, d}, x]

Rubi steps

\begin {align*} \int \text {Chi}(a+b x) \sinh (a+b x) \, dx &=\frac {\cosh (a+b x) \text {Chi}(a+b x)}{b}-\int \frac {\cosh ^2(a+b x)}{a+b x} \, dx\\ &=\frac {\cosh (a+b x) \text {Chi}(a+b x)}{b}-\int \left (\frac {1}{2 (a+b x)}+\frac {\cosh (2 a+2 b x)}{2 (a+b x)}\right ) \, dx\\ &=\frac {\cosh (a+b x) \text {Chi}(a+b x)}{b}-\frac {\log (a+b x)}{2 b}-\frac {1}{2} \int \frac {\cosh (2 a+2 b x)}{a+b x} \, dx\\ &=\frac {\cosh (a+b x) \text {Chi}(a+b x)}{b}-\frac {\text {Chi}(2 a+2 b x)}{2 b}-\frac {\log (a+b x)}{2 b}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.02, size = 45, normalized size = 0.98 \[ -\frac {\text {Chi}(2 (a+b x))}{2 b}+\frac {\text {Chi}(a+b x) \cosh (a+b x)}{b}-\frac {\log (a+b x)}{2 b} \]

Antiderivative was successfully verified.

[In]

Integrate[CoshIntegral[a + b*x]*Sinh[a + b*x],x]

[Out]

(Cosh[a + b*x]*CoshIntegral[a + b*x])/b - CoshIntegral[2*(a + b*x)]/(2*b) - Log[a + b*x]/(2*b)

________________________________________________________________________________________

fricas [F]  time = 4.05, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\operatorname {Chi}\left (b x + a\right ) \sinh \left (b x + a\right ), x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(Chi(b*x+a)*sinh(b*x+a),x, algorithm="fricas")

[Out]

integral(cosh_integral(b*x + a)*sinh(b*x + a), x)

________________________________________________________________________________________

giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\rm Chi}\left (b x + a\right ) \sinh \left (b x + a\right )\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(Chi(b*x+a)*sinh(b*x+a),x, algorithm="giac")

[Out]

integrate(Chi(b*x + a)*sinh(b*x + a), x)

________________________________________________________________________________________

maple [A]  time = 0.01, size = 43, normalized size = 0.93 \[ -\frac {\Chi \left (2 b x +2 a \right )}{2 b}+\frac {\Chi \left (b x +a \right ) \cosh \left (b x +a \right )}{b}-\frac {\ln \left (b x +a \right )}{2 b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(Chi(b*x+a)*sinh(b*x+a),x)

[Out]

-1/2*Chi(2*b*x+2*a)/b+Chi(b*x+a)*cosh(b*x+a)/b-1/2*ln(b*x+a)/b

________________________________________________________________________________________

maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\rm Chi}\left (b x + a\right ) \sinh \left (b x + a\right )\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(Chi(b*x+a)*sinh(b*x+a),x, algorithm="maxima")

[Out]

integrate(Chi(b*x + a)*sinh(b*x + a), x)

________________________________________________________________________________________

mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \mathrm {coshint}\left (a+b\,x\right )\,\mathrm {sinh}\left (a+b\,x\right ) \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(coshint(a + b*x)*sinh(a + b*x),x)

[Out]

int(coshint(a + b*x)*sinh(a + b*x), x)

________________________________________________________________________________________

sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sinh {\left (a + b x \right )} \operatorname {Chi}\left (a + b x\right )\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(Chi(b*x+a)*sinh(b*x+a),x)

[Out]

Integral(sinh(a + b*x)*Chi(a + b*x), x)

________________________________________________________________________________________