Optimal. Leaf size=78 \[ \frac {a (d x)^{m+2} \, _2F_1(1,m+2;m+3;a x)}{d^2 (m+1)^2 (m+2)}+\frac {\text {Li}_2(a x) (d x)^{m+1}}{d (m+1)}+\frac {\log (1-a x) (d x)^{m+1}}{d (m+1)^2} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.05, antiderivative size = 78, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.273, Rules used = {6591, 2395, 64} \[ \frac {(d x)^{m+1} \text {PolyLog}(2,a x)}{d (m+1)}+\frac {a (d x)^{m+2} \, _2F_1(1,m+2;m+3;a x)}{d^2 (m+1)^2 (m+2)}+\frac {\log (1-a x) (d x)^{m+1}}{d (m+1)^2} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 64
Rule 2395
Rule 6591
Rubi steps
\begin {align*} \int (d x)^m \text {Li}_2(a x) \, dx &=\frac {(d x)^{1+m} \text {Li}_2(a x)}{d (1+m)}+\frac {\int (d x)^m \log (1-a x) \, dx}{1+m}\\ &=\frac {(d x)^{1+m} \log (1-a x)}{d (1+m)^2}+\frac {(d x)^{1+m} \text {Li}_2(a x)}{d (1+m)}+\frac {a \int \frac {(d x)^{1+m}}{1-a x} \, dx}{d (1+m)^2}\\ &=\frac {a (d x)^{2+m} \, _2F_1(1,2+m;3+m;a x)}{d^2 (1+m)^2 (2+m)}+\frac {(d x)^{1+m} \log (1-a x)}{d (1+m)^2}+\frac {(d x)^{1+m} \text {Li}_2(a x)}{d (1+m)}\\ \end {align*}
________________________________________________________________________________________
Mathematica [A] time = 0.04, size = 53, normalized size = 0.68 \[ \frac {x (d x)^m (a x \, _2F_1(1,m+2;m+3;a x)+(m+2) ((m+1) \text {Li}_2(a x)+\log (1-a x)))}{(m+1)^2 (m+2)} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
fricas [F] time = 0.64, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\left (d x\right )^{m} {\rm Li}_2\left (a x\right ), x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (d x\right )^{m} {\rm Li}_2\left (a x\right )\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maple [C] time = 0.14, size = 144, normalized size = 1.85 \[ \frac {\left (d x \right )^{m} x^{-m} \left (-a \right )^{-m} \left (\frac {x^{m} \left (-a \right )^{m} \left (-a \,m^{2} x -2 a m x -m^{2}-3 m -2\right )}{\left (m +2\right ) \left (1+m \right )^{3} m}-\frac {x^{1+m} \left (-a \right )^{m} a \left (-2-m \right ) \ln \left (-a x +1\right )}{\left (m +2\right ) \left (1+m \right )^{2}}+\frac {x^{1+m} \left (-a \right )^{m} a \polylog \left (2, a x \right )}{1+m}+\frac {x^{m} \left (-a \right )^{m} \Phi \left (a x , 1, m\right )}{\left (1+m \right )^{2}}\right )}{a} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -a d^{m} \int -\frac {x x^{m}}{m^{2} - {\left (a m^{2} + 2 \, a m + a\right )} x + 2 \, m + 1}\,{d x} + \frac {{\left (d^{m} m + d^{m}\right )} x x^{m} {\rm Li}_2\left (a x\right ) + d^{m} x x^{m} \log \left (-a x + 1\right )}{m^{2} + 2 \, m + 1} \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int {\left (d\,x\right )}^m\,\mathrm {polylog}\left (2,a\,x\right ) \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (d x\right )^{m} \operatorname {Li}_{2}\left (a x\right )\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________