Optimal. Leaf size=80 \[ \frac {2 \sqrt {d x} \text {Li}_2(a x)}{d}+\frac {4 \sqrt {d x} \log (1-a x)}{d}+\frac {8 \tanh ^{-1}\left (\frac {\sqrt {a} \sqrt {d x}}{\sqrt {d}}\right )}{\sqrt {a} \sqrt {d}}-\frac {8 \sqrt {d x}}{d} \]
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Rubi [A] time = 0.05, antiderivative size = 80, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.385, Rules used = {6591, 2395, 50, 63, 206} \[ \frac {2 \sqrt {d x} \text {PolyLog}(2,a x)}{d}+\frac {4 \sqrt {d x} \log (1-a x)}{d}+\frac {8 \tanh ^{-1}\left (\frac {\sqrt {a} \sqrt {d x}}{\sqrt {d}}\right )}{\sqrt {a} \sqrt {d}}-\frac {8 \sqrt {d x}}{d} \]
Antiderivative was successfully verified.
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Rule 50
Rule 63
Rule 206
Rule 2395
Rule 6591
Rubi steps
\begin {align*} \int \frac {\text {Li}_2(a x)}{\sqrt {d x}} \, dx &=\frac {2 \sqrt {d x} \text {Li}_2(a x)}{d}+2 \int \frac {\log (1-a x)}{\sqrt {d x}} \, dx\\ &=\frac {4 \sqrt {d x} \log (1-a x)}{d}+\frac {2 \sqrt {d x} \text {Li}_2(a x)}{d}+\frac {(4 a) \int \frac {\sqrt {d x}}{1-a x} \, dx}{d}\\ &=-\frac {8 \sqrt {d x}}{d}+\frac {4 \sqrt {d x} \log (1-a x)}{d}+\frac {2 \sqrt {d x} \text {Li}_2(a x)}{d}+4 \int \frac {1}{\sqrt {d x} (1-a x)} \, dx\\ &=-\frac {8 \sqrt {d x}}{d}+\frac {4 \sqrt {d x} \log (1-a x)}{d}+\frac {2 \sqrt {d x} \text {Li}_2(a x)}{d}+\frac {8 \operatorname {Subst}\left (\int \frac {1}{1-\frac {a x^2}{d}} \, dx,x,\sqrt {d x}\right )}{d}\\ &=-\frac {8 \sqrt {d x}}{d}+\frac {8 \tanh ^{-1}\left (\frac {\sqrt {a} \sqrt {d x}}{\sqrt {d}}\right )}{\sqrt {a} \sqrt {d}}+\frac {4 \sqrt {d x} \log (1-a x)}{d}+\frac {2 \sqrt {d x} \text {Li}_2(a x)}{d}\\ \end {align*}
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Mathematica [A] time = 0.07, size = 63, normalized size = 0.79 \[ \frac {2 \sqrt {a} x \text {Li}_2(a x)+4 \sqrt {a} x (\log (1-a x)-2)+8 \sqrt {x} \tanh ^{-1}\left (\sqrt {a} \sqrt {x}\right )}{\sqrt {a} \sqrt {d x}} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.44, size = 135, normalized size = 1.69 \[ \left [\frac {2 \, {\left (\sqrt {d x} {\left (a {\rm Li}_2\left (a x\right ) + 2 \, a \log \left (-a x + 1\right ) - 4 \, a\right )} + 2 \, \sqrt {a d} \log \left (\frac {a d x + 2 \, \sqrt {a d} \sqrt {d x} + d}{a x - 1}\right )\right )}}{a d}, \frac {2 \, {\left (\sqrt {d x} {\left (a {\rm Li}_2\left (a x\right ) + 2 \, a \log \left (-a x + 1\right ) - 4 \, a\right )} - 4 \, \sqrt {-a d} \arctan \left (\frac {\sqrt {-a d} \sqrt {d x}}{a d x}\right )\right )}}{a d}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\rm Li}_2\left (a x\right )}{\sqrt {d x}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.02, size = 69, normalized size = 0.86 \[ \frac {2 \polylog \left (2, a x \right ) \sqrt {d x}}{d}+\frac {4 \sqrt {d x}\, \ln \left (\frac {-a d x +d}{d}\right )}{d}-\frac {8 \sqrt {d x}}{d}+\frac {8 \arctanh \left (\frac {a \sqrt {d x}}{\sqrt {a d}}\right )}{\sqrt {a d}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.41, size = 83, normalized size = 1.04 \[ -\frac {2 \, {\left (2 \, \sqrt {d x} {\left (\log \relax (d) + 2\right )} - \sqrt {d x} {\rm Li}_2\left (a x\right ) - 2 \, \sqrt {d x} \log \left (-a d x + d\right ) + \frac {2 \, d \log \left (\frac {\sqrt {d x} a - \sqrt {a d}}{\sqrt {d x} a + \sqrt {a d}}\right )}{\sqrt {a d}}\right )}}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {\mathrm {polylog}\left (2,a\,x\right )}{\sqrt {d\,x}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\operatorname {Li}_{2}\left (a x\right )}{\sqrt {d x}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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