Optimal. Leaf size=96 \[ \frac {1}{4} \text {RootSum}\left [-\text {$\#$1}^8+\text {$\#$1}^4 a+2 b\& ,\frac {2 \text {$\#$1}^4 \log \left (\sqrt [4]{a x^4+b}-\text {$\#$1} x\right )-2 \text {$\#$1}^4 \log (x)-3 a \log \left (\sqrt [4]{a x^4+b}-\text {$\#$1} x\right )+3 a \log (x)}{\text {$\#$1} a-2 \text {$\#$1}^5}\& \right ] \]
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Rubi [B] time = 1.33, antiderivative size = 499, normalized size of antiderivative = 5.20, number of steps used = 10, number of rules used = 5, integrand size = 38, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.132, Rules used = {6728, 377, 212, 208, 205} \begin {gather*} -\frac {\left (a-\frac {a^2-8 b}{\sqrt {a^2+8 b}}\right ) \tan ^{-1}\left (\frac {x \sqrt [4]{-a \sqrt {a^2+8 b}+a^2+4 b}}{\sqrt [4]{a-\sqrt {a^2+8 b}} \sqrt [4]{a x^4+b}}\right )}{2 \left (a-\sqrt {a^2+8 b}\right )^{3/4} \sqrt [4]{-a \sqrt {a^2+8 b}+a^2+4 b}}-\frac {\left (\frac {a^2-8 b}{\sqrt {a^2+8 b}}+a\right ) \tan ^{-1}\left (\frac {x \sqrt [4]{a \sqrt {a^2+8 b}+a^2+4 b}}{\sqrt [4]{\sqrt {a^2+8 b}+a} \sqrt [4]{a x^4+b}}\right )}{2 \left (\sqrt {a^2+8 b}+a\right )^{3/4} \sqrt [4]{a \sqrt {a^2+8 b}+a^2+4 b}}-\frac {\left (a-\frac {a^2-8 b}{\sqrt {a^2+8 b}}\right ) \tanh ^{-1}\left (\frac {x \sqrt [4]{-a \sqrt {a^2+8 b}+a^2+4 b}}{\sqrt [4]{a-\sqrt {a^2+8 b}} \sqrt [4]{a x^4+b}}\right )}{2 \left (a-\sqrt {a^2+8 b}\right )^{3/4} \sqrt [4]{-a \sqrt {a^2+8 b}+a^2+4 b}}-\frac {\left (\frac {a^2-8 b}{\sqrt {a^2+8 b}}+a\right ) \tanh ^{-1}\left (\frac {x \sqrt [4]{a \sqrt {a^2+8 b}+a^2+4 b}}{\sqrt [4]{\sqrt {a^2+8 b}+a} \sqrt [4]{a x^4+b}}\right )}{2 \left (\sqrt {a^2+8 b}+a\right )^{3/4} \sqrt [4]{a \sqrt {a^2+8 b}+a^2+4 b}} \end {gather*}
Antiderivative was successfully verified.
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Rule 205
Rule 208
Rule 212
Rule 377
Rule 6728
Rubi steps
\begin {align*} \int \frac {-2 b+a x^4}{\sqrt [4]{b+a x^4} \left (-b-a x^4+2 x^8\right )} \, dx &=\int \left (\frac {a+\frac {a^2-8 b}{\sqrt {a^2+8 b}}}{\left (-a-\sqrt {a^2+8 b}+4 x^4\right ) \sqrt [4]{b+a x^4}}+\frac {a-\frac {a^2-8 b}{\sqrt {a^2+8 b}}}{\left (-a+\sqrt {a^2+8 b}+4 x^4\right ) \sqrt [4]{b+a x^4}}\right ) \, dx\\ &=\left (a-\frac {a^2-8 b}{\sqrt {a^2+8 b}}\right ) \int \frac {1}{\left (-a+\sqrt {a^2+8 b}+4 x^4\right ) \sqrt [4]{b+a x^4}} \, dx+\left (a+\frac {a^2-8 b}{\sqrt {a^2+8 b}}\right ) \int \frac {1}{\left (-a-\sqrt {a^2+8 b}+4 x^4\right ) \sqrt [4]{b+a x^4}} \, dx\\ &=\left (a-\frac {a^2-8 b}{\sqrt {a^2+8 b}}\right ) \operatorname {Subst}\left (\int \frac {1}{-a+\sqrt {a^2+8 b}-\left (-4 b+a \left (-a+\sqrt {a^2+8 b}\right )\right ) x^4} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right )+\left (a+\frac {a^2-8 b}{\sqrt {a^2+8 b}}\right ) \operatorname {Subst}\left (\int \frac {1}{-a-\sqrt {a^2+8 b}-\left (-4 b+a \left (-a-\sqrt {a^2+8 b}\right )\right ) x^4} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right )\\ &=-\frac {\left (a-\frac {a^2-8 b}{\sqrt {a^2+8 b}}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {a-\sqrt {a^2+8 b}}-\sqrt {a^2+4 b-a \sqrt {a^2+8 b}} x^2} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right )}{2 \sqrt {a-\sqrt {a^2+8 b}}}-\frac {\left (a-\frac {a^2-8 b}{\sqrt {a^2+8 b}}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {a-\sqrt {a^2+8 b}}+\sqrt {a^2+4 b-a \sqrt {a^2+8 b}} x^2} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right )}{2 \sqrt {a-\sqrt {a^2+8 b}}}-\frac {\left (a+\frac {a^2-8 b}{\sqrt {a^2+8 b}}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {a+\sqrt {a^2+8 b}}-\sqrt {a^2+4 b+a \sqrt {a^2+8 b}} x^2} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right )}{2 \sqrt {a+\sqrt {a^2+8 b}}}-\frac {\left (a+\frac {a^2-8 b}{\sqrt {a^2+8 b}}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {a+\sqrt {a^2+8 b}}+\sqrt {a^2+4 b+a \sqrt {a^2+8 b}} x^2} \, dx,x,\frac {x}{\sqrt [4]{b+a x^4}}\right )}{2 \sqrt {a+\sqrt {a^2+8 b}}}\\ &=-\frac {\left (a-\frac {a^2-8 b}{\sqrt {a^2+8 b}}\right ) \tan ^{-1}\left (\frac {\sqrt [4]{a^2+4 b-a \sqrt {a^2+8 b}} x}{\sqrt [4]{a-\sqrt {a^2+8 b}} \sqrt [4]{b+a x^4}}\right )}{2 \left (a-\sqrt {a^2+8 b}\right )^{3/4} \sqrt [4]{a^2+4 b-a \sqrt {a^2+8 b}}}-\frac {\left (a+\frac {a^2-8 b}{\sqrt {a^2+8 b}}\right ) \tan ^{-1}\left (\frac {\sqrt [4]{a^2+4 b+a \sqrt {a^2+8 b}} x}{\sqrt [4]{a+\sqrt {a^2+8 b}} \sqrt [4]{b+a x^4}}\right )}{2 \left (a+\sqrt {a^2+8 b}\right )^{3/4} \sqrt [4]{a^2+4 b+a \sqrt {a^2+8 b}}}-\frac {\left (a-\frac {a^2-8 b}{\sqrt {a^2+8 b}}\right ) \tanh ^{-1}\left (\frac {\sqrt [4]{a^2+4 b-a \sqrt {a^2+8 b}} x}{\sqrt [4]{a-\sqrt {a^2+8 b}} \sqrt [4]{b+a x^4}}\right )}{2 \left (a-\sqrt {a^2+8 b}\right )^{3/4} \sqrt [4]{a^2+4 b-a \sqrt {a^2+8 b}}}-\frac {\left (a+\frac {a^2-8 b}{\sqrt {a^2+8 b}}\right ) \tanh ^{-1}\left (\frac {\sqrt [4]{a^2+4 b+a \sqrt {a^2+8 b}} x}{\sqrt [4]{a+\sqrt {a^2+8 b}} \sqrt [4]{b+a x^4}}\right )}{2 \left (a+\sqrt {a^2+8 b}\right )^{3/4} \sqrt [4]{a^2+4 b+a \sqrt {a^2+8 b}}}\\ \end {align*}
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Mathematica [B] time = 0.88, size = 499, normalized size = 5.20 \begin {gather*} -\frac {\left (a-\frac {a^2-8 b}{\sqrt {a^2+8 b}}\right ) \tan ^{-1}\left (\frac {x \sqrt [4]{-a \sqrt {a^2+8 b}+a^2+4 b}}{\sqrt [4]{a-\sqrt {a^2+8 b}} \sqrt [4]{a x^4+b}}\right )}{2 \left (a-\sqrt {a^2+8 b}\right )^{3/4} \sqrt [4]{-a \sqrt {a^2+8 b}+a^2+4 b}}-\frac {\left (\frac {a^2-8 b}{\sqrt {a^2+8 b}}+a\right ) \tan ^{-1}\left (\frac {x \sqrt [4]{a \sqrt {a^2+8 b}+a^2+4 b}}{\sqrt [4]{\sqrt {a^2+8 b}+a} \sqrt [4]{a x^4+b}}\right )}{2 \left (\sqrt {a^2+8 b}+a\right )^{3/4} \sqrt [4]{a \sqrt {a^2+8 b}+a^2+4 b}}-\frac {\left (a-\frac {a^2-8 b}{\sqrt {a^2+8 b}}\right ) \tanh ^{-1}\left (\frac {x \sqrt [4]{-a \sqrt {a^2+8 b}+a^2+4 b}}{\sqrt [4]{a-\sqrt {a^2+8 b}} \sqrt [4]{a x^4+b}}\right )}{2 \left (a-\sqrt {a^2+8 b}\right )^{3/4} \sqrt [4]{-a \sqrt {a^2+8 b}+a^2+4 b}}-\frac {\left (\frac {a^2-8 b}{\sqrt {a^2+8 b}}+a\right ) \tanh ^{-1}\left (\frac {x \sqrt [4]{a \sqrt {a^2+8 b}+a^2+4 b}}{\sqrt [4]{\sqrt {a^2+8 b}+a} \sqrt [4]{a x^4+b}}\right )}{2 \left (\sqrt {a^2+8 b}+a\right )^{3/4} \sqrt [4]{a \sqrt {a^2+8 b}+a^2+4 b}} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.87, size = 97, normalized size = 1.01 \begin {gather*} \frac {1}{4} \text {RootSum}\left [2 b+a \text {$\#$1}^4-\text {$\#$1}^8\&,\frac {-3 a \log (x)+3 a \log \left (\sqrt [4]{b+a x^4}-x \text {$\#$1}\right )+2 \log (x) \text {$\#$1}^4-2 \log \left (\sqrt [4]{b+a x^4}-x \text {$\#$1}\right ) \text {$\#$1}^4}{-a \text {$\#$1}+2 \text {$\#$1}^5}\&\right ] \end {gather*}
Antiderivative was successfully verified.
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fricas [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {a x^{4} - 2 \, b}{{\left (2 \, x^{8} - a x^{4} - b\right )} {\left (a x^{4} + b\right )}^{\frac {1}{4}}}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.02, size = 0, normalized size = 0.00 \[\int \frac {a \,x^{4}-2 b}{\left (a \,x^{4}+b \right )^{\frac {1}{4}} \left (2 x^{8}-a \,x^{4}-b \right )}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {a x^{4} - 2 \, b}{{\left (2 \, x^{8} - a x^{4} - b\right )} {\left (a x^{4} + b\right )}^{\frac {1}{4}}}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {2\,b-a\,x^4}{{\left (a\,x^4+b\right )}^{1/4}\,\left (-2\,x^8+a\,x^4+b\right )} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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