3.1.37 \(\int x^4 (1+x^5)^{2/3} \, dx\)

Optimal. Leaf size=13 \[ \frac {3}{25} \left (x^5+1\right )^{5/3} \]

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Rubi [A]  time = 0.00, antiderivative size = 13, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {261} \begin {gather*} \frac {3}{25} \left (x^5+1\right )^{5/3} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^4*(1 + x^5)^(2/3),x]

[Out]

(3*(1 + x^5)^(5/3))/25

Rule 261

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a + b*x^n)^(p + 1)/(b*n*(p + 1)), x] /; FreeQ
[{a, b, m, n, p}, x] && EqQ[m, n - 1] && NeQ[p, -1]

Rubi steps

\begin {align*} \int x^4 \left (1+x^5\right )^{2/3} \, dx &=\frac {3}{25} \left (1+x^5\right )^{5/3}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 13, normalized size = 1.00 \begin {gather*} \frac {3}{25} \left (x^5+1\right )^{5/3} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^4*(1 + x^5)^(2/3),x]

[Out]

(3*(1 + x^5)^(5/3))/25

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IntegrateAlgebraic [A]  time = 0.01, size = 13, normalized size = 1.00 \begin {gather*} \frac {3}{25} \left (1+x^5\right )^{5/3} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[x^4*(1 + x^5)^(2/3),x]

[Out]

(3*(1 + x^5)^(5/3))/25

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fricas [A]  time = 0.44, size = 9, normalized size = 0.69 \begin {gather*} \frac {3}{25} \, {\left (x^{5} + 1\right )}^{\frac {5}{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(x^5+1)^(2/3),x, algorithm="fricas")

[Out]

3/25*(x^5 + 1)^(5/3)

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giac [A]  time = 0.43, size = 9, normalized size = 0.69 \begin {gather*} \frac {3}{25} \, {\left (x^{5} + 1\right )}^{\frac {5}{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(x^5+1)^(2/3),x, algorithm="giac")

[Out]

3/25*(x^5 + 1)^(5/3)

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maple [A]  time = 0.07, size = 10, normalized size = 0.77

method	result	size
derivativedivides	\(\frac {3 \left (x^{5}+1\right )^{\frac {5}{3}}}{25}\)	\(10\)
default	\(\frac {3 \left (x^{5}+1\right )^{\frac {5}{3}}}{25}\)	\(10\)
risch	\(\frac {3 \left (x^{5}+1\right )^{\frac {5}{3}}}{25}\)	\(10\)
trager	\(\left (\frac {3}{25}+\frac {3 x^{5}}{25}\right ) \left (x^{5}+1\right )^{\frac {2}{3}}\)	\(16\)
meijerg	\(\frac {\hypergeom \left (\left [-\frac {2}{3}, 1\right ], \relax [2], -x^{5}\right ) x^{5}}{5}\)	\(17\)
gosper	\(\frac {3 \left (1+x \right ) \left (x^{4}-x^{3}+x^{2}-x +1\right ) \left (x^{5}+1\right )^{\frac {2}{3}}}{25}\)	\(29\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4*(x^5+1)^(2/3),x,method=_RETURNVERBOSE)

[Out]

3/25*(x^5+1)^(5/3)

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maxima [A]  time = 0.34, size = 9, normalized size = 0.69 \begin {gather*} \frac {3}{25} \, {\left (x^{5} + 1\right )}^{\frac {5}{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(x^5+1)^(2/3),x, algorithm="maxima")

[Out]

3/25*(x^5 + 1)^(5/3)

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mupad [B]  time = 0.14, size = 9, normalized size = 0.69 \begin {gather*} \frac {3\,{\left (x^5+1\right )}^{5/3}}{25} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4*(x^5 + 1)^(2/3),x)

[Out]

(3*(x^5 + 1)^(5/3))/25

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sympy [B]  time = 0.42, size = 26, normalized size = 2.00 \begin {gather*} \frac {3 x^{5} \left (x^{5} + 1\right )^{\frac {2}{3}}}{25} + \frac {3 \left (x^{5} + 1\right )^{\frac {2}{3}}}{25} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**4*(x**5+1)**(2/3),x)

[Out]

3*x**5*(x**5 + 1)**(2/3)/25 + 3*(x**5 + 1)**(2/3)/25

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