3.6.19 \(\int \frac {3 a b x-2 (a+b) x^2+x^3}{\sqrt {x (-a+x) (-b+x)} (-a b+(a+b) x-x^2+d x^3)} \, dx\)

Optimal. Leaf size=40 \[ -\frac {2 \tanh ^{-1}\left (\frac {\sqrt {x^2 (-a-b)+a b x+x^3}}{\sqrt {d} x^2}\right )}{\sqrt {d}} \]

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Rubi [F]  time = 11.96, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {3 a b x-2 (a+b) x^2+x^3}{\sqrt {x (-a+x) (-b+x)} \left (-a b+(a+b) x-x^2+d x^3\right )} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[(3*a*b*x - 2*(a + b)*x^2 + x^3)/(Sqrt[x*(-a + x)*(-b + x)]*(-(a*b) + (a + b)*x - x^2 + d*x^3)),x]

[Out]

(2*Sqrt[b]*Sqrt[x]*Sqrt[1 - x/a]*Sqrt[1 - x/b]*EllipticF[ArcSin[Sqrt[x]/Sqrt[b]], b/a])/(d*Sqrt[(a - x)*(b - x
)*x]) + (2*(a + b - 3*a*b*d)*Sqrt[x]*Sqrt[-a + x]*Sqrt[-b + x]*Defer[Subst][Defer[Int][x^2/(Sqrt[-a + x^2]*Sqr
t[-b + x^2]*(a*b - a*(1 + b/a)*x^2 + x^4 - d*x^6)), x], x, Sqrt[x]])/(d*Sqrt[(a - x)*(b - x)*x]) - (2*(1 - 2*a
*d - 2*b*d)*Sqrt[x]*Sqrt[-a + x]*Sqrt[-b + x]*Defer[Subst][Defer[Int][x^4/(Sqrt[-a + x^2]*Sqrt[-b + x^2]*(a*b
- a*(1 + b/a)*x^2 + x^4 - d*x^6)), x], x, Sqrt[x]])/(d*Sqrt[(a - x)*(b - x)*x]) + (2*a*b*Sqrt[x]*Sqrt[-a + x]*
Sqrt[-b + x]*Defer[Subst][Defer[Int][1/(Sqrt[-a + x^2]*Sqrt[-b + x^2]*(-(a*b) + a*(1 + b/a)*x^2 - x^4 + d*x^6)
), x], x, Sqrt[x]])/(d*Sqrt[(a - x)*(b - x)*x])

Rubi steps

\begin {align*} \int \frac {3 a b x-2 (a+b) x^2+x^3}{\sqrt {x (-a+x) (-b+x)} \left (-a b+(a+b) x-x^2+d x^3\right )} \, dx &=\int \frac {x \left (3 a b-2 (a+b) x+x^2\right )}{\sqrt {x (-a+x) (-b+x)} \left (-a b+(a+b) x-x^2+d x^3\right )} \, dx\\ &=\frac {\left (\sqrt {x} \sqrt {-a+x} \sqrt {-b+x}\right ) \int \frac {\sqrt {x} \left (3 a b-2 (a+b) x+x^2\right )}{\sqrt {-a+x} \sqrt {-b+x} \left (-a b+(a+b) x-x^2+d x^3\right )} \, dx}{\sqrt {x (-a+x) (-b+x)}}\\ &=\frac {\left (2 \sqrt {x} \sqrt {-a+x} \sqrt {-b+x}\right ) \operatorname {Subst}\left (\int \frac {x^2 \left (3 a b-2 (a+b) x^2+x^4\right )}{\sqrt {-a+x^2} \sqrt {-b+x^2} \left (-a b+(a+b) x^2-x^4+d x^6\right )} \, dx,x,\sqrt {x}\right )}{\sqrt {x (-a+x) (-b+x)}}\\ &=\frac {\left (2 \sqrt {x} \sqrt {-a+x} \sqrt {-b+x}\right ) \operatorname {Subst}\left (\int \left (\frac {1}{d \sqrt {-a+x^2} \sqrt {-b+x^2}}+\frac {a b-(b+a (1-3 b d)) x^2+(1-2 a d-2 b d) x^4}{d \sqrt {-a+x^2} \sqrt {-b+x^2} \left (-a b+(a+b) x^2-x^4+d x^6\right )}\right ) \, dx,x,\sqrt {x}\right )}{\sqrt {x (-a+x) (-b+x)}}\\ &=\frac {\left (2 \sqrt {x} \sqrt {-a+x} \sqrt {-b+x}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {-a+x^2} \sqrt {-b+x^2}} \, dx,x,\sqrt {x}\right )}{d \sqrt {x (-a+x) (-b+x)}}+\frac {\left (2 \sqrt {x} \sqrt {-a+x} \sqrt {-b+x}\right ) \operatorname {Subst}\left (\int \frac {a b-(b+a (1-3 b d)) x^2+(1-2 a d-2 b d) x^4}{\sqrt {-a+x^2} \sqrt {-b+x^2} \left (-a b+(a+b) x^2-x^4+d x^6\right )} \, dx,x,\sqrt {x}\right )}{d \sqrt {x (-a+x) (-b+x)}}\\ &=\frac {\left (2 \sqrt {x} \sqrt {-a+x} \sqrt {-b+x}\right ) \operatorname {Subst}\left (\int \left (\frac {(b+a (1-3 b d)) x^2}{\sqrt {-a+x^2} \sqrt {-b+x^2} \left (a b-a \left (1+\frac {b}{a}\right ) x^2+x^4-d x^6\right )}+\frac {(-1+2 a d+2 b d) x^4}{\sqrt {-a+x^2} \sqrt {-b+x^2} \left (a b-a \left (1+\frac {b}{a}\right ) x^2+x^4-d x^6\right )}+\frac {a b}{\sqrt {-a+x^2} \sqrt {-b+x^2} \left (-a b+a \left (1+\frac {b}{a}\right ) x^2-x^4+d x^6\right )}\right ) \, dx,x,\sqrt {x}\right )}{d \sqrt {x (-a+x) (-b+x)}}+\frac {\left (2 \sqrt {x} \sqrt {-a+x} \sqrt {1-\frac {x}{b}}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {-a+x^2} \sqrt {1-\frac {x^2}{b}}} \, dx,x,\sqrt {x}\right )}{d \sqrt {x (-a+x) (-b+x)}}\\ &=\frac {\left (2 a b \sqrt {x} \sqrt {-a+x} \sqrt {-b+x}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {-a+x^2} \sqrt {-b+x^2} \left (-a b+a \left (1+\frac {b}{a}\right ) x^2-x^4+d x^6\right )} \, dx,x,\sqrt {x}\right )}{d \sqrt {x (-a+x) (-b+x)}}+\frac {\left (2 (-1+2 a d+2 b d) \sqrt {x} \sqrt {-a+x} \sqrt {-b+x}\right ) \operatorname {Subst}\left (\int \frac {x^4}{\sqrt {-a+x^2} \sqrt {-b+x^2} \left (a b-a \left (1+\frac {b}{a}\right ) x^2+x^4-d x^6\right )} \, dx,x,\sqrt {x}\right )}{d \sqrt {x (-a+x) (-b+x)}}+\frac {\left (2 (a+b-3 a b d) \sqrt {x} \sqrt {-a+x} \sqrt {-b+x}\right ) \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {-a+x^2} \sqrt {-b+x^2} \left (a b-a \left (1+\frac {b}{a}\right ) x^2+x^4-d x^6\right )} \, dx,x,\sqrt {x}\right )}{d \sqrt {x (-a+x) (-b+x)}}+\frac {\left (2 \sqrt {x} \sqrt {1-\frac {x}{a}} \sqrt {1-\frac {x}{b}}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-\frac {x^2}{a}} \sqrt {1-\frac {x^2}{b}}} \, dx,x,\sqrt {x}\right )}{d \sqrt {x (-a+x) (-b+x)}}\\ &=\frac {2 \sqrt {b} \sqrt {x} \sqrt {1-\frac {x}{a}} \sqrt {1-\frac {x}{b}} F\left (\sin ^{-1}\left (\frac {\sqrt {x}}{\sqrt {b}}\right )|\frac {b}{a}\right )}{d \sqrt {(a-x) (b-x) x}}+\frac {\left (2 a b \sqrt {x} \sqrt {-a+x} \sqrt {-b+x}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {-a+x^2} \sqrt {-b+x^2} \left (-a b+a \left (1+\frac {b}{a}\right ) x^2-x^4+d x^6\right )} \, dx,x,\sqrt {x}\right )}{d \sqrt {x (-a+x) (-b+x)}}+\frac {\left (2 (-1+2 a d+2 b d) \sqrt {x} \sqrt {-a+x} \sqrt {-b+x}\right ) \operatorname {Subst}\left (\int \frac {x^4}{\sqrt {-a+x^2} \sqrt {-b+x^2} \left (a b-a \left (1+\frac {b}{a}\right ) x^2+x^4-d x^6\right )} \, dx,x,\sqrt {x}\right )}{d \sqrt {x (-a+x) (-b+x)}}+\frac {\left (2 (a+b-3 a b d) \sqrt {x} \sqrt {-a+x} \sqrt {-b+x}\right ) \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {-a+x^2} \sqrt {-b+x^2} \left (a b-a \left (1+\frac {b}{a}\right ) x^2+x^4-d x^6\right )} \, dx,x,\sqrt {x}\right )}{d \sqrt {x (-a+x) (-b+x)}}\\ \end {align*}

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Mathematica [C]  time = 4.30, size = 1418, normalized size = 35.45

result too large to display

Warning: Unable to verify antiderivative.

[In]

Integrate[(3*a*b*x - 2*(a + b)*x^2 + x^3)/(Sqrt[x*(-a + x)*(-b + x)]*(-(a*b) + (a + b)*x - x^2 + d*x^3)),x]

[Out]

((-2*I)*x*Sqrt[1 - x/b]*(EllipticF[I*ArcSinh[Sqrt[-(x/a)]], a/b]*(a + b - 3*a*b*d - 2*d^2*Root[-(a*b) + (a + b
)*#1 - #1^2 + d*#1^3 & , 1]*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 2]^2 - 2*d^2*Root[-(a*b) + (a + b)*#1
- #1^2 + d*#1^3 & , 1]^2*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 3] - 2*d^2*Root[-(a*b) + (a + b)*#1 - #
1^2 + d*#1^3 & , 2]*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 3]^2) - EllipticPi[a/Root[-(a*b) + (a + b)*#1
- #1^2 + d*#1^3 & , 1], I*ArcSinh[Sqrt[-(x/a)]], a/b]*(a + b - 2*a^2*d - 7*a*b*d - 2*b^2*d - d*Root[-(a*b) +
(a + b)*#1 - #1^2 + d*#1^3 & , 2]^2 + d^2*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 2]^3 + d^2*(-3*a*b + 4*
(a + b)*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 1] - 2*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 1]^2)
*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 3] - d^2*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 1]*Root[-(
a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 3]^2 + d^2*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 2]*(3*a*b + 2*(a
+ b)*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 3] - Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 3]^2)) -
d*(EllipticPi[a/Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 2], I*ArcSinh[Sqrt[-(x/a)]], a/b]*(2*a^2 + a*b +
2*b^2 + 6*a*b*d*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 3] - 2*(a + b)*d*Root[-(a*b) + (a + b)*#1 - #1^2
+ d*#1^3 & , 1]*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 3] + d*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 &
, 2]^2*(-Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 1] + Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 3]) +
d*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 2]*(3*a*b - 4*(a + b)*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3
& , 3])) + EllipticPi[a/Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 3], I*ArcSinh[Sqrt[-(x/a)]], a/b]*(3*a*b
- 3*a*b*d*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 3] - 2*(a + b)*d*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#
1^3 & , 1]*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 3] + d*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 1]
*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 3]^2 - d*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 2]*(6*a*b
- 2*(a + b)*Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 3] + Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 3]^
2)))))/(d^3*Sqrt[x/(-a + x)]*Sqrt[x*(-a + x)*(-b + x)]*(Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 1] - Root
[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 2])*(Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 1] - Root[-(a*b) +
(a + b)*#1 - #1^2 + d*#1^3 & , 3])*(Root[-(a*b) + (a + b)*#1 - #1^2 + d*#1^3 & , 2] - Root[-(a*b) + (a + b)*#1
- #1^2 + d*#1^3 & , 3]))

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IntegrateAlgebraic [A]  time = 0.48, size = 40, normalized size = 1.00 \begin {gather*} -\frac {2 \tanh ^{-1}\left (\frac {\sqrt {a b x+(-a-b) x^2+x^3}}{\sqrt {d} x^2}\right )}{\sqrt {d}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(3*a*b*x - 2*(a + b)*x^2 + x^3)/(Sqrt[x*(-a + x)*(-b + x)]*(-(a*b) + (a + b)*x - x^2 + d*x^
3)),x]

[Out]

(-2*ArcTanh[Sqrt[a*b*x + (-a - b)*x^2 + x^3]/(Sqrt[d]*x^2)])/Sqrt[d]

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fricas [B]  time = 1.77, size = 285, normalized size = 7.12 \begin {gather*} \left [\frac {\log \left (\frac {d^{2} x^{6} + 6 \, d x^{5} - {\left (6 \, {\left (a + b\right )} d - 1\right )} x^{4} + a^{2} b^{2} + 2 \, {\left (3 \, a b d - a - b\right )} x^{3} + {\left (a^{2} + 4 \, a b + b^{2}\right )} x^{2} - 4 \, {\left (d x^{4} + a b x - {\left (a + b\right )} x^{2} + x^{3}\right )} \sqrt {a b x - {\left (a + b\right )} x^{2} + x^{3}} \sqrt {d} - 2 \, {\left (a^{2} b + a b^{2}\right )} x}{d^{2} x^{6} - 2 \, d x^{5} + {\left (2 \, {\left (a + b\right )} d + 1\right )} x^{4} + a^{2} b^{2} - 2 \, {\left (a b d + a + b\right )} x^{3} + {\left (a^{2} + 4 \, a b + b^{2}\right )} x^{2} - 2 \, {\left (a^{2} b + a b^{2}\right )} x}\right )}{2 \, \sqrt {d}}, \frac {\sqrt {-d} \arctan \left (\frac {{\left (d x^{3} + a b - {\left (a + b\right )} x + x^{2}\right )} \sqrt {a b x - {\left (a + b\right )} x^{2} + x^{3}} \sqrt {-d}}{2 \, {\left (a b d x^{2} - {\left (a + b\right )} d x^{3} + d x^{4}\right )}}\right )}{d}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3*a*b*x-2*(a+b)*x^2+x^3)/(x*(-a+x)*(-b+x))^(1/2)/(-a*b+(a+b)*x-x^2+d*x^3),x, algorithm="fricas")

[Out]

[1/2*log((d^2*x^6 + 6*d*x^5 - (6*(a + b)*d - 1)*x^4 + a^2*b^2 + 2*(3*a*b*d - a - b)*x^3 + (a^2 + 4*a*b + b^2)*
x^2 - 4*(d*x^4 + a*b*x - (a + b)*x^2 + x^3)*sqrt(a*b*x - (a + b)*x^2 + x^3)*sqrt(d) - 2*(a^2*b + a*b^2)*x)/(d^
2*x^6 - 2*d*x^5 + (2*(a + b)*d + 1)*x^4 + a^2*b^2 - 2*(a*b*d + a + b)*x^3 + (a^2 + 4*a*b + b^2)*x^2 - 2*(a^2*b
+ a*b^2)*x))/sqrt(d), sqrt(-d)*arctan(1/2*(d*x^3 + a*b - (a + b)*x + x^2)*sqrt(a*b*x - (a + b)*x^2 + x^3)*sqr
t(-d)/(a*b*d*x^2 - (a + b)*d*x^3 + d*x^4))/d]

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {3 \, a b x - 2 \, {\left (a + b\right )} x^{2} + x^{3}}{{\left (d x^{3} - a b + {\left (a + b\right )} x - x^{2}\right )} \sqrt {{\left (a - x\right )} {\left (b - x\right )} x}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3*a*b*x-2*(a+b)*x^2+x^3)/(x*(-a+x)*(-b+x))^(1/2)/(-a*b+(a+b)*x-x^2+d*x^3),x, algorithm="giac")

[Out]

integrate((3*a*b*x - 2*(a + b)*x^2 + x^3)/((d*x^3 - a*b + (a + b)*x - x^2)*sqrt((a - x)*(b - x)*x)), x)

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maple [C]  time = 0.09, size = 293, normalized size = 7.32

method	result	size
elliptic	\(-\frac {2 a \sqrt {-\frac {-a +x}{a}}\, \sqrt {\frac {-b +x}{a -b}}\, \sqrt {\frac {x}{a}}\, \EllipticF \left (\sqrt {-\frac {-a +x}{a}}, \sqrt {\frac {a}{a -b}}\right )}{d \sqrt {a b x -a \,x^{2}-b \,x^{2}+x^{3}}}+\frac {2 \left (\munderset {\underline {\hspace {1.25 ex}}\alpha =\RootOf \left (d \,\textit {\_Z}^{3}-\textit {\_Z}^{2}+\left (a +b \right ) \textit {\_Z} -a b \right )}{\sum }\frac {\left (2 \underline {\hspace {1.25 ex}}\alpha ^{2} a d +2 \underline {\hspace {1.25 ex}}\alpha ^{2} b d -3 \underline {\hspace {1.25 ex}}\alpha a b d -\underline {\hspace {1.25 ex}}\alpha ^{2}+\underline {\hspace {1.25 ex}}\alpha a +\underline {\hspace {1.25 ex}}\alpha b -a b \right ) \left (\underline {\hspace {1.25 ex}}\alpha ^{2} d +\underline {\hspace {1.25 ex}}\alpha a d +a^{2} d -\underline {\hspace {1.25 ex}}\alpha +b \right ) \sqrt {-\frac {-a +x}{a}}\, \sqrt {\frac {-b +x}{a -b}}\, \sqrt {\frac {x}{a}}\, \EllipticPi \left (\sqrt {-\frac {-a +x}{a}}, \frac {\underline {\hspace {1.25 ex}}\alpha ^{2} d +\underline {\hspace {1.25 ex}}\alpha a d +a^{2} d -\underline {\hspace {1.25 ex}}\alpha +b}{a^{2} d}, \sqrt {\frac {a}{a -b}}\right )}{\left (3 \underline {\hspace {1.25 ex}}\alpha ^{2} d -2 \underline {\hspace {1.25 ex}}\alpha +a +b \right ) \sqrt {x \left (a b -a x -b x +x^{2}\right )}}\right )}{d^{2} a^{2}}\)	\(293\)
default	\(-\frac {2 a \sqrt {-\frac {-a +x}{a}}\, \sqrt {\frac {-b +x}{a -b}}\, \sqrt {\frac {x}{a}}\, \EllipticF \left (\sqrt {-\frac {-a +x}{a}}, \sqrt {\frac {a}{a -b}}\right )}{d \sqrt {a b x -a \,x^{2}-b \,x^{2}+x^{3}}}+\frac {2 \left (\munderset {\underline {\hspace {1.25 ex}}\alpha =\RootOf \left (d \,\textit {\_Z}^{3}-\textit {\_Z}^{2}+\left (a +b \right ) \textit {\_Z} -a b \right )}{\sum }\frac {\left (-2 \underline {\hspace {1.25 ex}}\alpha ^{2} a d -2 \underline {\hspace {1.25 ex}}\alpha ^{2} b d +3 \underline {\hspace {1.25 ex}}\alpha a b d +\underline {\hspace {1.25 ex}}\alpha ^{2}-\underline {\hspace {1.25 ex}}\alpha a -\underline {\hspace {1.25 ex}}\alpha b +a b \right ) \left (\underline {\hspace {1.25 ex}}\alpha ^{2} d +\underline {\hspace {1.25 ex}}\alpha a d +a^{2} d -\underline {\hspace {1.25 ex}}\alpha +b \right ) \sqrt {-\frac {-a +x}{a}}\, \sqrt {\frac {-b +x}{a -b}}\, \sqrt {\frac {x}{a}}\, \EllipticPi \left (\sqrt {-\frac {-a +x}{a}}, \frac {\underline {\hspace {1.25 ex}}\alpha ^{2} d +\underline {\hspace {1.25 ex}}\alpha a d +a^{2} d -\underline {\hspace {1.25 ex}}\alpha +b}{a^{2} d}, \sqrt {\frac {a}{a -b}}\right )}{\left (-3 \underline {\hspace {1.25 ex}}\alpha ^{2} d +2 \underline {\hspace {1.25 ex}}\alpha -a -b \right ) \sqrt {x \left (a b -a x -b x +x^{2}\right )}}\right )}{d^{2} a^{2}}\)	\(296\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((3*a*b*x-2*(a+b)*x^2+x^3)/(x*(-a+x)*(-b+x))^(1/2)/(-a*b+(a+b)*x-x^2+d*x^3),x,method=_RETURNVERBOSE)

[Out]

-2/d*a*(-(-a+x)/a)^(1/2)*((-b+x)/(a-b))^(1/2)*(1/a*x)^(1/2)/(a*b*x-a*x^2-b*x^2+x^3)^(1/2)*EllipticF((-(-a+x)/a
)^(1/2),(a/(a-b))^(1/2))+2/d^2/a^2*sum((2*_alpha^2*a*d+2*_alpha^2*b*d-3*_alpha*a*b*d-_alpha^2+_alpha*a+_alpha*
b-a*b)/(3*_alpha^2*d-2*_alpha+a+b)*(_alpha^2*d+_alpha*a*d+a^2*d-_alpha+b)*(-(-a+x)/a)^(1/2)*((-b+x)/(a-b))^(1/
2)*(1/a*x)^(1/2)/(x*(a*b-a*x-b*x+x^2))^(1/2)*EllipticPi((-(-a+x)/a)^(1/2),(_alpha^2*d+_alpha*a*d+a^2*d-_alpha+
b)/a^2/d,(a/(a-b))^(1/2)),_alpha=RootOf(d*_Z^3-_Z^2+(a+b)*_Z-a*b))

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {3 \, a b x - 2 \, {\left (a + b\right )} x^{2} + x^{3}}{{\left (d x^{3} - a b + {\left (a + b\right )} x - x^{2}\right )} \sqrt {{\left (a - x\right )} {\left (b - x\right )} x}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3*a*b*x-2*(a+b)*x^2+x^3)/(x*(-a+x)*(-b+x))^(1/2)/(-a*b+(a+b)*x-x^2+d*x^3),x, algorithm="maxima")

[Out]

integrate((3*a*b*x - 2*(a + b)*x^2 + x^3)/((d*x^3 - a*b + (a + b)*x - x^2)*sqrt((a - x)*(b - x)*x)), x)

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mupad [B]  time = 3.31, size = 69, normalized size = 1.72 \begin {gather*} \frac {\ln \left (\frac {a\,b-a\,x-b\,x+d\,x^3+x^2-2\,\sqrt {d}\,x\,\sqrt {x\,\left (a-x\right )\,\left (b-x\right )}}{a\,x-a\,b+b\,x+d\,x^3-x^2}\right )}{\sqrt {d}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-(x^3 - 2*x^2*(a + b) + 3*a*b*x)/((x*(a - x)*(b - x))^(1/2)*(a*b - d*x^3 + x^2 - x*(a + b))),x)

[Out]

log((a*b - a*x - b*x + d*x^3 + x^2 - 2*d^(1/2)*x*(x*(a - x)*(b - x))^(1/2))/(a*x - a*b + b*x + d*x^3 - x^2))/d
^(1/2)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3*a*b*x-2*(a+b)*x**2+x**3)/(x*(-a+x)*(-b+x))**(1/2)/(-a*b+(a+b)*x-x**2+d*x**3),x)

[Out]

Timed out

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