3.1.61 \(\int \frac {1}{x \sqrt {1+x^6}} \, dx\)

Optimal. Leaf size=14 \[ -\frac {1}{3} \tanh ^{-1}\left (\sqrt {x^6+1}\right ) \]

________________________________________________________________________________________

Rubi [A]  time = 0.01, antiderivative size = 14, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {266, 63, 207} \begin {gather*} -\frac {1}{3} \tanh ^{-1}\left (\sqrt {x^6+1}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/(x*Sqrt[1 + x^6]),x]

[Out]

-1/3*ArcTanh[Sqrt[1 + x^6]]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 207

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> -Simp[ArcTanh[(Rt[b, 2]*x)/Rt[-a, 2]]/(Rt[-a, 2]*Rt[b, 2]), x] /;
 FreeQ[{a, b}, x] && NegQ[a/b] && (LtQ[a, 0] || GtQ[b, 0])

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rubi steps

\begin {align*} \int \frac {1}{x \sqrt {1+x^6}} \, dx &=\frac {1}{6} \operatorname {Subst}\left (\int \frac {1}{x \sqrt {1+x}} \, dx,x,x^6\right )\\ &=\frac {1}{3} \operatorname {Subst}\left (\int \frac {1}{-1+x^2} \, dx,x,\sqrt {1+x^6}\right )\\ &=-\frac {1}{3} \tanh ^{-1}\left (\sqrt {1+x^6}\right )\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.00, size = 14, normalized size = 1.00 \begin {gather*} -\frac {1}{3} \tanh ^{-1}\left (\sqrt {x^6+1}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/(x*Sqrt[1 + x^6]),x]

[Out]

-1/3*ArcTanh[Sqrt[1 + x^6]]

________________________________________________________________________________________

IntegrateAlgebraic [A]  time = 0.02, size = 14, normalized size = 1.00 \begin {gather*} -\frac {1}{3} \tanh ^{-1}\left (\sqrt {1+x^6}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[1/(x*Sqrt[1 + x^6]),x]

[Out]

-1/3*ArcTanh[Sqrt[1 + x^6]]

________________________________________________________________________________________

fricas [B]  time = 0.45, size = 25, normalized size = 1.79 \begin {gather*} -\frac {1}{6} \, \log \left (\sqrt {x^{6} + 1} + 1\right ) + \frac {1}{6} \, \log \left (\sqrt {x^{6} + 1} - 1\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(x^6+1)^(1/2),x, algorithm="fricas")

[Out]

-1/6*log(sqrt(x^6 + 1) + 1) + 1/6*log(sqrt(x^6 + 1) - 1)

________________________________________________________________________________________

giac [B]  time = 0.31, size = 25, normalized size = 1.79 \begin {gather*} -\frac {1}{6} \, \log \left (\sqrt {x^{6} + 1} + 1\right ) + \frac {1}{6} \, \log \left (\sqrt {x^{6} + 1} - 1\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(x^6+1)^(1/2),x, algorithm="giac")

[Out]

-1/6*log(sqrt(x^6 + 1) + 1) + 1/6*log(sqrt(x^6 + 1) - 1)

________________________________________________________________________________________

maple [A]  time = 0.22, size = 17, normalized size = 1.21

method result size
trager \(\frac {\ln \left (\frac {\sqrt {x^{6}+1}-1}{x^{3}}\right )}{3}\) \(17\)
default \(\frac {\ln \left (\frac {\sqrt {x^{6}+1}-1}{\sqrt {x^{6}}}\right )}{3}\) \(19\)
meijerg \(\frac {\left (-2 \ln \relax (2)+6 \ln \relax (x )\right ) \sqrt {\pi }-2 \ln \left (\frac {1}{2}+\frac {\sqrt {x^{6}+1}}{2}\right ) \sqrt {\pi }}{6 \sqrt {\pi }}\) \(37\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x/(x^6+1)^(1/2),x,method=_RETURNVERBOSE)

[Out]

1/3*ln(((x^6+1)^(1/2)-1)/x^3)

________________________________________________________________________________________

maxima [B]  time = 0.51, size = 25, normalized size = 1.79 \begin {gather*} -\frac {1}{6} \, \log \left (\sqrt {x^{6} + 1} + 1\right ) + \frac {1}{6} \, \log \left (\sqrt {x^{6} + 1} - 1\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(x^6+1)^(1/2),x, algorithm="maxima")

[Out]

-1/6*log(sqrt(x^6 + 1) + 1) + 1/6*log(sqrt(x^6 + 1) - 1)

________________________________________________________________________________________

mupad [B]  time = 0.12, size = 10, normalized size = 0.71 \begin {gather*} -\frac {\mathrm {atanh}\left (\sqrt {x^6+1}\right )}{3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x*(x^6 + 1)^(1/2)),x)

[Out]

-atanh((x^6 + 1)^(1/2))/3

________________________________________________________________________________________

sympy [A]  time = 0.78, size = 8, normalized size = 0.57 \begin {gather*} - \frac {\operatorname {asinh}{\left (\frac {1}{x^{3}} \right )}}{3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/(x**6+1)**(1/2),x)

[Out]

-asinh(x**(-3))/3

________________________________________________________________________________________