Optimal. Leaf size=59 \[ \frac {3}{32} \tan ^{-1}\left (\frac {x}{\sqrt [4]{x^4+x^2}}\right )-\frac {3}{32} \tanh ^{-1}\left (\frac {x}{\sqrt [4]{x^4+x^2}}\right )+\frac {1}{16} \sqrt [4]{x^4+x^2} \left (4 x^3+x\right ) \]
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Rubi [B] time = 0.11, antiderivative size = 125, normalized size of antiderivative = 2.12, number of steps used = 8, number of rules used = 8, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.533, Rules used = {2021, 2024, 2032, 329, 331, 298, 203, 206} \begin {gather*} \frac {1}{16} \sqrt [4]{x^4+x^2} x+\frac {3 \left (x^2+1\right )^{3/4} x^{3/2} \tan ^{-1}\left (\frac {\sqrt {x}}{\sqrt [4]{x^2+1}}\right )}{32 \left (x^4+x^2\right )^{3/4}}-\frac {3 \left (x^2+1\right )^{3/4} x^{3/2} \tanh ^{-1}\left (\frac {\sqrt {x}}{\sqrt [4]{x^2+1}}\right )}{32 \left (x^4+x^2\right )^{3/4}}+\frac {1}{4} \sqrt [4]{x^4+x^2} x^3 \end {gather*}
Antiderivative was successfully verified.
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Rule 203
Rule 206
Rule 298
Rule 329
Rule 331
Rule 2021
Rule 2024
Rule 2032
Rubi steps
\begin {align*} \int x^2 \sqrt [4]{x^2+x^4} \, dx &=\frac {1}{4} x^3 \sqrt [4]{x^2+x^4}+\frac {1}{8} \int \frac {x^4}{\left (x^2+x^4\right )^{3/4}} \, dx\\ &=\frac {1}{16} x \sqrt [4]{x^2+x^4}+\frac {1}{4} x^3 \sqrt [4]{x^2+x^4}-\frac {3}{32} \int \frac {x^2}{\left (x^2+x^4\right )^{3/4}} \, dx\\ &=\frac {1}{16} x \sqrt [4]{x^2+x^4}+\frac {1}{4} x^3 \sqrt [4]{x^2+x^4}-\frac {\left (3 x^{3/2} \left (1+x^2\right )^{3/4}\right ) \int \frac {\sqrt {x}}{\left (1+x^2\right )^{3/4}} \, dx}{32 \left (x^2+x^4\right )^{3/4}}\\ &=\frac {1}{16} x \sqrt [4]{x^2+x^4}+\frac {1}{4} x^3 \sqrt [4]{x^2+x^4}-\frac {\left (3 x^{3/2} \left (1+x^2\right )^{3/4}\right ) \operatorname {Subst}\left (\int \frac {x^2}{\left (1+x^4\right )^{3/4}} \, dx,x,\sqrt {x}\right )}{16 \left (x^2+x^4\right )^{3/4}}\\ &=\frac {1}{16} x \sqrt [4]{x^2+x^4}+\frac {1}{4} x^3 \sqrt [4]{x^2+x^4}-\frac {\left (3 x^{3/2} \left (1+x^2\right )^{3/4}\right ) \operatorname {Subst}\left (\int \frac {x^2}{1-x^4} \, dx,x,\frac {\sqrt {x}}{\sqrt [4]{1+x^2}}\right )}{16 \left (x^2+x^4\right )^{3/4}}\\ &=\frac {1}{16} x \sqrt [4]{x^2+x^4}+\frac {1}{4} x^3 \sqrt [4]{x^2+x^4}-\frac {\left (3 x^{3/2} \left (1+x^2\right )^{3/4}\right ) \operatorname {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\frac {\sqrt {x}}{\sqrt [4]{1+x^2}}\right )}{32 \left (x^2+x^4\right )^{3/4}}+\frac {\left (3 x^{3/2} \left (1+x^2\right )^{3/4}\right ) \operatorname {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\frac {\sqrt {x}}{\sqrt [4]{1+x^2}}\right )}{32 \left (x^2+x^4\right )^{3/4}}\\ &=\frac {1}{16} x \sqrt [4]{x^2+x^4}+\frac {1}{4} x^3 \sqrt [4]{x^2+x^4}+\frac {3 x^{3/2} \left (1+x^2\right )^{3/4} \tan ^{-1}\left (\frac {\sqrt {x}}{\sqrt [4]{1+x^2}}\right )}{32 \left (x^2+x^4\right )^{3/4}}-\frac {3 x^{3/2} \left (1+x^2\right )^{3/4} \tanh ^{-1}\left (\frac {\sqrt {x}}{\sqrt [4]{1+x^2}}\right )}{32 \left (x^2+x^4\right )^{3/4}}\\ \end {align*}
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Mathematica [C] time = 0.01, size = 52, normalized size = 0.88 \begin {gather*} \frac {x \sqrt [4]{x^4+x^2} \left (\left (x^2+1\right )^{5/4}-\, _2F_1\left (-\frac {1}{4},\frac {3}{4};\frac {7}{4};-x^2\right )\right )}{4 \sqrt [4]{x^2+1}} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.14, size = 59, normalized size = 1.00 \begin {gather*} \frac {1}{16} \left (x+4 x^3\right ) \sqrt [4]{x^2+x^4}+\frac {3}{32} \tan ^{-1}\left (\frac {x}{\sqrt [4]{x^2+x^4}}\right )-\frac {3}{32} \tanh ^{-1}\left (\frac {x}{\sqrt [4]{x^2+x^4}}\right ) \end {gather*}
Antiderivative was successfully verified.
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fricas [B] time = 2.56, size = 102, normalized size = 1.73 \begin {gather*} \frac {1}{16} \, {\left (x^{4} + x^{2}\right )}^{\frac {1}{4}} {\left (4 \, x^{3} + x\right )} + \frac {3}{64} \, \arctan \left (\frac {2 \, {\left ({\left (x^{4} + x^{2}\right )}^{\frac {1}{4}} x^{2} + {\left (x^{4} + x^{2}\right )}^{\frac {3}{4}}\right )}}{x}\right ) + \frac {3}{64} \, \log \left (-\frac {2 \, x^{3} - 2 \, {\left (x^{4} + x^{2}\right )}^{\frac {1}{4}} x^{2} + 2 \, \sqrt {x^{4} + x^{2}} x + x - 2 \, {\left (x^{4} + x^{2}\right )}^{\frac {3}{4}}}{x}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.29, size = 57, normalized size = 0.97 \begin {gather*} \frac {1}{16} \, {\left ({\left (\frac {1}{x^{2}} + 1\right )}^{\frac {5}{4}} + 3 \, {\left (\frac {1}{x^{2}} + 1\right )}^{\frac {1}{4}}\right )} x^{4} - \frac {3}{32} \, \arctan \left ({\left (\frac {1}{x^{2}} + 1\right )}^{\frac {1}{4}}\right ) - \frac {3}{64} \, \log \left ({\left (\frac {1}{x^{2}} + 1\right )}^{\frac {1}{4}} + 1\right ) + \frac {3}{64} \, \log \left ({\left (\frac {1}{x^{2}} + 1\right )}^{\frac {1}{4}} - 1\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 3.08, size = 17, normalized size = 0.29
method | result | size |
meijerg | \(\frac {2 x^{\frac {7}{2}} \hypergeom \left (\left [-\frac {1}{4}, \frac {7}{4}\right ], \left [\frac {11}{4}\right ], -x^{2}\right )}{7}\) | \(17\) |
trager | \(\frac {x \left (4 x^{2}+1\right ) \left (x^{4}+x^{2}\right )^{\frac {1}{4}}}{16}-\frac {3 \ln \left (\frac {2 \left (x^{4}+x^{2}\right )^{\frac {3}{4}}+2 \sqrt {x^{4}+x^{2}}\, x +2 x^{2} \left (x^{4}+x^{2}\right )^{\frac {1}{4}}+2 x^{3}+x}{x}\right )}{64}-\frac {3 \RootOf \left (\textit {\_Z}^{2}+1\right ) \ln \left (\frac {2 \sqrt {x^{4}+x^{2}}\, \RootOf \left (\textit {\_Z}^{2}+1\right ) x -2 \RootOf \left (\textit {\_Z}^{2}+1\right ) x^{3}+2 \left (x^{4}+x^{2}\right )^{\frac {3}{4}}-2 x^{2} \left (x^{4}+x^{2}\right )^{\frac {1}{4}}-\RootOf \left (\textit {\_Z}^{2}+1\right ) x}{x}\right )}{64}\) | \(149\) |
risch | \(\frac {x \left (4 x^{2}+1\right ) \left (x^{2} \left (x^{2}+1\right )\right )^{\frac {1}{4}}}{16}+\frac {\left (-\frac {3 \ln \left (\frac {2 x^{6}+2 \left (x^{8}+3 x^{6}+3 x^{4}+x^{2}\right )^{\frac {1}{4}} x^{4}+2 \sqrt {x^{8}+3 x^{6}+3 x^{4}+x^{2}}\, x^{2}+5 x^{4}+2 \left (x^{8}+3 x^{6}+3 x^{4}+x^{2}\right )^{\frac {3}{4}}+4 \left (x^{8}+3 x^{6}+3 x^{4}+x^{2}\right )^{\frac {1}{4}} x^{2}+2 \sqrt {x^{8}+3 x^{6}+3 x^{4}+x^{2}}+4 x^{2}+2 \left (x^{8}+3 x^{6}+3 x^{4}+x^{2}\right )^{\frac {1}{4}}+1}{\left (x^{2}+1\right )^{2}}\right )}{64}+\frac {3 \RootOf \left (\textit {\_Z}^{2}+1\right ) \ln \left (-\frac {-2 \RootOf \left (\textit {\_Z}^{2}+1\right ) \left (x^{8}+3 x^{6}+3 x^{4}+x^{2}\right )^{\frac {1}{4}} x^{4}+2 x^{6}+2 \RootOf \left (\textit {\_Z}^{2}+1\right ) \left (x^{8}+3 x^{6}+3 x^{4}+x^{2}\right )^{\frac {3}{4}}-4 \RootOf \left (\textit {\_Z}^{2}+1\right ) \left (x^{8}+3 x^{6}+3 x^{4}+x^{2}\right )^{\frac {1}{4}} x^{2}-2 \sqrt {x^{8}+3 x^{6}+3 x^{4}+x^{2}}\, x^{2}+5 x^{4}-2 \RootOf \left (\textit {\_Z}^{2}+1\right ) \left (x^{8}+3 x^{6}+3 x^{4}+x^{2}\right )^{\frac {1}{4}}-2 \sqrt {x^{8}+3 x^{6}+3 x^{4}+x^{2}}+4 x^{2}+1}{\left (x^{2}+1\right )^{2}}\right )}{64}\right ) \left (x^{2} \left (x^{2}+1\right )\right )^{\frac {1}{4}} \left (x^{2} \left (x^{2}+1\right )^{3}\right )^{\frac {1}{4}}}{x \left (x^{2}+1\right )}\) | \(416\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int {\left (x^{4} + x^{2}\right )}^{\frac {1}{4}} x^{2}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int x^2\,{\left (x^4+x^2\right )}^{1/4} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^{2} \sqrt [4]{x^{2} \left (x^{2} + 1\right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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