Optimal. Leaf size=72 \[ \frac {7}{128} \tan ^{-1}\left (\frac {x}{\sqrt [4]{x^4-x^2}}\right )-\frac {7}{128} \tanh ^{-1}\left (\frac {x}{\sqrt [4]{x^4-x^2}}\right )+\frac {1}{192} \sqrt [4]{x^4-x^2} \left (32 x^5-4 x^3-7 x\right ) \]
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Rubi [B] time = 0.20, antiderivative size = 153, normalized size of antiderivative = 2.12, number of steps used = 9, number of rules used = 8, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.471, Rules used = {2021, 2024, 2032, 329, 331, 298, 203, 206} \begin {gather*} -\frac {7}{192} \sqrt [4]{x^4-x^2} x+\frac {7 \left (x^2-1\right )^{3/4} x^{3/2} \tan ^{-1}\left (\frac {\sqrt {x}}{\sqrt [4]{x^2-1}}\right )}{128 \left (x^4-x^2\right )^{3/4}}-\frac {7 \left (x^2-1\right )^{3/4} x^{3/2} \tanh ^{-1}\left (\frac {\sqrt {x}}{\sqrt [4]{x^2-1}}\right )}{128 \left (x^4-x^2\right )^{3/4}}+\frac {1}{6} \sqrt [4]{x^4-x^2} x^5-\frac {1}{48} \sqrt [4]{x^4-x^2} x^3 \end {gather*}
Antiderivative was successfully verified.
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Rule 203
Rule 206
Rule 298
Rule 329
Rule 331
Rule 2021
Rule 2024
Rule 2032
Rubi steps
\begin {align*} \int x^4 \sqrt [4]{-x^2+x^4} \, dx &=\frac {1}{6} x^5 \sqrt [4]{-x^2+x^4}-\frac {1}{12} \int \frac {x^6}{\left (-x^2+x^4\right )^{3/4}} \, dx\\ &=-\frac {1}{48} x^3 \sqrt [4]{-x^2+x^4}+\frac {1}{6} x^5 \sqrt [4]{-x^2+x^4}-\frac {7}{96} \int \frac {x^4}{\left (-x^2+x^4\right )^{3/4}} \, dx\\ &=-\frac {7}{192} x \sqrt [4]{-x^2+x^4}-\frac {1}{48} x^3 \sqrt [4]{-x^2+x^4}+\frac {1}{6} x^5 \sqrt [4]{-x^2+x^4}-\frac {7}{128} \int \frac {x^2}{\left (-x^2+x^4\right )^{3/4}} \, dx\\ &=-\frac {7}{192} x \sqrt [4]{-x^2+x^4}-\frac {1}{48} x^3 \sqrt [4]{-x^2+x^4}+\frac {1}{6} x^5 \sqrt [4]{-x^2+x^4}-\frac {\left (7 x^{3/2} \left (-1+x^2\right )^{3/4}\right ) \int \frac {\sqrt {x}}{\left (-1+x^2\right )^{3/4}} \, dx}{128 \left (-x^2+x^4\right )^{3/4}}\\ &=-\frac {7}{192} x \sqrt [4]{-x^2+x^4}-\frac {1}{48} x^3 \sqrt [4]{-x^2+x^4}+\frac {1}{6} x^5 \sqrt [4]{-x^2+x^4}-\frac {\left (7 x^{3/2} \left (-1+x^2\right )^{3/4}\right ) \operatorname {Subst}\left (\int \frac {x^2}{\left (-1+x^4\right )^{3/4}} \, dx,x,\sqrt {x}\right )}{64 \left (-x^2+x^4\right )^{3/4}}\\ &=-\frac {7}{192} x \sqrt [4]{-x^2+x^4}-\frac {1}{48} x^3 \sqrt [4]{-x^2+x^4}+\frac {1}{6} x^5 \sqrt [4]{-x^2+x^4}-\frac {\left (7 x^{3/2} \left (-1+x^2\right )^{3/4}\right ) \operatorname {Subst}\left (\int \frac {x^2}{1-x^4} \, dx,x,\frac {\sqrt {x}}{\sqrt [4]{-1+x^2}}\right )}{64 \left (-x^2+x^4\right )^{3/4}}\\ &=-\frac {7}{192} x \sqrt [4]{-x^2+x^4}-\frac {1}{48} x^3 \sqrt [4]{-x^2+x^4}+\frac {1}{6} x^5 \sqrt [4]{-x^2+x^4}-\frac {\left (7 x^{3/2} \left (-1+x^2\right )^{3/4}\right ) \operatorname {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\frac {\sqrt {x}}{\sqrt [4]{-1+x^2}}\right )}{128 \left (-x^2+x^4\right )^{3/4}}+\frac {\left (7 x^{3/2} \left (-1+x^2\right )^{3/4}\right ) \operatorname {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\frac {\sqrt {x}}{\sqrt [4]{-1+x^2}}\right )}{128 \left (-x^2+x^4\right )^{3/4}}\\ &=-\frac {7}{192} x \sqrt [4]{-x^2+x^4}-\frac {1}{48} x^3 \sqrt [4]{-x^2+x^4}+\frac {1}{6} x^5 \sqrt [4]{-x^2+x^4}+\frac {7 x^{3/2} \left (-1+x^2\right )^{3/4} \tan ^{-1}\left (\frac {\sqrt {x}}{\sqrt [4]{-1+x^2}}\right )}{128 \left (-x^2+x^4\right )^{3/4}}-\frac {7 x^{3/2} \left (-1+x^2\right )^{3/4} \tanh ^{-1}\left (\frac {\sqrt {x}}{\sqrt [4]{-1+x^2}}\right )}{128 \left (-x^2+x^4\right )^{3/4}}\\ \end {align*}
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Mathematica [C] time = 0.03, size = 69, normalized size = 0.96 \begin {gather*} \frac {x \sqrt [4]{x^2 \left (x^2-1\right )} \left (7 \, _2F_1\left (-\frac {1}{4},\frac {3}{4};\frac {7}{4};x^2\right )+\sqrt [4]{1-x^2} \left (8 x^4-x^2-7\right )\right )}{48 \sqrt [4]{1-x^2}} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.21, size = 72, normalized size = 1.00 \begin {gather*} \frac {1}{192} \sqrt [4]{-x^2+x^4} \left (-7 x-4 x^3+32 x^5\right )+\frac {7}{128} \tan ^{-1}\left (\frac {x}{\sqrt [4]{-x^2+x^4}}\right )-\frac {7}{128} \tanh ^{-1}\left (\frac {x}{\sqrt [4]{-x^2+x^4}}\right ) \end {gather*}
Antiderivative was successfully verified.
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fricas [B] time = 1.43, size = 123, normalized size = 1.71 \begin {gather*} \frac {1}{192} \, {\left (32 \, x^{5} - 4 \, x^{3} - 7 \, x\right )} {\left (x^{4} - x^{2}\right )}^{\frac {1}{4}} - \frac {7}{256} \, \arctan \left (\frac {2 \, {\left ({\left (x^{4} - x^{2}\right )}^{\frac {1}{4}} x^{2} + {\left (x^{4} - x^{2}\right )}^{\frac {3}{4}}\right )}}{x}\right ) + \frac {7}{256} \, \log \left (-\frac {2 \, x^{3} - 2 \, {\left (x^{4} - x^{2}\right )}^{\frac {1}{4}} x^{2} + 2 \, \sqrt {x^{4} - x^{2}} x - x - 2 \, {\left (x^{4} - x^{2}\right )}^{\frac {3}{4}}}{x}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.30, size = 89, normalized size = 1.24 \begin {gather*} \frac {1}{192} \, {\left (7 \, {\left (\frac {1}{x^{2}} - 1\right )}^{2} {\left (-\frac {1}{x^{2}} + 1\right )}^{\frac {1}{4}} - 18 \, {\left (-\frac {1}{x^{2}} + 1\right )}^{\frac {5}{4}} - 21 \, {\left (-\frac {1}{x^{2}} + 1\right )}^{\frac {1}{4}}\right )} x^{6} + \frac {7}{128} \, \arctan \left ({\left (-\frac {1}{x^{2}} + 1\right )}^{\frac {1}{4}}\right ) + \frac {7}{256} \, \log \left ({\left (-\frac {1}{x^{2}} + 1\right )}^{\frac {1}{4}} + 1\right ) - \frac {7}{256} \, \log \left (-{\left (-\frac {1}{x^{2}} + 1\right )}^{\frac {1}{4}} + 1\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 3.20, size = 33, normalized size = 0.46
method | result | size |
meijerg | \(\frac {2 \mathrm {signum}\left (x^{2}-1\right )^{\frac {1}{4}} x^{\frac {11}{2}} \hypergeom \left (\left [-\frac {1}{4}, \frac {11}{4}\right ], \left [\frac {15}{4}\right ], x^{2}\right )}{11 \left (-\mathrm {signum}\left (x^{2}-1\right )\right )^{\frac {1}{4}}}\) | \(33\) |
trager | \(\frac {x \left (32 x^{4}-4 x^{2}-7\right ) \left (x^{4}-x^{2}\right )^{\frac {1}{4}}}{192}+\frac {7 \ln \left (\frac {2 \left (x^{4}-x^{2}\right )^{\frac {3}{4}}-2 \sqrt {x^{4}-x^{2}}\, x +2 x^{2} \left (x^{4}-x^{2}\right )^{\frac {1}{4}}-2 x^{3}+x}{x}\right )}{256}+\frac {7 \RootOf \left (\textit {\_Z}^{2}+1\right ) \ln \left (\frac {-2 \sqrt {x^{4}-x^{2}}\, \RootOf \left (\textit {\_Z}^{2}+1\right ) x +2 \RootOf \left (\textit {\_Z}^{2}+1\right ) x^{3}+2 \left (x^{4}-x^{2}\right )^{\frac {3}{4}}-2 x^{2} \left (x^{4}-x^{2}\right )^{\frac {1}{4}}-\RootOf \left (\textit {\_Z}^{2}+1\right ) x}{x}\right )}{256}\) | \(168\) |
risch | \(\frac {x \left (32 x^{4}-4 x^{2}-7\right ) \left (x^{2} \left (x^{2}-1\right )\right )^{\frac {1}{4}}}{192}+\frac {\left (\frac {7 \ln \left (-\frac {-2 x^{6}+2 \left (x^{8}-3 x^{6}+3 x^{4}-x^{2}\right )^{\frac {1}{4}} x^{4}-2 \sqrt {x^{8}-3 x^{6}+3 x^{4}-x^{2}}\, x^{2}+5 x^{4}+2 \left (x^{8}-3 x^{6}+3 x^{4}-x^{2}\right )^{\frac {3}{4}}-4 \left (x^{8}-3 x^{6}+3 x^{4}-x^{2}\right )^{\frac {1}{4}} x^{2}+2 \sqrt {x^{8}-3 x^{6}+3 x^{4}-x^{2}}-4 x^{2}+2 \left (x^{8}-3 x^{6}+3 x^{4}-x^{2}\right )^{\frac {1}{4}}+1}{\left (-1+x \right )^{2} \left (1+x \right )^{2}}\right )}{256}-\frac {7 \RootOf \left (\textit {\_Z}^{2}+1\right ) \ln \left (\frac {-2 \left (x^{8}-3 x^{6}+3 x^{4}-x^{2}\right )^{\frac {1}{4}} \RootOf \left (\textit {\_Z}^{2}+1\right ) x^{4}-2 x^{6}+2 \RootOf \left (\textit {\_Z}^{2}+1\right ) \left (x^{8}-3 x^{6}+3 x^{4}-x^{2}\right )^{\frac {3}{4}}+2 \sqrt {x^{8}-3 x^{6}+3 x^{4}-x^{2}}\, x^{2}+4 \left (x^{8}-3 x^{6}+3 x^{4}-x^{2}\right )^{\frac {1}{4}} \RootOf \left (\textit {\_Z}^{2}+1\right ) x^{2}+5 x^{4}-2 \sqrt {x^{8}-3 x^{6}+3 x^{4}-x^{2}}-2 \RootOf \left (\textit {\_Z}^{2}+1\right ) \left (x^{8}-3 x^{6}+3 x^{4}-x^{2}\right )^{\frac {1}{4}}-4 x^{2}+1}{\left (-1+x \right )^{2} \left (1+x \right )^{2}}\right )}{256}\right ) \left (x^{2} \left (x^{2}-1\right )\right )^{\frac {1}{4}} \left (x^{2} \left (x^{2}-1\right )^{3}\right )^{\frac {1}{4}}}{x \left (x^{2}-1\right )}\) | \(451\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int {\left (x^{4} - x^{2}\right )}^{\frac {1}{4}} x^{4}\,{d x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int x^4\,{\left (x^4-x^2\right )}^{1/4} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int x^{4} \sqrt [4]{x^{2} \left (x - 1\right ) \left (x + 1\right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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