7.198 Problem number 2816

\[ \int \frac {(2+3 x)^{3/2} \sqrt {3+5 x}}{\sqrt {1-2 x}} \, dx \]

Optimal antiderivative \[ -\frac {1597 \EllipticE \left (\frac {\sqrt {21}\, \sqrt {1-2 x}}{7}, \frac {\sqrt {1155}}{33}\right ) \sqrt {33}}{750}-\frac {8 \EllipticF \left (\frac {\sqrt {21}\, \sqrt {1-2 x}}{7}, \frac {\sqrt {1155}}{33}\right ) \sqrt {33}}{125}-\frac {\left (2+3 x \right )^{\frac {3}{2}} \sqrt {1-2 x}\, \sqrt {3+5 x}}{5}-\frac {23 \sqrt {1-2 x}\, \sqrt {2+3 x}\, \sqrt {3+5 x}}{25} \]

command

integrate((2+3*x)^(3/2)*(3+5*x)^(1/2)/(1-2*x)^(1/2),x, algorithm="fricas")

Fricas 1.3.8 (sbcl 2.2.11.debian) via sagemath 9.6 output

\[ -\frac {3}{25} \, {\left (5 \, x + 11\right )} \sqrt {5 \, x + 3} \sqrt {3 \, x + 2} \sqrt {-2 \, x + 1} \]

Fricas 1.3.7 via sagemath 9.3 output

\[ {\rm integral}\left (-\frac {\sqrt {5 \, x + 3} {\left (3 \, x + 2\right )}^{\frac {3}{2}} \sqrt {-2 \, x + 1}}{2 \, x - 1}, x\right ) \]