\[ \int \frac {1}{(a \sin (e+f x))^{9/2} (b \tan (e+f x))^{3/2}} \, dx \]
Optimal antiderivative \[ -\frac {1}{5 b f \left (a \sin \left (f x +e \right )\right )^{\frac {9}{2}} \sqrt {b \tan \left (f x +e \right )}}+\frac {1}{30 a^{2} b f \left (a \sin \left (f x +e \right )\right )^{\frac {5}{2}} \sqrt {b \tan \left (f x +e \right )}}+\frac {1}{12 a^{4} b f \sqrt {a \sin \left (f x +e \right )}\, \sqrt {b \tan \left (f x +e \right )}}-\frac {\sqrt {\frac {\cos \left (f x +e \right )}{2}+\frac {1}{2}}\, \EllipticF \left (\sin \left (\frac {f x}{2}+\frac {e}{2}\right ), \sqrt {2}\right ) \left (\sqrt {\cos }\left (f x +e \right )\right ) \sqrt {b \tan \left (f x +e \right )}}{12 \cos \left (\frac {f x}{2}+\frac {e}{2}\right ) a^{4} b^{2} f \sqrt {a \sin \left (f x +e \right )}} \]
command
integrate(1/(a*sin(f*x+e))^(9/2)/(b*tan(f*x+e))^(3/2),x, algorithm="fricas")
Fricas 1.3.8 (sbcl 2.2.11.debian) via sagemath 9.6 output
\[ -\frac {5 \, {\left (\sqrt {2} \cos \left (f x + e\right )^{6} - 3 \, \sqrt {2} \cos \left (f x + e\right )^{4} + 3 \, \sqrt {2} \cos \left (f x + e\right )^{2} - \sqrt {2}\right )} \sqrt {-a b} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (f x + e\right ) + i \, \sin \left (f x + e\right )\right ) + 5 \, {\left (\sqrt {2} \cos \left (f x + e\right )^{6} - 3 \, \sqrt {2} \cos \left (f x + e\right )^{4} + 3 \, \sqrt {2} \cos \left (f x + e\right )^{2} - \sqrt {2}\right )} \sqrt {-a b} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (f x + e\right ) - i \, \sin \left (f x + e\right )\right ) + 2 \, {\left (5 \, \cos \left (f x + e\right )^{5} - 12 \, \cos \left (f x + e\right )^{3} - 5 \, \cos \left (f x + e\right )\right )} \sqrt {a \sin \left (f x + e\right )} \sqrt {\frac {b \sin \left (f x + e\right )}{\cos \left (f x + e\right )}}}{120 \, {\left (a^{5} b^{2} f \cos \left (f x + e\right )^{6} - 3 \, a^{5} b^{2} f \cos \left (f x + e\right )^{4} + 3 \, a^{5} b^{2} f \cos \left (f x + e\right )^{2} - a^{5} b^{2} f\right )}} \]
Fricas 1.3.7 via sagemath 9.3 output
\[ {\rm integral}\left (\frac {\sqrt {a \sin \left (f x + e\right )} \sqrt {b \tan \left (f x + e\right )}}{{\left (a^{5} b^{2} \cos \left (f x + e\right )^{4} - 2 \, a^{5} b^{2} \cos \left (f x + e\right )^{2} + a^{5} b^{2}\right )} \sin \left (f x + e\right ) \tan \left (f x + e\right )^{2}}, x\right ) \]