Optimal. Leaf size=199 \[ \frac {24 e^{\frac {x}{2}+x z} \pi ^4 x^3}{64 \pi ^4+20 \pi ^2 x^2+x^4}-\frac {24 e^{\frac {x}{2}+x z} \pi ^3 x^4 \cos (\pi z) \sin (\pi z)}{64 \pi ^4+20 \pi ^2 x^2+x^4}+\frac {12 e^{\frac {x}{2}+x z} \pi ^2 x^5 \sin ^2(\pi z)}{64 \pi ^4+20 \pi ^2 x^2+x^4}-\frac {4 e^{\frac {x}{2}+x z} \pi x^4 \cos (\pi z) \sin ^3(\pi z)}{16 \pi ^2+x^2}+\frac {e^{\frac {x}{2}+x z} x^5 \sin ^4(\pi z)}{16 \pi ^2+x^2} \]
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Rubi [A]
time = 0.07, antiderivative size = 199, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 3, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {12, 4519, 2225}
\begin {gather*} \frac {x^5 e^{x z+\frac {x}{2}} \sin ^4(\pi z)}{x^2+16 \pi ^2}-\frac {4 \pi x^4 e^{x z+\frac {x}{2}} \sin ^3(\pi z) \cos (\pi z)}{x^2+16 \pi ^2}-\frac {24 \pi ^3 x^4 e^{x z+\frac {x}{2}} \sin (\pi z) \cos (\pi z)}{x^4+20 \pi ^2 x^2+64 \pi ^4}+\frac {12 \pi ^2 x^5 e^{x z+\frac {x}{2}} \sin ^2(\pi z)}{x^4+20 \pi ^2 x^2+64 \pi ^4}+\frac {24 \pi ^4 x^3 e^{x z+\frac {x}{2}}}{x^4+20 \pi ^2 x^2+64 \pi ^4} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 2225
Rule 4519
Rubi steps
\begin {align*} \int e^{\frac {x}{2}+x z} x^4 \sin ^4(\pi z) \, dz &=x^4 \int e^{\frac {x}{2}+x z} \sin ^4(\pi z) \, dz\\ &=-\frac {4 e^{\frac {x}{2}+x z} \pi x^4 \cos (\pi z) \sin ^3(\pi z)}{16 \pi ^2+x^2}+\frac {e^{\frac {x}{2}+x z} x^5 \sin ^4(\pi z)}{16 \pi ^2+x^2}+\frac {\left (12 \pi ^2 x^4\right ) \int e^{\frac {x}{2}+x z} \sin ^2(\pi z) \, dz}{16 \pi ^2+x^2}\\ &=-\frac {24 e^{\frac {x}{2}+x z} \pi ^3 x^4 \cos (\pi z) \sin (\pi z)}{64 \pi ^4+20 \pi ^2 x^2+x^4}+\frac {12 e^{\frac {x}{2}+x z} \pi ^2 x^5 \sin ^2(\pi z)}{64 \pi ^4+20 \pi ^2 x^2+x^4}-\frac {4 e^{\frac {x}{2}+x z} \pi x^4 \cos (\pi z) \sin ^3(\pi z)}{16 \pi ^2+x^2}+\frac {e^{\frac {x}{2}+x z} x^5 \sin ^4(\pi z)}{16 \pi ^2+x^2}+\frac {\left (24 \pi ^4 x^4\right ) \int e^{\frac {x}{2}+x z} \, dz}{64 \pi ^4+20 \pi ^2 x^2+x^4}\\ &=\frac {24 e^{\frac {x}{2}+x z} \pi ^4 x^3}{64 \pi ^4+20 \pi ^2 x^2+x^4}-\frac {24 e^{\frac {x}{2}+x z} \pi ^3 x^4 \cos (\pi z) \sin (\pi z)}{64 \pi ^4+20 \pi ^2 x^2+x^4}+\frac {12 e^{\frac {x}{2}+x z} \pi ^2 x^5 \sin ^2(\pi z)}{64 \pi ^4+20 \pi ^2 x^2+x^4}-\frac {4 e^{\frac {x}{2}+x z} \pi x^4 \cos (\pi z) \sin ^3(\pi z)}{16 \pi ^2+x^2}+\frac {e^{\frac {x}{2}+x z} x^5 \sin ^4(\pi z)}{16 \pi ^2+x^2}\\ \end {align*}
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Mathematica [A]
time = 0.15, size = 136, normalized size = 0.68 \begin {gather*} \frac {e^{x \left (\frac {1}{2}+z\right )} x^4 \left (192 \pi ^4+60 \pi ^2 x^2+3 x^4-4 x^2 \left (16 \pi ^2+x^2\right ) \cos (2 \pi z)+x^2 \left (4 \pi ^2+x^2\right ) \cos (4 \pi z)-128 \pi ^3 x \sin (2 \pi z)-8 \pi x^3 \sin (2 \pi z)+16 \pi ^3 x \sin (4 \pi z)+4 \pi x^3 \sin (4 \pi z)\right )}{8 \left (64 \pi ^4 x+20 \pi ^2 x^3+x^5\right )} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.18, size = 128, normalized size = 0.64
method | result | size |
default | \(-\frac {x^{4} \left (-\frac {3 \,{\mathrm e}^{\frac {1}{2} x +x z}}{x}-\frac {x \,{\mathrm e}^{\frac {1}{2} x +x z} \cos \left (4 \pi z \right )}{16 \pi ^{2}+x^{2}}-\frac {4 \pi \,{\mathrm e}^{\frac {1}{2} x +x z} \sin \left (4 \pi z \right )}{16 \pi ^{2}+x^{2}}+\frac {4 x \,{\mathrm e}^{\frac {1}{2} x +x z} \cos \left (2 \pi z \right )}{4 \pi ^{2}+x^{2}}+\frac {8 \pi \,{\mathrm e}^{\frac {1}{2} x +x z} \sin \left (2 \pi z \right )}{4 \pi ^{2}+x^{2}}\right )}{8}\) | \(128\) |
risch | \(\frac {3 x^{3} {\mathrm e}^{\frac {x \left (1+2 z \right )}{2}}}{8}+\frac {x^{5} {\mathrm e}^{\frac {1}{2} x +x z} \cos \left (4 \pi z \right )}{128 \pi ^{2}+8 x^{2}}+\frac {x^{4} {\mathrm e}^{\frac {1}{2} x +x z} \pi \sin \left (4 \pi z \right )}{32 \pi ^{2}+2 x^{2}}-\frac {x^{5} {\mathrm e}^{\frac {1}{2} x +x z} \cos \left (2 \pi z \right )}{2 \left (4 \pi ^{2}+x^{2}\right )}-\frac {x^{4} {\mathrm e}^{\frac {1}{2} x +x z} \pi \sin \left (2 \pi z \right )}{4 \pi ^{2}+x^{2}}\) | \(134\) |
norman | \(\frac {\frac {24 \,{\mathrm e}^{\frac {1}{2} x +x z} \pi ^{4} x^{3}}{64 \pi ^{4}+20 \pi ^{2} x^{2}+x^{4}}-\frac {48 \pi ^{3} x^{4} {\mathrm e}^{\frac {1}{2} x +x z} \tan \left (\frac {\pi z}{2}\right )}{64 \pi ^{4}+20 \pi ^{2} x^{2}+x^{4}}+\frac {48 \pi ^{3} x^{4} {\mathrm e}^{\frac {1}{2} x +x z} \left (\tan ^{7}\left (\frac {\pi z}{2}\right )\right )}{64 \pi ^{4}+20 \pi ^{2} x^{2}+x^{4}}+\frac {16 \left (9 \pi ^{4}+10 \pi ^{2} x^{2}+x^{4}\right ) x^{3} {\mathrm e}^{\frac {1}{2} x +x z} \left (\tan ^{4}\left (\frac {\pi z}{2}\right )\right )}{64 \pi ^{4}+20 \pi ^{2} x^{2}+x^{4}}+\frac {24 \,{\mathrm e}^{\frac {1}{2} x +x z} \pi ^{4} x^{3} \left (\tan ^{8}\left (\frac {\pi z}{2}\right )\right )}{64 \pi ^{4}+20 \pi ^{2} x^{2}+x^{4}}-\frac {16 \pi \,x^{4} \left (11 \pi ^{2}+2 x^{2}\right ) {\mathrm e}^{\frac {1}{2} x +x z} \left (\tan ^{3}\left (\frac {\pi z}{2}\right )\right )}{64 \pi ^{4}+20 \pi ^{2} x^{2}+x^{4}}+\frac {16 \pi \,x^{4} \left (11 \pi ^{2}+2 x^{2}\right ) {\mathrm e}^{\frac {1}{2} x +x z} \left (\tan ^{5}\left (\frac {\pi z}{2}\right )\right )}{64 \pi ^{4}+20 \pi ^{2} x^{2}+x^{4}}+\frac {48 x^{3} \left (2 \pi ^{2}+x^{2}\right ) \pi ^{2} {\mathrm e}^{\frac {1}{2} x +x z} \left (\tan ^{2}\left (\frac {\pi z}{2}\right )\right )}{64 \pi ^{4}+20 \pi ^{2} x^{2}+x^{4}}+\frac {48 x^{3} \left (2 \pi ^{2}+x^{2}\right ) \pi ^{2} {\mathrm e}^{\frac {1}{2} x +x z} \left (\tan ^{6}\left (\frac {\pi z}{2}\right )\right )}{64 \pi ^{4}+20 \pi ^{2} x^{2}+x^{4}}}{\left (1+\tan ^{2}\left (\frac {\pi z}{2}\right )\right )^{4}}\) | \(433\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 5.23, size = 160, normalized size = 0.80 \begin {gather*} \frac {{\left ({\left (4 \, \pi ^{2} x^{2} + x^{4}\right )} \cos \left (4 \, \pi z\right ) e^{\left (x z + \frac {1}{2} \, x\right )} - 4 \, {\left (16 \, \pi ^{2} x^{2} + x^{4}\right )} \cos \left (2 \, \pi z\right ) e^{\left (x z + \frac {1}{2} \, x\right )} + 4 \, {\left (4 \, \pi ^{3} x + \pi x^{3}\right )} e^{\left (x z + \frac {1}{2} \, x\right )} \sin \left (4 \, \pi z\right ) - 8 \, {\left (16 \, \pi ^{3} x + \pi x^{3}\right )} e^{\left (x z + \frac {1}{2} \, x\right )} \sin \left (2 \, \pi z\right ) + 3 \, {\left (64 \, \pi ^{4} + 20 \, \pi ^{2} x^{2} + x^{4}\right )} e^{\left (x z + \frac {1}{2} \, x\right )}\right )} x^{4}}{8 \, {\left (64 \, \pi ^{4} x + 20 \, \pi ^{2} x^{3} + x^{5}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.76, size = 145, normalized size = 0.73 \begin {gather*} \frac {4 \, {\left ({\left (4 \, \pi ^{3} x^{4} + \pi x^{6}\right )} \cos \left (\pi z\right )^{3} - {\left (10 \, \pi ^{3} x^{4} + \pi x^{6}\right )} \cos \left (\pi z\right )\right )} e^{\left (x z + \frac {1}{2} \, x\right )} \sin \left (\pi z\right ) + {\left (24 \, \pi ^{4} x^{3} + 16 \, \pi ^{2} x^{5} + x^{7} + {\left (4 \, \pi ^{2} x^{5} + x^{7}\right )} \cos \left (\pi z\right )^{4} - 2 \, {\left (10 \, \pi ^{2} x^{5} + x^{7}\right )} \cos \left (\pi z\right )^{2}\right )} e^{\left (x z + \frac {1}{2} \, x\right )}}{64 \, \pi ^{4} + 20 \, \pi ^{2} x^{2} + x^{4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 147.27, size = 1277, normalized size = 6.42 \begin {gather*} x^{4} \left (\begin {cases} \frac {3 z \sin ^{4}{\left (\pi z \right )}}{8} + \frac {3 z \sin ^{2}{\left (\pi z \right )} \cos ^{2}{\left (\pi z \right )}}{4} + \frac {3 z \cos ^{4}{\left (\pi z \right )}}{8} - \frac {5 \sin ^{3}{\left (\pi z \right )} \cos {\left (\pi z \right )}}{8 \pi } - \frac {3 \sin {\left (\pi z \right )} \cos ^{3}{\left (\pi z \right )}}{8 \pi } & \text {for}\: x = 0 \\\frac {z e^{- 4 i \pi z} \sin ^{4}{\left (\pi z \right )}}{16} - \frac {i z e^{- 4 i \pi z} \sin ^{3}{\left (\pi z \right )} \cos {\left (\pi z \right )}}{4} - \frac {3 z e^{- 4 i \pi z} \sin ^{2}{\left (\pi z \right )} \cos ^{2}{\left (\pi z \right )}}{8} + \frac {i z e^{- 4 i \pi z} \sin {\left (\pi z \right )} \cos ^{3}{\left (\pi z \right )}}{4} + \frac {z e^{- 4 i \pi z} \cos ^{4}{\left (\pi z \right )}}{16} + \frac {7 i e^{- 4 i \pi z} \sin ^{4}{\left (\pi z \right )}}{24 \pi } + \frac {11 e^{- 4 i \pi z} \sin ^{3}{\left (\pi z \right )} \cos {\left (\pi z \right )}}{48 \pi } + \frac {5 e^{- 4 i \pi z} \sin {\left (\pi z \right )} \cos ^{3}{\left (\pi z \right )}}{48 \pi } - \frac {i e^{- 4 i \pi z} \cos ^{4}{\left (\pi z \right )}}{24 \pi } & \text {for}\: x = - 4 i \pi \\- \frac {z e^{- 2 i \pi z} \sin ^{4}{\left (\pi z \right )}}{4} + \frac {i z e^{- 2 i \pi z} \sin ^{3}{\left (\pi z \right )} \cos {\left (\pi z \right )}}{2} + \frac {i z e^{- 2 i \pi z} \sin {\left (\pi z \right )} \cos ^{3}{\left (\pi z \right )}}{2} + \frac {z e^{- 2 i \pi z} \cos ^{4}{\left (\pi z \right )}}{4} - \frac {5 i e^{- 2 i \pi z} \sin ^{4}{\left (\pi z \right )}}{24 \pi } + \frac {e^{- 2 i \pi z} \sin ^{3}{\left (\pi z \right )} \cos {\left (\pi z \right )}}{3 \pi } - \frac {i e^{- 2 i \pi z} \sin ^{2}{\left (\pi z \right )} \cos ^{2}{\left (\pi z \right )}}{2 \pi } - \frac {i e^{- 2 i \pi z} \cos ^{4}{\left (\pi z \right )}}{8 \pi } & \text {for}\: x = - 2 i \pi \\- \frac {z e^{2 i \pi z} \sin ^{4}{\left (\pi z \right )}}{4} - \frac {i z e^{2 i \pi z} \sin ^{3}{\left (\pi z \right )} \cos {\left (\pi z \right )}}{2} - \frac {i z e^{2 i \pi z} \sin {\left (\pi z \right )} \cos ^{3}{\left (\pi z \right )}}{2} + \frac {z e^{2 i \pi z} \cos ^{4}{\left (\pi z \right )}}{4} + \frac {5 i e^{2 i \pi z} \sin ^{4}{\left (\pi z \right )}}{24 \pi } + \frac {e^{2 i \pi z} \sin ^{3}{\left (\pi z \right )} \cos {\left (\pi z \right )}}{3 \pi } + \frac {i e^{2 i \pi z} \sin ^{2}{\left (\pi z \right )} \cos ^{2}{\left (\pi z \right )}}{2 \pi } + \frac {i e^{2 i \pi z} \cos ^{4}{\left (\pi z \right )}}{8 \pi } & \text {for}\: x = 2 i \pi \\\frac {z e^{4 i \pi z} \sin ^{4}{\left (\pi z \right )}}{16} + \frac {i z e^{4 i \pi z} \sin ^{3}{\left (\pi z \right )} \cos {\left (\pi z \right )}}{4} - \frac {3 z e^{4 i \pi z} \sin ^{2}{\left (\pi z \right )} \cos ^{2}{\left (\pi z \right )}}{8} - \frac {i z e^{4 i \pi z} \sin {\left (\pi z \right )} \cos ^{3}{\left (\pi z \right )}}{4} + \frac {z e^{4 i \pi z} \cos ^{4}{\left (\pi z \right )}}{16} - \frac {7 i e^{4 i \pi z} \sin ^{4}{\left (\pi z \right )}}{24 \pi } + \frac {11 e^{4 i \pi z} \sin ^{3}{\left (\pi z \right )} \cos {\left (\pi z \right )}}{48 \pi } + \frac {5 e^{4 i \pi z} \sin {\left (\pi z \right )} \cos ^{3}{\left (\pi z \right )}}{48 \pi } + \frac {i e^{4 i \pi z} \cos ^{4}{\left (\pi z \right )}}{24 \pi } & \text {for}\: x = 4 i \pi \\\frac {x^{4} e^{\frac {x}{2}} e^{x z} \sin ^{4}{\left (\pi z \right )}}{x^{5} + 20 \pi ^{2} x^{3} + 64 \pi ^{4} x} - \frac {4 \pi x^{3} e^{\frac {x}{2}} e^{x z} \sin ^{3}{\left (\pi z \right )} \cos {\left (\pi z \right )}}{x^{5} + 20 \pi ^{2} x^{3} + 64 \pi ^{4} x} + \frac {16 \pi ^{2} x^{2} e^{\frac {x}{2}} e^{x z} \sin ^{4}{\left (\pi z \right )}}{x^{5} + 20 \pi ^{2} x^{3} + 64 \pi ^{4} x} + \frac {12 \pi ^{2} x^{2} e^{\frac {x}{2}} e^{x z} \sin ^{2}{\left (\pi z \right )} \cos ^{2}{\left (\pi z \right )}}{x^{5} + 20 \pi ^{2} x^{3} + 64 \pi ^{4} x} - \frac {40 \pi ^{3} x e^{\frac {x}{2}} e^{x z} \sin ^{3}{\left (\pi z \right )} \cos {\left (\pi z \right )}}{x^{5} + 20 \pi ^{2} x^{3} + 64 \pi ^{4} x} - \frac {24 \pi ^{3} x e^{\frac {x}{2}} e^{x z} \sin {\left (\pi z \right )} \cos ^{3}{\left (\pi z \right )}}{x^{5} + 20 \pi ^{2} x^{3} + 64 \pi ^{4} x} + \frac {24 \pi ^{4} e^{\frac {x}{2}} e^{x z} \sin ^{4}{\left (\pi z \right )}}{x^{5} + 20 \pi ^{2} x^{3} + 64 \pi ^{4} x} + \frac {48 \pi ^{4} e^{\frac {x}{2}} e^{x z} \sin ^{2}{\left (\pi z \right )} \cos ^{2}{\left (\pi z \right )}}{x^{5} + 20 \pi ^{2} x^{3} + 64 \pi ^{4} x} + \frac {24 \pi ^{4} e^{\frac {x}{2}} e^{x z} \cos ^{4}{\left (\pi z \right )}}{x^{5} + 20 \pi ^{2} x^{3} + 64 \pi ^{4} x} & \text {otherwise} \end {cases}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.45, size = 114, normalized size = 0.57 \begin {gather*} \frac {1}{8} \, {\left ({\left (\frac {x \cos \left (4 \, \pi z\right )}{16 \, \pi ^{2} + x^{2}} + \frac {4 \, \pi \sin \left (4 \, \pi z\right )}{16 \, \pi ^{2} + x^{2}}\right )} e^{\left (x z + \frac {1}{2} \, x\right )} - 4 \, {\left (\frac {x \cos \left (2 \, \pi z\right )}{4 \, \pi ^{2} + x^{2}} + \frac {2 \, \pi \sin \left (2 \, \pi z\right )}{4 \, \pi ^{2} + x^{2}}\right )} e^{\left (x z + \frac {1}{2} \, x\right )} + \frac {3 \, e^{\left (x z + \frac {1}{2} \, x\right )}}{x}\right )} x^{4} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 1.11, size = 140, normalized size = 0.70 \begin {gather*} \frac {x^3\,{\mathrm {e}}^{\frac {x}{2}+x\,z}\,\left (24\,\Pi ^4-\frac {x^4\,\cos \left (2\,\Pi \,z\right )}{2}+\frac {x^4\,\cos \left (4\,\Pi \,z\right )}{8}+\frac {3\,x^4}{8}+\frac {15\,\Pi ^2\,x^2}{2}-\Pi \,x^3\,\sin \left (2\,\Pi \,z\right )-16\,\Pi ^3\,x\,\sin \left (2\,\Pi \,z\right )+\frac {\Pi \,x^3\,\sin \left (4\,\Pi \,z\right )}{2}+2\,\Pi ^3\,x\,\sin \left (4\,\Pi \,z\right )-8\,\Pi ^2\,x^2\,\cos \left (2\,\Pi \,z\right )+\frac {\Pi ^2\,x^2\,\cos \left (4\,\Pi \,z\right )}{2}\right )}{64\,\Pi ^4+20\,\Pi ^2\,x^2+x^4} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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