3.2.96 \(\int (b+3 d x^2) (b x+d x^3)^7 \, dx\) [196]

Optimal. Leaf size=15 \[ \frac {1}{8} \left (b x+d x^3\right )^8 \]

[Out]

1/8*(d*x^3+b*x)^8

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Rubi [A]
time = 0.01, antiderivative size = 15, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {1602} \begin {gather*} \frac {1}{8} \left (b x+d x^3\right )^8 \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(b + 3*d*x^2)*(b*x + d*x^3)^7,x]

[Out]

(b*x + d*x^3)^8/8

Rule 1602

Int[(Pp_)*(Qq_)^(m_.), x_Symbol] :> With[{p = Expon[Pp, x], q = Expon[Qq, x]}, Simp[Coeff[Pp, x, p]*x^(p - q +
 1)*(Qq^(m + 1)/((p + m*q + 1)*Coeff[Qq, x, q])), x] /; NeQ[p + m*q + 1, 0] && EqQ[(p + m*q + 1)*Coeff[Qq, x,
q]*Pp, Coeff[Pp, x, p]*x^(p - q)*((p - q + 1)*Qq + (m + 1)*x*D[Qq, x])]] /; FreeQ[m, x] && PolyQ[Pp, x] && Pol
yQ[Qq, x] && NeQ[m, -1]

Rubi steps

\begin {align*} \int \left (b+3 d x^2\right ) \left (b x+d x^3\right )^7 \, dx &=\frac {1}{8} \left (b x+d x^3\right )^8\\ \end {align*}

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Mathematica [B] Leaf count is larger than twice the leaf count of optimal. \(98\) vs. \(2(15)=30\).
time = 0.00, size = 98, normalized size = 6.53 \begin {gather*} \frac {b^8 x^8}{8}+b^7 d x^{10}+\frac {7}{2} b^6 d^2 x^{12}+7 b^5 d^3 x^{14}+\frac {35}{4} b^4 d^4 x^{16}+7 b^3 d^5 x^{18}+\frac {7}{2} b^2 d^6 x^{20}+b d^7 x^{22}+\frac {d^8 x^{24}}{8} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(b + 3*d*x^2)*(b*x + d*x^3)^7,x]

[Out]

(b^8*x^8)/8 + b^7*d*x^10 + (7*b^6*d^2*x^12)/2 + 7*b^5*d^3*x^14 + (35*b^4*d^4*x^16)/4 + 7*b^3*d^5*x^18 + (7*b^2
*d^6*x^20)/2 + b*d^7*x^22 + (d^8*x^24)/8

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Maple [A]
time = 0.21, size = 14, normalized size = 0.93

method result size
default \(\frac {\left (d \,x^{3}+b x \right )^{8}}{8}\) \(14\)
gosper \(\frac {x^{8} \left (d \,x^{2}+b \right )^{8}}{8}\) \(15\)
norman \(x^{22} b \,d^{7}+\frac {1}{8} d^{8} x^{24}+\frac {1}{8} x^{8} b^{8}+x^{10} b^{7} d +\frac {7}{2} x^{12} b^{6} d^{2}+7 x^{14} b^{5} d^{3}+\frac {35}{4} x^{16} b^{4} d^{4}+7 x^{18} b^{3} d^{5}+\frac {7}{2} x^{20} b^{2} d^{6}\) \(89\)
risch \(x^{22} b \,d^{7}+\frac {1}{8} d^{8} x^{24}+\frac {1}{8} x^{8} b^{8}+x^{10} b^{7} d +\frac {7}{2} x^{12} b^{6} d^{2}+7 x^{14} b^{5} d^{3}+\frac {35}{4} x^{16} b^{4} d^{4}+7 x^{18} b^{3} d^{5}+\frac {7}{2} x^{20} b^{2} d^{6}\) \(89\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((3*d*x^2+b)*(d*x^3+b*x)^7,x,method=_RETURNVERBOSE)

[Out]

1/8*(d*x^3+b*x)^8

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Maxima [A]
time = 0.28, size = 13, normalized size = 0.87 \begin {gather*} \frac {1}{8} \, {\left (d x^{3} + b x\right )}^{8} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3*d*x^2+b)*(d*x^3+b*x)^7,x, algorithm="maxima")

[Out]

1/8*(d*x^3 + b*x)^8

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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 88 vs. \(2 (13) = 26\).
time = 0.36, size = 88, normalized size = 5.87 \begin {gather*} \frac {1}{8} \, d^{8} x^{24} + b d^{7} x^{22} + \frac {7}{2} \, b^{2} d^{6} x^{20} + 7 \, b^{3} d^{5} x^{18} + \frac {35}{4} \, b^{4} d^{4} x^{16} + 7 \, b^{5} d^{3} x^{14} + \frac {7}{2} \, b^{6} d^{2} x^{12} + b^{7} d x^{10} + \frac {1}{8} \, b^{8} x^{8} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3*d*x^2+b)*(d*x^3+b*x)^7,x, algorithm="fricas")

[Out]

1/8*d^8*x^24 + b*d^7*x^22 + 7/2*b^2*d^6*x^20 + 7*b^3*d^5*x^18 + 35/4*b^4*d^4*x^16 + 7*b^5*d^3*x^14 + 7/2*b^6*d
^2*x^12 + b^7*d*x^10 + 1/8*b^8*x^8

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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 97 vs. \(2 (10) = 20\).
time = 0.02, size = 97, normalized size = 6.47 \begin {gather*} \frac {b^{8} x^{8}}{8} + b^{7} d x^{10} + \frac {7 b^{6} d^{2} x^{12}}{2} + 7 b^{5} d^{3} x^{14} + \frac {35 b^{4} d^{4} x^{16}}{4} + 7 b^{3} d^{5} x^{18} + \frac {7 b^{2} d^{6} x^{20}}{2} + b d^{7} x^{22} + \frac {d^{8} x^{24}}{8} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3*d*x**2+b)*(d*x**3+b*x)**7,x)

[Out]

b**8*x**8/8 + b**7*d*x**10 + 7*b**6*d**2*x**12/2 + 7*b**5*d**3*x**14 + 35*b**4*d**4*x**16/4 + 7*b**3*d**5*x**1
8 + 7*b**2*d**6*x**20/2 + b*d**7*x**22 + d**8*x**24/8

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Giac [A]
time = 3.25, size = 13, normalized size = 0.87 \begin {gather*} \frac {1}{8} \, {\left (d x^{3} + b x\right )}^{8} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((3*d*x^2+b)*(d*x^3+b*x)^7,x, algorithm="giac")

[Out]

1/8*(d*x^3 + b*x)^8

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Mupad [B]
time = 0.05, size = 88, normalized size = 5.87 \begin {gather*} \frac {b^8\,x^8}{8}+b^7\,d\,x^{10}+\frac {7\,b^6\,d^2\,x^{12}}{2}+7\,b^5\,d^3\,x^{14}+\frac {35\,b^4\,d^4\,x^{16}}{4}+7\,b^3\,d^5\,x^{18}+\frac {7\,b^2\,d^6\,x^{20}}{2}+b\,d^7\,x^{22}+\frac {d^8\,x^{24}}{8} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x + d*x^3)^7*(b + 3*d*x^2),x)

[Out]

(b^8*x^8)/8 + (d^8*x^24)/8 + b^7*d*x^10 + b*d^7*x^22 + (7*b^6*d^2*x^12)/2 + 7*b^5*d^3*x^14 + (35*b^4*d^4*x^16)
/4 + 7*b^3*d^5*x^18 + (7*b^2*d^6*x^20)/2

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