Optimal. Leaf size=171 \[ -\frac {\sqrt {a+b x}}{2 (b-c) x^2}-\frac {b \sqrt {a+b x}}{4 a (b-c) x}+\frac {\sqrt {a+c x}}{2 (b-c) x^2}+\frac {c \sqrt {a+c x}}{4 a (b-c) x}+\frac {b^2 \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{4 a^{3/2} (b-c)}-\frac {c^2 \tanh ^{-1}\left (\frac {\sqrt {a+c x}}{\sqrt {a}}\right )}{4 a^{3/2} (b-c)} \]
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Rubi [A]
time = 0.08, antiderivative size = 171, normalized size of antiderivative = 1.00, number of steps
used = 9, number of rules used = 5, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {2128, 43, 44,
65, 214} \begin {gather*} \frac {b^2 \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{4 a^{3/2} (b-c)}-\frac {c^2 \tanh ^{-1}\left (\frac {\sqrt {a+c x}}{\sqrt {a}}\right )}{4 a^{3/2} (b-c)}-\frac {\sqrt {a+b x}}{2 x^2 (b-c)}+\frac {\sqrt {a+c x}}{2 x^2 (b-c)}-\frac {b \sqrt {a+b x}}{4 a x (b-c)}+\frac {c \sqrt {a+c x}}{4 a x (b-c)} \end {gather*}
Antiderivative was successfully verified.
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Rule 43
Rule 44
Rule 65
Rule 214
Rule 2128
Rubi steps
\begin {align*} \int \frac {1}{x^2 \left (\sqrt {a+b x}+\sqrt {a+c x}\right )} \, dx &=\frac {\int \frac {\sqrt {a+b x}}{x^3} \, dx}{b-c}-\frac {\int \frac {\sqrt {a+c x}}{x^3} \, dx}{b-c}\\ &=-\frac {\sqrt {a+b x}}{2 (b-c) x^2}+\frac {\sqrt {a+c x}}{2 (b-c) x^2}+\frac {b \int \frac {1}{x^2 \sqrt {a+b x}} \, dx}{4 (b-c)}-\frac {c \int \frac {1}{x^2 \sqrt {a+c x}} \, dx}{4 (b-c)}\\ &=-\frac {\sqrt {a+b x}}{2 (b-c) x^2}-\frac {b \sqrt {a+b x}}{4 a (b-c) x}+\frac {\sqrt {a+c x}}{2 (b-c) x^2}+\frac {c \sqrt {a+c x}}{4 a (b-c) x}-\frac {b^2 \int \frac {1}{x \sqrt {a+b x}} \, dx}{8 a (b-c)}+\frac {c^2 \int \frac {1}{x \sqrt {a+c x}} \, dx}{8 a (b-c)}\\ &=-\frac {\sqrt {a+b x}}{2 (b-c) x^2}-\frac {b \sqrt {a+b x}}{4 a (b-c) x}+\frac {\sqrt {a+c x}}{2 (b-c) x^2}+\frac {c \sqrt {a+c x}}{4 a (b-c) x}-\frac {b \text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x}\right )}{4 a (b-c)}+\frac {c \text {Subst}\left (\int \frac {1}{-\frac {a}{c}+\frac {x^2}{c}} \, dx,x,\sqrt {a+c x}\right )}{4 a (b-c)}\\ &=-\frac {\sqrt {a+b x}}{2 (b-c) x^2}-\frac {b \sqrt {a+b x}}{4 a (b-c) x}+\frac {\sqrt {a+c x}}{2 (b-c) x^2}+\frac {c \sqrt {a+c x}}{4 a (b-c) x}+\frac {b^2 \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{4 a^{3/2} (b-c)}-\frac {c^2 \tanh ^{-1}\left (\frac {\sqrt {a+c x}}{\sqrt {a}}\right )}{4 a^{3/2} (b-c)}\\ \end {align*}
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Mathematica [A]
time = 10.14, size = 123, normalized size = 0.72 \begin {gather*} \frac {\sqrt {a} \left (-2 a \sqrt {a+b x}-b x \sqrt {a+b x}+2 a \sqrt {a+c x}+c x \sqrt {a+c x}\right )+b^2 x^2 \tanh ^{-1}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )-c^2 x^2 \tanh ^{-1}\left (\frac {\sqrt {a+c x}}{\sqrt {a}}\right )}{4 a^{3/2} (b-c) x^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.01, size = 120, normalized size = 0.70
method | result | size |
default | \(\frac {2 b^{2} \left (\frac {-\frac {\left (b x +a \right )^{\frac {3}{2}}}{8 a}-\frac {\sqrt {b x +a}}{8}}{x^{2} b^{2}}+\frac {\arctanh \left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{8 a^{\frac {3}{2}}}\right )}{b -c}-\frac {2 c^{2} \left (\frac {-\frac {\left (c x +a \right )^{\frac {3}{2}}}{8 a}-\frac {\sqrt {c x +a}}{8}}{x^{2} c^{2}}+\frac {\arctanh \left (\frac {\sqrt {c x +a}}{\sqrt {a}}\right )}{8 a^{\frac {3}{2}}}\right )}{b -c}\) | \(120\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.35, size = 243, normalized size = 1.42 \begin {gather*} \left [-\frac {\sqrt {a} b^{2} x^{2} \log \left (\frac {b x - 2 \, \sqrt {b x + a} \sqrt {a} + 2 \, a}{x}\right ) + \sqrt {a} c^{2} x^{2} \log \left (\frac {c x + 2 \, \sqrt {c x + a} \sqrt {a} + 2 \, a}{x}\right ) + 2 \, {\left (a b x + 2 \, a^{2}\right )} \sqrt {b x + a} - 2 \, {\left (a c x + 2 \, a^{2}\right )} \sqrt {c x + a}}{8 \, {\left (a^{2} b - a^{2} c\right )} x^{2}}, -\frac {\sqrt {-a} b^{2} x^{2} \arctan \left (\frac {\sqrt {b x + a} \sqrt {-a}}{a}\right ) - \sqrt {-a} c^{2} x^{2} \arctan \left (\frac {\sqrt {c x + a} \sqrt {-a}}{a}\right ) + {\left (a b x + 2 \, a^{2}\right )} \sqrt {b x + a} - {\left (a c x + 2 \, a^{2}\right )} \sqrt {c x + a}}{4 \, {\left (a^{2} b - a^{2} c\right )} x^{2}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{x^{2} \left (\sqrt {a + b x} + \sqrt {a + c x}\right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 1895 vs.
\(2 (139) = 278\).
time = 15.75, size = 1895, normalized size = 11.08 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 11.85, size = 1610, normalized size = 9.42 \begin {gather*} \frac {\frac {a^{3/2}\,b^3}{16\,\left (a^3\,c^2-a^3\,b\,c\right )}+\frac {a^{3/2}\,{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^2\,\left (\frac {b^3}{4}-\frac {7\,b^2\,c}{16}+\frac {b\,c^2}{4}\right )}{\left (a^3\,c^2-a^3\,b\,c\right )\,{\left (\sqrt {a+c\,x}-\sqrt {a}\right )}^2}-\frac {a^{3/2}\,\left (\frac {b^3}{16}+\frac {c\,b^2}{16}\right )\,\left (\sqrt {a+b\,x}-\sqrt {a}\right )}{\left (a^3\,c^2-a^3\,b\,c\right )\,\left (\sqrt {a+c\,x}-\sqrt {a}\right )}+\frac {\left (\frac {b^2}{8}-\frac {c^2}{8}\right )\,{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^3}{a^{3/2}\,c\,{\left (\sqrt {a+c\,x}-\sqrt {a}\right )}^3}}{\frac {{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^4}{{\left (\sqrt {a+c\,x}-\sqrt {a}\right )}^4}-\frac {\left (b+c\right )\,{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^3}{c\,{\left (\sqrt {a+c\,x}-\sqrt {a}\right )}^3}+\frac {b\,{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^2}{c\,{\left (\sqrt {a+c\,x}-\sqrt {a}\right )}^2}}-\frac {\left (\frac {c\,\left (b+c\right )}{4\,a^{3/2}\,\left (b-c\right )}-\frac {c\,\left (b^2-c^2\right )}{4\,a^{3/2}\,{\left (b-c\right )}^2}\right )\,\left (\sqrt {a+b\,x}-\sqrt {a}\right )}{\sqrt {a+c\,x}-\sqrt {a}}-\frac {\ln \left (\frac {\sqrt {a+b\,x}-\sqrt {a}}{\sqrt {a+c\,x}-\sqrt {a}}\right )\,\left (a^{3/2}\,b^2+a^{3/2}\,c^2\right )}{8\,a^3\,b-8\,a^3\,c}+\frac {c^2\,{\left (\sqrt {a+b\,x}-\sqrt {a}\right )}^2}{16\,a^{3/2}\,\left (b-c\right )\,{\left (\sqrt {a+c\,x}-\sqrt {a}\right )}^2}+\frac {\mathrm {atan}\left (\frac {\frac {\left (b+c\right )\,\left (\frac {\left (b+c\right )\,\left (\frac {64\,a^6\,b^3-64\,a^6\,b\,c^2}{64\,\left (a^6\,c^3-a^6\,b\,c^2\right )}-\frac {\left (\sqrt {a+b\,x}-\sqrt {a}\right )\,\left (64\,a^6\,b^3-128\,a^6\,b^2\,c+128\,a^6\,b\,c^2-64\,a^6\,c^3\right )}{32\,\left (a^6\,c^3-a^6\,b\,c^2\right )\,\left (\sqrt {a+c\,x}-\sqrt {a}\right )}\right )}{8\,a^3}-\frac {16\,a^3\,b^4+16\,a^3\,b\,c^3}{64\,\left (a^6\,c^3-a^6\,b\,c^2\right )}+\frac {\left (8\,a^3\,b^4+8\,a^3\,c^4\right )\,\left (\sqrt {a+b\,x}-\sqrt {a}\right )}{32\,\left (a^6\,c^3-a^6\,b\,c^2\right )\,\left (\sqrt {a+c\,x}-\sqrt {a}\right )}\right )\,1{}\mathrm {i}}{8\,a^3}-\frac {\left (b+c\right )\,\left (\frac {16\,a^3\,b^4+16\,a^3\,b\,c^3}{64\,\left (a^6\,c^3-a^6\,b\,c^2\right )}+\frac {\left (b+c\right )\,\left (\frac {64\,a^6\,b^3-64\,a^6\,b\,c^2}{64\,\left (a^6\,c^3-a^6\,b\,c^2\right )}-\frac {\left (\sqrt {a+b\,x}-\sqrt {a}\right )\,\left (64\,a^6\,b^3-128\,a^6\,b^2\,c+128\,a^6\,b\,c^2-64\,a^6\,c^3\right )}{32\,\left (a^6\,c^3-a^6\,b\,c^2\right )\,\left (\sqrt {a+c\,x}-\sqrt {a}\right )}\right )}{8\,a^3}-\frac {\left (8\,a^3\,b^4+8\,a^3\,c^4\right )\,\left (\sqrt {a+b\,x}-\sqrt {a}\right )}{32\,\left (a^6\,c^3-a^6\,b\,c^2\right )\,\left (\sqrt {a+c\,x}-\sqrt {a}\right )}\right )\,1{}\mathrm {i}}{8\,a^3}}{\frac {\left (b+c\right )\,\left (\frac {\left (b+c\right )\,\left (\frac {64\,a^6\,b^3-64\,a^6\,b\,c^2}{64\,\left (a^6\,c^3-a^6\,b\,c^2\right )}-\frac {\left (\sqrt {a+b\,x}-\sqrt {a}\right )\,\left (64\,a^6\,b^3-128\,a^6\,b^2\,c+128\,a^6\,b\,c^2-64\,a^6\,c^3\right )}{32\,\left (a^6\,c^3-a^6\,b\,c^2\right )\,\left (\sqrt {a+c\,x}-\sqrt {a}\right )}\right )}{8\,a^3}-\frac {16\,a^3\,b^4+16\,a^3\,b\,c^3}{64\,\left (a^6\,c^3-a^6\,b\,c^2\right )}+\frac {\left (8\,a^3\,b^4+8\,a^3\,c^4\right )\,\left (\sqrt {a+b\,x}-\sqrt {a}\right )}{32\,\left (a^6\,c^3-a^6\,b\,c^2\right )\,\left (\sqrt {a+c\,x}-\sqrt {a}\right )}\right )}{8\,a^3}-\frac {b\,c^4-b^5}{32\,\left (a^6\,c^3-a^6\,b\,c^2\right )}+\frac {\left (b+c\right )\,\left (\frac {16\,a^3\,b^4+16\,a^3\,b\,c^3}{64\,\left (a^6\,c^3-a^6\,b\,c^2\right )}+\frac {\left (b+c\right )\,\left (\frac {64\,a^6\,b^3-64\,a^6\,b\,c^2}{64\,\left (a^6\,c^3-a^6\,b\,c^2\right )}-\frac {\left (\sqrt {a+b\,x}-\sqrt {a}\right )\,\left (64\,a^6\,b^3-128\,a^6\,b^2\,c+128\,a^6\,b\,c^2-64\,a^6\,c^3\right )}{32\,\left (a^6\,c^3-a^6\,b\,c^2\right )\,\left (\sqrt {a+c\,x}-\sqrt {a}\right )}\right )}{8\,a^3}-\frac {\left (8\,a^3\,b^4+8\,a^3\,c^4\right )\,\left (\sqrt {a+b\,x}-\sqrt {a}\right )}{32\,\left (a^6\,c^3-a^6\,b\,c^2\right )\,\left (\sqrt {a+c\,x}-\sqrt {a}\right )}\right )}{8\,a^3}+\frac {\left (\sqrt {a+b\,x}-\sqrt {a}\right )\,\left (-b^4\,c-b^3\,c^2+b^2\,c^3+b\,c^4\right )}{16\,\left (a^6\,c^3-a^6\,b\,c^2\right )\,\left (\sqrt {a+c\,x}-\sqrt {a}\right )}}\right )\,\left (a^{3/2}\,b+a^{3/2}\,c\right )\,1{}\mathrm {i}}{4\,a^3} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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