3.6.78 \(\int \frac {\sqrt [3]{x}}{\sqrt [4]{x}+\sqrt {x}} \, dx\) [578]

Optimal. Leaf size=76 \[ -12 \sqrt [12]{x}+3 \sqrt [3]{x}-\frac {12 x^{7/12}}{7}+\frac {6 x^{5/6}}{5}-4 \sqrt {3} \tan ^{-1}\left (\frac {1-2 \sqrt [12]{x}}{\sqrt {3}}\right )+6 \log \left (1+\sqrt [12]{x}\right )-2 \log \left (1+\sqrt [4]{x}\right ) \]

[Out]

-12*x^(1/12)+3*x^(1/3)-12/7*x^(7/12)+6/5*x^(5/6)+6*ln(1+x^(1/12))-2*ln(1+x^(1/4))-4*arctan(1/3*(1-2*x^(1/12))*
3^(1/2))*3^(1/2)

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Rubi [A]
time = 0.02, antiderivative size = 76, normalized size of antiderivative = 1.00, number of steps used = 10, number of rules used = 7, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.368, Rules used = {1598, 348, 52, 60, 632, 210, 31} \begin {gather*} -4 \sqrt {3} \text {ArcTan}\left (\frac {1-2 \sqrt [12]{x}}{\sqrt {3}}\right )+\frac {6 x^{5/6}}{5}-\frac {12 x^{7/12}}{7}+3 \sqrt [3]{x}-12 \sqrt [12]{x}+6 \log \left (\sqrt [12]{x}+1\right )-2 \log \left (\sqrt [4]{x}+1\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^(1/3)/(x^(1/4) + Sqrt[x]),x]

[Out]

-12*x^(1/12) + 3*x^(1/3) - (12*x^(7/12))/7 + (6*x^(5/6))/5 - 4*Sqrt[3]*ArcTan[(1 - 2*x^(1/12))/Sqrt[3]] + 6*Lo
g[1 + x^(1/12)] - 2*Log[1 + x^(1/4)]

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 52

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^n/(b*(
m + n + 1))), x] + Dist[n*((b*c - a*d)/(b*(m + n + 1))), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 60

Int[1/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(2/3)), x_Symbol] :> With[{q = Rt[-(b*c - a*d)/b, 3]}, Simp[-
Log[RemoveContent[a + b*x, x]]/(2*b*q^2), x] + (Dist[3/(2*b*q), Subst[Int[1/(q^2 - q*x + x^2), x], x, (c + d*x
)^(1/3)], x] + Dist[3/(2*b*q^2), Subst[Int[1/(q + x), x], x, (c + d*x)^(1/3)], x])] /; FreeQ[{a, b, c, d}, x]
&& NegQ[(b*c - a*d)/b]

Rule 210

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^(-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])
], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 348

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = Denominator[n]}, Dist[k, Subst[Int[x^(k*(
m + 1) - 1)*(a + b*x^(k*n))^p, x], x, x^(1/k)], x]] /; FreeQ[{a, b, m, p}, x] && FractionQ[n]

Rule 632

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Dist[-2, Subst[Int[1/Simp[b^2 - 4*a*c - x^2, x], x]
, x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 1598

Int[(u_.)*(x_)^(m_.)*((a_.)*(x_)^(p_.) + (b_.)*(x_)^(q_.))^(n_.), x_Symbol] :> Int[u*x^(m + n*p)*(a + b*x^(q -
p))^n, x] /; FreeQ[{a, b, m, p, q}, x] && IntegerQ[n] && PosQ[q - p]

Rubi steps

\begin {align*} \int \frac {\sqrt [3]{x}}{\sqrt [4]{x}+\sqrt {x}} \, dx &=\int \frac {\sqrt [12]{x}}{1+\sqrt [4]{x}} \, dx\\ &=4 \text {Subst}\left (\int \frac {x^{10/3}}{1+x} \, dx,x,\sqrt [4]{x}\right )\\ &=\frac {6 x^{5/6}}{5}-4 \text {Subst}\left (\int \frac {x^{7/3}}{1+x} \, dx,x,\sqrt [4]{x}\right )\\ &=-\frac {12 x^{7/12}}{7}+\frac {6 x^{5/6}}{5}+4 \text {Subst}\left (\int \frac {x^{4/3}}{1+x} \, dx,x,\sqrt [4]{x}\right )\\ &=3 \sqrt [3]{x}-\frac {12 x^{7/12}}{7}+\frac {6 x^{5/6}}{5}-4 \text {Subst}\left (\int \frac {\sqrt [3]{x}}{1+x} \, dx,x,\sqrt [4]{x}\right )\\ &=-12 \sqrt [12]{x}+3 \sqrt [3]{x}-\frac {12 x^{7/12}}{7}+\frac {6 x^{5/6}}{5}+4 \text {Subst}\left (\int \frac {1}{x^{2/3} (1+x)} \, dx,x,\sqrt [4]{x}\right )\\ &=-12 \sqrt [12]{x}+3 \sqrt [3]{x}-\frac {12 x^{7/12}}{7}+\frac {6 x^{5/6}}{5}-2 \log \left (1+\sqrt [4]{x}\right )+6 \text {Subst}\left (\int \frac {1}{1+x} \, dx,x,\sqrt [12]{x}\right )+6 \text {Subst}\left (\int \frac {1}{1-x+x^2} \, dx,x,\sqrt [12]{x}\right )\\ &=-12 \sqrt [12]{x}+3 \sqrt [3]{x}-\frac {12 x^{7/12}}{7}+\frac {6 x^{5/6}}{5}+6 \log \left (1+\sqrt [12]{x}\right )-2 \log \left (1+\sqrt [4]{x}\right )-12 \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,-1+2 \sqrt [12]{x}\right )\\ &=-12 \sqrt [12]{x}+3 \sqrt [3]{x}-\frac {12 x^{7/12}}{7}+\frac {6 x^{5/6}}{5}-4 \sqrt {3} \tan ^{-1}\left (\frac {1-2 \sqrt [12]{x}}{\sqrt {3}}\right )+6 \log \left (1+\sqrt [12]{x}\right )-2 \log \left (1+\sqrt [4]{x}\right )\\ \end {align*}

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Mathematica [A]
time = 0.05, size = 83, normalized size = 1.09 \begin {gather*} -12 \sqrt [12]{x}+3 \sqrt [3]{x}-\frac {12 x^{7/12}}{7}+\frac {6 x^{5/6}}{5}-4 \sqrt {3} \tan ^{-1}\left (\frac {1-2 \sqrt [12]{x}}{\sqrt {3}}\right )+4 \log \left (1+\sqrt [12]{x}\right )-2 \log \left (1-\sqrt [12]{x}+\sqrt [6]{x}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^(1/3)/(x^(1/4) + Sqrt[x]),x]

[Out]

-12*x^(1/12) + 3*x^(1/3) - (12*x^(7/12))/7 + (6*x^(5/6))/5 - 4*Sqrt[3]*ArcTan[(1 - 2*x^(1/12))/Sqrt[3]] + 4*Lo
g[1 + x^(1/12)] - 2*Log[1 - x^(1/12) + x^(1/6)]

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Maple [A]
time = 0.31, size = 61, normalized size = 0.80

method	result	size
derivativedivides	\(\frac {6 x^{\frac {5}{6}}}{5}-\frac {12 x^{\frac {7}{12}}}{7}+3 x^{\frac {1}{3}}-12 x^{\frac {1}{12}}+4 \ln \left (1+x^{\frac {1}{12}}\right )-2 \ln \left (1-x^{\frac {1}{12}}+x^{\frac {1}{6}}\right )+4 \sqrt {3}\, \arctan \left (\frac {\left (2 x^{\frac {1}{12}}-1\right ) \sqrt {3}}{3}\right )\)	\(61\)
default	\(\frac {6 x^{\frac {5}{6}}}{5}-\frac {12 x^{\frac {7}{12}}}{7}+3 x^{\frac {1}{3}}-12 x^{\frac {1}{12}}+4 \ln \left (1+x^{\frac {1}{12}}\right )-2 \ln \left (1-x^{\frac {1}{12}}+x^{\frac {1}{6}}\right )+4 \sqrt {3}\, \arctan \left (\frac {\left (2 x^{\frac {1}{12}}-1\right ) \sqrt {3}}{3}\right )\)	\(61\)
meijerg	\(-\frac {3 x^{\frac {1}{12}} \left (-182 x^{\frac {3}{4}}+260 \sqrt {x}-455 x^{\frac {1}{4}}+1820\right )}{455}+4 x^{\frac {1}{12}} \left (\frac {\ln \left (1+x^{\frac {1}{12}}\right )}{x^{\frac {1}{12}}}-\frac {\ln \left (1-x^{\frac {1}{12}}+x^{\frac {1}{6}}\right )}{2 x^{\frac {1}{12}}}+\frac {\sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, x^{\frac {1}{12}}}{2-x^{\frac {1}{12}}}\right )}{x^{\frac {1}{12}}}\right )\)	\(81\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(1/3)/(x^(1/4)+x^(1/2)),x,method=_RETURNVERBOSE)

[Out]

6/5*x^(5/6)-12/7*x^(7/12)+3*x^(1/3)-12*x^(1/12)+4*ln(1+x^(1/12))-2*ln(1-x^(1/12)+x^(1/6))+4*3^(1/2)*arctan(1/3
*(2*x^(1/12)-1)*3^(1/2))

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Maxima [A]
time = 0.51, size = 60, normalized size = 0.79 \begin {gather*} 4 \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x^{\frac {1}{12}} - 1\right )}\right ) + \frac {6}{5} \, x^{\frac {5}{6}} - \frac {12}{7} \, x^{\frac {7}{12}} + 3 \, x^{\frac {1}{3}} - 12 \, x^{\frac {1}{12}} - 2 \, \log \left (x^{\frac {1}{6}} - x^{\frac {1}{12}} + 1\right ) + 4 \, \log \left (x^{\frac {1}{12}} + 1\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(1/3)/(x^(1/4)+x^(1/2)),x, algorithm="maxima")

[Out]

4*sqrt(3)*arctan(1/3*sqrt(3)*(2*x^(1/12) - 1)) + 6/5*x^(5/6) - 12/7*x^(7/12) + 3*x^(1/3) - 12*x^(1/12) - 2*log
(x^(1/6) - x^(1/12) + 1) + 4*log(x^(1/12) + 1)

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Fricas [A]
time = 0.35, size = 62, normalized size = 0.82 \begin {gather*} 4 \, \sqrt {3} \arctan \left (\frac {2}{3} \, \sqrt {3} x^{\frac {1}{12}} - \frac {1}{3} \, \sqrt {3}\right ) + \frac {6}{5} \, x^{\frac {5}{6}} - \frac {12}{7} \, x^{\frac {7}{12}} + 3 \, x^{\frac {1}{3}} - 12 \, x^{\frac {1}{12}} - 2 \, \log \left (x^{\frac {1}{6}} - x^{\frac {1}{12}} + 1\right ) + 4 \, \log \left (x^{\frac {1}{12}} + 1\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(1/3)/(x^(1/4)+x^(1/2)),x, algorithm="fricas")

[Out]

4*sqrt(3)*arctan(2/3*sqrt(3)*x^(1/12) - 1/3*sqrt(3)) + 6/5*x^(5/6) - 12/7*x^(7/12) + 3*x^(1/3) - 12*x^(1/12) -
2*log(x^(1/6) - x^(1/12) + 1) + 4*log(x^(1/12) + 1)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\sqrt [3]{x}}{\sqrt [4]{x} + \sqrt {x}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**(1/3)/(x**(1/4)+x**(1/2)),x)

[Out]

Integral(x**(1/3)/(x**(1/4) + sqrt(x)), x)

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Giac [A]
time = 4.30, size = 60, normalized size = 0.79 \begin {gather*} 4 \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, x^{\frac {1}{12}} - 1\right )}\right ) + \frac {6}{5} \, x^{\frac {5}{6}} - \frac {12}{7} \, x^{\frac {7}{12}} + 3 \, x^{\frac {1}{3}} - 12 \, x^{\frac {1}{12}} - 2 \, \log \left (x^{\frac {1}{6}} - x^{\frac {1}{12}} + 1\right ) + 4 \, \log \left (x^{\frac {1}{12}} + 1\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^(1/3)/(x^(1/4)+x^(1/2)),x, algorithm="giac")

[Out]

4*sqrt(3)*arctan(1/3*sqrt(3)*(2*x^(1/12) - 1)) + 6/5*x^(5/6) - 12/7*x^(7/12) + 3*x^(1/3) - 12*x^(1/12) - 2*log
(x^(1/6) - x^(1/12) + 1) + 4*log(x^(1/12) + 1)

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Mupad [B]
time = 3.08, size = 78, normalized size = 1.03 \begin {gather*} 4\,\ln \left (144\,x^{1/12}+144\right )-\ln \left (18-36\,x^{1/12}+\sqrt {3}\,18{}\mathrm {i}\right )\,\left (2+\sqrt {3}\,2{}\mathrm {i}\right )+\ln \left (36\,x^{1/12}-18+\sqrt {3}\,18{}\mathrm {i}\right )\,\left (-2+\sqrt {3}\,2{}\mathrm {i}\right )+3\,x^{1/3}+\frac {6\,x^{5/6}}{5}-12\,x^{1/12}-\frac {12\,x^{7/12}}{7} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^(1/3)/(x^(1/2) + x^(1/4)),x)

[Out]

4*log(144*x^(1/12) + 144) - log(3^(1/2)*18i - 36*x^(1/12) + 18)*(3^(1/2)*2i + 2) + log(3^(1/2)*18i + 36*x^(1/1
2) - 18)*(3^(1/2)*2i - 2) + 3*x^(1/3) + (6*x^(5/6))/5 - 12*x^(1/12) - (12*x^(7/12))/7

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