3.7.46 \(\int \frac {x^3}{\sqrt {a+b \sqrt {c+d x}}} \, dx\) [646]

Optimal. Leaf size=324 \[ -\frac {4 a \left (a^2-b^2 c\right )^3 \sqrt {a+b \sqrt {c+d x}}}{b^8 d^4}+\frac {4 \left (a^2-b^2 c\right )^2 \left (7 a^2-b^2 c\right ) \left (a+b \sqrt {c+d x}\right )^{3/2}}{3 b^8 d^4}-\frac {12 a \left (7 a^2-3 b^2 c\right ) \left (a^2-b^2 c\right ) \left (a+b \sqrt {c+d x}\right )^{5/2}}{5 b^8 d^4}+\frac {4 \left (35 a^4-30 a^2 b^2 c+3 b^4 c^2\right ) \left (a+b \sqrt {c+d x}\right )^{7/2}}{7 b^8 d^4}-\frac {20 a \left (7 a^2-3 b^2 c\right ) \left (a+b \sqrt {c+d x}\right )^{9/2}}{9 b^8 d^4}+\frac {12 \left (7 a^2-b^2 c\right ) \left (a+b \sqrt {c+d x}\right )^{11/2}}{11 b^8 d^4}-\frac {28 a \left (a+b \sqrt {c+d x}\right )^{13/2}}{13 b^8 d^4}+\frac {4 \left (a+b \sqrt {c+d x}\right )^{15/2}}{15 b^8 d^4} \]

[Out]

4/3*(-b^2*c+a^2)^2*(-b^2*c+7*a^2)*(a+b*(d*x+c)^(1/2))^(3/2)/b^8/d^4-12/5*a*(-3*b^2*c+7*a^2)*(-b^2*c+a^2)*(a+b*
(d*x+c)^(1/2))^(5/2)/b^8/d^4+4/7*(3*b^4*c^2-30*a^2*b^2*c+35*a^4)*(a+b*(d*x+c)^(1/2))^(7/2)/b^8/d^4-20/9*a*(-3*
b^2*c+7*a^2)*(a+b*(d*x+c)^(1/2))^(9/2)/b^8/d^4+12/11*(-b^2*c+7*a^2)*(a+b*(d*x+c)^(1/2))^(11/2)/b^8/d^4-28/13*a
*(a+b*(d*x+c)^(1/2))^(13/2)/b^8/d^4+4/15*(a+b*(d*x+c)^(1/2))^(15/2)/b^8/d^4-4*a*(-b^2*c+a^2)^3*(a+b*(d*x+c)^(1
/2))^(1/2)/b^8/d^4

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Rubi [A]
time = 0.17, antiderivative size = 324, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {378, 1412, 786} \begin {gather*} \frac {12 \left (7 a^2-b^2 c\right ) \left (a+b \sqrt {c+d x}\right )^{11/2}}{11 b^8 d^4}-\frac {20 a \left (7 a^2-3 b^2 c\right ) \left (a+b \sqrt {c+d x}\right )^{9/2}}{9 b^8 d^4}-\frac {12 a \left (7 a^2-3 b^2 c\right ) \left (a^2-b^2 c\right ) \left (a+b \sqrt {c+d x}\right )^{5/2}}{5 b^8 d^4}+\frac {4 \left (a^2-b^2 c\right )^2 \left (7 a^2-b^2 c\right ) \left (a+b \sqrt {c+d x}\right )^{3/2}}{3 b^8 d^4}-\frac {4 a \left (a^2-b^2 c\right )^3 \sqrt {a+b \sqrt {c+d x}}}{b^8 d^4}+\frac {4 \left (35 a^4-30 a^2 b^2 c+3 b^4 c^2\right ) \left (a+b \sqrt {c+d x}\right )^{7/2}}{7 b^8 d^4}+\frac {4 \left (a+b \sqrt {c+d x}\right )^{15/2}}{15 b^8 d^4}-\frac {28 a \left (a+b \sqrt {c+d x}\right )^{13/2}}{13 b^8 d^4} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^3/Sqrt[a + b*Sqrt[c + d*x]],x]

[Out]

(-4*a*(a^2 - b^2*c)^3*Sqrt[a + b*Sqrt[c + d*x]])/(b^8*d^4) + (4*(a^2 - b^2*c)^2*(7*a^2 - b^2*c)*(a + b*Sqrt[c
+ d*x])^(3/2))/(3*b^8*d^4) - (12*a*(7*a^2 - 3*b^2*c)*(a^2 - b^2*c)*(a + b*Sqrt[c + d*x])^(5/2))/(5*b^8*d^4) +
(4*(35*a^4 - 30*a^2*b^2*c + 3*b^4*c^2)*(a + b*Sqrt[c + d*x])^(7/2))/(7*b^8*d^4) - (20*a*(7*a^2 - 3*b^2*c)*(a +
 b*Sqrt[c + d*x])^(9/2))/(9*b^8*d^4) + (12*(7*a^2 - b^2*c)*(a + b*Sqrt[c + d*x])^(11/2))/(11*b^8*d^4) - (28*a*
(a + b*Sqrt[c + d*x])^(13/2))/(13*b^8*d^4) + (4*(a + b*Sqrt[c + d*x])^(15/2))/(15*b^8*d^4)

Rule 378

Int[((a_) + (b_.)*(v_)^(n_))^(p_.)*(x_)^(m_.), x_Symbol] :> With[{c = Coefficient[v, x, 0], d = Coefficient[v,
 x, 1]}, Dist[1/d^(m + 1), Subst[Int[SimplifyIntegrand[(x - c)^m*(a + b*x^n)^p, x], x], x, v], x] /; NeQ[c, 0]
] /; FreeQ[{a, b, n, p}, x] && LinearQ[v, x] && IntegerQ[m]

Rule 786

Int[((d_.) + (e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[ExpandIntegr
and[(d + e*x)^m*(f + g*x)*(a + c*x^2)^p, x], x] /; FreeQ[{a, c, d, e, f, g, m}, x] && IGtQ[p, 0]

Rule 1412

Int[((a_) + (c_.)*(x_)^(n2_.))^(p_.)*((d_) + (e_.)*(x_)^(n_))^(q_.), x_Symbol] :> With[{g = Denominator[n]}, D
ist[g, Subst[Int[x^(g - 1)*(d + e*x^(g*n))^q*(a + c*x^(2*g*n))^p, x], x, x^(1/g)], x]] /; FreeQ[{a, c, d, e, p
, q}, x] && EqQ[n2, 2*n] && FractionQ[n]

Rubi steps

\begin {align*} \int \frac {x^3}{\sqrt {a+b \sqrt {c+d x}}} \, dx &=\frac {\text {Subst}\left (\int \frac {(-c+x)^3}{\sqrt {a+b \sqrt {x}}} \, dx,x,c+d x\right )}{d^4}\\ &=\frac {2 \text {Subst}\left (\int \frac {x \left (-c+x^2\right )^3}{\sqrt {a+b x}} \, dx,x,\sqrt {c+d x}\right )}{d^4}\\ &=\frac {2 \text {Subst}\left (\int \left (-\frac {a \left (a^2-b^2 c\right )^3}{b^7 \sqrt {a+b x}}-\frac {\left (-7 a^2+b^2 c\right ) \left (-a^2+b^2 c\right )^2 \sqrt {a+b x}}{b^7}-\frac {3 \left (7 a^5-10 a^3 b^2 c+3 a b^4 c^2\right ) (a+b x)^{3/2}}{b^7}+\frac {\left (35 a^4-30 a^2 b^2 c+3 b^4 c^2\right ) (a+b x)^{5/2}}{b^7}-\frac {5 a \left (7 a^2-3 b^2 c\right ) (a+b x)^{7/2}}{b^7}-\frac {3 \left (-7 a^2+b^2 c\right ) (a+b x)^{9/2}}{b^7}-\frac {7 a (a+b x)^{11/2}}{b^7}+\frac {(a+b x)^{13/2}}{b^7}\right ) \, dx,x,\sqrt {c+d x}\right )}{d^4}\\ &=-\frac {4 a \left (a^2-b^2 c\right )^3 \sqrt {a+b \sqrt {c+d x}}}{b^8 d^4}+\frac {4 \left (a^2-b^2 c\right )^2 \left (7 a^2-b^2 c\right ) \left (a+b \sqrt {c+d x}\right )^{3/2}}{3 b^8 d^4}-\frac {12 a \left (7 a^2-3 b^2 c\right ) \left (a^2-b^2 c\right ) \left (a+b \sqrt {c+d x}\right )^{5/2}}{5 b^8 d^4}+\frac {4 \left (35 a^4-30 a^2 b^2 c+3 b^4 c^2\right ) \left (a+b \sqrt {c+d x}\right )^{7/2}}{7 b^8 d^4}-\frac {20 a \left (7 a^2-3 b^2 c\right ) \left (a+b \sqrt {c+d x}\right )^{9/2}}{9 b^8 d^4}+\frac {12 \left (7 a^2-b^2 c\right ) \left (a+b \sqrt {c+d x}\right )^{11/2}}{11 b^8 d^4}-\frac {28 a \left (a+b \sqrt {c+d x}\right )^{13/2}}{13 b^8 d^4}+\frac {4 \left (a+b \sqrt {c+d x}\right )^{15/2}}{15 b^8 d^4}\\ \end {align*}

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Mathematica [A]
time = 0.20, size = 232, normalized size = 0.72 \begin {gather*} \frac {4 \sqrt {a+b \sqrt {c+d x}} \left (-14336 a^7+768 a^5 b^2 (58 c-7 d x)+7168 a^6 b \sqrt {c+d x}-640 a^4 b^3 (32 c-7 d x) \sqrt {c+d x}+24 a^2 b^5 \sqrt {c+d x} \left (784 c^2-356 c d x+147 d^2 x^2\right )-16 a^3 b^4 \left (2936 c^2-680 c d x+245 d^2 x^2\right )+6 a b^6 \left (2880 c^3-928 c^2 d x+658 c d^2 x^2-539 d^3 x^3\right )-39 b^7 \sqrt {c+d x} \left (128 c^3-96 c^2 d x+84 c d^2 x^2-77 d^3 x^3\right )\right )}{45045 b^8 d^4} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^3/Sqrt[a + b*Sqrt[c + d*x]],x]

[Out]

(4*Sqrt[a + b*Sqrt[c + d*x]]*(-14336*a^7 + 768*a^5*b^2*(58*c - 7*d*x) + 7168*a^6*b*Sqrt[c + d*x] - 640*a^4*b^3
*(32*c - 7*d*x)*Sqrt[c + d*x] + 24*a^2*b^5*Sqrt[c + d*x]*(784*c^2 - 356*c*d*x + 147*d^2*x^2) - 16*a^3*b^4*(293
6*c^2 - 680*c*d*x + 245*d^2*x^2) + 6*a*b^6*(2880*c^3 - 928*c^2*d*x + 658*c*d^2*x^2 - 539*d^3*x^3) - 39*b^7*Sqr
t[c + d*x]*(128*c^3 - 96*c^2*d*x + 84*c*d^2*x^2 - 77*d^3*x^3)))/(45045*b^8*d^4)

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Maple [A]
time = 0.10, size = 383, normalized size = 1.18

method result size
derivativedivides \(\frac {\frac {4 \left (a +b \sqrt {d x +c}\right )^{\frac {15}{2}}}{15}-\frac {28 a \left (a +b \sqrt {d x +c}\right )^{\frac {13}{2}}}{13}+\frac {4 \left (-3 b^{2} c +21 a^{2}\right ) \left (a +b \sqrt {d x +c}\right )^{\frac {11}{2}}}{11}+\frac {4 \left (-8 \left (-b^{2} c +a^{2}\right ) a -2 a \left (-2 b^{2} c +6 a^{2}\right )-\left (-3 b^{2} c +15 a^{2}\right ) a \right ) \left (a +b \sqrt {d x +c}\right )^{\frac {9}{2}}}{9}+\frac {4 \left (\left (-b^{2} c +a^{2}\right ) \left (-2 b^{2} c +6 a^{2}\right )+8 a^{2} \left (-b^{2} c +a^{2}\right )+\left (-b^{2} c +a^{2}\right )^{2}-\left (-8 \left (-b^{2} c +a^{2}\right ) a -2 a \left (-2 b^{2} c +6 a^{2}\right )\right ) a \right ) \left (a +b \sqrt {d x +c}\right )^{\frac {7}{2}}}{7}+\frac {4 \left (-6 \left (-b^{2} c +a^{2}\right )^{2} a -\left (\left (-b^{2} c +a^{2}\right ) \left (-2 b^{2} c +6 a^{2}\right )+8 a^{2} \left (-b^{2} c +a^{2}\right )+\left (-b^{2} c +a^{2}\right )^{2}\right ) a \right ) \left (a +b \sqrt {d x +c}\right )^{\frac {5}{2}}}{5}+\frac {4 \left (\left (-b^{2} c +a^{2}\right )^{3}+6 \left (-b^{2} c +a^{2}\right )^{2} a^{2}\right ) \left (a +b \sqrt {d x +c}\right )^{\frac {3}{2}}}{3}-4 \left (-b^{2} c +a^{2}\right )^{3} a \sqrt {a +b \sqrt {d x +c}}}{d^{4} b^{8}}\) \(383\)
default \(\frac {\frac {4 \left (a +b \sqrt {d x +c}\right )^{\frac {15}{2}}}{15}-\frac {28 a \left (a +b \sqrt {d x +c}\right )^{\frac {13}{2}}}{13}+\frac {4 \left (-3 b^{2} c +21 a^{2}\right ) \left (a +b \sqrt {d x +c}\right )^{\frac {11}{2}}}{11}+\frac {4 \left (-8 \left (-b^{2} c +a^{2}\right ) a -2 a \left (-2 b^{2} c +6 a^{2}\right )-\left (-3 b^{2} c +15 a^{2}\right ) a \right ) \left (a +b \sqrt {d x +c}\right )^{\frac {9}{2}}}{9}+\frac {4 \left (\left (-b^{2} c +a^{2}\right ) \left (-2 b^{2} c +6 a^{2}\right )+8 a^{2} \left (-b^{2} c +a^{2}\right )+\left (-b^{2} c +a^{2}\right )^{2}-\left (-8 \left (-b^{2} c +a^{2}\right ) a -2 a \left (-2 b^{2} c +6 a^{2}\right )\right ) a \right ) \left (a +b \sqrt {d x +c}\right )^{\frac {7}{2}}}{7}+\frac {4 \left (-6 \left (-b^{2} c +a^{2}\right )^{2} a -\left (\left (-b^{2} c +a^{2}\right ) \left (-2 b^{2} c +6 a^{2}\right )+8 a^{2} \left (-b^{2} c +a^{2}\right )+\left (-b^{2} c +a^{2}\right )^{2}\right ) a \right ) \left (a +b \sqrt {d x +c}\right )^{\frac {5}{2}}}{5}+\frac {4 \left (\left (-b^{2} c +a^{2}\right )^{3}+6 \left (-b^{2} c +a^{2}\right )^{2} a^{2}\right ) \left (a +b \sqrt {d x +c}\right )^{\frac {3}{2}}}{3}-4 \left (-b^{2} c +a^{2}\right )^{3} a \sqrt {a +b \sqrt {d x +c}}}{d^{4} b^{8}}\) \(383\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3/(a+b*(d*x+c)^(1/2))^(1/2),x,method=_RETURNVERBOSE)

[Out]

4/d^4/b^8*(1/15*(a+b*(d*x+c)^(1/2))^(15/2)-7/13*a*(a+b*(d*x+c)^(1/2))^(13/2)+1/11*(-3*b^2*c+21*a^2)*(a+b*(d*x+
c)^(1/2))^(11/2)+1/9*(-8*(-b^2*c+a^2)*a-2*a*(-2*b^2*c+6*a^2)-(-3*b^2*c+15*a^2)*a)*(a+b*(d*x+c)^(1/2))^(9/2)+1/
7*((-b^2*c+a^2)*(-2*b^2*c+6*a^2)+8*a^2*(-b^2*c+a^2)+(-b^2*c+a^2)^2-(-8*(-b^2*c+a^2)*a-2*a*(-2*b^2*c+6*a^2))*a)
*(a+b*(d*x+c)^(1/2))^(7/2)+1/5*(-6*(-b^2*c+a^2)^2*a-((-b^2*c+a^2)*(-2*b^2*c+6*a^2)+8*a^2*(-b^2*c+a^2)+(-b^2*c+
a^2)^2)*a)*(a+b*(d*x+c)^(1/2))^(5/2)+1/3*((-b^2*c+a^2)^3+6*(-b^2*c+a^2)^2*a^2)*(a+b*(d*x+c)^(1/2))^(3/2)-(-b^2
*c+a^2)^3*a*(a+b*(d*x+c)^(1/2))^(1/2))

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Maxima [A]
time = 0.34, size = 268, normalized size = 0.83 \begin {gather*} \frac {4 \, {\left (3003 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {15}{2}} - 24255 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {13}{2}} a - 12285 \, {\left (b^{2} c - 7 \, a^{2}\right )} {\left (\sqrt {d x + c} b + a\right )}^{\frac {11}{2}} + 25025 \, {\left (3 \, a b^{2} c - 7 \, a^{3}\right )} {\left (\sqrt {d x + c} b + a\right )}^{\frac {9}{2}} + 6435 \, {\left (3 \, b^{4} c^{2} - 30 \, a^{2} b^{2} c + 35 \, a^{4}\right )} {\left (\sqrt {d x + c} b + a\right )}^{\frac {7}{2}} - 27027 \, {\left (3 \, a b^{4} c^{2} - 10 \, a^{3} b^{2} c + 7 \, a^{5}\right )} {\left (\sqrt {d x + c} b + a\right )}^{\frac {5}{2}} - 15015 \, {\left (b^{6} c^{3} - 9 \, a^{2} b^{4} c^{2} + 15 \, a^{4} b^{2} c - 7 \, a^{6}\right )} {\left (\sqrt {d x + c} b + a\right )}^{\frac {3}{2}} + 45045 \, {\left (a b^{6} c^{3} - 3 \, a^{3} b^{4} c^{2} + 3 \, a^{5} b^{2} c - a^{7}\right )} \sqrt {\sqrt {d x + c} b + a}\right )}}{45045 \, b^{8} d^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3/(a+b*(d*x+c)^(1/2))^(1/2),x, algorithm="maxima")

[Out]

4/45045*(3003*(sqrt(d*x + c)*b + a)^(15/2) - 24255*(sqrt(d*x + c)*b + a)^(13/2)*a - 12285*(b^2*c - 7*a^2)*(sqr
t(d*x + c)*b + a)^(11/2) + 25025*(3*a*b^2*c - 7*a^3)*(sqrt(d*x + c)*b + a)^(9/2) + 6435*(3*b^4*c^2 - 30*a^2*b^
2*c + 35*a^4)*(sqrt(d*x + c)*b + a)^(7/2) - 27027*(3*a*b^4*c^2 - 10*a^3*b^2*c + 7*a^5)*(sqrt(d*x + c)*b + a)^(
5/2) - 15015*(b^6*c^3 - 9*a^2*b^4*c^2 + 15*a^4*b^2*c - 7*a^6)*(sqrt(d*x + c)*b + a)^(3/2) + 45045*(a*b^6*c^3 -
 3*a^3*b^4*c^2 + 3*a^5*b^2*c - a^7)*sqrt(sqrt(d*x + c)*b + a))/(b^8*d^4)

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Fricas [A]
time = 0.43, size = 231, normalized size = 0.71 \begin {gather*} -\frac {4 \, {\left (3234 \, a b^{6} d^{3} x^{3} - 17280 \, a b^{6} c^{3} + 46976 \, a^{3} b^{4} c^{2} - 44544 \, a^{5} b^{2} c + 14336 \, a^{7} - 28 \, {\left (141 \, a b^{6} c - 140 \, a^{3} b^{4}\right )} d^{2} x^{2} + 64 \, {\left (87 \, a b^{6} c^{2} - 170 \, a^{3} b^{4} c + 84 \, a^{5} b^{2}\right )} d x - {\left (3003 \, b^{7} d^{3} x^{3} - 4992 \, b^{7} c^{3} + 18816 \, a^{2} b^{5} c^{2} - 20480 \, a^{4} b^{3} c + 7168 \, a^{6} b - 252 \, {\left (13 \, b^{7} c - 14 \, a^{2} b^{5}\right )} d^{2} x^{2} + 32 \, {\left (117 \, b^{7} c^{2} - 267 \, a^{2} b^{5} c + 140 \, a^{4} b^{3}\right )} d x\right )} \sqrt {d x + c}\right )} \sqrt {\sqrt {d x + c} b + a}}{45045 \, b^{8} d^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3/(a+b*(d*x+c)^(1/2))^(1/2),x, algorithm="fricas")

[Out]

-4/45045*(3234*a*b^6*d^3*x^3 - 17280*a*b^6*c^3 + 46976*a^3*b^4*c^2 - 44544*a^5*b^2*c + 14336*a^7 - 28*(141*a*b
^6*c - 140*a^3*b^4)*d^2*x^2 + 64*(87*a*b^6*c^2 - 170*a^3*b^4*c + 84*a^5*b^2)*d*x - (3003*b^7*d^3*x^3 - 4992*b^
7*c^3 + 18816*a^2*b^5*c^2 - 20480*a^4*b^3*c + 7168*a^6*b - 252*(13*b^7*c - 14*a^2*b^5)*d^2*x^2 + 32*(117*b^7*c
^2 - 267*a^2*b^5*c + 140*a^4*b^3)*d*x)*sqrt(d*x + c))*sqrt(sqrt(d*x + c)*b + a)/(b^8*d^4)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{3}}{\sqrt {a + b \sqrt {c + d x}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3/(a+b*(d*x+c)**(1/2))**(1/2),x)

[Out]

Integral(x**3/sqrt(a + b*sqrt(c + d*x)), x)

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Giac [A]
time = 3.60, size = 409, normalized size = 1.26 \begin {gather*} -\frac {4 \, {\left (15015 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {3}{2}} b^{6} c^{3} - 45045 \, \sqrt {\sqrt {d x + c} b + a} a b^{6} c^{3} - 19305 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {7}{2}} b^{4} c^{2} + 81081 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {5}{2}} a b^{4} c^{2} - 135135 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {3}{2}} a^{2} b^{4} c^{2} + 135135 \, \sqrt {\sqrt {d x + c} b + a} a^{3} b^{4} c^{2} + 12285 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {11}{2}} b^{2} c - 75075 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {9}{2}} a b^{2} c + 193050 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {7}{2}} a^{2} b^{2} c - 270270 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {5}{2}} a^{3} b^{2} c + 225225 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {3}{2}} a^{4} b^{2} c - 135135 \, \sqrt {\sqrt {d x + c} b + a} a^{5} b^{2} c - 3003 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {15}{2}} + 24255 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {13}{2}} a - 85995 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {11}{2}} a^{2} + 175175 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {9}{2}} a^{3} - 225225 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {7}{2}} a^{4} + 189189 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {5}{2}} a^{5} - 105105 \, {\left (\sqrt {d x + c} b + a\right )}^{\frac {3}{2}} a^{6} + 45045 \, \sqrt {\sqrt {d x + c} b + a} a^{7}\right )}}{45045 \, b^{8} d^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3/(a+b*(d*x+c)^(1/2))^(1/2),x, algorithm="giac")

[Out]

-4/45045*(15015*(sqrt(d*x + c)*b + a)^(3/2)*b^6*c^3 - 45045*sqrt(sqrt(d*x + c)*b + a)*a*b^6*c^3 - 19305*(sqrt(
d*x + c)*b + a)^(7/2)*b^4*c^2 + 81081*(sqrt(d*x + c)*b + a)^(5/2)*a*b^4*c^2 - 135135*(sqrt(d*x + c)*b + a)^(3/
2)*a^2*b^4*c^2 + 135135*sqrt(sqrt(d*x + c)*b + a)*a^3*b^4*c^2 + 12285*(sqrt(d*x + c)*b + a)^(11/2)*b^2*c - 750
75*(sqrt(d*x + c)*b + a)^(9/2)*a*b^2*c + 193050*(sqrt(d*x + c)*b + a)^(7/2)*a^2*b^2*c - 270270*(sqrt(d*x + c)*
b + a)^(5/2)*a^3*b^2*c + 225225*(sqrt(d*x + c)*b + a)^(3/2)*a^4*b^2*c - 135135*sqrt(sqrt(d*x + c)*b + a)*a^5*b
^2*c - 3003*(sqrt(d*x + c)*b + a)^(15/2) + 24255*(sqrt(d*x + c)*b + a)^(13/2)*a - 85995*(sqrt(d*x + c)*b + a)^
(11/2)*a^2 + 175175*(sqrt(d*x + c)*b + a)^(9/2)*a^3 - 225225*(sqrt(d*x + c)*b + a)^(7/2)*a^4 + 189189*(sqrt(d*
x + c)*b + a)^(5/2)*a^5 - 105105*(sqrt(d*x + c)*b + a)^(3/2)*a^6 + 45045*sqrt(sqrt(d*x + c)*b + a)*a^7)/(b^8*d
^4)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {x^3}{\sqrt {a+b\,\sqrt {c+d\,x}}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3/(a + b*(c + d*x)^(1/2))^(1/2),x)

[Out]

int(x^3/(a + b*(c + d*x)^(1/2))^(1/2), x)

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