Optimal. Leaf size=101 \[ \frac {2 a^2 \sqrt {-a+b (c x)^n}}{n}-\frac {2 a \left (-a+b (c x)^n\right )^{3/2}}{3 n}+\frac {2 \left (-a+b (c x)^n\right )^{5/2}}{5 n}-\frac {2 a^{5/2} \tan ^{-1}\left (\frac {\sqrt {-a+b (c x)^n}}{\sqrt {a}}\right )}{n} \]
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Rubi [A]
time = 0.05, antiderivative size = 101, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 6, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.316, Rules used = {374, 12, 272,
52, 65, 211} \begin {gather*} -\frac {2 a^{5/2} \text {ArcTan}\left (\frac {\sqrt {b (c x)^n-a}}{\sqrt {a}}\right )}{n}+\frac {2 a^2 \sqrt {b (c x)^n-a}}{n}-\frac {2 a \left (b (c x)^n-a\right )^{3/2}}{3 n}+\frac {2 \left (b (c x)^n-a\right )^{5/2}}{5 n} \end {gather*}
Antiderivative was successfully verified.
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Rule 12
Rule 52
Rule 65
Rule 211
Rule 272
Rule 374
Rubi steps
\begin {align*} \int \frac {\left (-a+b (c x)^n\right )^{5/2}}{x} \, dx &=\frac {\text {Subst}\left (\int \frac {c \left (-a+b x^n\right )^{5/2}}{x} \, dx,x,c x\right )}{c}\\ &=\text {Subst}\left (\int \frac {\left (-a+b x^n\right )^{5/2}}{x} \, dx,x,c x\right )\\ &=\frac {\text {Subst}\left (\int \frac {(-a+b x)^{5/2}}{x} \, dx,x,(c x)^n\right )}{n}\\ &=\frac {2 \left (-a+b (c x)^n\right )^{5/2}}{5 n}-\frac {a \text {Subst}\left (\int \frac {(-a+b x)^{3/2}}{x} \, dx,x,(c x)^n\right )}{n}\\ &=-\frac {2 a \left (-a+b (c x)^n\right )^{3/2}}{3 n}+\frac {2 \left (-a+b (c x)^n\right )^{5/2}}{5 n}+\frac {a^2 \text {Subst}\left (\int \frac {\sqrt {-a+b x}}{x} \, dx,x,(c x)^n\right )}{n}\\ &=\frac {2 a^2 \sqrt {-a+b (c x)^n}}{n}-\frac {2 a \left (-a+b (c x)^n\right )^{3/2}}{3 n}+\frac {2 \left (-a+b (c x)^n\right )^{5/2}}{5 n}-\frac {a^3 \text {Subst}\left (\int \frac {1}{x \sqrt {-a+b x}} \, dx,x,(c x)^n\right )}{n}\\ &=\frac {2 a^2 \sqrt {-a+b (c x)^n}}{n}-\frac {2 a \left (-a+b (c x)^n\right )^{3/2}}{3 n}+\frac {2 \left (-a+b (c x)^n\right )^{5/2}}{5 n}-\frac {\left (2 a^3\right ) \text {Subst}\left (\int \frac {1}{\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {-a+b (c x)^n}\right )}{b n}\\ &=\frac {2 a^2 \sqrt {-a+b (c x)^n}}{n}-\frac {2 a \left (-a+b (c x)^n\right )^{3/2}}{3 n}+\frac {2 \left (-a+b (c x)^n\right )^{5/2}}{5 n}-\frac {2 a^{5/2} \tan ^{-1}\left (\frac {\sqrt {-a+b (c x)^n}}{\sqrt {a}}\right )}{n}\\ \end {align*}
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Mathematica [A]
time = 0.16, size = 81, normalized size = 0.80 \begin {gather*} \frac {2 \sqrt {-a+b (c x)^n} \left (23 a^2-11 a b (c x)^n+3 b^2 (c x)^{2 n}\right )-30 a^{5/2} \tan ^{-1}\left (\frac {\sqrt {-a+b (c x)^n}}{\sqrt {a}}\right )}{15 n} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.61, size = 78, normalized size = 0.77
method | result | size |
derivativedivides | \(\frac {\frac {2 \left (-a +b \left (c x \right )^{n}\right )^{\frac {5}{2}}}{5}-\frac {2 a \left (-a +b \left (c x \right )^{n}\right )^{\frac {3}{2}}}{3}+2 a^{2} \sqrt {-a +b \left (c x \right )^{n}}-2 a^{\frac {5}{2}} \arctan \left (\frac {\sqrt {-a +b \left (c x \right )^{n}}}{\sqrt {a}}\right )}{n}\) | \(78\) |
default | \(\frac {\frac {2 \left (-a +b \left (c x \right )^{n}\right )^{\frac {5}{2}}}{5}-\frac {2 a \left (-a +b \left (c x \right )^{n}\right )^{\frac {3}{2}}}{3}+2 a^{2} \sqrt {-a +b \left (c x \right )^{n}}-2 a^{\frac {5}{2}} \arctan \left (\frac {\sqrt {-a +b \left (c x \right )^{n}}}{\sqrt {a}}\right )}{n}\) | \(78\) |
risch | \(-\frac {2 \left (3 b^{2} {\mathrm e}^{2 n \ln \left (c x \right )}-11 a \,{\mathrm e}^{n \ln \left (c x \right )} b +23 a^{2}\right ) \left (a -b \,{\mathrm e}^{n \ln \left (c x \right )}\right )}{15 n \sqrt {-a +b \,{\mathrm e}^{n \ln \left (c x \right )}}}-\frac {2 a^{\frac {5}{2}} \arctan \left (\frac {\sqrt {-a +b \,{\mathrm e}^{n \ln \left (c x \right )}}}{\sqrt {a}}\right )}{n}\) | \(93\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.38, size = 169, normalized size = 1.67 \begin {gather*} \left [\frac {15 \, \sqrt {-a} a^{2} \log \left (\frac {\left (c x\right )^{n} b - 2 \, \sqrt {\left (c x\right )^{n} b - a} \sqrt {-a} - 2 \, a}{\left (c x\right )^{n}}\right ) - 2 \, {\left (11 \, \left (c x\right )^{n} a b - 3 \, \left (c x\right )^{2 \, n} b^{2} - 23 \, a^{2}\right )} \sqrt {\left (c x\right )^{n} b - a}}{15 \, n}, -\frac {2 \, {\left (15 \, a^{\frac {5}{2}} \arctan \left (\frac {\sqrt {\left (c x\right )^{n} b - a}}{\sqrt {a}}\right ) + {\left (11 \, \left (c x\right )^{n} a b - 3 \, \left (c x\right )^{2 \, n} b^{2} - 23 \, a^{2}\right )} \sqrt {\left (c x\right )^{n} b - a}\right )}}{15 \, n}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 45.40, size = 114, normalized size = 1.13 \begin {gather*} \begin {cases} \frac {- 2 a^{\frac {5}{2}} \operatorname {atan}{\left (\frac {\sqrt {- a + b \left (c x\right )^{n}}}{\sqrt {a}} \right )} + 2 a^{2} \sqrt {- a + b \left (c x\right )^{n}} - \frac {2 a \left (- a + b \left (c x\right )^{n}\right )^{\frac {3}{2}}}{3} + \frac {2 \left (- a + b \left (c x\right )^{n}\right )^{\frac {5}{2}}}{5}}{n} & \text {for}\: n \neq 0 \\- \left (- a^{2} \sqrt {- a + b} + 2 a b \sqrt {- a + b} - b^{2} \sqrt {- a + b}\right ) \log {\left (c x \right )} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (b\,{\left (c\,x\right )}^n-a\right )}^{5/2}}{x} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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