Optimal. Leaf size=144 \[ \frac {3 (2+x)}{2 \sqrt {1+\frac {2 x}{1+x^2}}}-\frac {1+x^2}{2 (1+x) \sqrt {1+\frac {2 x}{1+x^2}}}-\frac {3 (1+x) \sinh ^{-1}(x)}{\sqrt {1+x^2} \sqrt {1+\frac {2 x}{1+x^2}}}-\frac {9 (1+x) \tanh ^{-1}\left (\frac {1-x}{\sqrt {2} \sqrt {1+x^2}}\right )}{2 \sqrt {2} \sqrt {1+x^2} \sqrt {1+\frac {2 x}{1+x^2}}} \]
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Rubi [A]
time = 0.06, antiderivative size = 144, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 8, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {6855, 984, 747,
827, 858, 221, 739, 212} \begin {gather*} \frac {3 (x+2)}{2 \sqrt {\frac {2 x}{x^2+1}+1}}-\frac {x^2+1}{2 (x+1) \sqrt {\frac {2 x}{x^2+1}+1}}-\frac {3 (x+1) \sinh ^{-1}(x)}{\sqrt {x^2+1} \sqrt {\frac {2 x}{x^2+1}+1}}-\frac {9 (x+1) \tanh ^{-1}\left (\frac {1-x}{\sqrt {2} \sqrt {x^2+1}}\right )}{2 \sqrt {2} \sqrt {x^2+1} \sqrt {\frac {2 x}{x^2+1}+1}} \end {gather*}
Antiderivative was successfully verified.
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Rule 212
Rule 221
Rule 739
Rule 747
Rule 827
Rule 858
Rule 984
Rule 6855
Rubi steps
\begin {align*} \int \frac {1}{\left (1+\frac {2 x}{1+x^2}\right )^{3/2}} \, dx &=\frac {\sqrt {1+2 x+x^2} \int \frac {\left (1+x^2\right )^{3/2}}{\left (1+2 x+x^2\right )^{3/2}} \, dx}{\sqrt {1+x^2} \sqrt {1+\frac {2 x}{1+x^2}}}\\ &=\frac {(4 (2+2 x)) \int \frac {\left (1+x^2\right )^{3/2}}{(2+2 x)^3} \, dx}{\sqrt {1+x^2} \sqrt {1+\frac {2 x}{1+x^2}}}\\ &=-\frac {1+x^2}{2 (1+x) \sqrt {1+\frac {2 x}{1+x^2}}}+\frac {(3 (2+2 x)) \int \frac {x \sqrt {1+x^2}}{(2+2 x)^2} \, dx}{\sqrt {1+x^2} \sqrt {1+\frac {2 x}{1+x^2}}}\\ &=\frac {3 (2+x)}{2 \sqrt {1+\frac {2 x}{1+x^2}}}-\frac {1+x^2}{2 (1+x) \sqrt {1+\frac {2 x}{1+x^2}}}-\frac {(3 (2+2 x)) \int \frac {-4+8 x}{(2+2 x) \sqrt {1+x^2}} \, dx}{8 \sqrt {1+x^2} \sqrt {1+\frac {2 x}{1+x^2}}}\\ &=\frac {3 (2+x)}{2 \sqrt {1+\frac {2 x}{1+x^2}}}-\frac {1+x^2}{2 (1+x) \sqrt {1+\frac {2 x}{1+x^2}}}-\frac {(3 (2+2 x)) \int \frac {1}{\sqrt {1+x^2}} \, dx}{2 \sqrt {1+x^2} \sqrt {1+\frac {2 x}{1+x^2}}}+\frac {(9 (2+2 x)) \int \frac {1}{(2+2 x) \sqrt {1+x^2}} \, dx}{2 \sqrt {1+x^2} \sqrt {1+\frac {2 x}{1+x^2}}}\\ &=\frac {3 (2+x)}{2 \sqrt {1+\frac {2 x}{1+x^2}}}-\frac {1+x^2}{2 (1+x) \sqrt {1+\frac {2 x}{1+x^2}}}-\frac {3 (1+x) \sinh ^{-1}(x)}{\sqrt {1+x^2} \sqrt {1+\frac {2 x}{1+x^2}}}-\frac {(9 (2+2 x)) \text {Subst}\left (\int \frac {1}{8-x^2} \, dx,x,\frac {2-2 x}{\sqrt {1+x^2}}\right )}{2 \sqrt {1+x^2} \sqrt {1+\frac {2 x}{1+x^2}}}\\ &=\frac {3 (2+x)}{2 \sqrt {1+\frac {2 x}{1+x^2}}}-\frac {1+x^2}{2 (1+x) \sqrt {1+\frac {2 x}{1+x^2}}}-\frac {3 (1+x) \sinh ^{-1}(x)}{\sqrt {1+x^2} \sqrt {1+\frac {2 x}{1+x^2}}}-\frac {9 (1+x) \tanh ^{-1}\left (\frac {1-x}{\sqrt {2} \sqrt {1+x^2}}\right )}{2 \sqrt {2} \sqrt {1+x^2} \sqrt {1+\frac {2 x}{1+x^2}}}\\ \end {align*}
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Mathematica [A]
time = 0.30, size = 106, normalized size = 0.74 \begin {gather*} \frac {(1+x) \left (\sqrt {1+x^2} \left (5+9 x+2 x^2\right )-6 (1+x)^2 \tanh ^{-1}\left (\frac {x}{\sqrt {1+x^2}}\right )+9 \sqrt {2} (1+x)^2 \tanh ^{-1}\left (\frac {1+x-\sqrt {1+x^2}}{\sqrt {2}}\right )\right )}{2 \left (\frac {(1+x)^2}{1+x^2}\right )^{3/2} \left (1+x^2\right )^{3/2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.16, size = 217, normalized size = 1.51
method | result | size |
risch | \(\frac {2 x^{4}+9 x^{3}+7 x^{2}+9 x +5}{2 \left (1+x \right ) \left (x^{2}+1\right ) \sqrt {\frac {\left (1+x \right )^{2}}{x^{2}+1}}}+\frac {\left (-3 \arcsinh \left (x \right )-\frac {9 \sqrt {2}\, \arctanh \left (\frac {\left (2-2 x \right ) \sqrt {2}}{4 \sqrt {\left (1+x \right )^{2}-2 x}}\right )}{4}\right ) \left (1+x \right )}{\sqrt {\frac {\left (1+x \right )^{2}}{x^{2}+1}}\, \sqrt {x^{2}+1}}\) | \(109\) |
trager | \(\frac {\left (x^{2}+1\right ) \left (2 x^{2}+9 x +5\right ) \sqrt {-\frac {-x^{2}-2 x -1}{x^{2}+1}}}{2 \left (1+x \right )^{3}}+3 \ln \left (-\frac {\sqrt {-\frac {-x^{2}-2 x -1}{x^{2}+1}}\, x^{2}-x^{2}+\sqrt {-\frac {-x^{2}-2 x -1}{x^{2}+1}}-x}{1+x}\right )+\frac {9 \RootOf \left (\textit {\_Z}^{2}-2\right ) \ln \left (\frac {\RootOf \left (\textit {\_Z}^{2}-2\right ) x^{2}+2 \sqrt {-\frac {-x^{2}-2 x -1}{x^{2}+1}}\, x^{2}-\RootOf \left (\textit {\_Z}^{2}-2\right )+2 \sqrt {-\frac {-x^{2}-2 x -1}{x^{2}+1}}}{\left (1+x \right )^{2}}\right )}{4}\) | \(193\) |
default | \(-\frac {\left (1+x \right ) \left (-\left (x^{2}+1\right )^{\frac {5}{2}} x +\left (x^{2}+1\right )^{\frac {3}{2}} x^{3}+\left (x^{2}+1\right )^{\frac {5}{2}}-\left (x^{2}+1\right )^{\frac {3}{2}} x^{2}-18 \arctanh \left (\frac {\left (-1+x \right ) \sqrt {2}}{2 \sqrt {x^{2}+1}}\right ) \sqrt {2}\, x^{2}-5 x \left (x^{2}+1\right )^{\frac {3}{2}}+6 \sqrt {x^{2}+1}\, x^{3}+24 \arcsinh \left (x \right ) x^{2}-36 \arctanh \left (\frac {\left (-1+x \right ) \sqrt {2}}{2 \sqrt {x^{2}+1}}\right ) \sqrt {2}\, x -3 \left (x^{2}+1\right )^{\frac {3}{2}}-6 \sqrt {x^{2}+1}\, x^{2}+48 \arcsinh \left (x \right ) x -18 \sqrt {2}\, \arctanh \left (\frac {\left (-1+x \right ) \sqrt {2}}{2 \sqrt {x^{2}+1}}\right )-30 x \sqrt {x^{2}+1}+24 \arcsinh \left (x \right )-18 \sqrt {x^{2}+1}\right )}{8 \left (\frac {x^{2}+2 x +1}{x^{2}+1}\right )^{\frac {3}{2}} \left (x^{2}+1\right )^{\frac {3}{2}}}\) | \(217\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.33, size = 205, normalized size = 1.42 \begin {gather*} \frac {10 \, x^{3} + 9 \, \sqrt {2} {\left (x^{3} + 3 \, x^{2} + 3 \, x + 1\right )} \log \left (-\frac {x^{2} + \sqrt {2} {\left (x^{2} - 1\right )} + {\left (2 \, x^{2} + \sqrt {2} {\left (x^{2} + 1\right )} + 2\right )} \sqrt {\frac {x^{2} + 2 \, x + 1}{x^{2} + 1}} - 1}{x^{2} + 2 \, x + 1}\right ) + 30 \, x^{2} + 12 \, {\left (x^{3} + 3 \, x^{2} + 3 \, x + 1\right )} \log \left (-\frac {x^{2} - {\left (x^{2} + 1\right )} \sqrt {\frac {x^{2} + 2 \, x + 1}{x^{2} + 1}} + x}{x + 1}\right ) + 2 \, {\left (2 \, x^{4} + 9 \, x^{3} + 7 \, x^{2} + 9 \, x + 5\right )} \sqrt {\frac {x^{2} + 2 \, x + 1}{x^{2} + 1}} + 30 \, x + 10}{4 \, {\left (x^{3} + 3 \, x^{2} + 3 \, x + 1\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\left (\frac {2 x}{x^{2} + 1} + 1\right )^{\frac {3}{2}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 5.33, size = 170, normalized size = 1.18 \begin {gather*} \frac {9 \, \sqrt {2} \log \left (\frac {{\left | -2 \, x - 2 \, \sqrt {2} + 2 \, \sqrt {x^{2} + 1} - 2 \right |}}{{\left | -2 \, x + 2 \, \sqrt {2} + 2 \, \sqrt {x^{2} + 1} - 2 \right |}}\right )}{4 \, \mathrm {sgn}\left (x + 1\right )} + \frac {3 \, \log \left (-x + \sqrt {x^{2} + 1}\right )}{\mathrm {sgn}\left (x + 1\right )} + \frac {\sqrt {x^{2} + 1}}{\mathrm {sgn}\left (x + 1\right )} + \frac {7 \, {\left (x - \sqrt {x^{2} + 1}\right )}^{3} + 5 \, {\left (x - \sqrt {x^{2} + 1}\right )}^{2} - 13 \, x + 13 \, \sqrt {x^{2} + 1} + 5}{{\left ({\left (x - \sqrt {x^{2} + 1}\right )}^{2} + 2 \, x - 2 \, \sqrt {x^{2} + 1} - 1\right )}^{2} \mathrm {sgn}\left (x + 1\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {1}{{\left (\frac {2\,x}{x^2+1}+1\right )}^{3/2}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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