3.10.40 \(\int \frac {1}{(1+x)^{2/3} (-1+x^2)^{2/3}} \, dx\) [940]

Optimal. Leaf size=20 \[ \frac {3 \sqrt [3]{-1+x^2}}{2 (1+x)^{2/3}} \]

[Out]

3/2*(x^2-1)^(1/3)/(1+x)^(2/3)

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Rubi [A]
time = 0.00, antiderivative size = 20, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.059, Rules used = {665} \begin {gather*} \frac {3 \sqrt [3]{x^2-1}}{2 (x+1)^{2/3}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/((1 + x)^(2/3)*(-1 + x^2)^(2/3)),x]

[Out]

(3*(-1 + x^2)^(1/3))/(2*(1 + x)^(2/3))

Rule 665

Int[((d_) + (e_.)*(x_))^(m_)*((a_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[e*(d + e*x)^m*((a + c*x^2)^(p + 1)/
(2*c*d*(p + 1))), x] /; FreeQ[{a, c, d, e, m, p}, x] && EqQ[c*d^2 + a*e^2, 0] &&  !IntegerQ[p] && EqQ[m + 2*p
+ 2, 0]

Rubi steps

\begin {align*} \int \frac {1}{(1+x)^{2/3} \left (-1+x^2\right )^{2/3}} \, dx &=\frac {3 \sqrt [3]{-1+x^2}}{2 (1+x)^{2/3}}\\ \end {align*}

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Mathematica [A]
time = 0.24, size = 20, normalized size = 1.00 \begin {gather*} \frac {3 \sqrt [3]{-1+x^2}}{2 (1+x)^{2/3}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/((1 + x)^(2/3)*(-1 + x^2)^(2/3)),x]

[Out]

(3*(-1 + x^2)^(1/3))/(2*(1 + x)^(2/3))

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Maple [A]
time = 0.25, size = 18, normalized size = 0.90

method result size
gosper \(\frac {3 \left (1+x \right )^{\frac {1}{3}} \left (-1+x \right )}{2 \left (x^{2}-1\right )^{\frac {2}{3}}}\) \(18\)
risch \(\frac {3 \left (1+x \right )^{\frac {1}{3}} \left (\frac {\left (x^{2}-1\right )^{2}}{1+x}\right )^{\frac {1}{3}} \left (-1+x \right )}{2 \left (x^{2}-1\right )^{\frac {2}{3}} \left (\left (-1+x \right )^{2} \left (1+x \right )\right )^{\frac {1}{3}}}\) \(44\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(1+x)^(2/3)/(x^2-1)^(2/3),x,method=_RETURNVERBOSE)

[Out]

3/2*(1+x)^(1/3)*(-1+x)/(x^2-1)^(2/3)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+x)^(2/3)/(x^2-1)^(2/3),x, algorithm="maxima")

[Out]

integrate(1/((x^2 - 1)^(2/3)*(x + 1)^(2/3)), x)

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Fricas [A]
time = 0.38, size = 14, normalized size = 0.70 \begin {gather*} \frac {3 \, {\left (x^{2} - 1\right )}^{\frac {1}{3}}}{2 \, {\left (x + 1\right )}^{\frac {2}{3}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+x)^(2/3)/(x^2-1)^(2/3),x, algorithm="fricas")

[Out]

3/2*(x^2 - 1)^(1/3)/(x + 1)^(2/3)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\left (\left (x - 1\right ) \left (x + 1\right )\right )^{\frac {2}{3}} \left (x + 1\right )^{\frac {2}{3}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+x)**(2/3)/(x**2-1)**(2/3),x)

[Out]

Integral(1/(((x - 1)*(x + 1))**(2/3)*(x + 1)**(2/3)), x)

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Giac [A]
time = 2.85, size = 13, normalized size = 0.65 \begin {gather*} \frac {3}{2} \, {\left (-\frac {2}{x + 1} + 1\right )}^{\frac {1}{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+x)^(2/3)/(x^2-1)^(2/3),x, algorithm="giac")

[Out]

3/2*(-2/(x + 1) + 1)^(1/3)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.05 \begin {gather*} \int \frac {1}{{\left (x^2-1\right )}^{2/3}\,{\left (x+1\right )}^{2/3}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((x^2 - 1)^(2/3)*(x + 1)^(2/3)),x)

[Out]

int(1/((x^2 - 1)^(2/3)*(x + 1)^(2/3)), x)

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