3.13.100 \(\int \frac {4 b+a x^3}{\sqrt [4]{b+a x^3} (b+a x^3+x^4)} \, dx\) [1300]

Optimal. Leaf size=94 \[ -\sqrt {2} \text {ArcTan}\left (\frac {-\frac {x^2}{\sqrt {2}}+\frac {\sqrt {b+a x^3}}{\sqrt {2}}}{x \sqrt [4]{b+a x^3}}\right )+\sqrt {2} \tanh ^{-1}\left (\frac {\sqrt {2} x \sqrt [4]{b+a x^3}}{x^2+\sqrt {b+a x^3}}\right ) \]

[Out]

-2^(1/2)*arctan((-1/2*x^2*2^(1/2)+1/2*(a*x^3+b)^(1/2)*2^(1/2))/x/(a*x^3+b)^(1/4))+2^(1/2)*arctanh(2^(1/2)*x*(a
*x^3+b)^(1/4)/(x^2+(a*x^3+b)^(1/2)))

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Rubi [F]
time = 0.44, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {4 b+a x^3}{\sqrt [4]{b+a x^3} \left (b+a x^3+x^4\right )} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[(4*b + a*x^3)/((b + a*x^3)^(1/4)*(b + a*x^3 + x^4)),x]

[Out]

4*b*Defer[Int][1/((b + a*x^3)^(1/4)*(b + a*x^3 + x^4)), x] + a*Defer[Int][x^3/((b + a*x^3)^(1/4)*(b + a*x^3 +
x^4)), x]

Rubi steps

\begin {align*} \int \frac {4 b+a x^3}{\sqrt [4]{b+a x^3} \left (b+a x^3+x^4\right )} \, dx &=\int \left (\frac {4 b}{\sqrt [4]{b+a x^3} \left (b+a x^3+x^4\right )}+\frac {a x^3}{\sqrt [4]{b+a x^3} \left (b+a x^3+x^4\right )}\right ) \, dx\\ &=a \int \frac {x^3}{\sqrt [4]{b+a x^3} \left (b+a x^3+x^4\right )} \, dx+(4 b) \int \frac {1}{\sqrt [4]{b+a x^3} \left (b+a x^3+x^4\right )} \, dx\\ \end {align*}

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Mathematica [A]
time = 0.64, size = 83, normalized size = 0.88 \begin {gather*} \sqrt {2} \left (-\text {ArcTan}\left (\frac {-x^2+\sqrt {b+a x^3}}{\sqrt {2} x \sqrt [4]{b+a x^3}}\right )+\tanh ^{-1}\left (\frac {\sqrt {2} x \sqrt [4]{b+a x^3}}{x^2+\sqrt {b+a x^3}}\right )\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(4*b + a*x^3)/((b + a*x^3)^(1/4)*(b + a*x^3 + x^4)),x]

[Out]

Sqrt[2]*(-ArcTan[(-x^2 + Sqrt[b + a*x^3])/(Sqrt[2]*x*(b + a*x^3)^(1/4))] + ArcTanh[(Sqrt[2]*x*(b + a*x^3)^(1/4
))/(x^2 + Sqrt[b + a*x^3])])

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Maple [F]
time = 0.01, size = 0, normalized size = 0.00 \[\int \frac {a \,x^{3}+4 b}{\left (a \,x^{3}+b \right )^{\frac {1}{4}} \left (a \,x^{3}+x^{4}+b \right )}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x^3+4*b)/(a*x^3+b)^(1/4)/(a*x^3+x^4+b),x)

[Out]

int((a*x^3+4*b)/(a*x^3+b)^(1/4)/(a*x^3+x^4+b),x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x^3+4*b)/(a*x^3+b)^(1/4)/(a*x^3+x^4+b),x, algorithm="maxima")

[Out]

integrate((a*x^3 + 4*b)/((a*x^3 + x^4 + b)*(a*x^3 + b)^(1/4)), x)

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Fricas [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x^3+4*b)/(a*x^3+b)^(1/4)/(a*x^3+x^4+b),x, algorithm="fricas")

[Out]

Timed out

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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x**3+4*b)/(a*x**3+b)**(1/4)/(a*x**3+x**4+b),x)

[Out]

Timed out

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*x^3+4*b)/(a*x^3+b)^(1/4)/(a*x^3+x^4+b),x, algorithm="giac")

[Out]

integrate((a*x^3 + 4*b)/((a*x^3 + x^4 + b)*(a*x^3 + b)^(1/4)), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {a\,x^3+4\,b}{{\left (a\,x^3+b\right )}^{1/4}\,\left (x^4+a\,x^3+b\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((4*b + a*x^3)/((b + a*x^3)^(1/4)*(b + a*x^3 + x^4)),x)

[Out]

int((4*b + a*x^3)/((b + a*x^3)^(1/4)*(b + a*x^3 + x^4)), x)

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