Optimal. Leaf size=125 \[ -\frac {2 \text {ArcTan}\left (\frac {\sqrt [4]{d} \left (-a b^2 x+\left (2 a b+b^2\right ) x^2+(-a-2 b) x^3+x^4\right )^{3/4}}{x (-b+x)^2}\right )}{d^{3/4}}+\frac {2 \tanh ^{-1}\left (\frac {\sqrt [4]{d} \left (-a b^2 x+\left (2 a b+b^2\right ) x^2+(-a-2 b) x^3+x^4\right )^{3/4}}{x (-b+x)^2}\right )}{d^{3/4}} \]
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Rubi [F]
time = 5.64, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps
used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {}
\begin {gather*} \int \frac {\left (a^2-2 a x+x^2\right ) \left (a b^2-2 (2 a-b) b x+(3 a-2 b) x^2\right )}{\left (x (-a+x) (-b+x)^2\right )^{3/4} \left (a^3 d+\left (b^2-3 a^2 d\right ) x+(-2 b+3 a d) x^2+(1-d) x^3\right )} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {align*} \int \frac {\left (a^2-2 a x+x^2\right ) \left (a b^2-2 (2 a-b) b x+(3 a-2 b) x^2\right )}{\left (x (-a+x) (-b+x)^2\right )^{3/4} \left (a^3 d+\left (b^2-3 a^2 d\right ) x+(-2 b+3 a d) x^2+(1-d) x^3\right )} \, dx &=\int \frac {(-a+x)^2 \left (a b^2-2 (2 a-b) b x+(3 a-2 b) x^2\right )}{\left (x (-a+x) (-b+x)^2\right )^{3/4} \left (a^3 d+\left (b^2-3 a^2 d\right ) x+(-2 b+3 a d) x^2+(1-d) x^3\right )} \, dx\\ &=\frac {\left (x^{3/4} (-a+x)^{3/4} (-b+x)^{3/2}\right ) \int \frac {(-a+x)^{5/4} \left (a b^2-2 (2 a-b) b x+(3 a-2 b) x^2\right )}{x^{3/4} (-b+x)^{3/2} \left (a^3 d+\left (b^2-3 a^2 d\right ) x+(-2 b+3 a d) x^2+(1-d) x^3\right )} \, dx}{\left (x (-a+x) (-b+x)^2\right )^{3/4}}\\ &=\frac {\left (x^{3/4} (-a+x)^{3/4} (-b+x)^{3/2}\right ) \int \frac {(-a+x)^{5/4} (-a b+(3 a-2 b) x)}{x^{3/4} \sqrt {-b+x} \left (a^3 d+\left (b^2-3 a^2 d\right ) x+(-2 b+3 a d) x^2+(1-d) x^3\right )} \, dx}{\left (x (-a+x) (-b+x)^2\right )^{3/4}}\\ &=\frac {\left (4 x^{3/4} (-a+x)^{3/4} (-b+x)^{3/2}\right ) \text {Subst}\left (\int \frac {\left (-a+x^4\right )^{5/4} \left (-a b+(3 a-2 b) x^4\right )}{\sqrt {-b+x^4} \left (a^3 d+\left (b^2-3 a^2 d\right ) x^4+(-2 b+3 a d) x^8+(1-d) x^{12}\right )} \, dx,x,\sqrt [4]{x}\right )}{\left (x (-a+x) (-b+x)^2\right )^{3/4}}\\ &=\frac {\left (4 x^{3/4} (-a+x)^{3/4} (-b+x)^{3/2}\right ) \text {Subst}\left (\int \left (\frac {a b \left (-a+x^4\right )^{5/4}}{\sqrt {-b+x^4} \left (-a^3 d-b^2 \left (1-\frac {3 a^2 d}{b^2}\right ) x^4+2 b \left (1-\frac {3 a d}{2 b}\right ) x^8-(1-d) x^{12}\right )}+\frac {(3 a-2 b) x^4 \left (-a+x^4\right )^{5/4}}{\sqrt {-b+x^4} \left (a^3 d+b^2 \left (1-\frac {3 a^2 d}{b^2}\right ) x^4-2 b \left (1-\frac {3 a d}{2 b}\right ) x^8+(1-d) x^{12}\right )}\right ) \, dx,x,\sqrt [4]{x}\right )}{\left (x (-a+x) (-b+x)^2\right )^{3/4}}\\ &=\frac {\left (4 (3 a-2 b) x^{3/4} (-a+x)^{3/4} (-b+x)^{3/2}\right ) \text {Subst}\left (\int \frac {x^4 \left (-a+x^4\right )^{5/4}}{\sqrt {-b+x^4} \left (a^3 d+b^2 \left (1-\frac {3 a^2 d}{b^2}\right ) x^4-2 b \left (1-\frac {3 a d}{2 b}\right ) x^8+(1-d) x^{12}\right )} \, dx,x,\sqrt [4]{x}\right )}{\left (x (-a+x) (-b+x)^2\right )^{3/4}}+\frac {\left (4 a b x^{3/4} (-a+x)^{3/4} (-b+x)^{3/2}\right ) \text {Subst}\left (\int \frac {\left (-a+x^4\right )^{5/4}}{\sqrt {-b+x^4} \left (-a^3 d-b^2 \left (1-\frac {3 a^2 d}{b^2}\right ) x^4+2 b \left (1-\frac {3 a d}{2 b}\right ) x^8-(1-d) x^{12}\right )} \, dx,x,\sqrt [4]{x}\right )}{\left (x (-a+x) (-b+x)^2\right )^{3/4}}\\ \end {align*}
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Mathematica [F]
time = 21.18, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (a^2-2 a x+x^2\right ) \left (a b^2-2 (2 a-b) b x+(3 a-2 b) x^2\right )}{\left (x (-a+x) (-b+x)^2\right )^{3/4} \left (a^3 d+\left (b^2-3 a^2 d\right ) x+(-2 b+3 a d) x^2+(1-d) x^3\right )} \, dx \end {gather*}
Verification is not applicable to the result.
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Maple [F]
time = 0.01, size = 0, normalized size = 0.00 \[\int \frac {\left (a^{2}-2 a x +x^{2}\right ) \left (a \,b^{2}-2 \left (2 a -b \right ) b x +\left (3 a -2 b \right ) x^{2}\right )}{\left (x \left (-a +x \right ) \left (-b +x \right )^{2}\right )^{\frac {3}{4}} \left (a^{3} d +\left (-3 a^{2} d +b^{2}\right ) x +\left (3 a d -2 b \right ) x^{2}+\left (1-d \right ) x^{3}\right )}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} -\int \frac {\left (x^2\,\left (3\,a-2\,b\right )+a\,b^2-2\,b\,x\,\left (2\,a-b\right )\right )\,\left (a^2-2\,a\,x+x^2\right )}{{\left (-x\,\left (a-x\right )\,{\left (b-x\right )}^2\right )}^{3/4}\,\left (x^2\,\left (2\,b-3\,a\,d\right )-a^3\,d+x\,\left (3\,a^2\,d-b^2\right )+x^3\,\left (d-1\right )\right )} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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