Optimal. Leaf size=135 \[ -\frac {3 b \left (x+x^3\right )^{2/3} \left (5-6 x^2+9 x^4\right )}{80 x^6}+\frac {1}{4} \left (a-i \sqrt {3} a\right ) \log \left (-i x+\sqrt {3} x-2 i \sqrt [3]{x+x^3}\right )+\frac {1}{4} \left (a+i \sqrt {3} a\right ) \log \left (i x+\sqrt {3} x+2 i \sqrt [3]{x+x^3}\right )-\frac {1}{2} a \log \left (-x+\sqrt [3]{x+x^3}\right ) \]
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Rubi [A]
time = 0.12, antiderivative size = 156, normalized size of antiderivative = 1.16, number of steps
used = 9, number of rules used = 7, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.350, Rules used = {2077, 2036,
335, 281, 245, 2041, 2039} \begin {gather*} \frac {\sqrt {3} a \sqrt [3]{x} \sqrt [3]{x^2+1} \text {ArcTan}\left (\frac {\frac {2 x^{2/3}}{\sqrt [3]{x^2+1}}+1}{\sqrt {3}}\right )}{2 \sqrt [3]{x^3+x}}-\frac {3 a \sqrt [3]{x} \sqrt [3]{x^2+1} \log \left (x^{2/3}-\sqrt [3]{x^2+1}\right )}{4 \sqrt [3]{x^3+x}}-\frac {3 b \left (x^3+x\right )^{2/3}}{16 x^6}+\frac {9 b \left (x^3+x\right )^{2/3}}{40 x^4}-\frac {27 b \left (x^3+x\right )^{2/3}}{80 x^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 245
Rule 281
Rule 335
Rule 2036
Rule 2039
Rule 2041
Rule 2077
Rubi steps
\begin {align*} \int \frac {b+a x^6}{x^6 \sqrt [3]{x+x^3}} \, dx &=\int \left (\frac {a}{\sqrt [3]{x+x^3}}+\frac {b}{x^6 \sqrt [3]{x+x^3}}\right ) \, dx\\ &=a \int \frac {1}{\sqrt [3]{x+x^3}} \, dx+b \int \frac {1}{x^6 \sqrt [3]{x+x^3}} \, dx\\ &=-\frac {3 b \left (x+x^3\right )^{2/3}}{16 x^6}-\frac {1}{4} (3 b) \int \frac {1}{x^4 \sqrt [3]{x+x^3}} \, dx+\frac {\left (a \sqrt [3]{x} \sqrt [3]{1+x^2}\right ) \int \frac {1}{\sqrt [3]{x} \sqrt [3]{1+x^2}} \, dx}{\sqrt [3]{x+x^3}}\\ &=-\frac {3 b \left (x+x^3\right )^{2/3}}{16 x^6}+\frac {9 b \left (x+x^3\right )^{2/3}}{40 x^4}+\frac {1}{20} (9 b) \int \frac {1}{x^2 \sqrt [3]{x+x^3}} \, dx+\frac {\left (3 a \sqrt [3]{x} \sqrt [3]{1+x^2}\right ) \text {Subst}\left (\int \frac {x}{\sqrt [3]{1+x^6}} \, dx,x,\sqrt [3]{x}\right )}{\sqrt [3]{x+x^3}}\\ &=-\frac {3 b \left (x+x^3\right )^{2/3}}{16 x^6}+\frac {9 b \left (x+x^3\right )^{2/3}}{40 x^4}-\frac {27 b \left (x+x^3\right )^{2/3}}{80 x^2}+\frac {\left (3 a \sqrt [3]{x} \sqrt [3]{1+x^2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt [3]{1+x^3}} \, dx,x,x^{2/3}\right )}{2 \sqrt [3]{x+x^3}}\\ &=-\frac {3 b \left (x+x^3\right )^{2/3}}{16 x^6}+\frac {9 b \left (x+x^3\right )^{2/3}}{40 x^4}-\frac {27 b \left (x+x^3\right )^{2/3}}{80 x^2}+\frac {\sqrt {3} a \sqrt [3]{x} \sqrt [3]{1+x^2} \tan ^{-1}\left (\frac {1+\frac {2 x^{2/3}}{\sqrt [3]{1+x^2}}}{\sqrt {3}}\right )}{2 \sqrt [3]{x+x^3}}-\frac {3 a \sqrt [3]{x} \sqrt [3]{1+x^2} \log \left (x^{2/3}-\sqrt [3]{1+x^2}\right )}{4 \sqrt [3]{x+x^3}}\\ \end {align*}
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Mathematica [A]
time = 2.41, size = 174, normalized size = 1.29 \begin {gather*} \frac {-15 b+3 b x^2-9 b x^4-27 b x^6+40 \sqrt {3} a x^{16/3} \sqrt [3]{1+x^2} \text {ArcTan}\left (\frac {\sqrt {3} x^{2/3}}{x^{2/3}+2 \sqrt [3]{1+x^2}}\right )-40 a x^{16/3} \sqrt [3]{1+x^2} \log \left (-x^{2/3}+\sqrt [3]{1+x^2}\right )+20 a x^{16/3} \sqrt [3]{1+x^2} \log \left (x^{4/3}+x^{2/3} \sqrt [3]{1+x^2}+\left (1+x^2\right )^{2/3}\right )}{80 x^5 \sqrt [3]{x+x^3}} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 5 vs. order
3.
time = 0.77, size = 44, normalized size = 0.33
method | result | size |
meijerg | \(\frac {3 a \,x^{\frac {2}{3}} \hypergeom \left (\left [\frac {1}{3}, \frac {1}{3}\right ], \left [\frac {4}{3}\right ], -x^{2}\right )}{2}-\frac {3 b \left (\frac {9}{5} x^{4}-\frac {6}{5} x^{2}+1\right ) \left (x^{2}+1\right )^{\frac {2}{3}}}{16 x^{\frac {16}{3}}}\) | \(44\) |
risch | \(-\frac {3 b \left (x^{2}+1\right ) \left (9 x^{4}-6 x^{2}+5\right )}{80 x^{5} \left (x \left (x^{2}+1\right )\right )^{\frac {1}{3}}}+\frac {3 a \,x^{\frac {2}{3}} \hypergeom \left (\left [\frac {1}{3}, \frac {1}{3}\right ], \left [\frac {4}{3}\right ], -x^{2}\right )}{2}\) | \(51\) |
trager | \(-\frac {3 b \left (x^{3}+x \right )^{\frac {2}{3}} \left (9 x^{4}-6 x^{2}+5\right )}{80 x^{6}}-\frac {a \left (6 \ln \left (180 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right )^{2} x^{2}+144 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right ) \left (x^{3}+x \right )^{\frac {2}{3}}+144 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right ) \left (x^{3}+x \right )^{\frac {1}{3}} x +114 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right ) x^{2}-9 \left (x^{3}+x \right )^{\frac {2}{3}}-9 x \left (x^{3}+x \right )^{\frac {1}{3}}-180 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right )^{2}-4 x^{2}+96 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right )-3\right ) \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right )-6 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right ) \ln \left (180 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right )^{2} x^{2}-144 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right ) \left (x^{3}+x \right )^{\frac {2}{3}}-144 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right ) \left (x^{3}+x \right )^{\frac {1}{3}} x -174 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right ) x^{2}+15 \left (x^{3}+x \right )^{\frac {2}{3}}+15 x \left (x^{3}+x \right )^{\frac {1}{3}}-180 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right )^{2}+20 x^{2}-36 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right )+8\right )-\ln \left (180 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right )^{2} x^{2}+144 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right ) \left (x^{3}+x \right )^{\frac {2}{3}}+144 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right ) \left (x^{3}+x \right )^{\frac {1}{3}} x +114 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right ) x^{2}-9 \left (x^{3}+x \right )^{\frac {2}{3}}-9 x \left (x^{3}+x \right )^{\frac {1}{3}}-180 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right )^{2}-4 x^{2}+96 \RootOf \left (36 \textit {\_Z}^{2}-6 \textit {\_Z} +1\right )-3\right )\right )}{2}\) | \(449\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.83, size = 118, normalized size = 0.87 \begin {gather*} \frac {40 \, \sqrt {3} a x^{6} \arctan \left (-\frac {196 \, \sqrt {3} {\left (x^{3} + x\right )}^{\frac {1}{3}} x - \sqrt {3} {\left (539 \, x^{2} + 507\right )} - 1274 \, \sqrt {3} {\left (x^{3} + x\right )}^{\frac {2}{3}}}{2205 \, x^{2} + 2197}\right ) - 20 \, a x^{6} \log \left (3 \, {\left (x^{3} + x\right )}^{\frac {1}{3}} x - 3 \, {\left (x^{3} + x\right )}^{\frac {2}{3}} + 1\right ) - 3 \, {\left (9 \, b x^{4} - 6 \, b x^{2} + 5 \, b\right )} {\left (x^{3} + x\right )}^{\frac {2}{3}}}{80 \, x^{6}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {a x^{6} + b}{x^{6} \sqrt [3]{x \left (x^{2} + 1\right )}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.42, size = 88, normalized size = 0.65 \begin {gather*} -\frac {3}{16} \, b {\left (\frac {1}{x^{2}} + 1\right )}^{\frac {8}{3}} + \frac {3}{5} \, b {\left (\frac {1}{x^{2}} + 1\right )}^{\frac {5}{3}} - \frac {1}{2} \, \sqrt {3} a \arctan \left (\frac {1}{3} \, \sqrt {3} {\left (2 \, {\left (\frac {1}{x^{2}} + 1\right )}^{\frac {1}{3}} + 1\right )}\right ) + \frac {1}{4} \, a \log \left ({\left (\frac {1}{x^{2}} + 1\right )}^{\frac {2}{3}} + {\left (\frac {1}{x^{2}} + 1\right )}^{\frac {1}{3}} + 1\right ) - \frac {1}{2} \, a \log \left ({\left | {\left (\frac {1}{x^{2}} + 1\right )}^{\frac {1}{3}} - 1 \right |}\right ) - \frac {3}{4} \, b {\left (\frac {1}{x^{2}} + 1\right )}^{\frac {2}{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 1.30, size = 54, normalized size = 0.40 \begin {gather*} \frac {3\,a\,x\,{\left (x^2+1\right )}^{1/3}\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{3},\frac {1}{3};\ \frac {4}{3};\ -x^2\right )}{2\,{\left (x^3+x\right )}^{1/3}}-\frac {3\,b\,{\left (x^3+x\right )}^{2/3}\,\left (9\,x^4-6\,x^2+5\right )}{80\,x^6} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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