Optimal. Leaf size=497 \[ -\frac {i \left (-i \sqrt {1-2 k+k^2-2 i \sqrt {2} \sqrt {k} \sqrt {1+k^2}}-i k^2 \sqrt {1-2 k+k^2-2 i \sqrt {2} \sqrt {k} \sqrt {1+k^2}}+\sqrt {2} \sqrt {k} \sqrt {1+k^2} \sqrt {1-2 k+k^2-2 i \sqrt {2} \sqrt {k} \sqrt {1+k^2}}\right ) \text {ArcTan}\left (\frac {\sqrt {1-2 k+k^2-2 i \sqrt {2} \sqrt {k} \sqrt {1+k^2}} x}{1+k x^2+\sqrt {1+\left (-1-k^2\right ) x^2+k^2 x^4}}\right )}{\left (-i+\sqrt {k}\right )^2 \left (i+\sqrt {k}\right )^2 (-i+k) (i+k)}+\frac {i \left (i \sqrt {1-2 k+k^2+2 i \sqrt {2} \sqrt {k} \sqrt {1+k^2}}+i k^2 \sqrt {1-2 k+k^2+2 i \sqrt {2} \sqrt {k} \sqrt {1+k^2}}+\sqrt {2} \sqrt {k} \sqrt {1+k^2} \sqrt {1-2 k+k^2+2 i \sqrt {2} \sqrt {k} \sqrt {1+k^2}}\right ) \text {ArcTan}\left (\frac {\sqrt {1-2 k+k^2+2 i \sqrt {2} \sqrt {k} \sqrt {1+k^2}} x}{1+k x^2+\sqrt {1+\left (-1-k^2\right ) x^2+k^2 x^4}}\right )}{\left (-i+\sqrt {k}\right )^2 \left (i+\sqrt {k}\right )^2 (-i+k) (i+k)} \]
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Rubi [A]
time = 0.17, antiderivative size = 47, normalized size of antiderivative = 0.09, number of steps
used = 3, number of rules used = 3, integrand size = 43, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.070, Rules used = {1976, 2137,
209} \begin {gather*} -\frac {\text {ArcTan}\left (\frac {\sqrt {k^2+1} x}{\sqrt {k^2 x^4+\left (-k^2-1\right ) x^2+1}}\right )}{\sqrt {k^2+1}} \end {gather*}
Antiderivative was successfully verified.
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Rule 209
Rule 1976
Rule 2137
Rubi steps
\begin {align*} \int \frac {-1+k^2 x^4}{\sqrt {\left (1-x^2\right ) \left (1-k^2 x^2\right )} \left (1+k^2 x^4\right )} \, dx &=-\text {Subst}\left (\int \frac {1}{1-\left (-1-k^2\right ) x^2} \, dx,x,\frac {x}{\sqrt {\left (1-x^2\right ) \left (1-k^2 x^2\right )}}\right )\\ &=-\frac {\tan ^{-1}\left (\frac {\sqrt {1+k^2} x}{\sqrt {\left (1-x^2\right ) \left (1-k^2 x^2\right )}}\right )}{\sqrt {1+k^2}}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 4 vs. order 3 in
optimal.
time = 8.50, size = 78, normalized size = 0.16 \begin {gather*} \frac {\sqrt {1-x^2} \sqrt {1-k^2 x^2} \left (F\left (\text {ArcSin}(x)\left |k^2\right .\right )-\Pi \left (-i k;\text {ArcSin}(x)\left |k^2\right .\right )-\Pi \left (i k;\text {ArcSin}(x)\left |k^2\right .\right )\right )}{\sqrt {\left (-1+x^2\right ) \left (-1+k^2 x^2\right )}} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 9 vs. order
3.
time = 0.12, size = 269, normalized size = 0.54
method | result | size |
elliptic | \(\frac {\arctan \left (\frac {\sqrt {\left (-x^{2}+1\right ) \left (-k^{2} x^{2}+1\right )}\, \sqrt {2}}{x \sqrt {2 k^{2}+2}}\right ) \sqrt {2}}{\sqrt {2 k^{2}+2}}\) | \(51\) |
default | \(\frac {\sqrt {-x^{2}+1}\, \sqrt {-k^{2} x^{2}+1}\, \EllipticF \left (x , k\right )}{\sqrt {k^{2} x^{4}-k^{2} x^{2}-x^{2}+1}}-\frac {\munderset {\underline {\hspace {1.25 ex}}\alpha =\RootOf \left (k^{2} \textit {\_Z}^{4}+1\right )}{\sum }\frac {-\frac {\arctanh \left (\frac {\left (2 k^{2} \underline {\hspace {1.25 ex}}\alpha ^{2}-k^{2}-1\right ) \left (\underline {\hspace {1.25 ex}}\alpha ^{2} k^{4}+k^{4} x^{2}-2 k^{2} \underline {\hspace {1.25 ex}}\alpha ^{2}+6 k^{2} x^{2}+\underline {\hspace {1.25 ex}}\alpha ^{2}-4 k^{2}+x^{2}-4\right )}{2 \left (k^{4}+6 k^{2}+1\right ) \sqrt {-k^{2} \underline {\hspace {1.25 ex}}\alpha ^{2}-\underline {\hspace {1.25 ex}}\alpha ^{2}}\, \sqrt {k^{2} x^{4}-k^{2} x^{2}-x^{2}+1}}\right )}{\sqrt {-k^{2} \underline {\hspace {1.25 ex}}\alpha ^{2}-\underline {\hspace {1.25 ex}}\alpha ^{2}}}+\frac {2 \sqrt {-x^{2}+1}\, \sqrt {-k^{2} x^{2}+1}\, \underline {\hspace {1.25 ex}}\alpha ^{3} k^{2} \EllipticPi \left (x , -k^{2} \underline {\hspace {1.25 ex}}\alpha ^{2}, k\right )}{\sqrt {k^{2} x^{4}-k^{2} x^{2}-x^{2}+1}}}{\underline {\hspace {1.25 ex}}\alpha ^{3}}}{4 k^{2}}\) | \(269\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.46, size = 62, normalized size = 0.12 \begin {gather*} -\frac {\arctan \left (\frac {2 \, \sqrt {k^{2} x^{4} - {\left (k^{2} + 1\right )} x^{2} + 1} \sqrt {k^{2} + 1} x}{k^{2} x^{4} - 2 \, {\left (k^{2} + 1\right )} x^{2} + 1}\right )}{2 \, \sqrt {k^{2} + 1}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (k x^{2} - 1\right ) \left (k x^{2} + 1\right )}{\sqrt {\left (x - 1\right ) \left (x + 1\right ) \left (k x - 1\right ) \left (k x + 1\right )} \left (k^{2} x^{4} + 1\right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {k^2\,x^4-1}{\left (k^2\,x^4+1\right )\,\sqrt {\left (x^2-1\right )\,\left (k^2\,x^2-1\right )}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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