Optimal. Leaf size=24 \[ \frac {x \left (2-\frac {e}{4}+\frac {-4+x}{x}+x\right )}{20 \log (x)} \]
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Rubi [F]
time = 0.14, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps
used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {}
\begin {gather*} \int \frac {16-12 x+e x-4 x^2+\left (12 x-e x+8 x^2\right ) \log (x)}{80 x \log ^2(x)} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {16+(-12+e) x-4 x^2+\left (12 x-e x+8 x^2\right ) \log (x)}{80 x \log ^2(x)} \, dx\\ &=\frac {1}{80} \int \frac {16+(-12+e) x-4 x^2+\left (12 x-e x+8 x^2\right ) \log (x)}{x \log ^2(x)} \, dx\\ &=\frac {1}{80} \int \left (\frac {16-(12-e) x-4 x^2}{x \log ^2(x)}+\frac {12-e+8 x}{\log (x)}\right ) \, dx\\ &=\frac {1}{80} \int \frac {16-(12-e) x-4 x^2}{x \log ^2(x)} \, dx+\frac {1}{80} \int \frac {12-e+8 x}{\log (x)} \, dx\\ &=\frac {1}{80} \int \left (\frac {12 \left (1-\frac {e}{12}\right )}{\log (x)}+\frac {8 x}{\log (x)}\right ) \, dx+\frac {1}{80} \int \frac {16-(12-e) x-4 x^2}{x \log ^2(x)} \, dx\\ &=\frac {1}{80} \int \frac {16-(12-e) x-4 x^2}{x \log ^2(x)} \, dx+\frac {1}{10} \int \frac {x}{\log (x)} \, dx+\frac {1}{80} (12-e) \int \frac {1}{\log (x)} \, dx\\ &=\frac {1}{80} (12-e) \text {li}(x)+\frac {1}{80} \int \frac {16-(12-e) x-4 x^2}{x \log ^2(x)} \, dx+\frac {1}{10} \text {Subst}\left (\int \frac {e^{2 x}}{x} \, dx,x,\log (x)\right )\\ &=\frac {1}{10} \text {Ei}(2 \log (x))+\frac {1}{80} (12-e) \text {li}(x)+\frac {1}{80} \int \frac {16-(12-e) x-4 x^2}{x \log ^2(x)} \, dx\\ \end {aligned} \end {gather*}
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Mathematica [A]
time = 0.04, size = 22, normalized size = 0.92 \begin {gather*} \frac {-16+12 x-e x+4 x^2}{80 \log (x)} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 4 vs. order
3.
time = 0.04, size = 54, normalized size = 2.25
method | result | size |
norman | \(\frac {-\frac {1}{5}+\left (-\frac {{\mathrm e}}{80}+\frac {3}{20}\right ) x +\frac {x^{2}}{20}}{\ln \left (x \right )}\) | \(21\) |
risch | \(-\frac {x \,{\mathrm e}-4 x^{2}-12 x +16}{80 \ln \left (x \right )}\) | \(21\) |
default | \(\frac {{\mathrm e} \expIntegral \left (1, -\ln \left (x \right )\right )}{80}+\frac {{\mathrm e} \left (-\frac {x}{\ln \left (x \right )}-\expIntegral \left (1, -\ln \left (x \right )\right )\right )}{80}+\frac {x^{2}}{20 \ln \left (x \right )}+\frac {3 x}{20 \ln \left (x \right )}-\frac {1}{5 \ln \left (x \right )}\) | \(54\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [C] Result contains higher order function than in optimal. Order 4 vs. order
3.
time = 0.30, size = 52, normalized size = 2.17 \begin {gather*} -\frac {1}{80} \, {\rm Ei}\left (\log \left (x\right )\right ) e + \frac {1}{80} \, e \Gamma \left (-1, -\log \left (x\right )\right ) - \frac {1}{5 \, \log \left (x\right )} + \frac {1}{10} \, {\rm Ei}\left (2 \, \log \left (x\right )\right ) + \frac {3}{20} \, {\rm Ei}\left (\log \left (x\right )\right ) - \frac {3}{20} \, \Gamma \left (-1, -\log \left (x\right )\right ) - \frac {1}{10} \, \Gamma \left (-1, -2 \, \log \left (x\right )\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.39, size = 21, normalized size = 0.88 \begin {gather*} \frac {4 \, x^{2} - x e + 12 \, x - 16}{80 \, \log \left (x\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.03, size = 19, normalized size = 0.79 \begin {gather*} \frac {4 x^{2} - e x + 12 x - 16}{80 \log {\left (x \right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.40, size = 21, normalized size = 0.88 \begin {gather*} \frac {4 \, x^{2} - x e + 12 \, x - 16}{80 \, \log \left (x\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 1.27, size = 28, normalized size = 1.17 \begin {gather*} -\frac {-4\,x^4+\left (\mathrm {e}-12\right )\,x^3+16\,x^2}{80\,x^2\,\ln \left (x\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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